100525 + Interview Questions in GENERAL QA IN GENERAL AWARENESS

1.	………..is the environment in which the service is delivered and where the rm and customer interact and any tangible components that facilitate performance or communication of the service. a. Physical evidence b. Process c. Place d. People
Answer» a. Physical evidence

Discussion

2.	…………..is a tool for simultaneously depicting the service process, the points of customer contact, and the evidence of service from the customer’s point of view. a. Front end planning b. Service Blueprinting c. Service Standardization d. None of these
Answer» Service Blueprinting .is a tool for simultaneously depicting the service process, the points of customer contact, and the evidence of service from the customer’s point of view.

Discussion

3.	Which of the following is not a type of Service encounters? a. Remote encounters b. Phone encounters c. Face to face encounters d. Check in Encounters
Answer» d. Check in Encounters

Discussion

4.	“…….is the culture where an appreciation for good service exists and where giving good service to internal as well as ultimate, external customers is considered a natural way of life and one of the most important norms by everyone.”a. Service culture b. Corporate culture c. Service Triangle d. Service Quality Dimensions
Answer» a. Service culture

Discussion

5.	Where is the bile produced? Which component of the food does it help to digest?
Answer» Bile is a fluid that is made and released by the liver and stored in the gallbladder. Bile helps with digestion. It breaks down fats into fatty acids, which can be taken into the body by the digestive tract.

Discussion

6.	BCG in BCG matrix stands for a. Boston Calmette Group b. British Consulting Group c. Boston Corporate Group d. Boston Consulting Group
Answer» d. Boston Consulting Group

Discussion

7.	The origins of Business Policy & Strategic Management can be retraced to a. 1930 b. 1911 c. 1879 d. 1938
Answer» The origins of Business Policy & Strategic Management can be retraced to 1911.

Discussion

8.	Differentiate between repetitive DNA and satellite DNA.Repetitive DNA Repeated DNA sequence may or may not be present in text. Sequence of N2 Bases present in more th--an 1copy in a genome. Variability may or may not be present.Satellite DNARepeated sequence occur in tandem.Part of DNA having repeated short seque--nces of the N2 Bases.Variability occurs.
Answer» Repetitive DNA It includes both highly repetitive and middle repetitive DNA. The middle repetitive DNA present in ther RNA genes code for the ribosomal RNAs. Satellite DNA It represents the highly repetitive DNA. It does not code for any proteins or RNA.

8.

Differentiate between repetitive DNA and satellite DNA.Repetitive DNA Repeated DNA sequence may or may not be present in text. Sequence of N2 Bases present in more th--an 1copy in a genome. Variability may or may not be present.Satellite DNARepeated sequence occur in tandem.Part of DNA having repeated short seque--nces of the N2 Bases.Variability occurs.

Answer»

Repetitive DNA

It includes both highly repetitive and middle repetitive DNA.
The middle repetitive DNA present in ther RNA genes code for the ribosomal RNAs.

Satellite DNA

It represents the highly repetitive DNA.
It does not code for any proteins or RNA.

Discussion

9.	Write an article stressing on ‘Positive thinking as the very core of success’ in about 150-200 words.
Answer» Positive Thinking Positive thinking brings inner peace, success, improved relationships, better health, happiness and satisfaction. It also helps the daily affairs of life move more smoothly, and makes life look bright and promising. Positive thinking is contagious. People around you pick your mental moods and are affected accordingly. Think about happiness, good health and success and you will cause people to like you and desire to help you, because they enjoy the vibrations that a positive mind emits. In order to make positive thinking yield results, you need to develop a positive attitude towards life, expect a successful outcome of whatever you do, but also take some necessary actions to ensure your success. It is not enough to think positively for a few moments, and then letting fears and lack of belief enter your mind. Some effort and inner work is necessary. Think positive and expect only favourable results and situations, even if your current circumstances are not as you wish them to be. In time, your mental attitude will affect your life and circumstances and change them accordingly. सकारात्मक सोच आंतरिक शांति, सफलता, अच्छे संबंध, बेहतर स्वास्थ्य, प्रसन्नता तथा संतोष लाती है। यह जीवन के प्रतिदिन के मामलों को और अधिक सुचारू रूप से चलते रहने में मदद करती है तथा जीवन को प्रसन्न तथा आशाजनक बनाती है। सकारात्मक सोच एक व्यक्ति से दूसरे व्यक्ति में फैलने वाली चीज है। आपके पास के लोग आपकी मनोदशा को जानकर उसके अनुसार ही आपसे प्रभावित होते हैं। प्रसन्नता, अच्छे स्वास्थ्य तथा सफलता के बारे में सोचो तथा आप लोगों को अपने आपको पसंद करवा लेंगे तथा वे आपकी मदद करने की इच्छा करेंगे क्योंकि वे उस स्पंदन का आनंद लेंगे जो कि एक सकारात्मक मस्तिष्क से बाहर निकलता है। सकारात्मक सोच से परिणाम प्राप्त करने के लिए, जो कुछ भी आप करते हैं उस सकारात्मक सोच के सिवाय आपको जीवन के प्रति सकारात्मक दृष्टिकोण विकसित करना होगा, लेकिन अपनी सफलता को पक्का करने के लिए कोई आवश्यक कदम भी उठायें। केवल कुछ क्षणों के लिए सकारात्मक सोचना ही पर्याप्त नहीं, फिर डर तथा विश्वास की कमी आपके मस्तिष्क में प्रवेश करती। कुछ प्रयास व आंतरिक कार्य अति आवश्यक हैं। सकारात्मक तरीके से सोचो तथा केवल अनुकूल परिणाम तथा स्थिति की आशा करो, भले ही आपकी वर्तमान स्थिति ऐसी नहीं हो जैसी कि आप होने की कामना करते हो। समय पर, आपका मानसिक दृष्टिकोण आपके जीवन और परिस्थितियों को प्रभावित करेगा तथा उन्हें उनके अनुसार बदलेगा।

9.

Write an article stressing on ‘Positive thinking as the very core of success’ in about 150-200 words.

Answer»

Positive Thinking

Positive thinking brings inner peace, success, improved relationships, better health, happiness and satisfaction. It also helps the daily affairs of life move more smoothly, and makes life look bright and promising.

Positive thinking is contagious. People around you pick your mental moods and are affected accordingly. Think about happiness, good health and success and you will cause people to like you and desire to help you, because they enjoy the vibrations that a positive mind emits.

In order to make positive thinking yield results, you need to develop a positive attitude towards life, expect a successful outcome of whatever you do, but also take some necessary actions to ensure your success.

