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Correct option is (B) 10 cm

Slant height of cone is \(l=\sqrt{r^2+h^2}\)

\(=\sqrt{6^2+8^2}=\sqrt{36+64}\)

\(=\sqrt{100}\) = 10 cm

Correct option is  B) 10 cm

(c) \(48\sqrt3\) cm².

Let each side of the base of the prism be a cm. 

Total surface area = \(72\sqrt3\) cm³ 

⇒ (Perimeter of the base × Height) + 2 (Area of base) = \(72\sqrt3\)

⇒ 3a x 4 + 2 \(\big(\frac{\sqrt3}{4}a^2\big)\) = \(72\sqrt3\)

⇒ \(\sqrt3a^2+24a-144\sqrt3=0\) ⇒ \(a^2+8\sqrt3a-144=0\)

⇒ \((a+12\sqrt3)(a-4\sqrt3)=0\)

⇒ \(a=-12\sqrt3\) or \(4\sqrt3\)  ⇒ a = \(4\sqrt3\)  as a > 0

∴ Volume of the prism = Area of the base × Height 

= \(\frac{\sqrt3}{4}\times(4\sqrt3)^2\times\,4cm^2=48\sqrt3\) cm².

Correct option is (A) lbh

Volume = Area of base \(\times\) Height

\(=lb\times h\)   (Base = rectangular side)

= \(lbh\)

Correct option is  A) lbh

(c) 10 cm, 132 cm²

For the first prism, a = 5 cm, b = 12 cm, c = 13 cm 

⇒ s = \(\frac{a+b+c}{2}=\frac{5+12+13}{2}\) = 15 cm

Area of the base = \(\sqrt{s(s-a)(s-b)(s-c)}\)

= \(\sqrt{15\times10\times3\times2}\) cm² = 30 cm²

Let V₁ be the volume of the prism. Then, 

V₁ = Area of the base x height 

⇒ V₁ = (30 × 18) cm³ = 540 cm³ 

Let S₁ be the total surface area of the prism. Then 

S₁ = Lateral surface area + 2 (Area of base) 

= (Perimeter of the base × height) + 2 (Area of base) 

= (30 × 18 + 2 × 30) cm² = 600 cm²

Let h be the height of new prism. Then, for the new prism 

a = 9 cm, b = 12 cm, c = 15 cm ⇒ s = \(\frac{9+12+15}{2}=18\) cm

Area of the base = \(\sqrt{s(s-a)(s-b)(s-c)}\)

= \(\sqrt{18\times9\times6\times3}\) cm² = 54 cm²

∴ V₂ = Volume of new prism = (54 × h) cm³ 

V₁ = V₂ ⇒ 54 × h = 540 ⇒ h = 10 cm. 

Let S₂ be the total surface area of the new prism. Then, 

S₂ = (36 × 10 + 2 × 54) cm² = 468 cm² 

Change in the whole surface area = S₁ – S₂ 

= (600 – 468) cm² = 132 cm².

Correct option is (A) 2πr (r + h)

Total surface area of a cylinder

= Curved surface area of cylinder + Area of base + Area of top

\(=2\pi rh+\pi r^2+\pi r^2=2\pi rh+2\pi r^2\)

= \(2\pi r\,(r+h)\)

A) 2πr (r + h)

Correct option is (B) \(42.875\,cm^3\)

Lateral surface area of cube \(=a^3\)

\(=(3.5)^3cm^3=42.875\,cm^3\)

Correct option is  B) 42.875 cm³

Let the original and changed dimensions are l, b, 

h and 31, 3b, 3h 

Original T.S.A. = 2 (lb + bh + lh) 

Changed T.S.A 

= 2 (3l . 3b + 3b . 3h + 3l. 3h)

Changed T S.A. = 2 (9lb + 9bh + 9lh) 

= 9 × [2 (lb + bh + lh)] 

= 9 [original T.S.A.] 

Thus original T.S.A. increased by 9 times if each dimension is tripled.

Correct answer is

(c) -5

Let us assume the edge of the cube be a 

We know that, 

Volume of the cube = a³

a³ = 729 cm³

a = \(\sqrt[3]{729}{}\)

a = 9 cm 

We also know that, 

Total surface area of cube 

= 6a² = 6 × 9 × 9 

= 486 cm²

Correct option is (D) 256 cm²

a = 8 cm

\(\therefore\) Lateral surface area of cube \(=4a^2\)

 \(=4\times8^2=64\times4\)

\(=256\,cm^2\)

Correct option is  D) 256 cm²

Let us assume the edge of the cube be a 

We know that, 

Total surface area of the cube = 6a²

6a² = 1176 cm²

a = \(\sqrt{\frac{1176}{6}}{}\)

a = \(\sqrt{196}\)

a = 14 cm 

We also know that, 

Volume of the cube = a³ = (14)³ 

= 2744 cm³

Correct answer is

(b) 3

Correct answer is

(d) 1

Correct answer is

(a) 7

Correct option is (D) Cylinder

Rectangle, Circle and Square is a 2D-object while Cylinder is a 3D-object.

Correct option is D) Cylinder

(i) We have, 

Length of the edge of the cube = a = 7 cm 

We know that, 

Volume of cube = a³ = 7³ = 343 m³ 

Also, 

Lateral surface area of the cube 

= 4a² = 4 × 7 × 7 

= 196 m² 

Total surface area of the cube 

= 6a² = 6 × 7 × 7 

= 294 m² 

(ii) We have, 

Length of the edge of the cube = a = 5.6 cm 

We know that, 

Volume of cube = a³ = (5.6)³ = 175.616 cm³ 

Also, 

Lateral surface area of the cube = 4a² 

= 4 × 5.6 × 5.6 

= 125.44 cm² 

Total surface area of the cube = 6a² 

= 6 × 5.6 × 5.6 

= 188.16 cm² 

(iii) We have, 

Length of the edge of the cube = a = 8 dm 5 cm = 85 cm 

We know that, 

Volume of cube = a³ = 85³ = 614125 cm³ 

Also, 

Lateral surface area of the cube = 4a² 

= 4 × 85 × 85 

= 28900 cm² 

Total surface area of the cube = 6a² 

= 6 × 85 × 85 

= 43350 cm²

Correct option is (A) 10 cm

Let edge of cube be a.

