Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Which compound is formed when an organic nitrogen compound is fused with sodium metal?

Answer»

Answer is NaCN

2.

0.2632g of silver bromide is obtained from 0.2562g of an organic compound. Find the percentage of bromine in the compound.

Answer»

1. Mass of organic compound (W1) = 0.2562g 

2. Mass of AgBr obtained (W2) = 0.2632g.

3.

Define Oxidation and Reduction on the basis of Electronic Concept.

Answer»

Electronic Concept of Oxidation and Reduction

Oxidation: The process in which there is loss of electrons.

Reduction: The process in which there is gain of electrons.

4.

Why is an organic compound fused with Sodium fortesting nitrogen,halogens and sulphur?

Answer»

On fusing with sodium metal the elements presents in an organic compounds are converted in to sodium salts which are water soluble which can be filtered and detected by the respectivetests.

5.

It is not advisable to use sulphuric acid in place of acetic acidfor acidification while testing sulphur by lead acetate test. Give reason.

Answer»

Lead acetate on reacting with sulphuric acid will give a white ppt of lead sulphatewhih interfere in the detection of sulphur.

(CH3COO)2Pb +H2SO4 → PbSO4+ 2CH3COOH

6.

0.189g of an organic substance containing chlorine gave carius method 0. 287g of silver chloride. Calculate the percentage of chlorine in the substance.

Answer»

1. Mass of organic compound taken (W1) = 0.189 g 

2. Mass of AgCli ppt (W2) = 0.287 g

7.

Explain the estimation of phosphorus in organic compound by carius method.

Answer»

It is also estimated by carius method the known mass of organic compound containing phosphorus is heated with fuming HNO3 when phosphorus is oxidised to phosphoric acid (H3PO4). To this, magnesia mixture (MgSO4 + NH4OH + NH3Cl) is added when phosphoric acid precipitates as magnesium ammonium phosphate (MgNH4PO4). This precipitate is filtered, washed, dried and ignited when it is converted to magnesium pyrophosphate (Mg2P2O3).

The weight of Mg2P2CO7 is determied from which the percentage of phosphorus is the compound can be calculated. Observations and Calculations: 

1. Mass of organic compound taken = w1, g. 

2. Mass of Mg2P2O7 obtained = W2g. 

We have contains 62g of phosphorus.

W2g of Mg2P2O7 Will contain \(\frac{62\times w_2}{222}\)g of phosphorus 

This amount of phosphorus was present in wig of the compound

∴ %P = \(\frac{62\times w_2}{222}\) x \(\frac{100}{w_1}\)

8.

What are formulae of (i) Sodium nitroprusside (ii) Ferric ferrocyanide?

Answer»

(i) Na2[Fe(CN)5NO] 

(ii) Fe2[Fe(CN)6]3

9.

Which class of compounds are tested with the help of Beilstein test.

Answer»

Halogen containing organic compounds but some other compounds like urea is respond to this test.

10.

Mention demerits of Bohr’s Atomic model.

Answer»

Demerits of Bohr’s atomic model :

  • Bohr’s atomic model (theory) failed to account for finer details of the atomic spectrum of hydrogen as observed in sophisticated spectroscopic experiments.
  • Bohr’s atomic model (theory) was unable to explain the spectrum of atoms other than hydrogen.
  • Bohr’s atomic model (theory) could not explain the splitting of spectral lines in the presence of a magnetic field (Zeeman effect) or electric field (Stark effect).
  • Bohr’s atomic model (theory) failed to explain the ability of atoms to form molecules by chemical bonds.
11.

Write postulates of Bohr’s Theory of hydrogen atom.

Answer»

Postulates of Bohr’s theory of hydrogen atom : 

i. The electron in the hydrogen atom can move around the nucleus in one of the many possible circular paths of fixed radius and energy. 

These paths are called orbits, stationary states or allowed energy states. 

These orbits are arranged concentrically around the nucleus in an increasing order of energy.

ii. The energy of an electron in the orbit does not change with time. 

However,

The electron will move from a lower stationary state to a higher stationary state if and when the required amount of energy is absorbed by the electron. 

Energy is emitted when electron moves from a higher stationary state to a lower stationary state. 

