100525 + Interview Questions in GENERAL QA IN GENERAL AWARENESS

1.	Expand D.S.S.
Answer» Dalita Sangharsha Samithi.

Discussion

2.	What are counter movements? Give example.
Answer» Social movements try to bring about a social change, while counter-movements arise in defence of it. For example, when Raja Ram Mohan Roy tried to campaign against Sati and formed Brahmo Samaj, the defenders of Sati formed Dharma Sabha and petitioned the British to not legislate Sati, thus exercising counter movement.

Discussion

3.	What is sanskritization? Discuss its factors.
Answer» M. N. Srinivas initially defines it as the tendency among the low castes to move higher in the caste hierarchy within a generation or two by adoping vegetarianism and toetotalism and by sanskritizing its rituals. M. N. Srinivas redefines sanskritization as a process by which a low caste Hindu or a tribal changes his customs, rituals, ideology and way of life in the direction of the upper, frequently twice-born caste. Major factors of Sanskritization:- 1. Rituals: Inspite of the Theoretical existence of certain restrictions, the low castes or other groups did manage to imitate the customs and rites of “Twice-born” (DWIJAS) castes. This is the best way of claiming higher position in the caste hierarchy. 2. Marriages: According to a strict rule of Brahminism, a Brahmin should give away his daughter in marriage before she attains puberty, failing which he would be committing a great sin. Marriages among the brahmins were indissoluble. Pre-puberty marriages were commonly practiced. On the other hand, among the low Hindu castes, post-puberty marriages were very common and the dissolution of a marriage was possible. Now in order to rise up in the caste hierarchy, the low Hindu castes started practicing pre-puberty marriages and marriages also became indissoluble. 3. Treatment of Widows: A Brahmin widow for instance, was not allowed to re-many, and received miserable treatment. She was required to shave her head and not allowed wearing any ornaments. She was regarded inauspicious, and not allowed to attend any important functions. On the other hand, among the low castes marriage was dissoluble and widow re-marriages were practiced. Widows were not required to shave their heads. In the imitation process, these groups, also banned widow-remarriages and started treating a widow in the same way as that of the ‘High’ Hindu castes. 4. Treatment of Women: Comparatively, women among the high Hindu castes receive bad treatment and hold only a secondary position. Virginity in brides and chastity in wives was preferred. A brahmin wife was expected to treat her husband as god. Women would perform a number of ‘vratas’ or religious vows for the long life of their husbands. At certain times, such as menstruation, child birth, then were treated as untouchables and their presence was considered as inauspicious. Hence they were not allowed to attend important functions. Women among the lower castes generally received good treatment and occupied a good position. In order to imitate the higher castes, they started treating women in a bad manner and gave them a secondary position. 5. Kinship: According to M.N. Srinivas, “In the sphere of kinship, sanskritization stresses the importance in the patrilineal lineage, sanskritization results in increasing the importance of sons. The members of high castes prefer sons to daughters, whereas among the lower castes both boys and girls are preferred. For instance among Non-Brahmins though a son is preferred, a daughter is also demanded. Their treatment is also not that harsh but that is changing now towords preference for sons. 6. Ideology: Sanskritization also resulted in the use of New Ideas and values, which have been frequently expressed in Sanskrit literature. The ideas and values such as Karma, Dharma, Papa, Punya, Maya, Samskara, Moksha, etc. The Twice-born castes used these ideas in their conversation. Through the process of Sanskritization, lower caste groups were exposed to these ideas and values which now frequent their conversations. 7. Food habits: Brahmins in India are by and large strict vegetarians except Kashmiri, Saraswath and Bengali brahmins. The lower castes are non-vegetarian. Sanskritization resulted in the change of food habits in the direction of the, higher, frequently twice-born castes. Some of the lowers castes became strict vegetarians and practiced teetctalism also, in order to move up in the cast hierarchy. 8. Dress habits: As Dwijas, Brahmins were entitled to wear the sacred thread ‘ Janivar ‘ after the Vedic rite of upanayana, while shudras were not entitled for that. Some of the lowers castes started wearing the sacred thread and also started imitating the P dress style of the brahmins such as wearing dhothi, shalya turban, Kachche panch, etc. 9. Nomenclature: The traditional and typical names of the lower castes (in Karnataka) were Kariya, Kempa, Kempi, Kala, Mala Honni, Timmi, etc. They started giving their new born named common among the Brahmins such as Rama, Krishna Shankara, Madhava Gowri, Parvathi, Lakshmi, Shobha Radha, etc.

