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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Which of the following is not a connective tissue?(1) Adipose tissue(2) Cartilage(3) Neuroglia(4) Blood |
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Answer» Correct option is (3) Neuroglia |
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| 2. |
Write the differences between hormone and enzyme. |
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| 3. |
Does the saliva have any other roles to play ? |
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Answer» Yes. Saliva helps in the chewing of food and makes it soft and slurry and helps in sliding of the food into oesophagus. |
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| 4. |
Given below are two statements:Statement I:Restriction endonucleases recognise specific sequence to cut DNA known as palindromic nucleotide sequence.Statement II:Restriction endonucleases cut the DNA strand a little away from the center of the palindromic site.In the light of the above statements, choose the most appropriate answer from the options given below:(1) Both Statement I and Statement II are incorrect (2) Statement I is correct but Statement II is incorrect(3) Statement I is incorrect but Statement II is correct (4) Both Statement I and Statement II are correct |
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Answer» (4) Both Statement I and Statement II are correct |
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| 5. |
Write about the passage that facilitates from the production of ovum or egg to fertilization. |
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Answer» Mature graffian follicle bursts and produces ovum. It enters directly into fallopian tube which has funnel like structure. From there after fertilization egg enters uterus as an embryo. |
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| 6. |
Do you want sugar _____ your tea ? A) with B) on C) by D) at |
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Answer» Correct option is A) with |
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| 7. |
I’m afraid _____ falling trees. A) from B) of C) with D) at |
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Answer» Correct option is A) from |
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| 8. |
I’m afraid ______ falling trees. A) from B) of C) with D) at |
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Answer» Correct option is B) of |
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| 9. |
She didn’t get a passing grade ______ her test. A) on B) with C) at D) of |
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Answer» Correct option is A) on |
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| 10. |
He didn’t pass his driving test. He wishes he _____ it. A) have passed B) had passed C) will pass D) pass |
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Answer» Correct option is B) had passed |
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| 11. |
I can see Amanda. ______ is waiting for the New York plane. A) I B) She C) His D) He |
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Answer» Correct option is B) She |
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| 12. |
I haven’t been to Beijing. I wish I _____ to Beijing. A) had been B) have been C) has been D) will be |
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Answer» Correct option is A) had been |
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| 13. |
Cherry blossoms, strawberry ice cream and pigs are all ___ |
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Answer» Correct answer is pink |
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| 14. |
Gladiolus is propagated by |
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Answer» Gladiolus is propagated by Corms |
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| 15. |
It is difficult to get ______ people how dangerous smoking is to their health. A) down in B) in at C) across to D) in with |
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Answer» Correct option is C) across to |
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| 16. |
Anthrax is a……….. disease of animals (Bacterial/fungal/protozoan) |
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Answer» Anthrax is a Bacterial disease of animals (Bacterial/fungal/protozoan) |
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| 17. |
Suggest some methods to assist infertile couples to have children. |
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Answer» Infertility is the inability of a couple to produce a baby even after unprotected intercourse. It might be due to abnormalities present in either male or female, or might be even both the partners. The techniques used to assist infertile couples to have children are as follows.
This involves in-vitro fertilization where the sperms meet the egg outside the body of a female. The zygote, hence produced, is then transferred in the uterus or fallopian tube of a normal female. The babies produced from this method are known as test tube babies.
It is a technique that involves the transfer of gamete (ovum) from a donor into the fallopian tube of the recipient female who is unable to produce eggs, but has the ability to conceive and can provide right conditions for the development of an embryo.
It is a method of injecting sperm directly into the ovum to form an embryo in laboratory.
