Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

What is periderm? How does periderm formation take place in the dicot stems?

Answer»

Phellogen, phellem, and phelloderm are together known as periderm. Due to secondary growth of the stem, the outer cortical and epidermis layer broken and replaced by another meristematic issue called phellogen. Phellogen or cork cambium cuts o cells on both sides the outer cells are called cork or phellem and the inner cells are phelloderm or secondary cortex.

2.

Three type of tissues formed during secondary growth together have protective functions. 1. Name the three types2. Name the opening found in outer part of mature woody dicot stem and give its function

Answer»

1. phellem, phellogen, and phelloderm 

2. lenticel, gaseous exchange

3.

From where do the secondary cambium appear?

Answer»

From permanent tissues

4.

What does the fascicular cambium gives rise to?

Answer»

Secondary vascular tissues and medullary rays

5.

Which type of meristems can be classified on the basis of positions in the plant body.

Answer»

Apical, intercalary and lateral

6.

Phloem is called the complex tissue while parenchyma is a simple tissue. Make the differences.

Answer»

Phloem is made up of more than one type of cells namely, sieve tube, companion cell, phloem parenchyma & phloem fiber.

 Parenchyma consists of same types of cells.

7.

We cannot nd the woody trunk in monocot plants. Why?

Answer»

Monocots do not possess cambium Hence, the secondary tissues are not formed.

8.

Tissues are specialised to perform mechanical function have thickening at corners, living and cellulosic. Name it.

Answer»

Tissues name is Collenchyma.

9.

Name tissue which provides mechanical strength to the plant’s organs.

Answer»

Sclerenchyma and xylem

10.

A cross-section of plant materials show the following features under microscope there are many vascular bundles scattered in the parenchymatous tissue, xylem is endarch. What kind of plant part shows the above anatomy.

Answer»

Monocot stem

11.

Find the odd one and give reason: Phellem, Phellogen, Phloem, Phelloderm

Answer»

Phloem. The other components are part of periderm

12.

Mention the characteristic features of sieve-tube members.

Answer»

Sieve tubes are cylindrical have endplates called sieve plates. They are dead elements of phloem.

13.

The product of photosynthesis is transported from the leaves to various parts of the plants and stored in some cells before being utilised. What are the cells/tissues that store them?

Answer»

Parenchyma tissue

14.

Xylem is the complex tissue that transports water in plants. 1. Name the main components of xylem. 2. Which of these is most likely suitable for conducting water?

Answer»

1. Xylem parenchyma, vessels, tracheid, xylem fibers. 

2. Vessels

15.

Identify the figure ‘A’ and ‘B’ and differentiate between ‘A’ and ‘B’.

Answer»
            A     B
 Dicotstem Dicot root
 Vascular bundles are arranged in a ring, limited no., conjoint, endarch & open Vascular bundles are radial, exarch
16.

While analysing the anatomy of a given slide, phloem, cambium & xylem are present. Identify the material.

Answer»

The material is Dicot stem.

17.

Examine the anatomy of two plants 1. Xylem vessels and tracheids are seen 2. Xylem vessels absent and tracheids present

Answer»

1. Angiosperm 

2. Gymnosperm

18.

Fill in the blanks: Stem: Endarch:: Root: …… interfascicular cambium: secondary xylem:: cork cambium: ………

Answer»

Exarch, phelloderm

19.

How do you correlate the activity of cambium with changing seasons?

Answer»

During winter season the cambium stops its activity. In spring season cambium becomes more active and produce large quantity of secondary tissue. The secondary xylem produced during spring season is called springwood. During autumn season and summer season the cambium becomes less active and produces small quantity of secondary tissue. The secondary xylem produced during this period is called autumn wood.

20.

What use are phloem fibers put to.

Answer»

Phloem fibers of plants like jute are used for making ropes.

21.

How can we correlate the activity of cambium with changing season?

Answer»

In spring season the activity of cambium is more and produces large no. of xylem vessels with wide lumen. But in Autumn season the activity of cambium is less and produces fewer no. of xylem vessels with narrow lumen.

22.

Identify the plant group from the data given below. (a) Habit-Tree (b) Xylem vessels present (c) Absence of companion cells in phloem (d) No fruits

Answer»

The plant group is Gymnosperm

23.