It is not enough to think positively for a few moments, and then letting fears and lack of belief enter your mind. Some effort and inner work is necessary.

Think positive and expect only favourable results and situations, even if your current circumstances are not as you wish them to be. In time, your mental attitude will affect your life and circumstances and change them accordingly.

सकारात्मक सोच आंतरिक शांति, सफलता, अच्छे संबंध, बेहतर स्वास्थ्य, प्रसन्नता तथा संतोष लाती है। यह जीवन के प्रतिदिन के मामलों को और अधिक सुचारू रूप से चलते रहने में मदद करती है तथा जीवन को प्रसन्न तथा आशाजनक बनाती है।

सकारात्मक सोच एक व्यक्ति से दूसरे व्यक्ति में फैलने वाली चीज है। आपके पास के लोग आपकी मनोदशा को जानकर उसके अनुसार ही आपसे प्रभावित होते हैं। प्रसन्नता, अच्छे स्वास्थ्य तथा सफलता के बारे में सोचो तथा आप लोगों को अपने आपको पसंद करवा लेंगे तथा वे आपकी मदद करने की इच्छा करेंगे क्योंकि वे उस स्पंदन का आनंद लेंगे जो कि एक सकारात्मक मस्तिष्क से बाहर निकलता है।

सकारात्मक सोच से परिणाम प्राप्त करने के लिए, जो कुछ भी आप करते हैं उस सकारात्मक सोच के सिवाय आपको जीवन के प्रति सकारात्मक दृष्टिकोण विकसित करना होगा, लेकिन अपनी सफलता को पक्का करने के लिए कोई आवश्यक कदम भी उठायें।

केवल कुछ क्षणों के लिए सकारात्मक सोचना ही पर्याप्त नहीं, फिर डर तथा विश्वास की कमी आपके मस्तिष्क में प्रवेश करती। कुछ प्रयास व आंतरिक कार्य अति आवश्यक हैं।

सकारात्मक तरीके से सोचो तथा केवल अनुकूल परिणाम तथा स्थिति की आशा करो, भले ही आपकी वर्तमान स्थिति ऐसी नहीं हो जैसी कि आप होने की कामना करते हो। समय पर, आपका मानसिक दृष्टिकोण आपके जीवन और परिस्थितियों को प्रभावित करेगा तथा उन्हें उनके अनुसार बदलेगा।

Discussion

10.	What is genetic engineering?
Answer» Genetic engineering is the use of genetic knowledge to artificially manipulate genes: It is one of the fields of biotechnology.

Discussion

11.	Bilaterally symmetrical and coelomate animals are exemplified by:(1) Annelida (2) Ctenophora (3) Platyhelminthes (4) Aschelminthes
Answer» (3) Platyhelminthes

Discussion

12.	Which of the following is the most abundant protein in the animals ? (1) Insulin (2) Haemoglobin (3) Collagen (4) Lectin
Answer» (3) Collagen

Discussion

13.	Embryo culture is used in- (a) Clonal propagation (b) Induction of somaclonal variation (c) Removal of obstacles of hybridization (d) Development of virus free plants
Answer» Embryo culture is used in Removal of obstacles of hybridization.

Discussion

14.	Ray florets have :(1) Half inferior ovary (2) Inferior ovary (3) Superior ovary(4) Hypogynouns ovary
Answer» (4) Hypogynouns ovary

Discussion

15.	Which of the following pairs is of unicellular algae? (1) Chlorella and Spirulina (2) Laminaria and Sargassum (3) Gelidium and Gracilaria (4) Anabaena and Volvox
Answer» (1) Chlorella and Spirulina

Discussion

16.	Variations found in tissue culture is- (a) Somaclonal variation (b) Clonal variations (c) Somatic variation (d) Tissue culture variations
Answer» Variations found in tissue culture is Somaclonal variation.

Discussion

17.	If the distance between two consecutive base pairs is 0.34 nm and the total number of base pairs of a DNA double helix in a typical mammalian cell is 6.6 × 109 bp, then the length of the DNA is approximately :(1) 2.7 meters (2) 2.0 meters (3) 2.5 meters (4) 2. 2 meters
Answer» (4) 2.2 meters

Discussion

18.	Find least positive integer such that (2i)n/(1-i)n-2 is a positive integer.
Answer» Find least positive integer such that \(\frac {(2i)^n}{(1-i)^{n-2}}\) is a positive integer For n = 1, \(\frac {(2i)^n}{(1-i)^{n-2}}\) = \(\frac {(2i)^1}{(1-i)^{1-2}}\)= (2i) (1-i) = 2i - 2i²= 2i + 2 which is a complex number For n = 2, \(\frac {(2i)^n}{(1-i)^{n-2}}\) = \(\frac {(2i)^2}{(1-i)^{2-2}}\)= \(\frac {2^2i^2}{1}\)= -4 which is a negative integer For n = 3, \(\frac {(2i)^n}{(1-i)^{n-2}}\) = \(\frac {(2i)^3}{(1-i)^{3-2}}\)= \(\frac {2^3i^3}{1-i}\)= \(\frac {8i}{1-i}\) = \(\frac {8i}{1-i}\) x \(\frac {1+c}{1+c}\) = \(\frac {-8i-8i^2}{1-i^2}\) = \(\frac {-8i-8}{1+1}\) = -4i + 4 which is a complex number For n = 4, \(\frac {(2i)^n}{(1-i)^{n-2}}\)= \(\frac {(2i)^4}{(1-i)^{4-2}}\)= \(\frac {2^4i^4}{(1-i)^2} = \frac {16}{1-2i + i^2}\) = \(\frac {16}{1-2i - 1} = \frac {-8}{i}\) = \(\frac {-8i}{i^2}\) = 8i which is a complex number For n = 5, \(\frac {(2i)^n}{(1-i)^{n-2}}\) = \(\frac {(2i)^5}{(1-i)^{3}}\)= \(\frac {2^5i^5}{1-i^3+3i^2=3i}\) = \(\frac {32\,i}{1+i-3-3\,i} = \frac {32\,i}{-2(1+i)} = \frac {32\,i(1-i)}{-2(1-i^2)}\) = \(\frac {16\,i + 16\,i^2}{2}\) = -8 i -8 which is a complex number For n = 6, \(\frac {(2i)^n}{(1-i)^{n-2}}\) = \(\frac {(2i)^6}{(1-i)^{4}}\)= \(\frac {2^6i^6}{1-4i+6i^2-4i^3+1}\) = \(\frac {64\,i^4i^2}{2-6-4i+4i} = \frac {-64}{-4}\) = 16 which is a positive integer Hence, required least positive integer is 6

18.

