Explore topic-wise InterviewSolutions in Current Affairs.

Viruses obtained by infecting bacteria having radioactive sulphur contained radioactive protein but not radioactive DNA because DNA does not contain sulphur and proteins contain sulphur.

1. Proteins are large, complex molecules and store information required to govern cell metabolism. Hence it was assumed that variations found in species were caused by proteins. 

2. On the other hand, DNA was considered as a small, simple molecule whose composition does not vary much among species. 

3. Variations in the DNA molecules are different than the variation in shape, electrical charge and function shown by proteins. 

4. Hence, initially proteins (and not DNA) were considered as genetic material.

Viruses obtained by infecting bacteria having radioactive phosphorus, contained radioactive DNA (labelled DNA). but not radioactive proteins because DNA contains phosphorus (labelled DNA) but proteins do not.

1. Griffith obtained live S-strain bacteria from the blood of the dead mice. 

2. In a mixture of live R-bacteria and heat killed S-bacteria, live R-strain bacteria picked up something (transforming principle) from the heat-killed S bacterium and got changed into Stype. 

3. Transforming principle allowed R-type bacteria to synthesize capsule and thus they became virulent. 

4. Hence, on injecting a mixture of heatkilled S bacteria and live R bacteria, the mice died.

Financial institutions means banks may differ in the type and number of services they provide to customers.

The services most often provided include a variety of checking accounts, savings accounts; certificates of deposits, and loans, including car loans and home mortgages.

Additional services may include safe deposit boxes and investment related services. Education loans to students also.

The main reason behind poor house holds depends on informal lenders/sources because banks do not wish to give loans to the poor, who have no collateral. Bank loans require proper documents and collateral. Banks prefer not to lend money to the poor farmers and landless labourers, because more often than not they don’t have the required documents to take loan.

But rich people have more properties, they should submits proper documents to banks for loan.

According to this, rich people are benefited with low rate of interest but poor people are suffered with high rate of interest. So formal sector loans need to expand in rural areas for the development of poor.

• No, everyone cannot get loan at cheap rates. 
• Only priority sector, like agriculture, animal husbandary, poultry, etc. gets loan at cheaper rates. 
• Banks have to extend 40% of their loans to priority sector.

1. The loans issued by formal organizations has increased from 15.8% in 1961 to 52% in 2003. There is an increase of 36.2%.

2. The loans issued by informal organizations have been reduced from 84.0 to 48%. There is a decrease of 36%

• Due to vast geographical conditions and diversified cultures the Reserve Bank of India cannot check or supervise informal credit. 
• Most of the transactions are on oral agreement between the borrower and the lender. 
• There will not be any registered transaction. Most of the cases a lot of black money is involved. 
• Hence it is difficult for the RBI to supervise informal credit.

(d) All of the above

(c) Both of them

2⁵ = 2 × 2 × 2 × 2 × 2 = 32 

5² = 5 × 5 = 25 

32 > 25 

Therefore, 2⁵ > 5²

2³ =2 × 2 × 2 = 8

3²= 3 × 3 = 9

Therefore, 3² > 2³

Every human being has an immense source of energy. But sadly, an average man uses only twenty percent of his mental power. The rest of it remains unused. If human beings learn to use their unused powers, they can face and master all circumstances. Thus through the proper use of human energy, complete peace can be attained.

1. When the writer arrived in the school, first of all he saw a girl with bandaged eyes being led carefully between the flower-beds s by a little boy.

2. Miss Beam was middle-aged, full of authority, yet kindly and understanding.

3. The window of Miss Beam’s room overlooked a large garden and a playground at the back.

4. A girl with a crutch watching the others at play seemed to be a hopeless cripple.

5. Peeping through bandage is considered as dishonour.

6. Millie was wearing a blue cotton skirt and a pink blouse.

1. realising
2. control
3. God
4. strange
5. focus
6. twenty.

He changed himself by self-realization.

Miss Beam adopted a unique method to teach her students valuable lessons of life. Her lessons were introduced to her students in the form of a role play. The students performed the role of a blind, a lame or a dumb person to experience the pain and misfortune such people actually do. The students also learnt to be thoughtful, kind and patient to one and all.

