This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Unbalanced equation is called A) Basic equation B) Skeleton equation C) Stoichiometric equation D) Fundamental equation |
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Answer» B) Skeleton equation |
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| 2. |
Fill in the blank:i. Organic waste is decomposed by micro-organism and as a result manure and……..are formed.ii. ……….is formed on mixing yeast in glucose solution under proper condition.iii. The chemical reaction during which H2(g) is lost is termed as………iv. Corrosion can be prevented by using………v. The chemical reactions in which heat is liberated are called………..reactions. |
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Answer» i. Organic waste is decomposed by micro-organism and as a result manure and bio gas are formed. ii. Alcohol is formed on mixing yeast in glucose solution under proper condition. iii. The chemical reaction during which H2(g) s lost is termed as oxidation. iv. Corrosion can be prevented by using antirust solution. v. The chemical reactions in which heat is liberated are called exothermic reactions. |
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| 3. |
A balanced equation contains A) Equal number of moles of reactants and productsB) Equal number of molecules of reactants and products C) Equal number of atoms of different elements on reactant side and product side D) All the above |
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Answer» C) Equal number of atoms of different elements on reactant side and product side |
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| 4. |
How does the rate of a reaction depend on the size of the particles of reactants? |
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Answer» (1) In the reaction of dil. HCl and Shahabad tile, CO2 effervescence is formed slowly. On the other hand, C2 effervescence forms at faster speed with the powder of Shahabad tile. (2) The above observation indicates that the rate of a reaction depends upon the size of the particles of the reactants taking part in the reaction. Smaller the size of the reactant particles taking part in a reaction faster will be the rate of reaètion. |
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| 5. |
What is difference between mineral and ore? Explain it. |
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Answer» The naturally occurring chemical substance in which metal occurs in the earth’s crust is called mineral. On the other hand, the mineral from which metal can be economically and conveniently extracted is called an ore. |
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| 6. |
Does a new substance form when a solute dissolves in a solvent? |
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Answer» It is not necessary that a new substance is always formed. |
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| 7. |
Write true or false for the following statements: During endothermic reactions, heat is transferred from the reacting substances to the surroundings. |
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Answer» False During endothermic reactions, heat is transferred from the surroundings to the reacting substances. On the other hand, heat is transferred from the reacting substances to the surroundings. Hence, the given statement is false |
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| 8. |
Write true or false for the following statements: The insoluble substance formed during a chemical reaction is known as a precipitate. |
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Answer» True The insoluble substance formed during a chemical reaction is known as a precipitate. The precipitate formed in a double displacement reaction. Hence, the given statement is true. |
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| 9. |
What is the difference in the process of dissolution and a chemical reaction. |
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Answer» In the process of dissolution, new substance is not necessarily formed. Whereas in a chemical reaction a new substance is definitely formed. |
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| 10. |
The luster of the surface of the aluminium utensils in the house is lost after a few days. Why does this happen? |
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Answer» The aluminium utensils when kept in the house for a few days, oxidation of aluminium takes place, a thin laver aluminium oxide (Al2O3) is deposited on the surface. Hence, aluminium utensils lose their lustre in a few days. |
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| 11. |
Differentiate between s-block and p-block elements. |
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Answer» s-Block elements:
p-Block elements:
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| 12. |
What is lanthanide and actinide series? |
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Answer» i. Lanthanide series: The fourteen elements after lanthanum (Z = 57) i.e., from cerium (Z = 58) to lutetium (Z = 71) are named after their preceding member (57La) present in the third group and 6th period and are called lanthanides. They are kept in separate series called lanthanide series at the bottom of the modem periodic table. ii. Actinide series: The fourteen elements after actinium i.e., from thorium (Z = 90) to lawrencium (Z = 103) are named after 89Ac present in third period and 7th group. They are kept in separate series called actinide series at the bottom of the modem periodic table. The lanthanide and actinide series make up the inner transition metals. The lanthanide series includes elements 58 to 71, which fill their 4f sublevel progressively. The actinides are elements 89 to 103 and fill their 5f sublevel progressively.