Find least positive integer such that (2i)n/(1-i)n-2 is a positive integer.

Answer»

Find least positive integer such that \(\frac {(2i)^n}{(1-i)^{n-2}}\) is a positive integer

For n = 1, \(\frac {(2i)^n}{(1-i)^{n-2}}\) = \(\frac {(2i)^1}{(1-i)^{1-2}}\)= (2i) (1-i)

= 2i - 2i²= 2i + 2 which is a complex number

For n = 2, \(\frac {(2i)^n}{(1-i)^{n-2}}\) = \(\frac {(2i)^2}{(1-i)^{2-2}}\)= \(\frac {2^2i^2}{1}\)= -4 which is a negative integer

For n = 3, \(\frac {(2i)^n}{(1-i)^{n-2}}\) = \(\frac {(2i)^3}{(1-i)^{3-2}}\)= \(\frac {2^3i^3}{1-i}\)= \(\frac {8i}{1-i}\)

= \(\frac {8i}{1-i}\) x \(\frac {1+c}{1+c}\) = \(\frac {-8i-8i^2}{1-i^2}\)

= \(\frac {-8i-8}{1+1}\) = -4i + 4 which is a complex number

For n = 4, \(\frac {(2i)^n}{(1-i)^{n-2}}\)= \(\frac {(2i)^4}{(1-i)^{4-2}}\)= \(\frac {2^4i^4}{(1-i)^2} = \frac {16}{1-2i + i^2}\)

= \(\frac {16}{1-2i - 1} = \frac {-8}{i}\)

= \(\frac {-8i}{i^2}\) = 8i which is a complex number

For n = 5, \(\frac {(2i)^n}{(1-i)^{n-2}}\) = \(\frac {(2i)^5}{(1-i)^{3}}\)= \(\frac {2^5i^5}{1-i^3+3i^2=3i}\)

= \(\frac {32\,i}{1+i-3-3\,i} = \frac {32\,i}{-2(1+i)} = \frac {32\,i(1-i)}{-2(1-i^2)}\)

= \(\frac {16\,i + 16\,i^2}{2}\) = -8 i -8 which is a complex number

For n = 6, \(\frac {(2i)^n}{(1-i)^{n-2}}\) = \(\frac {(2i)^6}{(1-i)^{4}}\)= \(\frac {2^6i^6}{1-4i+6i^2-4i^3+1}\)

= \(\frac {64\,i^4i^2}{2-6-4i+4i} = \frac {-64}{-4}\) = 16 which is a positive integer

Hence, required least positive integer is 6

Discussion

19.	Di-deoxynucleotide differs from deoxynucleotide in lacking an atom/group of atoms which is : A. hydrogen B. hydroxyl group C. carboxyl group D. phosphate group
Answer» Answer is A. hydrogen

Discussion

20.	Find the number of days from 21st February 1900 to 4th June 1900
Answer» \(\because\) \(\cfrac{1900}4\) = 475 \(\because\) 1900 is completely divisible by 4. \(\therefore\) 1900 is a leap year \(\therefore\) Number of days from 21 February of year 1900 is 29 = 9 days of February + 31 days of March + 30 days of April + 31 days of May + 4 days of June = 9 + 31 + 30 + 31 + 4 = 105 days

20.

Find the number of days from 21st February 1900 to 4th June 1900

Answer»

\(\because\) \(\cfrac{1900}4\) = 475

\(\because\) 1900 is completely divisible by 4.

\(\therefore\) 1900 is a leap year

\(\therefore\) Number of days from 21 February of year 1900 is 29

= 9 days of February + 31 days of March + 30 days of April + 31 days of May + 4 days of June

= 9 + 31 + 30 + 31 + 4 = 105 days

Discussion

21.	In the formation of r DNA molecule , the enzyme which is used to cleave the Gene of interest and vector is : A. DNA ligase B. EcoRI C. DNA polymerase D. Alkaline phosphatase
Answer» A. DNA ligase

Discussion

22.	In an autoradiogram, we read the DNA sequence as 3‟ GTAGCGATCA 5‟.Trace the sequence of original strand in the autoradiogram : A. 5‟ ACTAGCGATG 3‟ B. 5‟ CATCGCTAGT 3‟ C. 3‟ ACTAGCGATG 5‟ D. 3‟ CATCGCTAGT 5‟
Answer» B. 5’ CATCGCTAGT 3’

Discussion

23.	The short, single-stranded oligonucleotide DNA sequence which anneal to the 3‟ region of the denatured strands of DNA. A. Primers B. Template C. Taq polymerase D. dNTPs
Answer» Answer is A. Primers

Discussion

24.	40. Solve for \( x \), if \( x=\frac{1}{2+\frac{1}{2+\frac{1}{2+\cdots \infty}}} \)
Answer» \(x = {1\over 2+ \frac{1} {2+ \frac{1}{2 ....∞}}}\) \(→ x = {1\over 2+x}\) \(→x^2+2x=1 \) \(→x^2+2x-1=0\) → \(x = {-2 \pm \sqrt{2²-4(1)(-1)} \over 2(1)}\). →\(x = {-2 \pm \sqrt{8} \over 2}\) →\(x = {-2 \pm 2\sqrt{2} \over 2}\) \(→x = {-1 \pm \sqrt{2} }\)

24.

40. Solve for \( x \), if \( x=\frac{1}{2+\frac{1}{2+\frac{1}{2+\cdots \infty}}} \)

Answer»

\(x = {1\over 2+ \frac{1} {2+ \frac{1}{2 ....∞}}}\)

\(→ x = {1\over 2+x}\) \(→x^2+2x=1 \)

\(→x^2+2x-1=0\)

→ \(x = {-2 \pm \sqrt{2²-4(1)(-1)} \over 2(1)}\).

→\(x = {-2 \pm \sqrt{8} \over 2}\)

→\(x = {-2 \pm 2\sqrt{2} \over 2}\)

\(→x = {-1 \pm \sqrt{2} }\)

Discussion

25.	Listed below are four different single strands of DNA. Which of these would you expect to be cleaved by a restriction endonuclease? Give reason. (a) ACTCCAGAATTCACTCCG(b) ACTCCACTCCCGACTCCG(c) GCCTCATTCGAAGCCTGA(d) GAGCGGTTTATCTGAGCAG
Answer» (a) ACTCCAGAATTCACTCCG, (c) GCCTCATTCGAAGCCTGA Restriction enzymes recognize palindromic sequences.