The energy change does not take place in a continuous manner.

iii. The frequency of radiation absorbed or emitted when transition occurs between two stationary states that differ in energy by ΔE is given by the following expression :

ν = \(\frac{vE}{h}=\frac{E_2-E_1}{h}\) ………….(1)

Where E1 and E2 are the energies of the lower and higher allowed energy states respectively. 

This expression is commonly known as Bohr’s frequency rule.

iv. The angular momeñtum of an electron in a given stationary state can be expressed as mvr = n × h/2π

Where, n 1,2, 3

Thus,

An electron can move only in those orbits for which its angular momentum is integral multiple of h/2π.

Thus,

Only certain fixed orbits are allowed.

12.

What are the Characteristics of electromagnetic radiations?

Answer»

Characteristics of electromagnetic radiations: 

Wavelength: It may be defined as the distance between two neighbouring crests or troughs of wave as shown. It is denoted by λ. 

Frequency (ν): It may be defined as the number of waves which pass through a particular point in one second.

Velocity (v): It is defined as the distance travelled by a wave in one second. In vacuum all types of electromagnetic radiations travel with the same velocity. Its value is 3 x 108 m sec-1. It is denoted by v

Wave number: Wave number (bar v) is defined as the number of wavelengths per unit length.

Velocity = frequency x wavelength c = νλ

13.

Arrange the following type of radiations in increasing order of frequency (a) radiation from microwave oven (b) amber light from traffic signal (c) radiation from FM radio (d) cosmic rays from outer space and (e) X-rays.

Answer»

Cosmic rays < X-rays < amber colour < microwave < FM.

14.

A 5f orbital hasa. one nodeb. two nodesc. three nodesd. four nodes

Answer»

Correct option is d. four nodes

15.

Find the wave length of Yellow emission of sodium whose frequency 5.09 x 1014 per sec.

Answer»

wave length = C/V0 = 3x 108 /5.09x1014 

= 5.89 x10-7 meter

16.

Write the difference between orbit &amp; orbital.

Answer»
OrbitOrbital
1. A definite circular path around the nucleus in which electron suppose to be revolved.It is a 3-dimensional network around the nucleus in which probability of finding the electron is maximum.
2. It represents planar motion of 2-dimensional electrons around the nucleus.It represents the 3-dimensional motion of electron around the nucleus.
17.

What is the difference between an orbit and orbital?

Answer»

1. An orbit is a well defined path of electron that revolves around the nucleus.

2. An orbital is the space around the nucleus, where the probability of finding electrons is maximum.

18.

Electrons must …………… energy to move to a higher energy level.A) absorb B) emit C) radiate D) no change

Answer»

Correct option is A) absorb

19.

(a) What is meant by (i) atomic number, and (ii) mass number, of an element? Explain with the help of an example. (b) What is the relation between the atomic number and mass number of an element? (c) If an element M has mass number 24 and atomic number 12, how many neutrons does its atom contain?

Answer»

(a) Atomic no. is the number of protons in one atom of an element. 

Mass no. is the total number of protons and neutrons present in one atom of the element.

Example- The total no. of protons in a carbon atom is 6, so its atomic no. is 6. 

Also, one atom of Na contains 11 protons and 12 neutrons, so its mass no. is 23. 

(b). Mass No. = Atomic no. + No. of neutrons 

(c). No. of neutrons = Mass No. – Atomic no. 

= 24 – 12 = 12

20.

Mention the properties of cathode rays.

Answer»

The properties of cathode rays are:

1. cathode rays are negatively charged particles 

2. cathode rays are a stream of particles which travels in straight line. 

3. Cathode rays can effect a photographic plate

21.

Why cannot the motion of an electron around the nucleus be determined accurately?

Answer»

It is because we need high energy radiation to see an electron which change the velocity of electron.

22.

(a) Describe Bohr’s model of the atom. How did Neils Bohr explain the stability of atom? (b) An element has an atomic number of 11 and its mass number is 23. What is the arrangement of electrons in the shells? State nuclear composition of an atom of the element.

Answer»

(a) Bohr Model of atom: 

An atom is made up of three particles: Electrons, neutrons and protons. 

