Explore topic-wise InterviewSolutions in Current Affairs.

Bulbs in parallel: A number of bulbs arranged directly.

The safety device used in, an electric circuit is a fuse.

In a series circuit, electricity has only one path to flow through.

Parallel circuit: Circuits in which a power source is directly connected to two or more components are called parallel circuits.

A parallel circuit has more than one path for the flow of electricity.

Cell: A single unit for electrolysis or conversion of chemical into electric energy, usually consisting of a container with electrodes and an electrolyte; a battery also called electrochemical cell.

Series circuit: An electric circuit connected so that current passes through each circuit element in turn without branching.

Battery: Two or more connected cells that produce a direct current by converting chemical energy to electrical energy.

An electric iron, electric cooker, and electric heater contain a coil of wire made up of Nichrome.

All components in our houses are connected in parallel.

Connecting small cells in series, we get a battery.

The battery cells in the torchlight are kept in series.

The two terminals of an electric cell are called positive (+ve) and negative (-ve).

An electric bulb glows when an electric current passes through it.

This Nichrome is called the filament of the appliance.

In a series connection of bulbs, if one bulb gets fused, all the other bulbs in the series will stop glowing.

In a closed electric circuit, the electric current passes from one terminal of the electric cell to the other terminal.

The two muscular layers present In the anal sphincter control the exit of stools from the body.

Oesophagus is a muscular and an elastic tube.

The schematic diagram of the oesophagus tells about its structure, secretion and function.

Yes, the control is voluntary in adults and it is involuntary in infants.

An electric bulb has a filament that is connected to its terminals.

• Strength of aqueous solution of H₂O₂ is expressed in ‘volume’ units i.e., volume strength.
• The commercially marketed 30% (by mass) solution of H₂O₂ has volume strength of 100 volume.
• It means that 1 mL of 30% solution of H₂O₂ will give 100 mL oxygen at STP.

Thus, Volume strength refers to the volume of oxygen (O₂) in litres at STP obtained by decomposition of 1 litre of the sample.

30°C to 35°C could be the range of temperature for us to relish food items.

correct option is B) Soldier

A) Services sector

Correct option is B) Services

A) Final goods

correct option is C) Services

D) all of the above

The stranger did not seem to show so much of concern as Satish’s mother. Satish’s mother dominated the conversation. She went on advising the two boys. She thought Arun’s ‘mother’ was incapable of taking care of her son.

When the train was about to move, Arun kissed the strange woman on her cheek. He addressed her as ‘mother’ and bade her goodbye.

i) sp²

ii) sp³

i) Used as molecular wires. 

ii) Used in integrated circuits.

Nanotubes are allotropic form of carbon.

Nanotubes: Nanotubes are another allotropic form of carbon.

Catenation: Any element forms bands among its own atoms to give big molecules. This property is called catenation.

Tetravalency: The valency of a carbon atom is four. This valency of carbon otherwise is called tetravalency.

All the substances around us are alike because everything around is made up of matter. The air we breathe, the food we eat, stones, clouds, water, plants, and animals – each thing is matter.

सही विकल्प है (घ) सन् 1978 में।

चीन में आर्थिक सुधार 1978 ई० से लागू किए गए। ये सुधार विभिन्न चरणों में शुरू किए गए। प्रारम्भिक चरण में कृषि, विदेशी व्यापार तथा निवेश क्षेत्रकों में सुधार किए गए। उदाहरण के लिए कृषि क्षेत्रक कम्यून (सामूहिक) भूमि को छोटे-छोटे भू-खण्डों में बाँट दिया गया जिन्हें कृषि प्रयोग के लिए अलग-अलग परिवारों को आवंटित किया गया। कर देने के बाद शेष आय के वे स्वयं स्वामी थे। दूसरे चरण में औद्योगिक क्षेत्र में सुधार किए गए। ग्रामीण उद्योगों की स्थापना के लिए निजी क्षेत्रक को प्रोत्साहित किया गया। इसके फलस्वरूप सार्वजनिक क्षेत्रक को निजी क्षेत्रक की प्रतिस्पर्धा का सामना करना पड़ा। सुधार प्रक्रिया में ‘दोहरी कीमत निर्धारण पद्धति’ (Dual pricing policy) लागू की गई—
⦁    सरकार द्वारा निर्धारित कीमत,

⦁    बाजार द्वारा निर्धारित कीमत।

आगतों और निर्गतों की एक निर्धारित मात्रा का क्रय-विक्रय सरकार द्वारा निर्धारित कीमतों पर किया जाता था जबकि शेष मात्रा का क्रय-विक्रय बाजार द्वारा निर्धारित कीमतों पर किया जाता था। विदेशी निवेशकों को आकर्षित करने के लिए विशेष आर्थिक क्षेत्र’ (Special economic zones) स्थाषित किए गए। परिणामस्वरूप चीन की औद्योगिक संवृद्धि दर तेजी से बढ़ती गई।

Adsorption is the phenomenon of accumulation of higher concentration of one substance on the surface of another (in bulk) due to unbalanced/unsatisfied attractive forces on the surface.

When a chalk is dipped in ink, it is observed that the ink molecules are adsorbed at the surface of chalk and the surface becomes coloured, while the solvent of the ink goes deeper into the chalk due to absorption.