The following are the characters of Dicot stem and Monocot stem. Identify the character and write in appropriate column. a. collenchymatous hypodermis b. Sclerenchymatous hypodermis c. Open bundle d. Closed bundle e. Bundle cap presentf. Bundle sheath present h. Xylem polygonal g. Xylem circularDicot stemMonocot stem

Answer»
DICOTSTEM MONOCOT STEM
    a      b
    c      d
    e       f
    g      h
24.

If one debarks a tree, what parts of the plant is being removed?

Answer»

Phloem is removed and food translocation becomes difficult.

25.

Cork cambium forms tissues that form the cork. Do you agree with this statement? Give reasons.

Answer»

Cork cambium develops in cortex region during secondary growth in stem. Cork cambium cut off cork (phellum) towards the outside and secondary cortex or phellodem towards the inner-side.

26.

Both apical and intercalary meristems are meristems (a) primary (b) secondary (c) lateral (d) none of these

Answer»

Both apical and intercalary meristems are meristems primary

27.

Observe the diagrams and identify the tissue types.

Answer»

a. Collenchyma 

b. Sclerenchyma

28.

Sclerieds present in(a) fruit wall of nuts(b) pulp of guava(c) seed coat of legumes(d) all of these

Answer»

(d) all of these

29.

Match the Following.     A         BNostocProtonemaGonyaulaxrespiratory rootChlorellared tideCycasSpace travelersRhizophoraheterocystFunariaCoralloid root

Answer»
     A         B
Nostocheterocyst
Gonyaulaxred tide
ChlorellaSpace travelers
CycasCoralloid root
RhizophoraRespiratory root
FunariaProtonema
30.

Bark does not include (a) secondary xylem (b) secondary phloem (c) periderm (d) primary phloem

Answer»

(a) secondary xylem

31.

Observe the diagram and identify the tissue types. Justify your answer.

Answer»
  • The first figure is the Sclerenchymatus tissue. 
  • The second figure is the collenchymatous tissue. 
  • In sclerenchyma tissue, the cell walls are lignified and dead. 
  • In collenchymatous tissue, the cell walls are thick and living.
32.

Match column A with B and C.    A      B       CCollenchymaLateral meristemFood ConductionCambiumCompanion cellHypodermis of dicot stemSieve tubeThickened at cornersSecondary growth

Answer»
    A      B       C
CollenchymaThickened at cornersHypodermis of dicot stem
CambiumLateral meristemSecondary growth
Sieve tubeCompanion cellFood Conduction
33.

Differentiate the following 1. Bark & Periderm 2. Heartwood &Sapwood 3. Endarch & Exarch

Answer»

1. Bark – It is the tissue outside vascular cambium. 

Periderm – It is the outer protective tissue It includes phellem, phellogen, and phelloderm. 

2. Heartwood – It is the dark coloured, nonfunctional central part of wood resistant to the attack of microorganisms. 

Sap wood – It is the light coloured, functional and peripheral part of wood.

3. Endarch – It is the arrangement of xylem in which protoxylem facing towards centre and metaxylem towards the periphery, eg. stem. 

Exarch – It is the arrangement of xylem in which Metaxylem facing towards centre and protoxylem towards periphery.eg: Root.

34.

1. Distinguish between heartwood and sapwood. 2. Heartwood is durable why?

Answer»

1. Distinguish between heartwood and sapwood 

Heartwood

  • found in the central part 
  • nonfunctional 
  • dark coloured

Sapwood

  • found in peripheral part 
  • functional 
  • light coloured

2. Heartwood is resistant to microbial attack and it is filled with resin, gum, essential oil, aromatic oil, and tannins. Hence heartwood is durable

35.

What are elements in innovation process

Answer»

Elements of Innovation: Collaboration, Ideation, Implementation and Value Creation. Innovation requires collaboration, ideation, implementation and value creation. Community developers actively engaged in innovation illustrated each of these elements during breakout sessions.

36.

Describe types of project.

Answer»

The important types of projects mentioned in the following points. 

(1) Research and Development projects: Those traders are fast being intruded into by technological innovation a lot of money is required to be invested on the research and development programmes. 

(2) Diversification project: Any project which wants to reduce its risks instead of giving its product to the same market, can start its business in different markets.

(3) Expansion projects: For any business organisation, when there is growing an instance demand of its product resulting in short supply, it becomes quite imperative increase its production capacity. As such additional capital investment is needed. 

