Explore topic-wise InterviewSolutions in Current Affairs.

Correct option is (C) (A), (B) only 

Enzyme inhibitors can be competitive inhibitors (inhibit the attachment of substrate on active site of enzyme) and non-competitive inhibitor (changes the active site of enzyme after binding at allosteric site.)

Types of Scripting Language
PHP.
ASP.NET.
Node. js.
Java.
Ruby.
Perl.
Python.

#include <stdio.h>

int main()
{
  int i, a = 1, count;
 

  while(a <= 100)
  {
    count = 0;
    i = 2;
    while(i <= a/2)
    {
      if(a%i == 0)
      {
        count++;
break;
      }
      i++;
    }
    if(count == 0 && a != 1 )
    {
printf(" %d ", a);
    }
    a++;
  }
  return 0;
}

#include <stdio.h>

void main()
{
int i, num, odd_sum = 0, even_sum = 0;

printf("Enter the value of num\n");
scanf("%d", &num);
for (i = 1; i <= num; i++)
{
if (i % 2 == 0)
even_sum = even_sum + i;
else
odd_sum = odd_sum + i;
}
printf("Sum of all odd numbers = %d\n", odd_sum);
printf("Sum of all even numbers = %d\n", even_sum);
}

output :

(i) Angular velocity [M⁰L⁰T^-1] rad s^-1 

(ii) Velocity gradient [M⁰L⁰T^-1] s^-1 

(iii) Frequency [M⁰L⁰T^-1] Hz

Correct option is (d) 200 μC

If 1,2,3,4 uF capacitors are connected in parallel then

C_eq = 1+2+3+4 =10μF

Given: V = 20 volt

So charge flown from the battery

q = 10 x 20 μC

q = 200 μC

Electric dipole moment, p = 4 × 10⁻⁹ C m
Angle made by p with a uniform electric field, θ = 30°
Electric field, E = 5 × 10⁴ N C⁻¹
Torque acting on the dipole is given by the relation, τ = pE sinθ =4×10⁻⁹×5×10⁴×sin30=20×10⁻⁵×1/2=10⁻⁴ Nm
Therefore, the magnitude of the torque acting on the dipole is 10⁻⁴ N m.

Many charges flow to and from earth, over which cosmic rays are a tiny part. For instance, an energetic particle arriving in earths atmosphere will create many particle pair of which some must be capable to leave earth and you have the solar wind A strong voltage at earth would already be notices, since it would charge the mean energy of the electrons that arrive.

Correct option is C) behave

Correct option is B) information

Correct option is C) permission

Correct option  (d) 9.1 kΩ

Explanation:

R = 91 × 10² ± 10% ≈ 9.1 kΩ

i. c 

ii. b 

iii. d 

iv. b 

v. d

(d) 90°

The angle between two vector is always  90°.

The correct answer is Periyar.

• Rann of Kutch is an inland drainage area.
• Inland drainage is that drainage in which rivers do not reach an ocean or sea but empty their waters in a lake or an inland sea.
• Narmada flows between Vindhya and Satpura range. Rivers Luni, Ghaggar, Rupnarain, Medha, etc have inland drainage.
• The Ghaggar is the most important river of inland drainage.
• It is a seasonal stream that rises on the lower slopes of the Himalayas and forms a boundary between Haryana and Punjab.
• It gets lost in the dry sands of Rajasthan near Hanumangarh after traversing a distance of 465 km.

The correct answer is ​Vikram Sarabhai.

• Vikram Sarabhai was a scientist, a great industrialist and a founder of many industries in India.

• Vikram Ambalal Sarabhai was an Indian physicist and astronomer who started space research and helped generate nuclear power in India.
• He is universally revered as the Father of the Indian Space Program.
• Sarabhai Chemicals, Sarabhai glass, Sarabhai Geigy Limited are some of the industries founded by Vikram Sarabhai.
• He was also the founder of Ahmedabad Textile Industrial Association and Ahmedabad Money Association.
• He was awarded Padma Bhushan in 1966 and the Padma Vibhushan (posthumously) in 1972.

International Union for Conservation of Nature and Natural Resources.

(a) More tolerant to abiotic stress 

(b) Provide better yields of crop 

(c) Reduced post harvest losses 

(d) Increased nutritional value of food.

The slope of regression (z) has a great significance in order to find a species-area relationship. It has been found that in smaller areas (where the species-area relationship is analysed), the value of slopes of regression is similar regardless of the taxonomic group or the region. However, when a similar analysis is done in larger areas, then the slope of regression is much steeper.

Species extinction occuring at present is due to anthropogenic causes where as the earlier extinction was due to natural causes.

Correct Option (a) Auxin in apical part of shoot have the ability to bans part the cytokinin from root in the apical part of shoot 

The correct answer is Rahr Plain.

• The sandy coastal plain of 'kanthi' lies in Rahr Plain region of West Bengal.
• Kanthi or Contai is a city in the Purba Medinipur district.

Correct option is (d) 2

Correct option is: (B) - \(\frac{1}{\sqrt{2}}\)

Correct option is: (D) Fourth

Correct answer is (D) 10

Answer is (2) b² – b = 30

Let z = α ± iβ be roots of the equation 

So 2α = –b and α² + β² = 45, (α + 1)² + β² = 40

So (α + 1)² – α² = – 5

⇒ 2α + 1 = – 5 ⇒ 2α = – 6

so b = 6

hence b² – b = 30 

Given ,

Ag/Ag⁺ (0.005M) // Ag⁺ (0.5M)/ Ag(s)

A+ anode Ag → Ag⁺ (0.005M)^+e

A + Cathode Ag⁺ (0.5M) + e^- → Ag(s)

over all cell reaction - 

Ag⁺ (0.5M) → Ag⁺ (0.005)

as we know concentration cell , the standard electrode potential (E°) equal to zero.

using nearest equation --

E_cell = E° - \(\frac{RT}{nF}\) \(ln(\frac{[Ag^+]}{[Ag^+]})\)

∴ E_cell  = 0 - \(\frac{RT}{F}\) \(ln\frac{0.005}{0.5}\)

E_cell  = -0.0591 log 10^-2

= 0.0591 x 2

E_cell = 0.1182 v

if concentration of Ag⁺ change from 0.005 M to 0.01 M

then

E_cell = log \((\frac{0.01}{0.5})\)

= -0.0591 log (0.02)

= (-0.0591) x (-1.699)

E_cell  = 0.1 v

Hence the potential of cell will be 0.1 v

Disease like Dysentery and Malaria are caused by Protozoa.

Yeast Micro organism use in the baking industry for making breads.