3.

What is sanskritization? Discuss its factors.

Answer»

M. N. Srinivas initially defines it as the tendency among the low castes to move higher in the caste hierarchy within a generation or two by adoping vegetarianism and toetotalism and by sanskritizing its rituals. M. N. Srinivas redefines sanskritization as a process by which a low caste Hindu or a tribal changes his customs, rituals, ideology and way of life in the direction of the upper, frequently twice-born caste.

Major factors of Sanskritization:-

1. Rituals: Inspite of the Theoretical existence of certain restrictions, the low castes or other groups did manage to imitate the customs and rites of “Twice-born” (DWIJAS) castes. This is the best way of claiming higher position in the caste hierarchy.

2. Marriages: According to a strict rule of Brahminism, a Brahmin should give away his daughter in marriage before she attains puberty, failing which he would be committing a great sin. Marriages among the brahmins were indissoluble. Pre-puberty marriages were commonly practiced.

On the other hand, among the low Hindu castes, post-puberty marriages were very common and the dissolution of a marriage was possible. Now in order to rise up in the caste hierarchy, the low Hindu castes started practicing pre-puberty marriages and marriages also became indissoluble.

3. Treatment of Widows: A Brahmin widow for instance, was not allowed to re-many, and received miserable treatment. She was required to shave her head and not allowed wearing any ornaments. She was regarded inauspicious, and not allowed to attend any important functions.

On the other hand, among the low castes marriage was dissoluble and widow re-marriages were practiced. Widows were not required to shave their heads. In the imitation process, these groups, also banned widow-remarriages and started treating a widow in the same way as that of the ‘High’ Hindu castes.

4. Treatment of Women: Comparatively, women among the high Hindu castes receive bad treatment and hold only a secondary position. Virginity in brides and chastity in wives was preferred. A brahmin wife was expected to treat her husband as god. Women would perform a number of ‘vratas’ or religious vows for the long life of their husbands. At certain times, such as menstruation, child birth, then were treated as untouchables and their presence was considered as inauspicious.

Hence they were not allowed to attend important functions. Women among the lower castes generally received good treatment and occupied a good position. In order to imitate the higher castes, they started treating women in a bad manner and gave them a secondary position.

5. Kinship: According to M.N. Srinivas, “In the sphere of kinship, sanskritization stresses the importance in the patrilineal lineage, sanskritization results in increasing the importance of sons. The members of high castes prefer sons to daughters, whereas among the lower castes both boys and girls are preferred.

For instance among Non-Brahmins though a son is preferred, a daughter is also demanded. Their treatment is also not that harsh but that is changing now towords preference for sons.

6. Ideology: Sanskritization also resulted in the use of New Ideas and values, which have been frequently expressed in Sanskrit literature. The ideas and values such as Karma, Dharma, Papa, Punya, Maya, Samskara, Moksha, etc. The Twice-born castes used these ideas in their conversation. Through the process of Sanskritization, lower caste groups were exposed to these ideas and values which now frequent their conversations.

7. Food habits: Brahmins in India are by and large strict vegetarians except Kashmiri, Saraswath and Bengali brahmins. The lower castes are non-vegetarian. Sanskritization resulted in the change of food habits in the direction of the, higher, frequently twice-born castes. Some of the lowers castes became strict vegetarians and practiced teetctalism also, in order to move up in the cast hierarchy.

