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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Control of the users’ access to network resources through charges is the main responsibility of ________(a) Reactive Fault Management(b) Reconfigured Fault Management(c) Accounting Management(d) Security Management |
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Answer» The correct answer is (c) Accounting Management The best I can explain: The accounting management keeps track of the users and their access rights to the network and controls the user’s access by communicating with the security management. The accounting management takes support of the Management Information Block to perform its operations. |
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| 2. |
In Network Management System, the division that is responsible for controlling access to network based on a predefined policy is called _________(a) Fault Management(b) Secured Management(c) Active Management(d) Security Management |
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Answer» The correct option is (d) Security Management Explanation: Security management is also responsible to provide confidentiality, authentication and encryption in addition to controlling access to network. Without security management, the network and its traffic would be vulnerable to be exploited by attackers. |
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| 3. |
Control of users’ access to network resources through charges is the main responsibility of ______________(a) Reactive Fault Management(b) Reconfigured Fault Management(c) Accounting Management(d) Security Management |
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Answer» Correct answer is (c) Accounting Management The explanation: Control of users’ access to network resources through charges is the main responsibility of accounting management. The accounting management creates a log of the users activity on the network too and goes hand-in-hand with the configurations management. |
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| 4. |
Which of this is not a class of IP address?(a) Class E(b) Class C(c) Class D(d) Class F |
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Answer» The correct option is (d) Class F The explanation: Class F is not a class of IP addressing. There are only five classes of IP addresses: Class A (0.0.0.0 to 127.255.255.255), Class B (128.0.0.0 to 191.255.255.255), Class C (192.0.0.0 to 223.255.255.255), Class D (224.0.0.0 to 239.255.255.255), and Class E (240.0.0.0 to 255.255.255.255). |
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| 5. |
The _________ field determines the lifetime of IPv6 datagram(a) Hop limit(b) TTL(c) Next header(d) Type of traffic |
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Answer» The correct choice is (a) Hop limit The explanation: The Hop limit value is decremented by one by a router when the datagram is forwarded by the router. When the value becomes zero the datagram is discarded. The field is 8-bits wide, so an IPv6 packet can live up to 255 router hops only. |
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| 6. |
Communication between a computer and a keyboard involves ______________ transmission.(a) Automatic(b) Half-duplex(c) Full-duplex(d) Simplex |
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Answer» The correct answer is (d) Simplex To explain I would say: In simplex transmission, data flows in single direction which in this case refers to the data flowing from the keyboard to the computer. Another example would be of the mouse where the data flows from the mouse to the computer only. |
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| 7. |
Network addresses are a very important concept of ________(a) Routing(b) Mask(c) IP Addressing(d) Classless Addressing |
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Answer» Correct choice is (c) IP Addressing Explanation: Network addresses are a very important concept of IP addressing. The first address in a block is used as network address that represents the organization. The network address can be found by AND’ing any address in the block or class by the default mask. |
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| 8. |
In the IPv6 header, the traffic class field is similar to which field in the IPv4 header?(a) Fragmentation field(b) Fast-switching(c) ToS field(d) Option field |
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Answer» Correct option is (c) ToS field To explain: The traffic class field is used to specify the priority of the IP packet which is a similar functionality to the Type of Service field in the IPv4 header. It’s an 8-bit field and its values are not defined in the RFC 2460. |
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| 9. |
Which among the following features is present in IPv6 but not in IPv4?(a) Fragmentation(b) Header checksum(c) Options(d) Anycast address |
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Answer» Correct choice is (d) Anycast address To explain I would say: There is an anycast address in IPv6 which allows sending messages to a group of devices but not all devices in a network. Anycast address is not standardized in IPv4. |
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| 10. |
A few leftmost bits in each address of IPv6 address define its category is called ________(a) Prefix type(b) Postfix type(c) Reserved type(d) Local type |
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Answer» Correct choice is (a) Prefix type Easiest explanation: Prefix is the bits in the IP address which are placed in leftmost position. A network prefix in IPv6 is given by a CIDR format-liked number at the end of the address. |
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| 11. |
IPv6 does not use _________ type of address.(a) broadcast(b) multicast(c) anycast(d) unicast |
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Answer» Right answer is (a) broadcast For explanation I would say: There is no concept of broadcast address in IPv6. Instead, there is an anycast address in IPv6 which allows sending messages to a group of devices but not all devices in a network. Anycast address is not standardized in IPv4. |
