Explore topic-wise InterviewSolutions in Current Affairs.

c. V_n = √(4RKTB) 

b. V_n is directly proportional to√bandwidth 

b. 2607.1Ω 

R₁ = R_in1 + Req1 = 700 + 1800 = 2500Ω

R₂ = (R_o1 R_in2)/ (R_o1 + R_in2) + R_eq2 = 30 * 80/(30 + 80) + 12 = 40.92KΩ

R₃ = R_o2 = 1.2MΩ

Equivalent input noise resistance of a two stage amplifier is given by

R_eq = R₁ + R₂/ A²₁ + R₃/ (A²₁ A²₂)

= 2500 + 40.92 * 10³/(20)² + 1.2 * 10⁶/(20)²(25)²

= 2607.1Ω

d. F_N = F₁ + (F₂ – 1)/ G₁ + (F₃ – 1)/ G₁G₂+…+(F_N – 1)/G₁G₂G₃G_N

It is defined as the time rate of change of charge passing through a predetermined area with respect to time. It is caused by drift of free electrons through a conductor to a particular direction. The measuring unit of electric change is Coulomb and the unit of time is second, the measuring unit of electric current is Coulombs per second and this logical unit of current has a specific name Ampere after the famous French scientist André-Marie Ampere. Here the area is the cross-sectional area of the metal wire. If Δq units of charge flowing through the cross sectional area A in Δt units of time, then the resulting current i is given by,

\(i = \frac{\Delta q}{\Delta t}\) C/S

1 Ampere (A) = \(\frac{1\,\text{coulomb}}{\text{second}}=\frac{Q}{t}\)

The magnitude of electric current is measured in coulombs per second. The SI unit of electric current is Ampere and is denoted by the letter A. Ampere is defined as one coulomb of charge moving past a point in one second. If there are 6.241 x 10¹⁸ electrons flowing through our frame in one second then the electrical current flowing through it is ‘One Ampere.’

Given:

Cost price of Earpiece for suman = Rs. 100

Profit % of Suman = 10%

Profit % of Rachna = 20%

Loss % of Deepti = 36.36%

Formula Used:

\({\rm{Selling\;Price}} = \;\frac{{\left( {100{\rm{\;}} + {\rm{\;Profit\;\% }}} \right)}}{{100}}{\rm{\;}} \times {\rm{Cost\;Price\;}}\)

Calculation:

By Ratio Method,

\({\rm{Profit\;\% \;}} = {\rm{\;}}\frac{{{\rm{profit}}}}{{{\rm{Cost\;Price}}}}\)

10% = 1/10 (If C.P. is 10 units and profit is 1 unit then S.P. will be 11 Units)

20% = 1/5

36.36 = 4/11

Now,

\({\rm{Suman}} \times {\rm{\;}}\frac{{{\rm{S}}.{\rm{P}}.1}}{{{\rm{C}}.{\rm{P}}.1}}{\rm{\;}} \times \frac{{{\rm{S}}.{\rm{P}}.2}}{{{\rm{C}}.{\rm{P}}.2}}{\rm{\;}} \times {\rm{\;}}\frac{{{\rm{S}}.{\rm{P}}.3}}{{{\rm{C}}.{\rm{P}}.3}} = {\rm{New\;C}}.{\rm{P}}.{\rm{\;of\;Suman}}\)

 The Original C.P. of Suman is ‘Rs. 100’

New C.P. of Suman

⇒ \(100 \times {\rm{\;}}\frac{{11 \times 6 \times 7}}{{10 \times 5 \times 11}} = {\rm{Rs\;}}84\)

 Profit of Suman = (Original C.P. – New C.P.)

⇒ (100 - 84) = Rs.16

Profit of Suman in First Transaction 

⇒ \(\frac{{10}}{{100}}\; \times 100 = 10\)

Total Profit of Suman

⇒ (Rs. 16 + Rs. 10) = Rs. 26

∴ Total Profit earned by Suman is Rs. 26.

Correct option is C. To verify the law of conservation of mass. 

Correct option is C. (iii) Alveoli: Thin-walled sac like structures for exchange of gases.

Correct answer is B. (i)-amylase, (ii)-pepsin, (iii)-trypsin

Trypsin is secreted by pancreas which helps in digesting proteins. Salivary amylase is present in saliva which help in digesting starch in food. Pepsin secreted by gastric glands which helps in protein digestion.

Correct option is B. (i) - amylase, (ii) - pepsin, (iii) - trypsin

Correct option is D. water content in the guard cells

Correct option is B. Blood is transferred to lungs for oxygenation and is pumped into various organs simultaneously.