8. Dress habits: As Dwijas, Brahmins were entitled to wear the sacred thread ‘ Janivar ‘ after the Vedic rite of upanayana, while shudras were not entitled for that. Some of the lowers castes started wearing the sacred thread and also started imitating the P dress style of the brahmins such as wearing dhothi, shalya turban, Kachche panch, etc.

9. Nomenclature: The traditional and typical names of the lower castes (in Karnataka) were Kariya, Kempa, Kempi, Kala, Mala Honni, Timmi, etc. They started giving their new born named common among the Brahmins such as Rama, Krishna Shankara, Madhava Gowri, Parvathi, Lakshmi, Shobha Radha, etc.

Discussion

4.	Mark the statement as true or false. Indian independence in 1947 marked a big and complete break with the colonial past.
Answer» The answer is: False

Discussion

5.	What is Sanskritization?
Answer» “The tendency among the low castes to move higher in the caste hierarchy in a generation or two by adopting vegetarianism and teetotalism and by sanskritizing its rituals.

Discussion

6.	Explain the policies of assimilation and integration uscd to establish national identity.
Answer» The policies of assimilation involve outright suppression of ethnic, linguistic or religious identies. Policies of integration try to assert a single. national identity by trying to remove ethnic, national and cultural differences in the political and public dorains, while still allowing it in private domains. The purpose of both sets of identities is to formulate a single national identity.

Discussion

7.	“The theory of Demographic Transition suggests that population growth is linked to overall levels of economic development and that every society follows a typical pattern of development related population growth.” Choose the incorrect statement about Demographic Transition Theory. a) The growth rate in phase I and phase II are high. b) The growth rate in phase II is high due to low death rate. c) The growth rate in phase I and phase III are low.d) The growth rate in phase III is approximately same as in phase I.
Answer» a) The growth rate in phase I and phase II are high.

Discussion

8.	Compare x and y bond angle from the above given molecules.A. `xgty`B. `ygtx`C. `x=y`D. Cannot be predicted
Answer» Correct Answer - B

Discussion

9.	Which of the following cations of Mn will have highest ionization energy?A. `Mn^(+2)`B. `Mn^(+4)`C. `Mn^(+6)`D. `Mn^(+7)`
Answer» Correct Answer - D

Discussion

10.	`CH_(3)-CH_(2)-underset(CH_(3))underset(\|)overset(CH_(3))overset(\|)(C)-CH_(2)-Br overset(NaOH//H_(2)O)rarr` Which fo the following statements is incorrect about the given reactionA. The reaction proceeds through `S_(N) 2` mechanismB. The reaction intermediate is planar `(sp^(2))`C. The major product will be `3-` Methylpentan`-3-ol`D. The major product has no stereogenic centre
Answer» Correct Answer - 1 `CH_(3)-CH_(2)-underset(CH_(3))underset(\|)overset(CH_(3))overset(\|)(C)-overset(o+)(CH_(2))overset(CH_(3)^(-)"shift")rarrCH_(3)-CH_(2)-underset(CH_(3))underset(\|)overset(o+)(C)-CH_(2)-CH_(3)` `underset(darr overset(-)(O)H)("Less stable")" "underset(darroverset(-)(O)H)("More stable cation")` `underset(" (minor)")(CH_(3)-CH_(2)-underset(CH_(3))underset(\|)overset(CH_(3))overset(\|)(C)-CH_(2)OH)" "underset("(Major)")underset("3-Methylpentan-3-ol")(CH_(3)-CH_(2)-underset(CH_(3))underset(\|)overset(OH)overset(\|)(C)-CH_(2)-CH_(2))`

Discussion

11.	Compare x and y bond angle from the above given molecules.A. `xgty`B. `ygtx`C. `x=y`D. Cannot be predicted
Answer» Correct Answer - B

Discussion

12.	Which of the following general properly of geometrical isomer is mis`-`match?A. Dipole moment `rarr` cis `gt` TransB. Stability `rarr`cis `lt` TransC. Boling point `rarr` cis `gt` TransD. Melting Point `rarr` cis `gt` Trans
Answer» Correct Answer - D