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| 12. |
IPv6 does not use ________ type of address.(a) Broadcast(b) Multicast(c) Any cast(d) Unicast |
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Answer» Right option is (a) Broadcast To explain: There is no concept of broadcast address in IPv6. Instead, there is an anycast address in IPv6 which allows sending messages to a group of devices but not all devices in a network. Anycast address is not standardized in IPv4. |
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| 13. |
First address in a block is used as network address that represents the ________(a) Class Network(b) Entity(c) Organization(d) Codes |
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Answer» Correct answer is (c) Organization To explain: First address in a block is used as network address that represents the organization. The network address can be found by AND’ing any address in the block by the default mask. The last address in a block represents the broadcast address. |
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| 14. |
In a simple echo-request message, the value of the sum is 01010000 01011100. Then, value of checksum is ___________(a) 10101111 10100011(b) 01010000 01011100(c) 10101111 01011100(d) 01010000 10100011 |
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Answer» Right option is (a) 10101111 10100011 The explanation is: The sender side adds the bits of the fragmented packet to find a sum. Checksum is the compliment of the sum (exchange 0’s and 1’s). The receiver then has to verify the checksum by adding the bits of the received packet to ensure that the packet is error-free. |
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| 15. |
The first Network was called ________(a) CNNET(b) NSFNET(c) ASAPNET(d) ARPANET |
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Answer» The correct option is (d) ARPANET The best explanation: ARPANET stands for Advanced Research Projects Agency Networks. It was the first network to be implemented which used the TCP/IP protocol in the year 1969. |
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| 16. |
A _______ is the physical path over which a message travels.(a) Path(b) Medium(c) Protocol(d) Route |
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Answer» The correct option is (b) Medium The explanation: Messages travel from sender to receiver via a physical path called the medium using a set of methods/rules called protocol. Mediums can be guided (wired) or unguided (wireless). |
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| 17. |
Which organization has authority over interstate and international commerce in the communications field?(a) ITU-T(b) IEEE(c) FCC(d) ISOC |
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Answer» Correct choice is (c) FCC To elaborate: FCC is the abbreviation for Federal Communications Commission. FCC is responsible for regulating all interstate communications originating or terminating in USA. It was founded in the year 1934. |
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| 18. |
Which of this is not a network edge device?(a) PC(b) Smartphones(c) Servers(d) Switch |
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Answer» Correct choice is (d) Switch For explanation: Network edge devices refer to host systems, which can host applications like web browser. A switch can’t operate as a host, but as a central device which can be used to manage network communication. |
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| 19. |
Data communication system within a building or campus is________(a) LAN(b) WAN(c) MAN(d) PAN |
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Answer» The correct choice is (a) LAN The best I can explain: LAN is an abbreviation for Local Area Network. This network interconnects computers in a small area such as schools, offices, residence etc. It is the most versatile kind of data communication system where most of the computer network concepts can be visibly used. |
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| 20. |
A _________ set of rules that governs data communication.(a) Protocols(b) Standards(c) RFCs(d) Servers |
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Answer» Right choice is (a) Protocols For explanation: In communications, a protocol refers to a set of rules and regulations that allow a network of nodes to transmit and receive information. Each layer in the network model has a protocol set, for example, the transport layer has TCP and UDP protocols. |
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| 21. |
Three or more devices share a link in ________ connection.(a) Unipoint(b) Multipoint(c) Point to point(d) Simplex |
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Answer» Correct option is (b) Multipoint The best I can explain: A multipoint communication is established when three or many network nodes are connected to each other. Frame relay, Ethernet and ATM are some examples of multipoint connections. |
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| 22. |
Who gave the name ‘C++’? |
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Answer» The name C++ is given by Rick Mascitti. |
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| 23. |
Define computer memory. |
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Answer» The working place in a computer where all the data and instructions are stored is called memory. |
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| 24. |
Define algorithm. |
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Answer» An algorithm is a “step by step procedure to solve a given problem in a finite number of steps”. |
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| 25. |
Give anyone example of non-impact printer? |
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Answer» One example of non-impact printer is Ink jet printer. |
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| 26. |
Expand the term OMR. |
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Answer» Optical Mark Reader/Recognition. |