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| 13. |
Differentiate between d-block and f-block elements. |
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Answer» d-Block elements:
f-Block elements:
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| 14. |
How are dominance, co-dominance and incomplete dominance patterns of inheritance different from each other ? |
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Answer» Dominance: It is a phenomenon in which when two contrasting alleles are present together, only one expresses itself and is called dominant whereas the other which does not express itself is called recessive. Co-dominance: It is a phenomenon in which when two contrasting alleles are present together, both of the alleles express themselves. Incomplete dominance: It is a phenomenon in which when two contrasting alleles are present together neither of the alleles is dominant over other and the phenotype formed is intermediate of the two alleles. . ., Red flower × White flower → Pink flower colour |
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| 15. |
………… elements are known as chalcogens. (A) Group 17 (B) Group 18 (C) Group 16(D) Group 1 |
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Answer» Correct option is: (C) Group 16 Group 16 elements are known as chalcogens. Correct option is (C) Group 16 |
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| 16. |
How can we predict chemical reactivity of elements based on their oxide formation reactions and the nature of oxides formed? |
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| 17. |
Explain the terms:i. Valency of an element ii. Oxidation state (or oxidation number) iii. Chemical reactivity |
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Answer» i. Valency of an element:
ii. Oxidation state (or oxidation number):
iii. Chemical reactivity:
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| 18. |
Which of the following is not an exothermic reaction ? ………………… 1) C + O2 → CO2 2) N2 + O2 → 2NO3) CaCO3→ CaO + CO2 4) HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l)A) 2 B) 2, 3 C) 1 D) 1, 4 |
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Answer» Correct option is B) 2, 3 |
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| 19. |
Which of the following is not an exothermic reaction? A) C + O2 → CO2 B) CaO + H2O → Ca(OH)2 C) N2 + O2 → 2NO D) CH4 + 2O2 → CO2 + 2H2O |
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Answer» C) N2 + O2 → 2NO |
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| 20. |
What is the difference among the following chemical combination reactions ? 1) 2H2 + O2 → 2H2O 2) 2CO + O2 → 2CO2 3) NH3 + HCl → NH4Cl A) In reactants of first equation both are elements. B) In reactants of second equation one is compound and other one is element.C) In equation three both the reactants are compounds. D) All are correct. |
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Answer» D) All are correct |
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| 21. |
13Al is a metal, 14Si is a metalloid and 15P is a nonmetal. |
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| 22. |
Chlorides of two metals are common laboratory chemicals and both are colourless.One of the metals reacts vigorously with water while the other reacts slowly. Place the two metals in the appropriate block in the periodic table. Justify your answer. |
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Answer» i. Metals are present in all the four blocks of the periodic table. ii. Salts of metals in the f-block and p-block (except AlCl3) are not common laboratory chemicals. Therefore, the choice is between sand d-block. iii. From the given properties their placement is done as shown below:
iv. The colourless nature of the less reactive metal in the d-block implies that the inner d subshell is completely filled. |
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| 23. |
Write the outer electronic configuration of the following using orbital notation method. Justify.A. Ge (belongs to period 4 and group 14) B. Po (belongs to period 6 and group 16) C. Cu (belongs to period 4 and group 11) |
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Answer» A. Ge (belongs to period 4 and group 14) : a. Ge belongs to period 4. Therefore, n = 4. b. Group 14 indicates that the element belongs to the p-block of the modem periodic table. c. The general outer electronic configuration of group 14 elements is ns2 np2. d. Thus, the outer electronic configuration of Ge is 4s2 4p2. B. Po (belongs to period 6 and group 16) : a. Po belongs to period 6. Therefore, n = 6. b. Group 16 indicates that the element belongs to the p-block of the modem periodic table. c. The general outer electronic configuration of group 16 elements is ns2 np4. d. Thus, the outer electronic configuration of Po is 6s2 6p4. C. Cu (belongs to period 4 and group 11) : a. Cu belongs to period 4. Therefore, n = 4. b. Group 11 indicates that the element belongs to the d-block of the modem periodic table. c. The general outer electronic configuration of the d-block elements is ns0-2 (n-1)d1-10. d. The expected configuration of Cu is 4s2 3d9. However, The observed configuration of Cu is 4s1 3d10. This is due to the extra stability associated with completely filled d-subshell. Thus, The outer electronic configuration of Cu is 4s1 3d10. |