Discussion

13.	The following two isomeric alkenes are related as`-` `(I)` `CH_(3)-CH=CH-CH_(2)-CH_(2)-CH_(3)` `(II)` `CH_(3)-CH_(2)-CH=CH-CH_(2)-CH_(3)`A. MetamersB. Positions isomersC. Metamers as well as position isomersD. Geometrical isomers
Answer» Correct Answer - B

Discussion

14.	Total number of isomeric alkene possible with compound having molecular formula `C_(4)H_(8)` isA. `4`B. `5`C. `6`D. `7`
Answer» Correct Answer - A

Discussion

15.	Choose the word from the options given to form a compound word with “dream”. (a) right (b) night (c) day (d) dry
Answer» Correct answer is (c) day

Discussion

16.	Why do some plants adapted to a dry environment open their stomata only at night?
Answer» During the day in dry habitats the guard cells become flaccid and the stomata close; concurrently carbon dioxide is disallowed to pass to participate in diurnal photosynthesis. Some plants from dry regions solve this problem through the method of nocturnal carbon dioxide fixation. At night, when water loss by transpiration is lower, the stomata open, carbon dioxide enters and it is stored within the parenchymal tissues. During the day the stored gas is mobilized to be used in photosynthesis.

Discussion

17.	Dialkyl sulohide are known as :A. sulphonal mercaptanB. mercaptanC. thiethersD. thioesters
Answer» Correct Answer - C `C_2H_5-S-C_2H_5` is diethyl sulphide and is also called diethyl thioether.

Discussion

18.	The reaction, `(CH_(3))CBr+C_2H_5-O Na to ` yields :A. `CH_(3)-overset(CH_(3))overset(\|)underset(CH_(3))underset(\|)C-OCH_2CH_3`B. `CH_(3)-underset(CH_(3))underset(\|)C=CH_2`C. `CH_(3)-underset(CH_(3))underset(\|)overset(CH_(2)CH_(3))overset(\|)C-OCH_3`D. All the above
Answer» Correct Answer - B

Discussion

19.	Complete the following flow chart and answer the questions below:i) In which method pine oil is used? ii) Explain that method of concentration in brief.
Answer» Magnetic separation method, froth floatation method (Flow chart expected.) i. In froth floatation method ii. the finely ground ore is put into a big tank containing ample amount of water. Certain oils such as pine oil, eucalyptus oil, is added in the water for the formation of froth. Due to agitation a foam is formed from oil, water and air bubbles together and floats on the surface of water.

19.

Complete the following flow chart and answer the questions below:i) In which method pine oil is used? ii) Explain that method of concentration in brief.

Answer»

Magnetic separation method, froth floatation method (Flow chart expected.)

i. In froth floatation method

ii. the finely ground ore is put into a big tank containing ample amount of water.

Certain oils such as pine oil, eucalyptus oil, is added in the water for the formation of froth.

Due to agitation a foam is formed from oil, water and air bubbles together and floats on the surface of water.

Discussion

20.	Complete the process of iron rusting by filling the blanks. Suggest a way to prohibit the process.The iron rust is formed due to .............. reaction. Different regions on iron surface become anode and cathode. Reaction on anode region : Fe (s) → Fe2+ (aq) + 2e- Reaction on anode region : O2 (g) + 4H+ (aq) +................. → 2H2O((l)When Fe2+ ions migrate from anode region they react with.......... to form Fe3+ A reddish coloured hydrated oxide is formed from............. ions. It is called rust2Fe3+ (aq) + 4H2 O(l) → ............... + 6H+ (aq)A way to prevent rusting ..................................
Answer» Electrochemical 4 e ^- With water Fe³⁺ Fe₂O₃ . H₂O_(s) (Marks should be given for complete process and correct answers) Prevention by colouring with acrylic paints, Zn plating, galvanizing, anodizing, alloying etc.) (Any one way of prevention expected.)

20.