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| 27. |
What is syntax error? |
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Answer» It refers to an error in the syntax of a sequence of characters or tokens that is intended to be written in a particular programming language. |
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| 28. |
Expand OMR ? |
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Answer» Optical Mark reader/recognition. |
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| 29. |
Write a note on main frame computers. |
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Answer» Main frame computers are fastest and largest expensive computers. They are normally used for business computations. |
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| 30. |
Define debugging? |
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Answer» Bug is a problem in a program and debug means finding a solution to that problem. |
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| 31. |
Define keyword. |
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Answer» All keywords (reserved words) are basically the sequences of characters that have one or more fixed meanings. |
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| 32. |
Mention any one type of chart in ESS. |
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Answer» The different categories of charts are column, line, pie, bar, xy scattered, etc., |
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| 33. |
What is a worksheet? |
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Answer» It is a sheet that contains rows and columns, to store data like student marks, salary of employees, etc.,. |
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| 34. |
Define a token? |
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Answer» The smallest individual units in a program are known as tokens. |
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| 35. |
What is header in word processor? |
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Answer» A header is a special area a|the top of every page normally allocated in the top margin area. |
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| 36. |
What is the purpose of break statement? |
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Answer» ‘break’ statement terminates the loop / switch and transfers control to the statement following the loop / switch . |
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| 37. |
What is the extraction operator in C++? |
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Answer» cin is used in conjuction with >> operator, known as extraction or get from operator in C++. |
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| 38. |
Name any two word processors. |
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Answer» The two word processors are MS word, Word perfect. |
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| 39. |
Which is the insertion operator? |
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Answer» cout is used in conjuction with << operator, known as insertion or put to operator. |
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| 40. |
Define token in C++. |
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Answer» The smallest individual units in a program are known as tokens, on lexical units. |
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| 41. |
Symbolise the following proposition: 3x = 9 and x < 7 |
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Answer» (i) Let p:3x = 9, q = x < 7 Given in symbols is p ∧ q |
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| 42. |
What does the keyword ‘void’ represent? |
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Answer» The data type ‘void’ has no values and no operations means it is empty. It plays a role of generic data type and can represent any of the other standard types. |
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| 43. |
What is a selection statement? |
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Answer» Selection statements are used to execute certain block of statements for evaluating the conditions. |
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| 44. |
What are formal parameters? |
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Answer» Formal arguments are the names of the arguments/parameters in the function header of called function. |
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| 45. |
What is the purpose of break statement? |
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Answer» The break statement can be used to terminate a repeated structure (loops) such as while, do while and for and multi branching statements like switch. |
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| 46. |
The _______ operator is used to connect multiple verb actions together into a pipeline.(a) pipe(b) piper(c) start(d) end |
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Answer» The correct answer is (a) pipe For explanation I would say: It is denoted by %>% sign. |
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| 47. |
Define actual arguments. |
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Answer» The data that is passed by the calling function as arguments/parameters is known as actual arguments, i.e., the arguments which are present at the time of function call. |
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| 48. |
What is a header? |
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Answer» A header in word processor is a special area at the top of every page, normally allocated in the top margin area. |
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| 49. |
Name the stream insertion operator. |
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Answer» cout is used in conjuction with << operator, known as insertion or put to operator. |
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| 50. |
Write the declaration syntax of one dimensional array. |
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Answer» datatype array name [size]; |
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