I feel that every school should adopt this method of teaching. The values students gain from such sessions only help them become better citizens. If every individual learns to care and respect each other, the world would become a better place to live in.

Correct option is A. Cramming

Correct option is B. blind

Malaria, dengue.

Correct option is (A) –1

\((\frac{4}{5})^3\times(\frac{4}{5})^{-6}=(\frac{4}{5})^{2x-1}\)

\(\Rightarrow\) \((\frac{4}{5})^{3+(-6)}=(\frac{4}{5})^{2x-1}\)

\(\Rightarrow\) \((\frac{4}{5})^{3-6}=(\frac{4}{5})^{2x-1}\)

\(\Rightarrow\) \((\frac{4}{5})^{2x-1}=(\frac{4}{5})^{-3}\)

\(\therefore\) 2x - 1 = -3

\(\Rightarrow\) \(x=\frac{-3+1}2=\frac{-2}2=-1\)

Correct option is  A) – 1

Correct option is (D) 17/6

\(1+2^{-1}+3^{-1}+4^0=1+\frac12+\frac13+1=\frac{6+3+2+6}6\) \(=\frac{17}{6}\)

Correct option is  D) 17/6

Correct option is (A) 2/3

\(3^0-3^{-1}=1-\frac13=\frac{3-1}3=\frac{2}3\)

Correct option is  A) 2/3 

Correct option is (D) 2

We have m = 3, n = 1

Then \(m^n-n^m\) = \(3^1-1^3\) = 3 - 1 = 2

Correct option is  D) 2

Correct option is (A) 5/7

\((\frac{25}{49})^\frac{1}{2}=\left(\cfrac{5^2}{7^2}\right)^\frac{1}{2}=\left[(\frac{5}{7})^2\right]^\frac{1}{2}\) \(=(\frac{5}{7})^{2\times\frac12}=(\frac{5}{7})^1=\frac{5}{7}\)

Correct option is  A) 5/7

Correct option is (D) 1/4096

\(\left((\frac{1}{4})^2\right)^3=(\frac{1^2}{4^2})^3=(\frac1{16})^3\) \(=\frac{1^3}{16^3}=\frac{1}{4096}\)

Correct option is   D) \(\frac{1}{4096}\)

Correct option is (D) 2

\(\sqrt[5]{32}=(32)^\frac15=(2^5)^\frac15=(2)^{5\times\frac15}\) \(=2^1=2\)

Correct option is D) 2

Correct option is (B) 2

\(7^{2n+1}\div49=\frac{7^{2n+1}}{49}=\frac{7^{2n+1}}{7^2}\) \(=7^{2n+1-2}=7^{2n-1}\)

\(\because\) \(7^{2n+1}\div49=7^3\)

\(\therefore\) \(7^{2n-1}=7^3\)

\(\Rightarrow\) 2n - 1 = 3

\(\Rightarrow\) \(n=\frac{3+1}2=\frac42=2\)

Correct option is  B) 2

Correct option is (D) 543.67

\((5\times10^2)+(4\times10)+(3\times10^0)\) \(+(6\times10^{-1})+(7\times10^{-2})\)

= 500+40+3+0.6+0.07

= 543.67

Correct option is  D) 543.67

(a) 16/81

Explanation: 

(-2/3)⁴ 

= (-2/3)(-2/3)(-2/3)(-2/3) 

= 16/81

(c) – 32

Explanation: (–2)^2×3-1

= (-2)^6-1

= (-2)⁵

= -32

Given a = 2, b = 3

a^a + b^b = 2² + 3³ 

= (2 × 2) + (3 × 3 × 3)

= 4 + 27 = 31

Therefore, if a = 2, b = 3 then a^a + b^b = 31

Given a = 2, b = 3 

(a + b)^b = (2 + 3)³ = 5³

= 5 × 5 × 5 = 125 

Therefore, if a = 2, b = 3

then (a + b)^b =125

Given a = 2, b = 3 

a^b + b^a = 2³ + 3² 

= (2 × 2 × 2) + (3 × 3). 

