This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Why _____ sent late? A) the order was B) it was C) they were D) was the order |
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Answer» Correct option is D) was the order |
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| 2. |
Can I have _____ stamps, please? A) a B) an C) some D) any |
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Answer» Correct option is C) some |
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| 3. |
The term 'white revolution' is related with:1. crops2. fish3. milk4. Leather |
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Answer» Correct Answer - Option 3 : milk The correct answer is Milk.
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| 4. |
An aqueous blue coloured solution of a transition metal sulphate reacts with `H_(2)S` to give a black precipitate. The black precipitate dissolves in `50%` nitric acid forming a blue coloured solution. The blue solution on treatment with KI in weakly acidic medium turns yellow`//` brown and produces a white precipitate. Identify the transition metal ion from the following ions.A. `Co^(2+)`B. `Cu^(2+)`C. `Hg^(2+)`D. `Pb^(2+)` |
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Answer» Correct Answer - 2 `CuSO_(4)+H_(2)S rarrCuSdarr("black")+H_(2)SO_(4)` `CuS+2HNO_(3)rarrCu(NO_(3))_(2)("blue solution")+NO+S+H_(2)O` `2Cu^(2+)+4I^(-) rarrCu_(2)I_(2) darr("white")+I_(2) uarr ("colour of solution is yellow"//"brown")` |
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| 5. |
A ________ from the local paper asked for details of the accident. A) salesman B) newsagent C) reporter D) typewriter E) broadcaster |
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Answer» Correct option is C) reporter |
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| 6. |
_____ the stamps put on the package or in it? A) Do B) Does C) Are D) Will |
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Answer» Correct option is C) Are |
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| 7. |
A newsagent _____ stamps. A) sells B) is sold C) was sold D) sell |
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Answer» Correct option is A) sells |
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| 8. |
vector(i.j) = (a) 0(b) 1(c) vector k(d) vector -k |
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Answer» Answer is (a) 0 |
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| 9. |
The sum of intergers from `1` to `100` that are divisible by `2` or `5` is -A. `2550`B. `1050`C. `3050`D. `4150` |
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Answer» Correct Answer - C Sum of integers divided by `2` `= 2 + 4 + 6 + 8 +"….."+100 = 50 xx 51 = 2550` Sum of integers divided by `5` ltbRgt `= 5 + 10 + 15 +"….."+ 100 = 51 xx 20 = 1050` Sum of intergers divided by `10` `= 10 + 20 +"….."+ 100 = 550` `:.` Required sum `= 2550 + 1050 - 550 = 3050` |
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| 10. |
vector(k x j) = (a) 0(b) 1(c) vector i(d) vector -i |
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Answer» Answer is (d) vector -i |
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| 11. |
An `AP` consists of `23` terms. If the sum of the three terms of in the middle is `141` and the sum of the last three terms is `261`, then the first term isA. `6`B. `5`C. `4`D. `5` |
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Answer» Correct Answer - D `t_(11) + t_(12) + t_(13) = 141` and `t_(21) + t_(22) + t_(23) = 261` `:. 3a + 33d = 141 rArr a + 11d = 47` and `3a + 63d = 261 rArr a + 21d = 87` On solving eqs. `(i)` and `(ii)`, we get `a = 3, d = 4`. |