1. The protons and neutrons are located in a small nucleus at the centre of atom 

2. The electrons revolve rapidly around the nucleus at the centre of the atom 

3. There is a limit to the number of electrons that each energy level can hold 

4. Each energy level is associated with a fixed amount of energy. 

5. There is no change in the energy of electrons as long as they keep revolving in the same energy level. 

Bohr explained the stability through the concept of revolution of electrons in different energy levels. The change in the energy of an electron occurs when it jumps from lower to higher energy levels. When it gains energy, it excite from lower to higher and vice versa. Thus energy is not lost and the atom remains stable. 

(b) Given: 

Atomic no. = 11 

Mass no. = 23 

Then, electronic configuration – (2,8,1) 

Nuclear composition is – 11 protons and 12 neutrons

23.

Electrons must ………………. energy to move to a lower energy level. A) absorb B) emit C) radiate D) both B &amp; C

Answer»

D) both B & C

24.

Based on scientists and their inventions match Set – I with Set – II:Set – ISet – IIP. Bohr Buryx. Existence of a nucleusQ. Thompsony. Maximum no. of electrons in a shellR. Rutherfordz. Subatomic particleA) P – y, Q – z, R – x B) P – y, Q – x, R – z C) P – x, Q – y, R – z D) P – z, Q – x, R – y

Answer»

A) P – y, Q – z, R – x

25.

What is absorption spectrum?

Answer»

Absorption spectrum: The spectrum formed by the absorption of energy when electron jumps from lower energy level to higher energy level is called absorption spectrum. It contains dark lines on bright background.

26.

Explain the significance of three quantum numbers in predicting the positions of an electron in an orbit.(OR) How are quantum numbers helpful to understand the atomic structure?

Answer»

Significance of three quantum numbers in predicting the positions of an electron in an orbit. 

1) Principal quantum number (n) : 

The principal quantum number explains about the size and energy of shells (or) orbitals. It is denoted by n. 

As ‘n’ increases, the orbitals become larger and the electrons in those orbitals are farther from the nucleus.

It takes values 1, 2, 3, 4, ……………. for that the shells are represented by letters K, L, M, N, ……….

The number of electrons in a shell is limited to 2n2

2) The Angular – momentum quantum number (l) : 

The angular momentum quantum number defines the shape of the orbital occupied by the electron and the orbital angular momentum of the electron, is in motion.

l takes values from 0 to n – 1 for these values the orbitals are designated by letters s, p, d, f, ………….. etc. 

l also governs the degree with which the electron is attached to nucleus. The larger the value of l, the smaller is the bond with which it is maintained with the nucleus.

3) Magnetic orbital quantum number (m ) : 

The orientation of orbital with external magnetic field determines magnetic orbital quantum number. 

m| has integer values between – l and l including zero. 

The number of values for m, are 2l + l, which give the number of orbitals per sub-shell. The maximum number of electrons in orbitals in the sub-shell is 2 (2l + l).

27.

Rutherford’s model could not explain A) positivity of the atom B) negativity of the atomC) neutrality of the atom D) stability of the atom

Answer»

D) stability of the atom

28.

The common property of the above atoms is A) same number of shells B) same atomic number C) same valency D) above all

Answer»

C) same valency

29.

Explain the cleansing action of soaps.

Answer»

When soap is dissolved in water, its hydrophobic ends attach themselves to dirt and remove it from the cloth.

First, the molecules of soap arrange themselves in micelle formation and trap the dirt at the centre of the cluster.

These micelles remain suspended in water like particles in a colloidal solution.

The various micelles present in water do not come together to form a precipitate as each micelle repels the other because of the ion-ion repulsion.

Thus, the dust particles remain trapped in micelles (which remain suspended) and are easily rinsed away with water.

 Hence, soap micelles remove dirt by dissolving it in water.

30.

Most of the mass of an atom is concentrated in A) protons B) electrons C) neutronsD) nucleus

Answer»

Correct option is D) nucleus

31.

How many quantum numbers are needed to designate an orbital?

Answer» Three quantum numbers.
32.

Rainbow is an example for continuous spectrum – explain. (OR)Which is naturally occurring continuous spectrum ? Explain.