Complete the process of iron rusting by filling the blanks. Suggest a way to prohibit the process.The iron rust is formed due to .............. reaction. Different regions on iron surface become anode and cathode. Reaction on anode region : Fe (s) → Fe2+ (aq) + 2e- Reaction on anode region : O2 (g) + 4H+ (aq) +................. → 2H2O((l)When Fe2+ ions migrate from anode region they react with.......... to form Fe3+ A reddish coloured hydrated oxide is formed from............. ions. It is called rust2Fe3+ (aq) + 4H2 O(l) → ............... + 6H+ (aq)A way to prevent rusting ..................................

Answer»

Electrochemical

4 e ^-

With water

Fe³⁺

Fe₂O₃ . H₂O_(s)

(Marks should be given for complete process and correct answers)

Prevention by colouring with acrylic paints, Zn plating, galvanizing, anodizing, alloying etc.)

(Any one way of prevention expected.)

Discussion

21.	Number of moles in 1.6 kg of oxygen is A. 30 mol B. 50 mol C. 40 mol D. 60 mol
Answer» The Correct option is B. 50 mol

Discussion

22.	Observe the figure and answer the following questions.a) Identify the block shown by box A and write an electronic configuration of any one element of this block. b) Identify the block of element denoted by letter B and write its period number.
Answer» a) The block shown by box A is s-Block. S(16) = 2, 8, 6 (electronic configuration of any element in s block) b) The block of element denoted by letter B is d – Block. The period number of that element is 4.

22.

Observe the figure and answer the following questions.a) Identify the block shown by box A and write an electronic configuration of any one element of this block. b) Identify the block of element denoted by letter B and write its period number.

Answer»

a) The block shown by box A is s-Block. S(16) = 2, 8, 6 (electronic configuration of any element in s block)

b) The block of element denoted by letter B is d – Block. The period number of that element is 4.

Discussion

23.	Quantity R/NA defines A. Plank's constant B. Boltzmann constant C. gravitational constant D. Avagadro's constant
Answer» B. Boltzmann constant

Discussion

24.	At absolute zero, volume of gas is equal to A. 0 m3 B. 1 m3 C. 2 m3 D. 3 m3
Answer» The Correct option is A. 0 m³

Discussion

25.	Light travels with a velocity 1.5 x 108 m/s in a medium. On entering second medium its velocity becomes 0.75 x 108 m/s. What is the refractive index of the second medium with respect to the first medium?
Answer» Given : Velocity of light in a first medium = V₁ = 1.5 x 10⁸ m/s Velocity of light in second medium = V₂ = 0.75 x 10⁸ m/s Refractive index of second medium = ₂n₁ = ? ₂n₁ = 1 / 2 ₂n₁ = 1.5 x 10⁸ / 0.75 x 10⁸ = 2 Hence, the refractive index of second medium with respect to first medium is 2.

25.

Light travels with a velocity 1.5 x 108 m/s in a medium. On entering second medium its velocity becomes 0.75 x 108 m/s. What is the refractive index of the second medium with respect to the first medium?

Answer»

Given :

Velocity of light in a first medium = V₁ = 1.5 x 10⁸ m/s

Velocity of light in second medium = V₂ = 0.75 x 10⁸ m/s

Refractive index of second medium = ₂n₁ = ?

₂n₁ = 1 / 2

₂n₁ = 1.5 x 10⁸ / 0.75 x 10⁸

= 2

Hence, the refractive index of second medium with respect to first medium is 2.