Artificial insemination is a method of transferring semen (sperm) from a healthy male donor into the vagina or uterus of the recipient female. It is employed when the male partner is not able to inseminate the female or has low sperm counts. |
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| 18. |
Given below are some of the offspring obtained by self-pollinating the above plant. Analyze the offspring and answer the questions.a) ttRr b) ttRR c) TTrr d) ttrri) Identify the dominant characters in each of the offspring?ii) What explanation would you give for the expression of characters in the offspring which were hidden in the parental plant? |
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Answer» i. a) dwarf, red flower b) dwarf, red flower c) tall, white flower d) dwarf, white flower ii. The expression of characters in the offsprings which were hidden in the parental plant is due to the independent assortment of each character. |
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| 19. |
Analyze the illustration of a nucleotide molecule and answer the questions.a) Identify A and B in the illustration. b) ‘Nucleotides are found in DNA alone’. What is your opinion regarding these statements? Substantiate. |
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Answer» a) A – Phosphate B – Sugar b) 1. does not agree 2. Like DNA, RNA is also made up of nucleotides |
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| 20. |
The components and features of nucleic acid are given below. Analyze them and complete the table.a) ribose sugar b) double helical shape c) Uracil d) one strand e) deoxyribose sugar f) thymineDNARNA................................ |
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| 21. |
Match the hominids with their correct brain size :(a) Homo habilis(i) 900 cc(b) Homo neanderthalensis(ii) 1350 cc(c) Homo erectus(iii) 650-800 cc(d) Homo sapiens(iv) 1400 ccSelect the correct option. |
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Answer» Correct option: (3) Explanation: The correct match of hominids and their brain sizes are : Homo habilis — 650-800 cc Homo neanderthalensis — 1400 cc Homo erectus — 900 cc Homo sapiens — 1350 cc |
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| 22. |
‘While some mutations are harmful, some of them are helpful.” Analyze the statement. |
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Answer» This statement is correct. Certain mutations are harmful and some are helpful for survival of the organism. Mutations also lead to evolution. |
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| 23. |
Vipin wrote the following as situations that create variations in organisms. Choose the right ones.a) Mutation b) Formation of mRNA c) Crossing over of chromosomes d) Action of rRNA |
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Answer» a) Mutation c) Crossing over of chromosomes |
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| 24. |
Genes which are the specific units of DNA control the metabolic activities and are also responsible for specific characters. They control the process of protein synthesis. Binu has a doubt on the above note.‘Does the RNA have no role in protein synthesis?’ What explanation would you give to Binu’s doubt? Substantiate. |
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| 25. |
Which chromosome is different in male and female? |
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Answer» Sex chromosome is different. The sex chromosome of female is are XX and in male are XY. |
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| 26. |
‘‘Some specific processes during Meiosis helps to create variation in characters among organisms Analyse this statement and explain the process. |
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Answer» Homologous chromosomes from father and mother pair exchange chromosomal material during meiosis. Tbi3 is “Crossing Over” in meiosis. |
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| 27. |
Fill in the blanks in the illustration related to chromosomes in man. |
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Answer» A) Autosomes B) 2 C) XY |
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| 28. |
Observe the diagram Identify the process which occurs in Chromosomes during meiosis. |
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Answer» Crossing over |
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| 29. |
Observe the figure and answer the questions given below.a) Name the process shown in the figure.b) Write the importance of this process. |
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Answer» a) Crossing over b) Causes variation |
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| 30. |