(4) Replacement project: Such project refer to the events of ruining or destruction of the capital assets, or the technological failure resulting into a statement, there is a need of replacement project. As such in this event, the old machines and equipments are required to be replaced with new one replacement projects for establishing new infrastructure are induced in this project planning. 

(5) Miscellaneous Projects: Such ventures that need to invest in those projects which are not directly related to the earning of profits for example due to legal obligations an organisation is required to instal the pollutions control equipment. As such projects, it is the miscellaneous projects which are required.

37.

a) tracheids to vesselsb)roots to leaves c)roots to ste

Answer»

Xylem is the vascular tissue responsible for the transport of water and nutrients from the roots in the soil to the above-ground parts of the plant.

Answer is option (b)

38.

Why doesn't a long lasting vaccine against common cold exist yet?

Answer»

Viruses that present a high mutation rate like the virus that causes the common cold escape easily from the action of vaccines against them. After a primary immune response (natural or artificially induced) against the virus in the next season of infection new mutant resistant strains appear and the protection obtained with the immune response of the last season is lost. (One could say that the high mutation rate is a form of “immunization” found by these viruses.)

39.

Which of the following statement is incorrect regarding defects in solid. (1) In schottky defect density decreases (2) In Frenkel defect density remain unchanged (3) In interstitial defect density increases(4) Due to electronic vacancy density of solid increases

Answer»

Correct option is (4) Due to electronic vacancy density of solid increases

Theory based

40.

What is the value of the Bohr's radius for the first orbit of hydrogen atom?

Answer»

\(rn=\frac {52.9( n2 ) }{Z}pm\)

For first orbit of H-atom, n = 1

Atomic number (z) of H-atom = 1

∴r1 \(= \frac{52.9(1) ^2}{1}\)

= 52.9 pm = 5.29 × 10-11m

41.

The minimum energy needed to eject an electron from Pt where thresholdfrequency was given(a) Work function(b) Kinetic energy(c) Atomic energy(d) Mechanical energy

Answer»

Correct option is (a) Work function

Wo (minimum energy to eject electron is work function) = hvo. (Threshold frequency) h = 6.6 x 10-34 J/S

42.

Which pair among the following is colourless?(a) Sc3+, Zn2+(b) Ti2, Cu2+(c) Fe3+, Mn2+(d) Fe3+, Cu2+

Answer»

Correct option is  (a) Sc3+, Zn2+

Sc3+ - [Ar]

Zn2+- 3d10

Both of them have completely filled orbitals.

Therefore, both are colourless

43.

Among the following species N2, N2+, N2–, N22–, O2, O2+, O2–, O22– the number of species showing diamagnetism is __.

Answer»

Correct answer is 2.

Diamagnetic species are: N2, O22–

44.

The work function for a metal is 4eV. To emit a photoelectron of zero velocity from the surface of the metal, the wavelength of incident light should be :A. `2700Å`B. `1700Å`C. `5900Å`D. `3100Å`

Answer» Correct Answer - D
The work function for a metal ……….
`E_(ev) = (12400eV-Å)/(lambda Å)`
45.

Which of the following gives N2 on thermal decomposition?(a) B2(NO)3(b) Ba(N3)2(c) NaNO3(d) HNO3

Answer»

Correct option is (b) Ba(N3)2

Ba(N3)2 → Ba + 3N2

46.

the difference in wavelength of second and third

Answer»
1/R =  911 A  (aprox.)

47.

If log3 {log3 [log3 x]} = log3 3, then what is the value of x?1. 32. 273. 394. 327

Answer» Correct Answer - Option 4 : 327

Concept:

Properties of logarithms:

\(\rm \frac{log a}{logb}=\log_ba\)

(logx)n = nlogx

\(\rm \log_aa=1\)

 

Calculation:

Here, log3 {log3 [log3 x]} = log3 3

⇒ log3 {log3 [log3 x]} = 1                ....(∵ \(\rm \log_aa=1\))

⇒ {log3 [log3 x]} = 31 = 3

⇒ [log3 x] = 33 = 27

⇒ x = 327

Hence, option (4) is correct.
48.