25.

Listed below are four different single strands of DNA. Which of these would you expect to be cleaved by a restriction endonuclease? Give reason. (a) ACTCCAGAATTCACTCCG(b) ACTCCACTCCCGACTCCG(c) GCCTCATTCGAAGCCTGA(d) GAGCGGTTTATCTGAGCAG

Answer»

(a) ACTCCAGAATTCACTCCG, (c) GCCTCATTCGAAGCCTGA

Restriction enzymes recognize palindromic sequences.

Discussion

26.	20. Bleeding disease is due to the deficiency of :a. Painb. Rectalc. Vitamin \( E \).d. Vitamin K
Answer» The bleeding disease is due to the deficiency of Vitamin K. Vitamin K plays a major role in the process of blood clotting. It is involved in the posttranslational modification, and activation of the clotting factor II (prothrombin), VII, IX, and X in the liver. The deficiency of vitamin K results in the lack of active prothrombin. Due to this blood clotting is adversely affected, and the clotting time is increased.

26.

20. Bleeding disease is due to the deficiency of :a. Painb. Rectalc. Vitamin \( E \).d. Vitamin K

Answer»

The bleeding disease is due to the deficiency of Vitamin K.

Vitamin K plays a major role in the process of blood clotting. It is involved in the posttranslational modification, and activation of the clotting factor II (prothrombin), VII, IX, and X in the liver.

The deficiency of vitamin K results in the lack of active prothrombin. Due to this blood clotting is adversely affected, and the clotting time is increased.

Discussion

27.	The basic steps involved in RDT are illustrated schematically belowIn the given figure , DNA fragment is cleaved using enzyme “A” . Identify this enzyme. A. DNA ligase B. EcoRI C. DNA polymerase D. Alkaline phosphatase
Answer» A. DNA ligase

Discussion

28.	aerobic respiration of one glucose produce
Answer» 10NADH+2FADH₂ +2ATP+2GTP

Discussion

29.	Gene prediction and counting Gene prediction is an important problem for computational biology and there are various algorithms that do gene prediction using known genes as a training data set. The following table shows Genome size and gene predictions between several organisms.Organism No.of chromo somesGenome size in base pairsThe Number of predicted genesPart of the genome that encodes for proteinBacteria Escherichia coli1500,000500090%Yeast Saccharomyces cerevisiae1612,068,000634070%Worm Caenorhabditis elegans6100,000,00019,00027%Fly Drosophila melanogaster4175,000,000196,000,00013,60020%Weed Arabidopsis thaliana5157,000,00025,49820%Human Homo sapiens233,000,000,00020,000 - 25,000<5%Based on your observation and analysis, answer the following questions.1. Even if we know where the genes are in a given genome, it‟s difficult to count them due to A. splice Variants B. overlapping genes C. exons D. Both A and B2. Which organism has the maximum part of the genome coding for the proteins? A. Escherichia coli B. Saccharomyces cerevisiae C. Caenorhabditis elegans D. Drosophila melanogaster3. Part of the genome that encodes for protein in Homo sapiens is less than 5 % , one of the probable reason/s for this could be A. Repeated Sequence B. Exons C. Both “a” and “ b” D. SNP‟s 4. The relationship between number of chromosomes and genome size in base pairs is A. direct B. indirect C. no relationship D. correlation of 0.55. Computational Gene prediction is referred to as A. In –silico Gene prediction B. In –Vivo Gene prediction C. In - vitro Gene prediction D. Microarray prediction6. After observing the table, it seems that the relationship between the intuitive complexity of an organism and the number of genes in its genome is A. No simple correlation B. Simple correlation C. Inverse correlation D. Depending on the organism, can be simple or Inverse
Answer» 1. D. Both A and B 2. A. Escherichia coli 3. A. Repeated Sequence 4. C. no relationship 5. A. In –silico Gene prediction 6. A. No simple correlation

29.

Gene prediction and counting Gene prediction is an important problem for computational biology and there are various algorithms that do gene prediction using known genes as a training data set. The following table shows Genome size and gene predictions between several organisms.Organism No.of chromo somesGenome size in base pairsThe Number of predicted genesPart of the genome that encodes for proteinBacteria Escherichia coli1500,000500090%Yeast Saccharomyces cerevisiae1612,068,000634070%Worm Caenorhabditis elegans6100,000,00019,00027%Fly Drosophila melanogaster4175,000,000196,000,00013,60020%Weed Arabidopsis thaliana5157,000,00025,49820%Human Homo sapiens233,000,000,00020,000 - 25,000<5%Based on your observation and analysis, answer the following questions.1. Even if we know where the genes are in a given genome, it‟s difficult to count them due to A. splice Variants B. overlapping genes C. exons D. Both A and B2. Which organism has the maximum part of the genome coding for the proteins? A. Escherichia coli B. Saccharomyces cerevisiae C. Caenorhabditis elegans D. Drosophila melanogaster3. Part of the genome that encodes for protein in Homo sapiens is less than 5 % , one of the probable reason/s for this could be A. Repeated Sequence B. Exons C. Both “a” and “ b” D. SNP‟s 4. The relationship between number of chromosomes and genome size in base pairs is A. direct B. indirect C. no relationship D. correlation of 0.55. Computational Gene prediction is referred to as A. In –silico Gene prediction B. In –Vivo Gene prediction C. In - vitro Gene prediction D. Microarray prediction6. After observing the table, it seems that the relationship between the intuitive complexity of an organism and the number of genes in its genome is A. No simple correlation B. Simple correlation C. Inverse correlation D. Depending on the organism, can be simple or Inverse

Answer»

1. D. Both A and B

2. A. Escherichia coli

3. A. Repeated Sequence

4. C. no relationship

5. A. In –silico Gene prediction

6. A. No simple correlation

Discussion

30.	Consider that 10 is increased by 10% and then again increased by 25%. Let us find the final value.
Answer» 10% of 10 =\(10\times \frac{10}{100}\)= 1 10 is Increased by 10% = 10+1 = 11 25% of 11 =\(11\times\frac{25}{100}\)= \(\frac{11}{4}\) Now,11 is increased by 25% = \(11+\frac{11}{4}=\frac{55}{4}=13.75\) Final value = 13.75

30.

Consider that 10 is increased by 10% and then again increased by 25%. Let us find the final value.