Answer»

1. Rainbow is a spectrum of different colours (VIBGYOR) with different wavelengths. 

2. These colours are continuously distributed. 

3. There is no fixed boundary for each colour. 

4. Hence, rainbow is a continuous spectrum.

33.

How many elliptical orbits are added by Sommerfeld in third Bohr’s orbit ? What was the purpose of adding these elliptical orbits?

Answer»

Sommerfeld added two elliptical orbits to Bohr’s third orbit.

Purpose of adding elliptical orbits : 

1. Bohr’s model failed to account for splitting of line spectra and line spectrum. 

2. In an attempt to account for the structure of line spectrum, Sommerfeld modified Bohr’s atomic model by adding elliptical orbits.

34.

According to Bohr, while electrons are revolving in …………….. A) discrete B) stationary C) higher energy D) both A &amp; B

Answer»

D) both A & B

35.

What type of metals are used in photoelectric cell? Give one example.

Answer»

The metals having large size and less work function are used in photo electriccell.eg. Li

36.

Which series of lines of the hydrogen spectrum lie in the visible region?

Answer»

Balmer series of lines of the hydrogen spectrum lies in the visible regio

Four of the Balmer lines are in the technically "visible" part of the spectrum, with wavelengths longer than 400 nm and shorter than 700 nm.
37.

What physical meaning is attributed to the square of the absolute value of wave function, \(|\psi|^2\)?

Answer»

\(|\psi|^2\) show the probability of finding the electron at a point with coordinates (x, y, z).

38.

State physical significance of Ψ2.

Answer»

Ψ2 represents probability of finding an electron.

39.

Mention the physical significance of ψ and ψ2.

Answer»

Physical significance of ψ: All the information about the electron in an atom is stored in its orbital wave function ψ and quantum mechanics makes it possible to extract this information out of ψ.

Physical significane of ψ2: From the value of | ψ|2 at different points with in an atom, it is possible to predict the region around the nucleus where electron will most probably be found.

40.

What is the physical significance of ψ2 up?

Answer»

ψ2 represent probability of finding an electron.

41.

Atoms having these orbitals are stable A) half filled B) completely filled C) both A and B D) none of these

Answer»

C) both A and B

42.

From the figure match the following: a) X-rays — i) 700nm-1000nm b) IRrays — ii) lm to 1 km c) Radio rays — iii) Above 1 km d) Broadcast — iv) 0.01 to 10 nm bond A) a → iv, b → i, c → ii, d → iii B) a →i, b → ii, c → iii, d → iv C) a → iv, b → iii, c → ii, d → n D) a → iii, b → iv, c →i, d → ii

Answer»

A) a → iv, b → i, c → ii, d → iii

43.

Why are Bohr's orbits called stationary states?

Answer»

This is because the energies of the orbits in which the electrons revolve are fixed.

44.

What do you mean by saying that energy of the electron is quantized?

Answer»

This means that the electrons in an atom have only definite values of energies.

45.

When electrons from various energy levels fall to first energy level in hydrogen, name the series of spectral lines.

Answer»

Lyman Series

46.

Which rule is violated in the following electronic configuration?

Answer»

The rule violated is Hund’s rule.

47.

The rule violated in this electron configuration is 1s2 , 2s°, 2p3 A) Pauli’s exclusion principle B) Hund’s rule C) Aufbau principle D) Heisenberg uncertainty principle

Answer»

Correct option is  C) Aufbau principle

48.

The rule violated in electron configurations of Chromium and Copper is …………. A) Aufbau B) Hund C) Pauli’s exclusionD) Heisenberg uncertainty

Answer»

Correct option is  A) Aufbau

49.

Quantum mechanical model was proposed by ……………….. A) Neils Bohr B) Sommerfeld C) Erwin SchrodingerD) Lande

Answer»

C) Erwin Schrodinger

50.

Why Rutherford’s model could not explain the stability of an atom?

Answer»

According to the electromagnetic theory of Marwells, charged particles when accelerated should emit electromagnetic radiation. Therefore, an electron in an orbit will emit radiation; the orbit will then continue to shrink which does not happen in an atom.