A pea plant with genetic constitution TtRr (Tall plant which produces red flower) was subjected to self-pollination. The genetic constitution of some of the progenies obtained are given below. Write the expressed character of the given progenies based on their genetic constitution.(a) TTRr (b) ttrr (c) ttRr (d) Ttrr |
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Answer» a) TTRr – tall plant with red flower b) ttrr – dwarf plant with white flower c) ttRr – dwarf plant with red flower d) Ttrr – tall plant with white flower |
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| 31. |
The different stages of protein synthesis given below. Rearrange them appropriately.a) tRNA carries different types of amino acids.b) mRNA come out from the nucleus. c) mRNA is formed from DNA. d) Amino acids are joined together based on the messages in mRNA. e) mRNA reaches in ribosome. f) Protein is synthesized. |
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Answer» c → b → e → a → d → f |
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| 32. |
The stages in the process of protein synthesis are given below. Prepare a flowchart using the stages.a) tRNA carries different kinds of amino acids to the ribosome.b) mRNA reaches outside the nucleus. c) mRNA forms from DNA d) Amino acids are added based on the information in mRNA e) mRNA reaches ribosome. f) Proteins are synthesized. |
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Answer» c → b → e → a → d → f |
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| 33. |
Find the odd one. Write down the common feature of the others.a) Bypass surgery, ECG, EEG, Pacemaker b) Adenine, Cytosine, Thymine, Uracil |
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Answer» a) EEG: Related with the treatment of heart diseases b) Uracil: Nitrogen bases in DNA/Thymine: Nitrogen bases in RNA. |
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| 34. |
Fill up the blanks in the table showing gene action in protein synthesis. |
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Answer» a) RNA is being synthesized b) RNA comes out through nuclear membrane c) RNA1 combines with ribosomes |
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| 35. |
Gopalettan is trying to develop new varieties of pea plants in his garden. Given below is the illustration of the experiment which he conducted. Observe this and answer the questions that follow.a) Which law of hereditary can be used to explain the reason of violet flowered plants in the F1 generation?b) Among these, which are the dominant and recessive characters?c) What will be the characters appearing in the F2 generation if the plants in the F1 generation are self-pollinated? In what ratio? |
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Answer» a) Law of dominance. (When a pair of contrasting characters combines, only one character is expressed, while the other remains hidden.) b) Dominant is violet and recessive is white. c) Yellow and green seeds in 3:1 ratio. |
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| 36. |
How do proteins control expression of traits .Explain with the help of an example. |
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Answer» Cellular DNA is the information source for making proteins in the cell. A section of DNA that provides information for one protein is called the gene for that protein. Genes are sections or segments of DNA that are carried on the chromosomes and determine specific human characteristics, such as height or hair color. |
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| 37. |
A frequency distribution that contains a class with limits of "10 and under 20" would have a midpoint: (a) 10 (b) 14.9 (c) 15 (d) 20 |
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Answer» Correct option is (c) 15 |
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| 38. |
The lower and upper class limits are 20 and 30, the midpoints of the class is: (a) 20 (b) 25 (c) 30 (d) 50 |
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Answer» Correct option is (b) 25 |
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| 39. |
Is service INCLUDED? A) involved B) embraced C) urged D) excluded E) improved |
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Answer» Correct option is D) excluded |
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| 40. |
In an exclusive classification, the limits excluded are: (a) Upper limits (b) Lower limits (c) Both lower and upper limits (d) Either lower or upper limits |
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Answer» (d) Either lower or upper limits |
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| 41. |
An ideal gas follows following process `P^(2)V= constant. Then on expansion, the tempereture of gasA. decreasesB. increasesC. remain constantD. none of these |