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| 12. |
vector(a.a) = (a) 0(b) 1(c) |vector a|2(d) |vector a| |
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Answer» Answer is (c) |vector a|2 |
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| 13. |
The direction cosines of the y-axis are (a) (0,0,0)(b) (1,0,0)(c) (0,1,0)(d) (0,0,1) |
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Answer» Answer is (c) (0,1,0) |
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| 14. |
If `bx+cy=a`, there `a, b, c` are of the same sign, be a line such that the area enclosed by the line and the axes of reference is `1/8` square units, then : (A) `b,a,c` are in G.P. (B) `b, 2a, c` arein G.P. (C) `b, a/2, c` are in A.P. (D) `b, -2a, c` are in G.P.A. `b, a, c` and `G.P.`B. `b, 2a, -c` are in `G.P.`C. `b, a//2, c` are in `A.P.`D. `b, +2a, c` are in `G.P.` |
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Answer» Correct Answer - D Given equation is `bx + cy = a`, where `a,b,c` are of the intersects the axes at `A((a)/(b),0)` and `B(0,(a)/(c))` `rArr` Area enclosed between the axes and the line `= (1)/(2).(a)/(b).(a)/(c) = (a^(2))/(2bc) = (1)/(8)` `4a^(2)=bc`, so `b +- 2a,c` are in `G.P`. |
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| 15. |
Let solution of inequality `(16^((1)/(x)))/2^(x+3)gt1` is `(-oo, a) cup (b, c)` thenA. `a^(2) + b^(2) + 9c^(2) = 25`B. `a + b + c gt 0`C. `a^(2) + b^(2) + c^(2) = 17`D. `a + b + c lt 0` |
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Answer» Correct Answer - A::C::D `(2^((4)/(x)))/(2^(x+3))gt1` `2^((4)/(x)-x-3)gt1` `(4)/(x)-x-3gt0` `(4-x^(2)-3x)/(x)gt0` `(x^(2)+3x-4)/(x)lt0` `((x+4)(x-1))/(x)lt0` `x in (-oo,-4)cup(0,1)` `a=-4, b=0, c=1` |
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| 16. |
For the equation `1 + log_(x) ((4 - x)/(10)) = (log_(10)(log_(10)p) - 1)log_(x)10`, which one of the following(s) is (are) correct?A. if `p = 10^(3)`, then the equation has two real solutionsB. if `p = 10^(4)`, then the equation has exactly solutionsC. if `p in (10^(4), oo)`, then the equation has no real solutionsD. if `p in (1, 10^(4))`, then the equation has two distinct real solutions. |
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Answer» Correct Answer - B::C `1 + log_(x)((4 - x)/(10)) = (log_(10)(log_(10)p)-1)log_(x)10` `(log_(10)x+log_(10)((4 - x)/(10)))/(log_(10)x) = (log_(10)((log_(10)p)/(10)))/(log_(10)x)` `x((4 - x)/(10)) = (log_(10)p)/(10)x ne 1` `x^(2) - 4x + log_(10)p = 0` `x = (4 +- sqrt(16 - 4 xx 1 xx log_(10)p))/(2)` `x = 2 +- sqrt(4 - log_(10)p)` `(1)` if `p = 10^(3)` then equation becomes `x^(2) - 4x + 3 = 0 (x - 3)(x - 1) = 0` but `x ne 1` `(2)` if `p = 10^(4)`, then `x = 2` is only real solution. (3) if `p gt 10^(4) rArr log_(10)p gt 4` (4) if `1 lt p lt 10^(4) rArr 0 lt log_(10)p lt 4` then equation has two real distinct solutions but `p ne 10^(3)` |
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| 17. |
In the equation `A+B+C+D+E=FG`. Where `FG` is the two digit number whose value is `10F+G` and letters `A,B,C,D,E,F` and `G` each represents different and `FG` is as large as possible If a five digit number is made using the digits `A,B,C,D,E` without repetition tenA. the probability that the number is divisible by 11 is `2/5`B. the probability that the number is divisible by 11 is `1/5`C. the probability that the number is divisible 4 is `1/4`D. the probability that the number is divisible by 4 is `2/5` |