Discussion

26.	Graph of p against 1/V is A. curve B. straight line C. parabola D. hyperbola
Answer» B. straight line

Discussion

27.	Space occupied by gas is A. area B. volume C. space D. mass
Answer» The Correct option is B. volume

Discussion

28.	Molar gas constant has value A. 7 J mol-1 K-1 B. 8 J mol-1 K-1 C. 8.31 J mol-1 K-1 D. 5 J mol-1 K-1
Answer» C. 8.31 J mol^-1 K^-1

Discussion

29.	The ideal gas equation is A. PV = constant B. PT = constant C. V/T D. PV = nRT
Answer» The Correct option is D. PV = nRT

Discussion

30.	10 mole of carbon contains A. 6.02 × 1024 atoms B. 6.03 × 1023 atoms C. 6.02 × 1023 atoms D. 6.04 × 1024 atoms
Answer» A. 6.02 × 10²⁴atoms

Discussion

31.	Escape velocity for a particle is about A. 5 km s-1 B. 8 km s-1 C. 11 km s-1 D. 14 km s-1
Answer» The Correct option is C. 11 km s^-1

Discussion

32.	If average kinetic energy of molecules is higher, then temperature of gas is A. high B. low C. zero D. infinite
Answer» The Correct option is A. high

Discussion

33.	Gases deviate from gas laws at A. high temperature only B. low pressure only C. high pressure and low temperature D. low temperature only
Answer» C. high pressure and low temperature

Discussion

34.	If we double the temperature of an ideal gas, then it's average kinetic energy will be A. halved B. triple the original C. fourth times of original D. doubled
Answer» The Correct option is D. doubled

Discussion

35.	Force exerted on a person by atmosphere is A. 200 000 N B. 300 000 N C. 400 000 N D. 500 000 N
Answer» A. 200 000 N

Discussion

36.	At standard pressure and temperature the average speed of molecules is A. 400 m s-1 B. 500 m s-1 C. 600 m s-1 D. 700 m s-1
Answer» The Correct option is A. 400 m s^-1

Discussion

37.	Pressure of gas depends on the A. density of gas B. mean square speed of gas molecules C. both A and B D. temperature
Answer» C. both A and B

Discussion

38.	As compared to the volume occupied by gas, the volume of particles is A. more B. infinite C. negligible D. less than the volume of gas
Answer» C. negligible

Discussion

39.	Law which relates pressure and volume of gas is A. Charles's law B. Avogadro's law C. Boyle's law D. ideal gas law
Answer» C. Boyle's law

Discussion

40.	Surface area of a typical person is about A. 1 m2 B. 2 m2 C. 3 m2 D. 4 m2
Answer» The Correct option is B. 2 m²

Discussion

41.	Write the IUPAC names of following hydrocarbons. a) CH3-CHOH-CH3 b) CH3-CH2-COOH
Answer» a) CH₃-CHOH-CH₃ : Propan – 2 - ol b) CH₃-CH₂-COOH : Propanoic acid

41.

Write the IUPAC names of following hydrocarbons. a) CH3-CHOH-CH3 b) CH3-CH2-COOH

Answer»

a) CH₃-CHOH-CH₃ : Propan – 2 - ol

b) CH₃-CH₂-COOH : Propanoic acid

Discussion

42.	Observe the following reaction and answer the following questions.CuSO4 (aq) + Fe (s) → FeSO4 (aq) + Cu (s) a) Identify and write the type of chemical reaction. b) Write the definition of above reaction.
Answer» a) displacement reaction. b) The reaction in which the place of the ion of a less reactive element in a compound is taken by another more reactive element by formation of its own ions, is called displacement reaction.

42.

Observe the following reaction and answer the following questions.CuSO4 (aq) + Fe (s) → FeSO4 (aq) + Cu (s) a) Identify and write the type of chemical reaction. b) Write the definition of above reaction.

Answer»

a) displacement reaction.

b) The reaction in which the place of the ion of a less reactive element in a compound is taken by another more reactive element by formation of its own ions, is called displacement reaction.

Discussion

43.	Normal force exerted per unit area by gas on walls of container is A. temperature B. energy C. pressure D. friction
Answer» The Correct option is C. pressure

Discussion

44.	Choose and write the correct option.(i) The halogen which is liquid at room temperature is .................. a) fluorine b) astetine c) bromine d) iodine (ii) Which of the following process to be carried out to avoid the formation of greenish layer on brass vessels due to corrosion? a) plating b) anodization c) tinning d) alloying (iii) What type of reaction is shown below?CH4 +CI2 CH3 - CI +CHIa) Addition b) Substitution c) Decomposition d) Reduction (iv) The temperature of ice can be decreased below 00 C by mixing ............. in it. a) saw dust b) sand c) salt d) coal (v) The image obtained while finding the focal length of convex lens is .................... a) a real and erect. b) virtual and erect. c) real and inverted. d) virtual and inverted.
Answer» (i) c) bromine (ii) c) tinning (iii) b) Substitution (iv) c) salt (v) c) real and inverted.