Answer»

10% of 10 =\(10\times \frac{10}{100}\)= 1

10 is Increased by 10% = 10+1 = 11

25% of 11 =\(11\times\frac{25}{100}\)= \(\frac{11}{4}\)

Now,11 is increased by 25% =

\(11+\frac{11}{4}=\frac{55}{4}=13.75\)

Final value = 13.75

Discussion

31.	Heart diseases
Answer» Heart disease describes a range of conditions that affect your heart. Heart diseases include: Blood vessel disease, such as coronary artery disease Heart rhythm problems (arrhythmias) Heart defects you're born with (congenital heart defects) Heart valve disease Disease of the heart muscle Heart infection

31.

Heart diseases

Answer»

Heart disease describes a range of conditions that affect your heart. Heart diseases include:

Blood vessel disease, such as coronary artery disease
Heart rhythm problems (arrhythmias)
Heart defects you're born with (congenital heart defects)
Heart valve disease
Disease of the heart muscle
Heart infection

Discussion

32.	Find the term in x2 and the term independent of x in the expansion of (2x + 1/x)12.
Answer» \(\because\) General term in expansion of (x + a)ⁿ is T_r+1 = ⁿC_r x^n-ra^r \(\therefore\) General term in expansion of (2x + 1/x)¹² is T_r+1 = ¹²C_r (2x)^n-r(1/x)^r = ¹²C_r 2^n-r x^n-r-r = ¹²C_r 2^n-r x^n-2r = ¹²C_r 2^12-r x^12-2r---(1) (\(\because\) n = 12) For term in x², we have 12 - 2r = 2 ⇒ 2r = 12 - 2 = 10 ⇒ r = 10/2 = 5 \(\therefore\) Term in x² in the expansion of (2x + 1/x)¹² is T₆ = ¹²C₅2^12-5 x² (from (1)) = ¹²C₅2⁷ x² For constant term (term independent of x), we have 12 - 2r = 0 ⇒ 2r = 12 ⇒ r = 12/2 = 6 \(\therefore\) constant term (term independent of x) in the expansion of (2x + 1/x)¹² T₇ = ¹²C₆2^12-6x⁰ (From (1)) = ¹²C₆.2⁶

32.

Find the term in x2 and the term independent of x in the expansion of (2x + 1/x)12.

Answer»

\(\because\) General term in expansion of (x + a)ⁿ is

T_r+1 = ⁿC_r x^n-ra^r

\(\therefore\) General term in expansion of (2x + 1/x)¹² is

T_r+1 = ¹²C_r (2x)^n-r(1/x)^r

= ¹²C_r 2^n-r x^n-r-r

= ¹²C_r 2^n-r x^n-2r

= ¹²C_r 2^12-r x^12-2r---(1) (\(\because\) n = 12)

For term in x², we have

12 - 2r = 2

⇒ 2r = 12 - 2 = 10

⇒ r = 10/2 = 5

\(\therefore\) Term in x² in the expansion of (2x + 1/x)¹² is

T₆ = ¹²C₅2^12-5 x² (from (1))

= ¹²C₅2⁷ x²

For constant term (term independent of x), we have

12 - 2r = 0

⇒ 2r = 12

⇒ r = 12/2 = 6

\(\therefore\) constant term (term independent of x) in the expansion of

(2x + 1/x)¹² T₇ = ¹²C₆2^12-6x⁰ (From (1))

= ¹²C₆.2⁶

Discussion

33.	Define Pollination. Give its two types. Explain different agents in cross pollination:
Answer» pollination is the process of transfer of pollens from another to stigma. there are 2 types of pollination 1. self pollination- when pollens are transferred from anther of a flower to the stigma of the same flower or different flower of the same plant. eg hibiscus. 2. cross pollination - when pollens are transferred from anther of one flower to the stigma of the other flower of the same species. for example papaya. the different age ts of pollination are air , water, insects etc

Discussion

34.	Determine whether * is a binary operation Which is defined by a * b = a + b, a, b ∈ N.
Answer» a * b = a + b, a, b ∈ N Let a & b are arbitrary natural number. Then a + b ∈ N (\(\because\) Sum of natural numbers is natural number) ⇒ a * b ∈ N \(\forall\) a, b ∈ N \(\therefore\) * is a binary operation.

34.

Determine whether * is a binary operation Which is defined by a * b = a + b, a, b ∈ N.

Answer»

a * b = a + b, a, b ∈ N

Let a & b are arbitrary natural number.

Then a + b ∈ N (\(\because\) Sum of natural numbers is natural number)

⇒ a * b ∈ N \(\forall\) a, b ∈ N

\(\therefore\) * is a binary operation.

Discussion

35.	What should be subtracted from 7x/x2+x-12 to obtain (3/x-3) ?
Answer» Let number be n. =>(7/x+x-12)-n=(3/x-3) =>(7/x+x-12)-(3/x-3)=n =>7/x+x-12-3/x+3=n =>4/x+x-9=n =>n=4/x+x-9

35.

What should be subtracted from 7x/x2+x-12 to obtain (3/x-3) ?

Answer»

Let number be n.

=>(7/x+x-12)-n=(3/x-3)

=>(7/x+x-12)-(3/x-3)=n

=>7/x+x-12-3/x+3=n

=>4/x+x-9=n

=>n=4/x+x-9

Discussion

36.	If \( 8 m=40 \), the the value of \( m= \)
Answer» m=5 as 8m=40 m=40/8 m=5 8m = 40 m = 40/8 m= 5 5 is the answer

Discussion

37.	There are two trails up the mountain, ____. A) both of which are difficult B) either of them is difficult C) that are difficult trails D) they are difficult
Answer» Correct option is A) both of which are difficult

Discussion

38.	I ate two sandwiches, ____ were delicious. A) one of them B) both of which C) either of which D) none of whom
Answer» Correct option is B) both of which

Discussion

39.	Name any three major oilseed crops of India.
Answer» Major oilseed crops of India: Mustard, Rapeseed, Sunflower, Soybean

39.

Name any three major oilseed crops of India.

Answer»

Major oilseed crops of India:

Mustard, Rapeseed, Sunflower, Soybean

Discussion

40.	Name any two phosphorus containing fertilizers.
Answer» Phosphorus containing fertilizers: Single super phosphate, Double super phosphate, triple super phosphate, Diammonium Phosphate (DAP), Mono ammonium Phosphate (MAP).

40.

Name any two phosphorus containing fertilizers.

Answer»

Phosphorus containing fertilizers:

Single super phosphate, Double super phosphate, triple super phosphate, Diammonium Phosphate (DAP), Mono ammonium Phosphate (MAP).