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Answer» Correct Answer - C `9,8,6,5,4` (`A` and `B`)………`9+8+6+5+4=32` `|(9+8)-(6+5+4)|=2` not divisible by 11 `|(9+6)-(8+5+4)|=3` not divisible by 11 `|(9+5)-(8+6+4)|=4` not divisible by 11 `|(9+4)-(8+6+5)|=6` not divisible by 11 `|(8+6)-(9+5+4)|=4` not divisible by 11 `|(8+5)-(9+6+4)|=6` not divisible by 11 `|(8+4)-(9+6+5)|=8` not divisible by 11 `|(6+5)-(9+8+4)|=10` not divisible by 11 `|(6+4)-(9+8+4)|=12` not divisible by 11 `|(5+4)-(9+8+6)|=14` not divisible by 11 (C) .......... `ul4, ul8` `ul5, ul6` `ul6, ul4` `ul8, ul4` `ul9, ul6` Probability `=(5xx3!)/(5!)=1/4` |
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| 18. |
If the coefficient of `x^((n^(2)+n-18)/2)` in `(x-1)(x^(2)-2)(x^(3)-3)(x^(4)-4)….(x^(n)-n)`, where `(nge8)` is `k`, then `k` is equal to ___________ |
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Answer» Highest power of `x=(n(n+1))/2=m` (let) have to find coefficient of `x^(m-9)` `=9+(-8xx-1)+(-7xx-2)+(-6xx-3)+(-5xx-4)+(-6xx-2xx-1)+(-5xx-3xx-1)+(-4xx-3xx-2)=0` |
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| 19. |
The direction ratios of the line joining the points (x1,y1,z1) and (x2,y2,z2) are |
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Answer» Answer is (a) x1 + x2,y1 + y2,z1 + z2 |
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| 20. |
If `a,b,c` are three positive real numbers then the minimum value of `(a+3c)/(a+2b+c)+(4b)/(a+b+3c)-(8c)/(a+b+3c)` is `alpha+betasqrt(2)` (where `a,b in Z)`, then `|alpha+beta|` is equal to_____ |
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Answer» Correct Answer - 5 Let `a+2b+c=x,a+b+2c=y,a+b+3c=z` `a=-x+5y-3z,b=z+x-2, c-z-y` Apply A.M. `ge` G.M. `(a+3c)/(a+2b+c)+(4b)/(a+b+2c)-(8c)/(a+b+3c) ge -17 + 12 sqrt(2)` |
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| 21. |
If `a, b` and `c` are positive real and `a = 2b + 3c`, then the equation `ax^(2) + bx + c = 0` has real roots forA. `|(b)/(c) - 4|ge 2sqrt(7)`B. `|(c)/(b) - 4|ge 2sqrt(7)`C. `|(a)/(c) - 11|ge 4sqrt(7)`D. `|(a)/(b) + 11|ge 1sqrt((13)/(3))` |
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Answer» Correct Answer - A::C `a = 2b + 3c` Equation `ax^(2) + bx + c = 0` has real roots `b^(2) - 4ac ge 0 rArr b^(2) - 4(2b + 3c)c ge 0` `rArr c^(2)[((b)/(c))^(2) - 8((b)/(c))-12]ge0` `rArr ((b)/(c))^(2) - 8((b)/(c)) + 16 ge 28` `rArr ((b)/(c) - 4)^(2) ge 28 rArr |(b)/(c)-4|ge2sqrt(7)` Similarly `|(a)/(c)-11|ge4sqrt(7)` |
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| 22. |
In what time will Rs. 1000 become Rs. 1331 at 10% per annum compounded annually? |
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Answer» Principal = Rs. 1000; Amount = Rs. 1331; Rate = 10% p.a. Let the time be n years. Then, [ 1000 (1+ (10/100))n ] = 1331 or (11/10)n = (1331/1000) = (11/10)3 n = 3 years. |
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| 23. |
If A = [(1,1,1),(1,1,1),(1,1,1)], then A2 is (a) 27A (b) 2A(c) 3A(d) 1 |
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Answer» Answer is (c) 3A |
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| 24. |
A matrix A = [aij]n x n is said to be symmetric if-(a) aij = 0(b) aij = -aji(c) aij = aji(d) aij = 1 |
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Answer» Answer is (c) aij = aji |
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| 25. |
If L.C.M and H.C.F of two numbers are 640 and 16 respectively, then how many such pairs are possible?1. 12. 23. 34. None of these |
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Answer» Correct Answer - Option 2 : 2 Given: L.C.M of two numbers = 640 H.C.F of two numbers = 16 Concept used: If H.C.F of two natural numbers is H, then numbers should be Hx and Hy respectively, where x and y should be relatively prime number. Formula used: The Product of H.C.F and L.C.M of any two numbers is equal to the product of that numbers. Calculation: Let, numbers be 16x and 16y respectively. Using formula, ⇒ 16x × 16y = 16 × 640 ⇒ x × y = 640/16 = 40 ⇒ x × y = 40 Possibilities of x, y = (1, 40), (2, 20), (4, 10), (5, 8) Here, only (1, 40) and (5, 8) are such pairs of relatively prime numbers. ∴ Only two pairs are possible. |