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| 24. |
Cu forms coloured salts while Zn forms colourless salts. |
Answer»
Hence, Cu forms coloured salts while Zn forms colourless salts. |
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| 25. |
On what basis is the modern periodic table divided into four blocks? |
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Answer» The modem periodic table is divided into four blocks based on the subshell in which the last electron enters. |
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| 26. |
What is the general trend followed while filling of electrons across a period in the modern periodic table. |
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| 27. |
State the general outer electronic configuration of s-block and p-block elements. |
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Answer» The general outer electronic configuration of s-block elements is ns1-2. The general electronic configuration for the p-block elements is ns2np1-6. |
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| 28. |
Why elements of group 1 and group 2 are known as s-block elements? |
Answer»
Therefore, the elements of group 1 and group 2 are known as s-block elements. |
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| 29. |
Give reason: Helium which is the first element of group 18 is placed in the p-block even though its last electron enters in s subshell. |
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| 30. |
Explain in brief about the f-block elements. |
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| 31. |
How many elements are present in the 6th period? Explain. |
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| 32. |
Write a note on the characteristics of the d-block elements. |
Answer»
Properties of d-Block Elements
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| 33. |
Why does the fifth period of the modern periodic table contain 18 electrons? |
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Answer» The fifth period accommodates 18 elements as a result of successive filling of electrons in the 5s, 4d and 5p subshells. |
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| 34. |
What is the subshell in which the last electron of the first element in the 6th period enters? |
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Answer» The 6th period begins by filling the last electron in the shell with n = 6. The lowest energy subshell of any shell is ‘s’. Therefore, the last electron of the first element in the 6th period enters the subshell ‘6s’. |
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| 35. |
What are main group elements? |
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Answer» The p-block elements together with s-block elements are called main group elements or representative elements. |
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| 36. |
The last electron enters a (n-1)d orbital only after the ns subshell is completely filled.Explain. |
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Answer» A d subshell is present in the shells with n ≥ 3 and according to the (n+1) rule, the energy of ns orbital is less than that of the (n-1)d orbital. As a result, the last electron enters a (n-1)d orbital only after the ns subshell is completely filled. |
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| 37. |
The CORRECT order of increasing radii of the elements Na, Si, Al and P is …………… (A) Si < Al < P < Na (B) Al < Si < P < Na (C) P < Si < Al < Na (D) Al < P < Si < Na |
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Answer» Correct option is: (C) P < Si < Ai < Na As we move along a period from left to right the radii of element decrease. Na, Si, Al and P are third period elements Therefore, the order of radii is Na > Al > Si > P (C) P < Si < Al < Na |
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| 38. |
State the characteristics of s-block elements. |
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| 39. |
Why the elements belonging to the same group do have similar chemical properties? |
Answer»
Hence, The elements belonging to the same group show similar chemical properties. |
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| 40. |
Predict the block, periods and groups to which the following elements belong.i. Mg (Z = 12) ii. V (Z = 23) iii. Sb (Z = 51) iv. Rn (Z = 86) v. Na (Z = 11) vi. Cl (Z = 17) |