\(\therefore a^3=1000=10^3\)   \((\because\) Volume of cube \(=a^3)\)

\(\Rightarrow\) a = 10 cm

Correct option is  A) 10 cm

Volume V = lbh = 12 × 10 × 8 = 960cm³

Correct option is (C) 6

There are total 6 surfaces in a cuboid.

Correct option is  C) 6

Correct option is (C) 180 cm

There are 12 edges in a cube and each edge is of equal length (15 cm).

\(\therefore\) Total length of all the edges of the cube \(=12\times15\)

= 180 cm

Correct option is  C) 180 cm

Volume V = l³ = 10 × 10 × 10 = 1000cm³

V = edge³ = 1000 = 10 × 10 × 10 = 10³ 

∴ Edge =10 cm

The correct answer is (D) 3 – phosphoglyceraldehyde → 1, 3-bisphosphoglycerate

Volume of a cube of side (s) is V₁ = a³ 

If the length of the side is reduced by half then s = a/2

∴ Volume of cube (V₂ ) = s³ 

= (a/2)³

= a/2 x a/2 x a/2

= a³/8 = 1/8(a³)

∴ V₂ = 1/8 × V₁ 

∴ V₁ = 8V₂

Correct option is (B) 210 cm²

Lateral surface area of cuboid \(=2\,(l+b)h\)

\(=2\,(12+9)\times5\)

\(=10\times21\) = \(210\,cm^2\)

Correct option is  B) 210 cm²

Two kinds of diabetes are:

(i) Diabetes insipidus 

(ii) Diabetes mellitus.

Symptoms and causes of diabetes insipidus:

(i) It is due to deficiency of antidiuretic hormone (ADH).

(ii) In this urination is frequent and copious, resulting in loss of water from the body and the person feels thirsty.

Symptoms and causes of diabetes mellitus:

(i) It is due to insufficient secretion of insulin hormone.

(ii) Presence of glucose in urine and high level of glucose in blood.

The correct answer is (B) 2 – phosphoglycerate

The Answer is  14,400 cm².

Given:-

dimensions of cuboid=120*60*30. 

Volume of Cuboid=l*b*h

Volume of Cuboid=120*60*30= 2,16,000  cm³

Volume of Cuboid = Volume of Cube = 2,16,000   [given]

Volume of Cube= a³ or side³

2,16,000= a³

60=a

TSA of Cube= 4a²

TSA=    4*(60)²  = 14,400 cm²

Dihydroxyacetone phosphate (DHAP) and 3-phosphoglyceraldehyde (3- PGAL) are the products of cleavage in glycolysis.

In glycolysis, dehydration occurs when 2-Phosphoglyceric acid loses a water molecule (dehydration) to form phosphoenol pyruvic acid in presence of the enzyme enolase.

(B) carbohydrate & (D) glycoprotein

1. Thyroid

2. Thyroxin

3. Insulin

4. Controls blood sugar level

5. Adrenal

6. Adrenaline

7. Pituitary

8. Stimulates thyroid gland

A financial ratio is a mathematical number that measures the relationship between two accounting figures.

Balance Sheet ratios are

• Current ratio
• Liquid ratio.

The common size statement requires choose of common base.

Explanation: Common size statements require choosing a common base for drawing conclusions. All the items in the balance sheet or the income statement are converted as a percentage of a common base and compared to the previous year or for the same period with different firms. The common base is an aggregate such as total of balance sheet or total of net sales.

(D) All the above

Gross profit ratio = \(\frac{Gross\,profit}{Net\,sales}\times100\)

Where Gross profit = Net sales – Cost of goods sold.

Cost of goods sold = Opening stock + Purchase – Purchase return + Direct expense – Closing stock

Net sales = Sales – Sales return.

Comparative balance sheet is a technique of financial analysis in which financial figures for two or more years are placed side by side to facilitate comparison, these are called comparative financial balance sheet.

Cost of goods sold = Opening stock + Purchase – Purchase return + Direct expense – Closing stock

These are the final accounts prepared at the end of the accounting period and include balance sheet and statement of profit and loss along with notes to accounts

Gross profit = Rs. 220,000(Given)

Operating Expenses = Rs. 85,000(Given)

Non-Operating Expenses = Rs. 30,000(Given)

Operating Profit = Gross Profit - Operating Expenses

Operating Profit = 220,000 - 85,000 = Rs. 135,000

1. Bank and Financial Organisations.
2. Creditors.
3. Govt, and Other Departments.
4. Debenture holders and Other Future Investors.

Gross profit = Net sales – Cost of goods sold.

Cost of goods sold = Opening stock + Purchase – Purchase return + Direct expense – Closing stock

Net sales = Sales – Sales return.

Current ratio = \(\frac{Current\,assets}{Current\,liabilities}\)

• Balance Sheet
• Profit & Loss Account
• Notes to Account and Explanatory Notes
• Cash Flow Statement.

Financial analysis is used only by the creditors. 

False

Financial statements are affected by personal judgement like, by which method, stock’s valuation will done. Its decision will personal decision of manager which will effected of financial statements.