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Answer» `P^(2)V=` constant PV=nRT `P=(nRT)/(V)` `P^(2)V=((nRT)/(V))^(2)V` `=((nRT)^(2))/(V)=` constant `V alpha T^(2)` increases in expansion |
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| 42. |
A gas at a pressure of 5 atm is heated from `0^(@)C` to `546^(@)C` and simultaneously compressed to one third of its original volume. Hence final pressure is:A. 10atmB. 30atmC. 45atmD. 5atm |
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Answer» `(PV)/(T)=` constant `(5xxV)/(273)=(ptxx(V)/(3))/(819)` `rArrP_(r)=45atm` |
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| 43. |
The bond that undergoes heterolytic cleavage most readily isA. C-OB. C-CC. C-HD. O-H |
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Answer» Correct Answer - A C-O bond undergoes heterolytic cleavage most easily. |
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| 44. |
(A) Tertiary butyl carbonion is more stable than methyl carbanion. (R) `+I` effect of the three methyl groups in tertiary butyl carbanion tends to make it more stable than methyl carbanion.A. If both (A) and (R) are correct and (R) is the correct explanation of (A).B. If both (A) and (R) are correct but (R) is not the correct explanation of (A).C. If (A) is correct but (R) is incorrect.D. IF (A) is incorrect but (R) is correct. |
| Answer» Correct Answer - D | |
| 45. |
Electrophillic addition reaction proceed in two steps. The first step involves the addition of an electrophile. Name the type of intermediate formed in the first step of the following addition reaction. `H_(2)C-HC=CH_(2)+H^(+) rarr` ?A. `2^(@)` carbocationB. `1^(@)` carbocationC. `2^(@)` carbanionD. `1^(@)` Carbanion |
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Answer» Correct Answer - A `H_(3)C-CH=CH_(2)+H^(+) to underset(("most stable"))underset(2^(@)"carbocation")(H_(3)C-overset(+)CH=CH_(3))` |
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| 46. |
(A) Heterolytic fission involves the breaking of a covalent bond in such a way that both the electrons of the shared pair are carried away by one of tha atoms. (R) Heterolytic fission occurs readily in polar covalent bonds.A. If both (A) and (R) are correct and (R) is the correct explanation of (A).B. If both (A) and (R) are correct but (R) is not the correct explanation of (A).C. If (A) is correct but (R) is incorrect.D. IF (A) is incorrect but (R) is correct. |
| Answer» Correct Answer - B | |
| 47. |
Norman Borlaug is associated withA. green revolutionB. yellow revolutionC. white revolutionD. blue revolution |
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Answer» Correct Answer - A Norman borlaug is associted with green revolution.The green revolution means an increas in the production of crops particlularly cereals such as wheat rice and maize. |
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| 48. |
Why cannot the dilute solution of hydrogen peroxide be concentrated by strong heating? |
| Answer» `H_(2)O_(2)` decomposes into `H_(2)` and `O_(2)`. | |
| 49. |
The decrease in stability of higher oxidation state in p-block with increasing atomic number is due to:A. Increase in bond energy as going down the groupB. Inert pair effectC. Both (A) and (B)D. None is correct |
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Answer» Correct Answer - B Owing to inert pair effect. The inert pair effect is the reluctance of s-orbital electrons to participate in chemical bonding. |
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| 50. |
With the help of thermochemical equations given below, determine `Delta_(r )H^(Θ)` at `298 K` for the following reaction: `C("graphite")+2H_(2)(g) rarr CH_(4)(g),Delta_(r )H^(Θ) = ?` `C("graphite")+O_(2)(g) rarr CH_(2)(g), Delta_(r )H^(Θ) = -393.5 kJ mol^(-1)` ...(1) `H_(2)(g) +1//2O_(2)(g) rarr H_(2)O(l)`, `Delta_(r )H^(Θ) = -285.8 kJ mol^(-1)` ...(2) `CO_2(2)(g)+2H_(2)O(l) rarr CH_(4)(g)+2O_(2)(g)`, `Delta_(r )H^(Θ) = +890.3 kJ mol^(-1)` ...(3) |
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Answer» Here we want one mole of `C_(("graphite"))` as reactant, so we write down eauation (i), we want two mole of `H_(2)(g)` as reactant, so we multiply equation (ii) by `2`, we want one mole of `CH_(4)(g)` as product, so we write down equation (iii) as such, `C_(("graphite"))+O_(2)(g) rarr CO_(2)(g), Delta_(r )H^(Θ)=-393.5 kJ mol^(-1)` ...(i) `2H_(2)(g)+O_(2) rarr 2H_(2)O(l), Delta_(r)H^(Θ)=2(-285.8 kJ mol^(-1))` ...(ii) `CO_(2)(g)+2H_(2)O(l) rarr CH_(4)(g)+2O_(2)(g), Delta_(r)H^(Θ)=+890.3 kJ mol^(-1)` ...(iii) Adding we obtain `C_(("graphite"))+2H_(2)(g) rarr CH_(4)(g), Delta_(r)H^(Θ)=-74.8 kJ mol^(-1)` |
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