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| 26. |
tan-1 √3 - cot-1 (-√3) =(a) π(b) 0(c) 2√3(d) -π/2 |
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Answer» Answer is (d) -π/2 |
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| 27. |
If P416 is divisible by 11, find the lowest natural value of P.A. 5B. 6C. 7D. 91. A2. C3. B4. D |
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Answer» Correct Answer - Option 4 : D Given: A number P416 is given which is divisible by 11 Concept used: A number is divisible by 11 if the difference between the sum of its odd digit and sum of its even digit is zero or divisible by 11. Calculations: According to the question, we have P416 is divisible by 11, then the sum of its odd digit is ⇒ Sum of odd digits = P + 1 And, Sum of its even digits is ⇒ Sum of even digits = 6 + 4 ⇒ Sum of even digits = 10 Now, Comparing them ⇒ P + 1 = 10 ⇒ P = 10 - 1 ⇒ P = 9 P = 9 is the smallest number which divides P416 by 11 ∴ The value of P is 9. |
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| 28. |
The following figure shows the graph of `y= p(x)`, where `p(x)` is a polynomial in variable `x`. The number of zeroes of the polynomial `p(x)` is A. 1B. 2C. 3D. 4 |
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Answer» Correct Answer - C Correct Answer - 3 |
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| 29. |
The distance of the point `P(3, -4)` from the origin isA. 7 unitsB. 5 unitsC. 4 unitsD. 3 units |
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Answer» Correct Answer - B Correct Answer - 5 units |
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| 30. |
If function f : N → N be defined by f(x) = 4x + 3 than f-1 (x) =(a) 4x - 3(b) (4x - 3)/2(c) (x + 3)/2(d) (x - 3)/4 |
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Answer» Answer is (d) (x - 3)/4 |
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| 31. |
The L.C.M of two positive integers is thrice the larger number and the H.C.F of the numbers is 5. The smaller number is?1. 252. 153. 124. 20 |
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Answer» Correct Answer - Option 2 : 15 GIVEN: L.C.M = 3 × Larger number H.C.F = 5 CONCEPT: Numbers = (H.C.F × x) , (H.C.F × y) where x and y are co - prime numbers FORMULA USED: L.C.M × H.C.F = Product of numbers CALCULATIONS: Let the larger number be 5x and the smaller number be 5y. A.T.Q L.C.M = 3 × 5x L.C.M × H.C.F = Product of numbers ⇒ 3 × 5x × 5 = 5x × 5y ⇒ y = 3 ⇒ Smaller number = 5y = 5 × 3 = 15 ∴ The smaller number is is 15. |
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| 32. |
A number is chosen at random from the numbers `-5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5`. Then the probability that square of this number is less than or equal to 1 is _____________ . |
| Answer» Correct Answer - `(3)/(11)` | |
| 33. |
sin-1 (sin 2π/3) = (a) 2π/3(b) π/6(c) 4π/3(d) π/3 |
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Answer» Answer is (d) π/3 |
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| 34. |
The L.C.M of two positive integers is thrice the larger number and the difference of the smaller number and the H.C.F is 12. The smaller number is:1. 182. 123. 164. 8 |