Discussion

41.	ii) जर \( \left\|\begin{array}{ll}4 & 5 \\ m & 3\end{array}\right\|=22 \) तर \( m \) ची किंमत काढा.
Answer» Answer : m = -2 Explanation : \| 4 5 \| = 22 \| m 3 \| => (4×3) - (m×5) = 22 => 12 - m×5 = 22 => m = - { (22 - 12)/5 } => m = -2 Answer is correct \(\begin{vmatrix}4&5\\m&3\end{vmatrix}=22\) ⇒ (4 x 3) - (m x 5) = 22

41.

ii) जर \( \left|\begin{array}{ll}4 & 5 \\ m & 3\end{array}\right|=22 \) तर \( m \) ची किंमत काढा.

Answer»

Answer : m = -2

Explanation : | 4 5 | = 22

| m 3 |

=> (4×3) - (m×5) = 22

=> 12 - m×5 = 22

=> m = - { (22 - 12)/5 }

=> m = -2

Answer is correct

\(\begin{vmatrix}4&5\\m&3\end{vmatrix}=22\)

⇒ (4 x 3) - (m x 5) = 22

Discussion

42.	Enumerate four importance of filling in preparation of sandwiches.
Answer» Four importance of filling in preparation of sandwiches are to provide. 1.Flavour 2.Body 3.Moisture 4.Nutrients

42.

Enumerate four importance of filling in preparation of sandwiches.

Answer»

Four importance of filling in preparation of sandwiches are to provide.

1.Flavour

2.Body

3.Moisture

4.Nutrients

Discussion

43.	Read the below questions carefully and answer the given questions:The economy, the relief and social development is deeply influenced the economic progress. In the social development, the area can be applied to the development of economic progress there. Indian agriculture, almost completely dependent on. agriculture (aggregated). In which development of the monsoon has given significant contributions to providing a major and strong basis. Monsoon is called a pivotal point of the country. Apart from agriculture, the entire production is dependent oh agricultural production, If monsoon rainfall is in appropirate amount, the agricultural production increases. But because of the failure of monsoon, the crops dried. The country goes dry and the grains are reduced in the stores.(a) Discuss the important features of the monsoon.(b) Why the Indian Economy (budget) is called gambling of monsoon winds?
Answer» (a) In India rainfall is mainly in July to September. This is the period of southwest monsoons blowing from sea to land. There are three important features of the monsoon rainfall. Erratic: Rainfall is not reliable in India. It is not necessary that rain continues to be same. Due to this erratic situation of rain, the situation of starvation and famine is arranged. This erratic situation of rainfall is more in the inner parts of the country and in Rajasthan. Uneven Distribution: There is uneven distribution of rainfall in India. Western slopes of western ghats and Meghalaya or in the hills of Assam. There is more than 250 cm. rainfall. In contrast Rajasthan, West Gujarat, North Kashmir etc., the rainfall is less than 25 cm. Uncertainty: The amount of rainfall in India is not certain. Sometimes monsoon winds reached before time, It rains a lot. But sometimes the rainfall is low or sometimes ends up before a time. As a result the situation of drying is generated in the country. (b) Indian monsoon is a gambling of monsoon winds. This sentence reveals that the advancement of India’s economy depends on that how much appropriate time of any year, distribution and quantity. If the rain comes on time and its quantity is also suitable, a good crop of agriculture can be expected. For example- crops are good due to good monsoon, so three things happen. Fair raw materials available for factories. The industry-related factors of cotton, jute, oil seeds etc. are flourishing. When the agriculture and industries are strengthened from good monsoon, the productivity increases. On one hand, the export is promoted. On the other hand international trade is flourishing. Wealth grows in the country and people’s standard of living improves. Due to good monsoon, there is an increase in water in the rivers, the water level of the dams rises high. Where this water helps in the production of hydropower, the irrigation system improves. This creates a stir in economic activities in the country. There is no doubt that today due to the advancement of science, we can grow a good crop even in the absence of monsoon, but we have to think about whether all farmers can benefit from lack of rainfall or unequal distribution of rainfall. A good monsoon affects every section and every region of the country. If the monsoon is suitable, the country’s economic development is assured. Therefore, it is fair to call the Indian economy a gamble of monsoon winds.

43.

Read the below questions carefully and answer the given questions:The economy, the relief and social development is deeply influenced the economic progress. In the social development, the area can be applied to the development of economic progress there. Indian agriculture, almost completely dependent on. agriculture (aggregated). In which development of the monsoon has given significant contributions to providing a major and strong basis. Monsoon is called a pivotal point of the country. Apart from agriculture, the entire production is dependent oh agricultural production, If monsoon rainfall is in appropirate amount, the agricultural production increases. But because of the failure of monsoon, the crops dried. The country goes dry and the grains are reduced in the stores.(a) Discuss the important features of the monsoon.(b) Why the Indian Economy (budget) is called gambling of monsoon winds?

Answer»

(a) In India rainfall is mainly in July to September. This is the period of southwest monsoons blowing from sea to land. There are three important features of the monsoon rainfall.

Erratic: Rainfall is not reliable in India. It is not necessary that rain continues to be same. Due to this erratic situation of rain, the situation of starvation and famine is arranged. This erratic situation of rainfall is more in the inner parts of the country and in Rajasthan.
Uneven Distribution: There is uneven distribution of rainfall in India. Western slopes of western ghats and Meghalaya or in the hills of Assam. There is more than 250 cm. rainfall. In contrast Rajasthan, West Gujarat, North Kashmir etc., the rainfall is less than 25 cm.
Uncertainty: The amount of rainfall in India is not certain. Sometimes monsoon winds reached before time, It rains a lot. But sometimes the rainfall is low or sometimes ends up before a time. As a result the situation of drying is generated in the country.

(b) Indian monsoon is a gambling of monsoon winds. This sentence reveals that the advancement of India’s economy depends on that how much appropriate time of any year, distribution and quantity. If the rain comes on time and its quantity is also suitable, a good crop of agriculture can be expected.

For example- crops are good due to good monsoon, so three things happen.

Fair raw materials available for factories. The industry-related factors of cotton, jute, oil seeds etc. are flourishing.
When the agriculture and industries are strengthened from good monsoon, the productivity increases. On one hand, the export is promoted. On the other hand international trade is flourishing. Wealth grows in the country and people’s standard of living improves.
Due to good monsoon, there is an increase in water in the rivers, the water level of the dams rises high. Where this water helps in the production of hydropower, the irrigation system improves. This creates a stir in economic activities in the country. There is no doubt that today due to the advancement of science, we can grow a good crop even in the absence of monsoon, but we have to think about whether all farmers can benefit from lack of rainfall or unequal distribution of rainfall. A good monsoon affects every section and every region of the country. If the monsoon is suitable, the country’s economic development is assured. Therefore, it is fair to call the Indian economy a gamble of monsoon winds.