= 8 + 9 = 17 

Therefore, if a = 2, b = 3 

then a^b + b^a = 17

As we know that , 2 × 2 × 2 × 2 = 16

∴ 16 = 2⁴

∴ 16^-2 = (2⁴)^-2 = 2^-8…..(by the laws of exponents i.e. (a^m)ⁿ = a^(mn)

Correct option is (B)  -1/6

\(-4^{-1}+8^{-1}\div(\frac{2}{3})^{-1}\) \(=-\frac14+\left(\frac18\times\left[(\frac{2}{3})^{-1}\right]^{-1}\right)\)

\(=\frac{-1}4+\left(\frac18\times(\frac{2}{3})^{-1\times-1}\right)\)

\(=\frac{-1}4+\frac18\times\frac{2}{3}\) \(=\frac{-1}4+\frac1{12}\)

\(=\frac{-3+1}{12}=\frac{-2}{12}\) \(=\frac{-1}{6}\)

Correct option is  B)  -1/6

The correct answer is A) Benzoate

Correct option is (D) –5

\((\frac{-1}{5})^{-1}=(-5^{-1})^{-1}=(-1)^{-1}\times(5^{-1})^{-1}\) \(=\frac1{-1}\times5=-5\)

Correct option is  D) – 5

We know that, 2^-2= 1/2²

And 2^-3 = 1/2³

From the law of exponents , we know that a^m × aⁿ = a^(m+n)

∴ 2^-2 × 2^-3 

= 1/2² × 1/2³ 

= 1/2³ x 2² 

= 1/2³⁺² 

= 1/2⁵ 

= 2^-5

∴ 2^-2 × 2^-3 = 2^-5

Correct option is (D) 3²⁴

\([(3^2)^3]^4=(3^{2\times3})^4=3^{2\times3\times4}\) \(=3^{24}\)

Correct option is  D) 3²⁴

Correct option is (A) 27/8

\((\frac{2}{3})^{-3}=\left[(\frac{2}{3})^{-1}\right]^3=(\frac32)^{3}\) \(=\frac{3^3}{2^3}=\frac{27}{8}\)

Correct option is  A) 27/8 

Correct option is (A) 0

\(1+(9-10)^{-5}\) \(=1+(-1)^{-5}=1+\frac1{(-1)^{5}}=1+\frac1{-1}\) = 1-1 = 0

Correct option is  A) 0

As we know 100² = 100 × 100 = 10000

100¹ = 10000/100 = 1000

100⁰ = 100/100 = 1

Continuing the above pattern , we get ,

100^-1 = 1/100

Similarly , 100^-2= 1/100 ÷ 100 

= 1/100 × 1/100 

= 1/10000 

= 1/100²

100^-3 = 1/10000 ÷ 100 

= 1/10000 ÷ 100 

= 1/1000000 

= 1/100³

Similarly we can say that , 100^-10= 1/100¹⁰

(i) 27⁶ = 27 × 27 × 27 × 27 × 27 × 27

(ii) 101⁵ = 101 × 101 × 101 × 101 × 101

(iii) (2b)⁴ = 2b × 2b × 2b × 2b

(iv) 3a⁸ = 3 × a× a × a × a × a × a × a × a

Correct option is (D) x > y

\(x=3^{400},y=4^{300}\)

\(\Rightarrow\) \(x=(3^4)^{100}=(81)^{100}\)

and \(y=4^{300}=(4^3)^{100}=64^{100}\)

\(\because\) 64 < 81

\(\Rightarrow\) \((64)^{100}<(81)^{100}\)

\(\Rightarrow\) y < x or x > y

Correct option is  D) x > y

Correct option is (A) 3

\(\sqrt[4]{81}=(81)^\frac14=(3^4)^\frac14=(3)^{4\times\frac14}\) \(=3^1=3\)

Correct option is  A) 3

(1)²⁵⁰ = 1 × 1 × 1 ……… 250 times = 1

∴ (1)²⁵⁰ = 1

Correct option is (D) 1/8

\(64^{-0.5}=\frac1{64^{0.5}}=\frac1{(2^6)^\frac12}\) \(=\frac1{2^{6\times\frac12}}=\frac1{2^3}=\frac18\)

Correct option is  D) 1/8

Correct option is (B) 16

\(64^{\frac23}=(2^6)^{\frac23}=(2)^{6\times\frac23}\) \(=2^{2\times2}=2^{4}=16\)

Correct option is  B) 16