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Answer» Correct Answer - Option 1 : 18 Given: L.C.M = 3 × larger number Smaller number – H.C.F = 12 Formula used: The Product of H.C.F and L.C.M of any two numbers is equal to the product of that numbers. Calculation: Let, a = smaller number and b = larger number L.C.M of a, b = 3 × b = 3b a – H.C.F = 12, H.C.F = a – 12 Using formula, L.C.M × H.C.F = a × b ⇒ 3b × (a – 12) = ab ⇒ 3ab – 36b = ab ⇒ 2ab = 36b a = 36/2 = 18 ∴ Smaller number = 18 |
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| 35. |
If n = 35, then find the difference between n2 and √ (n + 1).1. 12192. 12203. 12184. 1217 |
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Answer» Correct Answer - Option 1 : 1219 Given n = 35 n2 = 1225 √ (n + 1) = √ (35 + 1) = 6 Now, n2 - √ (n + 1) = 1225 - 6 = 1219 |
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| 36. |
The relation 'less than' in the set of natural numbers is : -(a) only reflexive (b) only symmetric (c) equivalence (d) only transitive |
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Answer» Answer is (d) only transitive |
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| 37. |
If function f : R → R be defined by f(x) = (3 - x3)1/3, then fof(x) is : -(a) x1/3(b) x3 (c) (3 - x3) (d) x |
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Answer» Answer is (d) x |
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| 38. |
Fill the two blanks in the sequence 2, ____ , 26, ____ so that the sequence forms an A.P. |
| Answer» Correct Answer - `14:38` | |
| 39. |
If an operation * is defined by a * b = a2 + b2, then (1 * 2) * 5 is (a) 3125 (b) 625 (c) 125 (d) 50 |
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Answer» Answer is (d) 50 |
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| 40. |
2 minutes 30 seconds of internet download bill is 18 rupees, then how much will be the bill of 3 minutes 20 seconds? (Up to one decimal place)A. 24B. 24.1C. 24.2D. 23.91. B2. D3. A4. C |
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Answer» Correct Answer - Option 3 : A Given: Bill for 2 minutes 30 seconds = Rs. 18 Calculations: 2 minutes = 2 × 60 ⇒ 120 seconds 2 minutes 30 seconds = 120 + 30 ⇒ 150 seconds Cost of 150 seconds = Rs. 18 ⇒ Cost of 1 second = 18/150 3 minutes = 3 × 60 ⇒ 180 seconds 3 minutes 20 seconds = 180 + 20 ⇒ 200 seconds Cost of 200 seconds = (18/150) × 200 ⇒ 3600/150 ⇒ Rs. 24 ∴ The bill of 3 minutes 20 seconds is Rs. 24. |
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| 41. |
The perimeters of tow similar triangles `DeltaABC ` and `DeltaPQR` are 35cm and 45 cm respectively, then the ratio of the areas of the two triangles is _______. |
| Answer» Correct Answer - `49: 81` | |
| 42. |
The perimeters of two similar triangles are 26 cm and 39 cm. The ratio of their areas will be(a) 2:3(b) 6:9(c) 4:6(d) 4:9 |
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Answer» Correct answer is: (d) 4:9 A1/A2=(P1/P2)2=(26/39)2 A1/A2=(2/3)2=4/9 |
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| 43. |
Find the highest common factor of (4 × 54 × 3125), (16 × 5 × 8) and (32 × 27 × 11 × 49).1. 242. 403. 84. 4 |
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Answer» Correct Answer - Option 3 : 8 Given: Numbers are (4 × 54 × 3125), (16 × 5 × 8) and (32 × 27 × 11 × 49). Concept Used: Factorization Method Calculation: 4 × 54 × 3125, ⇒ 2 × 2 × 54 × 3125 ⇒ 2 × 2 × 2 × 3 × 3 × 3 × 3125 ⇒ 23 × 33 × 5 × 5 × 5 × 5 × 5 ⇒ 23 × 33 × 55 16 × 5 × 8, ⇒ 2 × 2 × 2 × 2 × 5 × 8 ⇒ 2 × 2 × 2 × 2 × 5 × 2 × 2 × 2 ⇒ 27 × 5 32 × 27 × 11 × 49 ⇒ 2 × 2 × 2 × 2 × 2 × 27 × 11 × 49 ⇒ 2 × 2 × 2 × 2 × 2 × 3 × 3 × 3 × 11 × 49 ⇒ 25 × 33 × 11 × 7 × 7 ⇒ 25 × 33 × 72 × 11 Now taking H.C.F. of, (23 × 33 × 55), (27 × 5) and (25 × 33 × 72 × 11) Now by taking common factors, we get ⇒ 23 ⇒ 8 ∴ Heighest Common Factors of given numbers is 8. |