Discussion

44.	121. Bank does not provide loans fora) Crop loansb) Education loansc) Home loansd) Drinking \& Gambling
Answer» Ans. d) Drinking & Gambling

Discussion

45.	What is the next number after 9, 39 ,144
Answer» Next number is 2475. Explanation: 9, 39, 144, .... 9 x 4 + 3¹ = 39 39 x 3 + 3⁴ = 144 by seeing the pattern multiple 4 came to 3 and power of 3 increased by 3 units Following the same pattern 144 x 2 + 3⁷ = 2475

45.

What is the next number after 9, 39 ,144

Answer»

Next number is 2475.

Explanation:
9, 39, 144, ....
9 x 4 + 3¹ = 39
39 x 3 + 3⁴ = 144
by seeing the pattern multiple 4 came to 3 and power of 3 increased by 3 units
Following the same pattern
144 x 2 + 3⁷ = 2475

Discussion

46.	An alternating current is given by \( i=14.14 \sin 377 t \) find 1. RMS value of current. 2. Frequency. 3 . Instantaneous value of current when \( t-3 mS \). 4. Time taken by current to reach 10 Amp for third time after passing through zero and increasing positively.
Answer» Given i = 14.14 sin 377t (i) RMS value of current i_rms = \(\frac{I_m}{\sqrt2}\) i_rms = \(\frac{14.14}{\sqrt2}\) i_rms = 10 ampere (ii) Frequency \(\omega\) = 377 2πf = 377 f = 377/2π f = 377/6.28 f = 60.03 Hz (iii) Instantaneous current I = 14.14 sin 377 t I = 14.14 sin (377x 3 x 10^-3) I = 14.14 x sin (1.131) I = 12.78 amp

46.

An alternating current is given by \( i=14.14 \sin 377 t \) find 1. RMS value of current. 2. Frequency. 3 . Instantaneous value of current when \( t-3 mS \). 4. Time taken by current to reach 10 Amp for third time after passing through zero and increasing positively.

Answer»

Given i = 14.14 sin 377t

(i) RMS value of current

i_rms = \(\frac{I_m}{\sqrt2}\)

i_rms = \(\frac{14.14}{\sqrt2}\)

i_rms = 10 ampere

(ii) Frequency

\(\omega\) = 377

2πf = 377

f = 377/2π

f = 377/6.28

f = 60.03 Hz

(iii) Instantaneous current

I = 14.14 sin 377 t

I = 14.14 sin (377x 3 x 10^-3)

I = 14.14 x sin (1.131)

I = 12.78 amp

Discussion

47.	The number of critical points of the function f(x)= 2sinx \|cosx\| in [0,6π] is
Answer» f(x) = 2 sin x \| cos x \|, x ∈ [0, 6π] f(x) = \(\begin{cases}2\,sin\,x\,cos\,x,&x\,\in[0,\frac{\pi}{2}]\cup[\frac{3\pi}{2},\frac{5\pi}{2}]\cup[\frac{7\pi}{2},\frac{9\pi}{2}]\cup[\frac{11\pi}{2},6\pi]\\-2\,sin\,x\,cos\,x,&x\,\in[\frac{\pi}{2},\frac{3\pi}{2}]\cup[\frac{5\pi}{2},\frac{7\pi}{2}]\cup[\frac{9\pi}{2},\frac{11\pi}{2}]\end{cases}\) ⇒ f(x) = \(\begin{cases}sin\,2x,&x\,\in[0,\frac{\pi}{2}]\cup[\frac{3\pi}{2},\frac{5\pi}{2}]\cup[\frac{7\pi}{2},\frac{9\pi}{2}]\cup[\frac{11\pi}{2},6\pi]\\-sin\,2x,&x\,\in[\frac{\pi}{2},\frac{3\pi}{2}]\cup[\frac{5\pi}{2},\frac{7\pi}{2}]\cup[\frac{9\pi}{2},\frac{11\pi}{2}]\end{cases}\) By differentiating f(x) w.r.t. x, we obtain, f'(x) = \(\begin{cases}2\,cos\,2x,&x\,\in[0,\frac{\pi}{2}]\cup[\frac{3\pi}{2},\frac{5\pi}{2}]\cup[\frac{7\pi}{2},\frac{9\pi}{2}]\cup[\frac{11\pi}{2},6\pi]\\-2\,cos\,2x,&x\,\in[\frac{\pi}{2},\frac{3\pi}{2}]\cup[\frac{5\pi}{2},\frac{7\pi}{2}]\cup[\frac{9\pi}{2},\frac{11\pi}{2}]\end{cases}\) For critical points, we have to find these x which gives f'(x) = 0 Now, f'(x) = 0 gives cos 2x = 0 = cos(2n+1)π/2 ⇒ 2x = (2n+1)π/2 ⇒ x = (2n+1)π/4, n ∈ 0, 1, 2, .... , 12. Hence, number of critical points are 13. Alternative :→ f(x) = 2 sin x \| cos x \| ⇒ f(x) = \| sin 2x \| Then f'(x) = \| 2 cos 2x \| Thus, f'(x) = 0 gives \| cos 2x \| = 0 ⇒ cos 2x = 0 (∵ \|x\| = 0 ⇒ x = 0) ⇒ cos 2x = 0 = cos(2n+1)π/2 ⇒ 2x = (2n+1)π/2 ⇒ x = (2n+1)π/4 Since, x ∈ [0, 6π] ∴ x = (2n+1)π/4, n = 0, 1, 2, .... , 12 are critical points of function f(x). Hence, number of critical points = 13.

47.