Correct option is (C) 2x – 3y = 13

(A) Put x = 2 & y = -3 in equation 2x – 3y = 10, we get

\(2\times2-3\times-3\) = 4+9 = 13 \(\neq\) 10 (Not satisfied)

\(\therefore\) (2, -3) is not a solution of 2x – 3y = 10.

(B) Put x = 2 & y = -3 in equation 2x + 3y = -13, we get

\(2\times2+3\times-3\) = -13

\(\Rightarrow\) 4 - 9 = -13

\(\Rightarrow\) -5 = -13   (Not satisfied)

\(\therefore\) (2, -3) is not a solution of equation 2x + 3y = -13.

(C) Put x = 2 & y = -3 in equation 2x – 3y = 13, we get

\(2\times2-3\times-3\) = 13

\(\Rightarrow\) 4+9 = 13

\(\Rightarrow\) 13 = 13   (Satisfied)

Hence, (2, -3) is a solution of equation 2x – 3y = 13.

(D) Put x = 2 & y = -3 in equation 2x + 3y = 13, we get

\(2\times2+3\times-3=13\)

\(\Rightarrow\) 4 - 9 = 13

\(\Rightarrow\) -5 = 13   (Not satisfied)

\(\therefore\) (2, -3) is not a solution of equation 2x + 3y = 13.

Correct option is C) 2x – 3y = 13

Correct option is (D) 4x + 6y – 11 = 0

The condition for inconsistent system of equations is \(\frac{a_1}{a_2}=\frac{b_1}{b_2}\neq\frac{c_1}{c_2}.\)

(A) \(\frac{a_1}{a_2}=\frac24=\frac12,\)

\(\frac{b_1}{b_2}=\frac3{-6}=\frac{-1}2\)

\(\because\) \(\frac{a_1}{a_2}\neq\frac{b_1}{b_2}\)

\(\therefore\) System of equations is consistent.

(B) \(\frac{a_1}{a_2}=\frac22=1,\)

\(\frac{b_1}{b_2}=\frac3{1}=3\)

\(\therefore\) \(\frac{a_1}{a_2}\neq\frac{b_1}{b_2}\)

\(\therefore\) System of equations is consistent.

(C) \(\frac{a_1}{a_2}=\frac21=2,\)

\(\frac{b_1}{b_2}=\frac3{3}=1\)

\(\therefore\) \(\frac{a_1}{a_2}\neq\frac{b_1}{b_2}\)

\(\therefore\) System of equations is consistent.

(D) \(\frac{a_1}{a_2}=\frac24=\frac12,\)

\(\frac{b_1}{b_2}=\frac3{6}=\frac{1}2\) and

\(\frac{c_1}{c_2}=\frac{-5}{-11}=\frac5{11}\)

\(\therefore\) \(\frac{a_1}{a_2}=\frac{b_1}{b_2}\neq\frac{c_1}{c_2}\)

\(\therefore\) System of equations is inconsistent.

Hence, equation 4x + 6y – 11 = 0 is inconsistent to equation 2x + 3y - 5 = 0.

Correct option is D) 4x + 6y – 11 = 0

Correct option is (C) 3 – x = y² + 4

(A) 5 + 4x = y + 3

\(\Rightarrow\) 4x - y + 5 - 3 = 0

\(\Rightarrow\) 4x - y + 2 = 0 which is a linear equation.

(B) x + 2y = y – x

\(\Rightarrow\) x + 2y - y + x = 0

\(\Rightarrow\) 2x + y = 0 which is a linear equation.

(C) \(3 – x = y^2 + 4\)

\(\Rightarrow\) \(y^2+4-3+x=0\)

\(\Rightarrow\) \(y^2+x+1=0\) which is not a linear equation.

(D) x + y = 0 is a linear equation.

Correct option is C) 3 – x = y² + 4

Correct option is D) {-1/2, 1/4}

Correct option is (C) 3 – x = y + 4

(A) \(5 + 4x^2 = y + 3\)

\(\Rightarrow\) \(4x^2-y+2=0\) which is not a linear equation.

(B) \(x + 2y = y^2 - x\)

\(\Rightarrow\) \(y^2-2x-2y=0\) which is not a linear equation.

(C) \(3 - x = y + 4\)

\(\Rightarrow\) \(x+y+1=0\) which is a linear equation.

(D) \(x^2 + y = 0\) which is not a linear equation.

Correct option is C) 3 – x = y + 4

Correct option is (D) Quadratic polynomial

\(4y^2 - 5y + 1\) is a quadratic polynomial in variable y.

Correct option is D) Quadratic polynomial.

Correct option is (C) -1

For no solution, we have

\(\frac{a_1}{a_2}=\frac{b_1}{b_2}\neq\frac{c_1}{c_2}\)

\(\Rightarrow\) \(\frac{3k+1}{k^2+1}=\frac{3}{k-2}\neq\frac{-2}{-5}\)

\(\Rightarrow\) \(\frac{3k+1}{k^2+1}=\frac{3}{k-2}\)

\(\Rightarrow\) \((3k+1)(k-2)=3(k^2+1)\)   (By cross multiplication)

\(\Rightarrow\) \(3k^2+k-6k-2\) \(=3k^2+3\)

\(\Rightarrow\) -5k - 2 = 3

\(\Rightarrow\) -5k = 3+2 = 5

\(\Rightarrow\) k = \(\frac5{-5}\) = - 1

Correct option is C) -1