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Answer» i. Mg (Z = 12): Atomic number of Mg is 12. Electronic configuration is 1s2 2s2 2p6 3s2. Block: Since the last electron enters s subshell (3 s), Mg belongs to s-block. Period: n = 3. Therefore, it is present in the third period. Group: For s-block element, group number = number of valence electrons = 2. Hence, it belongs to group 2. ii. V (Z = 23): Atomic number of V is 23. Electronic configuration is 1s2 2s2 2p6 3s2 3p6 3d3 4s2. Block: Since the last electron enters d subshell (3d), V belongs to d-block. Period: n = 4. Therefore, it is present in the fourth period. Group: For d-block elements, group number = 2 + number of (n – 1) d electrons = 2 + 3 = 5. Hence, it belongs to group 5. iii. Sb (Z = 51): Atomic number of Sb is 51. Electronic configuration is 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p3. Block: Since the last electron enters p subshell (5p), Sb belongs to p-block. Period: n = 5. Therefore, it is present in the fifth period. Group: For p block elements, group number = 18 – number of electrons required to complete octet = 18 – 3 = 15. Hence, it belongs to group 15. iv. Rn (Z = 86): Atomic number of Rn is 86. Electronic configuration is 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 4d10 4f14 5s2 5p6 5d10 6s2 6p6. Block: Since the last electron enters p subshell (6p), Rn belongs to p-block. Period: n = 6. Therefore, it is present in the sixth period. Group: For p block elements, group number = 18 – number of electrons required to complete octet = 18 – 0 = 18. Hence, it belongs to group 18. v. Na (Z = 11): Atomic number of Na is 11. Electronic configuration is 1s2 2s2 2p6 3s1. Block: Since the last electron enters s subshell (3s), Na belongs to s-block. Period: n = 3. Therefore, it is present in the third period. Group: For s-block element, number of the group = number of valence electrons = 1. Hence, it belongs to group 1. vi. Cl (Z = 17): Atomic number of Cl is 17. Electronic configuration is 1s2 2s2 2p6 3s2 3p5. Block: Since the last electron enters p subshell (3p), Cl belongs to p-block. Period: n = 3. Therefore, it is present in the third period. Group: For p block elements, group number = 18 – number of electrons required to complete octet = 18 – 1 = 17. Hence, it belongs to group 17. |
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| 41. |
Give some other examples of periodic events. |
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Answer» Following are some other examples of periodic events :
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| 42. |
Which principle is followed in the distribution of electrons in an atom? |
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Answer» The distribution of electrons in an atom is according to the following three principles : 1. Aufbau principle 2. Pauli’s exclusion principle 3. Hund’s rule of maximum multiplicity [Note : According to aufbau principle, electrons are filled in the subshells in the increasing order of their energies which follows the following order : s < p < d < f.] |
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| 43. |
The fourth, fifth and sixth periods are long periods and contain …………… (A) 18, 18 and 36 (B) 18, 28 and 32 (C) 18, 15 and 31 (D) 18, 18 and 32 |
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Answer» Correct option is: (D) 18, 18 and 32 First, second, third, fourth, fifth and sixth periods contain 2, 8, 8, 18, 18, 32 elements respectively. While seventh periods is incomplete Hence, fourth, fifth and sixth period contain 18, 18, 32 element respectively. (D) 18, 18 and 32 |
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| 44. |
A neutralization reaction is a ……………. reaction. A) decomposition B) displacement C) combination D) double displacement |
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Answer» D) double displacement |
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| 45. |
Write word equations for the following skeletal equations: (a) KClO3 → KCl + O2 (b) Zn + HCl → ZnCl2 + H2(c)FeCl2 + Cl2 → FeCl3(d) CO + O2 → CO2(e) Ca + O2 → CaO (f) Na + O2 → Na2O (g) NaOH + H2SO4 → Na2SO4 + H2O (h) AgBr → Ag + Br2(i) KNO2 → KNO2 + O2 |
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Answer» (a) 2KClO3 → 2KCl + O2 (b) Zn + 2HCl → ZnCl2 + H2 (c) 2FeCl2 + Cl2 → 2FeCl3 (d) 2CO + O2 → 2CO2 (e) 2Ca + O2 → 2CaO (f) 4Na + O2 → 2Na2O (g) 2NaOH + H2SO4 → Na2SO4 + 2H2O (h) 2AgBr → 2Ag + Br2 (i) 2KNO2 → 2KNO2 + O2 |
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| 46. |
What are the valence electrons? For s-block and p-block elements show that number of valence electrons is equal to its group number. |
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| 47. |
What is Activity Series ? |
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Answer» Activity Series: The activity series of metals is a list of metals in the order of their decreasing chemical activity |
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| 48. |
Explain the importance of electronegativity. |
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| 49. |
The CORRECT order of radii is …………… (A) N < Be < B (B) F- < O2- <N3-(C) Na < Li < K(D) Fe3+< Fe2+ < Fe4+ |
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Answer» Correct option is: (B) F- < O2- <N3- Isoelectronic species with more negative changes have large ionic radii than less negative. Therefore, the correct order of radii is \(N^{3^\circ} > O^{2^\circ} > F^-\) (B) F- < O2- <N3- |
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| 50. |
Atomic number of V is 23 and its electronic configuration is …………….(A) 1s2 2s2 2p6 3p6 3d3 4s2 (B) 1s2 2s2 2d3 3p6 2p6 4s2 (C) 2s2 1s2 2p6 3s2 3d3 4s2 (D) 1s2 2s2 2p6 3s2 3p6 3d3 4s2 |
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Answer» (D) 1s2 2s2 2p6 3s2 3p6 3d3 4s2 |
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