The number of critical points of the function f(x)= 2sinx |cosx| in [0,6π] is

Answer»

f(x) = 2 sin x | cos x |, x ∈ [0, 6π]

f(x) = \(\begin{cases}2\,sin\,x\,cos\,x,&x\,\in[0,\frac{\pi}{2}]\cup[\frac{3\pi}{2},\frac{5\pi}{2}]\cup[\frac{7\pi}{2},\frac{9\pi}{2}]\cup[\frac{11\pi}{2},6\pi]\\-2\,sin\,x\,cos\,x,&x\,\in[\frac{\pi}{2},\frac{3\pi}{2}]\cup[\frac{5\pi}{2},\frac{7\pi}{2}]\cup[\frac{9\pi}{2},\frac{11\pi}{2}]\end{cases}\)

⇒ f(x) = \(\begin{cases}sin\,2x,&x\,\in[0,\frac{\pi}{2}]\cup[\frac{3\pi}{2},\frac{5\pi}{2}]\cup[\frac{7\pi}{2},\frac{9\pi}{2}]\cup[\frac{11\pi}{2},6\pi]\\-sin\,2x,&x\,\in[\frac{\pi}{2},\frac{3\pi}{2}]\cup[\frac{5\pi}{2},\frac{7\pi}{2}]\cup[\frac{9\pi}{2},\frac{11\pi}{2}]\end{cases}\)

By differentiating f(x) w.r.t. x, we obtain,

f'(x) = \(\begin{cases}2\,cos\,2x,&x\,\in[0,\frac{\pi}{2}]\cup[\frac{3\pi}{2},\frac{5\pi}{2}]\cup[\frac{7\pi}{2},\frac{9\pi}{2}]\cup[\frac{11\pi}{2},6\pi]\\-2\,cos\,2x,&x\,\in[\frac{\pi}{2},\frac{3\pi}{2}]\cup[\frac{5\pi}{2},\frac{7\pi}{2}]\cup[\frac{9\pi}{2},\frac{11\pi}{2}]\end{cases}\)

For critical points, we have to find these x which gives f'(x) = 0

Now, f'(x) = 0 gives cos 2x = 0 = cos(2n+1)π/2

⇒ 2x = (2n+1)π/2

⇒ x = (2n+1)π/4, n ∈ 0, 1, 2, .... , 12.

Hence, number of critical points are 13.

Alternative :→ f(x) = 2 sin x | cos x |

⇒ f(x) = | sin 2x |

Then f'(x) = | 2 cos 2x |

Thus, f'(x) = 0 gives | cos 2x | = 0

⇒ cos 2x = 0 (∵ |x| = 0 ⇒ x = 0)

⇒ cos 2x = 0 = cos(2n+1)π/2

⇒ 2x = (2n+1)π/2

⇒ x = (2n+1)π/4

Since, x ∈ [0, 6π]

∴ x = (2n+1)π/4, n = 0, 1, 2, .... , 12 are critical points of function f(x).

Hence, number of critical points = 13.

Discussion

48.	A converging lens forms a three times magnified image of an object, which can be take on a screen. If the focal length of the lens is 30 cm, then the distance of the object from the lens is (a) - 55 cm (b) - 50 cm (c) - 45 cm (d) - 40 cm
Answer» Correct option is (d) - 40 cm

Discussion

49.	Explain the process of transportation of substances in phloem.
Answer» Trans-location, i.e., transportation of food, in plants takes place through phloem. Sieve tubes with the help of adjacent companion cells in the phloem move the soluble food in the form of sucrose, amino acids etc in both upward and downward directions. Live cells of phloem actively take up material like sucrose using energy from ATP. This increases the osmotic pressure of the tissue causing water to move into it. This pressure moves the material in the phloem to tissues which have less pressure. According to the needs of the plants food from leaves to storage organs of roots, fruits and seeds and the growing regions or from stored parts such as roots or stem to the buds (in Spring) which needs energy to grow is transported.

49.

Explain the process of transportation of substances in phloem.

Answer»

Trans-location, i.e., transportation of food, in plants takes place through phloem. Sieve tubes with the help of adjacent companion cells in the phloem move the soluble food in the form of sucrose, amino acids etc in both upward and downward directions. Live cells of phloem actively take up material like sucrose using energy from ATP. This increases the osmotic pressure of the tissue causing water to move into it.

This pressure moves the material in the phloem to tissues which have less pressure. According to the needs of the plants food from leaves to storage organs of roots, fruits and seeds and the growing regions or from stored parts such as roots or stem to the buds (in Spring) which needs energy to grow is transported.

Discussion

50.	Identify the two components of Phloem tissue that help in transportation of food in plants (a) Phloem parenchyma & sieve tubes (b) Sieve tubes & companion cell. (c) Phloem parenchyma & companion cell. (d) Phloem fibres and sieve tubes
Answer» Correct option is (b) Sieve tubes & companion cell.

Discussion

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aerobic respiration of one glucose produce

Consider that 10 is increased by 10% and then again increased by 25%. Let us find the final value.

Heart diseases

Find the term in x2 and the term independent of x in the expansion of (2x + 1/x)12.

Define Pollination. Give its two types. Explain different agents in cross pollination:

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What should be subtracted from 7x/x2+x-12 to obtain (3/x-3) ?​

If \( 8 m=40 \), the the value of \( m= \)

There are two trails up the mountain, ____. A) both of which are difficult B) either of them is difficult C) that are difficult trails D) they are difficult

I ate two sandwiches, ____ were delicious. A) one of them B) both of which C) either of which D) none of whom

Name any three major oilseed crops of India.

Name any two phosphorus containing fertilizers.

ii) जर \( \left|\begin{array}{ll}4 & 5 \\ m & 3\end{array}\right|=22 \) तर \( m \) ची किंमत काढा.

Enumerate four importance of filling in preparation of sandwiches.

121. Bank does not provide loans fora) Crop loansb) Education loansc) Home loansd) Drinking \& Gambling

What is the next number after 9, 39 ,144

An alternating current is given by \( i=14.14 \sin 377 t \) find 1. RMS value of current. 2. Frequency. 3 . Instantaneous value of current when \( t-3 mS \). 4. Time taken by current to reach 10 Amp for third time after passing through zero and increasing positively.

The number of critical points of the function f(x)= 2sinx |cosx| in [0,6π] is

A converging lens forms a three times magnified image of an object, which can be take on a screen. If the focal length of the lens is 30 cm, then the distance of the object from the lens is (a) - 55 cm (b) - 50 cm (c) - 45 cm (d) - 40 cm

Explain the process of transportation of substances in phloem.

Identify the two components of Phloem tissue that help in transportation of food in plants (a) Phloem parenchyma &amp; sieve tubes (b) Sieve tubes &amp; companion cell. (c) Phloem parenchyma &amp; companion cell. (d) Phloem fibres and sieve tubes

The origins of Business Policy & Strategic Management can be retraced to a. 1930 b. 1911 c. 1879 d. 1938

What should be subtracted from 7x/x2+x-12 to obtain (3/x-3) ?

Identify the two components of Phloem tissue that help in transportation of food in plants (a) Phloem parenchyma & sieve tubes (b) Sieve tubes & companion cell. (c) Phloem parenchyma & companion cell. (d) Phloem fibres and sieve tubes