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| 44. |
There are 20 vehicles-cars and motorcycles in a parking area. If there are 56 wheels together, how many cars are there?(a) 8(b) 10(c) 12(d) 20 |
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Answer» Correct answer is: (a) 8 Let no of Cars=x Let no of motorcycles=y X + y=20 4x + 2y=56 Solving the above equations No of cars=x=8 |
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| 45. |
In a parking area, the total number of wheels of all the cars (four-wheelers) and scooters/motorbikes (two-wheelers) is 100 more than twice the number of parked vehicles. The number of cars parked is 1. 352. 453. 504. 55 |
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Answer» Correct Answer - Option 3 : 50 Calculation Let the number of two-wheelers = x Let the number of four-wheelers = y So, the total vehicles = x+y Total number of wheels = 2x + 2y According to question, ⇒2x + 4y = 2(x+y) + 100 ⇒ 2x + 4y = 2x + 2y + 100 ⇒ 2y = 100 ⇒ y = 50 ∴ The number of cars is 50. |
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| 46. |
Write a note on decomposition process |
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Answer» Decomposition or rot is the process by which dead organic substances are broken down into simpler organic or inorganic matter such as carbon dioxide, water, simple sugars and mineral salts. explanation :- The process is a part of the nutrient cycle and is essential for recycling the finite matter that occupies physical space in the biosphere. Bodies of living organisms begin to decompose shortly after death. Animals, such as worms, also help decompose the organic materials. Organisms that do this are known as decomposers. Although no two organisms decompose in the same way, they all undergo the same sequential stages of decomposition. The science which studies decomposition is generally referred to as taphonomy from the Greek word taphos, meaning tomb. Decomposition can also be a gradual process for organisms that have extended periods of dormancy. |
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| 47. |
What is Golgi bodies? |
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Answer» The Golgi apparatus, or Golgi complex, functions as a factory in which proteins received from the ER are further processed and sorted for transport to their eventual destinations: lysosomes, the plasma membrane, or secretion. |
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| 48. |
The process involved in the uptake of minerals from soil by the root hair is: Active transport |
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Answer» The minerals present in the soil can be absorbed through their root hair cells. However, the concentration of minerals in the soil is very low. While water is absorbed by the plants through osmosis, minerals are absorbed as ions by active transport (transport against the law of diffusion, by spending cellular energy). |
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| 49. |
Which among the following is the characteristic of viroids (1) Larger than viruses (2) Have free infectious DNA (3) Have free infectious RNA (4) Have high molecular weight RNA |
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Answer» Correct option is (3) Have free infectious RNA |
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| 50. |
Centers for sense of smell are located ………(a) Cerebellum (b) Midbrain (c) Olfactory lobes (d) Cerebrum |
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Answer» (c) Olfactory lobes |
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