The relation R = {(1, 1), (2, 2), (3, 3), (1, 2), (2, 3), (1, 3)} on a set A = {1, 2, 3} is1. reflexive transitive but not symmetric2. reflexive, symmetric but not transitive3. symmetric, transitive but not reflexive4. reflexive but neither symmetric not transitive

Answer» Correct Answer - Option 1 : reflexive transitive but not symmetric

Concept:

Let A be a set in which the relation R defined. 

1.R is said to be a Reflexive Relation  (a, a) ∈ R

2. R is said to be a symmetric relation, if (a, b) ∈ R ⇒ (b, a) ∈ R

3. R is said to be a transitive relation, if (a, b) ∈ R , (b, c) ∈ R ⇒ (a, c) ∈ R

 

 

Calculations:

Given set is A = {1, 2, 3}

and the relation is R = {(1, 1), (2, 2), (3, 3), (1, 2), (2, 3), (1, 3)} 

Let A be a set in which the relation R defined.

1.R is said to be a Reflexive Relation  (a, a) ∈ R

2. R is said to be a symmetric relation, if (a, b) ∈ R ⇒ (b, a) ∈ R

3. R is said to be a transitive relation, if (a, b) ∈ R , (b, c) ∈ R ⇒ (a, c) ∈ R

 

Since, 1, 2 , 3 ∈ A and (1, 1), (2, 2), (3, 3) \(\rm ∈ R\)

⇒ Every element maps to itself.

⇒ R is Reflexive 

Now, 1, 2 , 3 \(\rm ∈ R\)

(1, 2), (2, 3) \(\rm ∈ R\) ⇒  (1, 3) \(\rm ∈ R\)

R relates 1 to 2 and 2 to 3, then R also relates 1 to 3

⇒ R is Transitive 

Here, R is not symmetric relation, as (a, b) ∈ R \(\neq \) (b, a) ∈ R

Hence, The relation R = {(1, 1), (2, 2), (3, 3), (1, 2), (2, 3), (1, 3)} on a set A = {1, 2, 3} is reflexive transitive but not symmetric.

49.

Relation R = {(1, 2), (2, 3), (1, 3)} is a/an1. Reflexive2. Transitive3. Symmetric4. None of these

Answer» Correct Answer - Option 2 : Transitive

Concept:

A relation R in a set A is called 

  • Reflexive, if (a, a) ∈ R, for every a ∈ A.
  • Symmetric, if (a, b) ∈ R implies that (b, a) ∈ R, for all a, b ∈A.
  • Transitive, if (a, b) ∈ R and (b, c) ∈ R  implies that (a, c) ∈ R, for all a, b, c ∈A.

Calculation:

Given: R = {(1, 2), (2, 3), (1, 3)}

Reflexive:

As we can see that, (1, 1), (2, 2) does not belong to R. Hence R is not reflexive.

Symmetric:

As we can see that, (1, 2) ∈ R but (2, 1) does not belong to R. Hence relation R is not symmetric.

Transitive:

As we can see that (1, 2), (2, 3)∈ R and (1, 3) also belong to R. Hence relation R is transitive.

Hence, option 2 is the correct answer.

50.

For real number x and y we have xRy ⇔ \(\rm y-x+\sqrt{3}\) is an irrational number then, the relation R is1. Reflexive2. Symmetric3. Transitive4. None of these

Answer» Correct Answer - Option 1 : Reflexive

Concept:

A relation R in a set A is called 

  • Reflexive, if (a, a) ∈ R, for every a ∈ A.
  • Symmetric, if (a, b) ∈ R implies that (b, a) ∈ R, for all a, b ∈A.
  • Transitive, if (a, b) ∈ R and (b, c) ∈ R  implies that (a, c) ∈ R, for all a, b, c ∈A.

Calculation:

Given: R = {(x, y) : y - x + √3 is an irrational number, where x, y ∈ R}

Reflexive:

If xRx ⇔ x - x + √3 = √3 and we know that √3  is irrational number.

Hence, relation R is reflexive.

Symmetric:

If x = 1, y = √3 and we can see that y - x + √3 = 2√3 - 1 which is an irrational number. So, (x, y) ∈ R.

But we can see that, x - y + √3 = 1 and 1 is not an irrational number. So, (y, x) does not belongs to R.

Hence, relation R is not symmetric.

Transitive:

As we can see that, (√3, √2) ∈ R, (√2, 1) ∈ R but (√3, 1) does not belongs to R

Hence, relation R is not transitive.