44.

Choose and write the correct option.(i) The halogen which is liquid at room temperature is .................. a) fluorine b) astetine c) bromine d) iodine (ii) Which of the following process to be carried out to avoid the formation of greenish layer on brass vessels due to corrosion? a) plating b) anodization c) tinning d) alloying (iii) What type of reaction is shown below?CH4 +CI2 CH3 - CI +CHIa) Addition b) Substitution c) Decomposition d) Reduction (iv) The temperature of ice can be decreased below 00 C by mixing ............. in it. a) saw dust b) sand c) salt d) coal (v) The image obtained while finding the focal length of convex lens is .................... a) a real and erect. b) virtual and erect. c) real and inverted. d) virtual and inverted.

Answer»

(i) c) bromine

(ii) c) tinning

(iii) b) Substitution

(iv) c) salt

(v) c) real and inverted.

Discussion

45.	(i) Which type of microscope has the arrangement of lenses shown in the adjoining figure?ii. Label the figure correctly. iii. Write the working of this microscope. iv. Where does this microscope used? v. Suggest a way to increase the efficiency of this microscope.
Answer» i. Compound microscope ii. Scientifically and technically correct figure. (Object, Objective lens, Eye piece, Image) iii. Magnification is obtained by the combined effect of two lenses. The magnification occurs in two stages. The image formed by the first lens acts as the object for the second lens. Clear image can be obtained by adjusting the distance between two lenses. iv. To study small sized objects like blood cells, animal and plant cells, bacteria. v. Any relevant remedy (For example, Selection of lens with appropriate focal length)

45.

(i) Which type of microscope has the arrangement of lenses shown in the adjoining figure?ii. Label the figure correctly. iii. Write the working of this microscope. iv. Where does this microscope used? v. Suggest a way to increase the efficiency of this microscope.

Answer»

i. Compound microscope

ii. Scientifically and technically correct figure.

(Object, Objective lens, Eye piece, Image)

iii. Magnification is obtained by the combined effect of two lenses. The magnification occurs in two stages. The image formed by the first lens acts as the object for the second lens. Clear image can be obtained by adjusting the distance between two lenses.

iv. To study small sized objects like blood cells, animal and plant cells, bacteria.

v. Any relevant remedy (For example, Selection of lens with appropriate focal length)

Discussion

46.	Gravitational potential is always A. infinite B. zero C. positive D. negative
Answer» The Correct option is D. negative

Discussion

47.	Each 1 kg mass experiences force of A. 7 N B. 9.81 N C. 20 N D. 100 N
Answer» The Correct option is B. 9.81 N

Discussion

48.	The closer satellite is to Earth, its speed should be A. more fast B. more slow C. zero D. any constant value
Answer» The Correct option is A. more fast

Discussion

49.	Satellite around Earth follows a circular path because A. gravitational force is parallel to velocity B. gravitational force is anti parallel to velocity C. gravitational force is perpendicular to velocity D. gravitational force is anti perpendicular to
Answer» C. gravitational force is perpendicular to velocity

Discussion

50.	As distance increases, value of gravitational field strength A. also increases B. decreases C. remains constant D. may increase or decrease
Answer» B. decreases

Discussion

Explore topic-wise InterviewSolutions in Current Affairs.

Expand D.S.S.

What are counter movements? Give example.

What is sanskritization? Discuss its factors.

Mark the statement as true or false. Indian independence in 1947 marked a big and complete break with the colonial past.

What is Sanskritization?

Explain the policies of assimilation and integration uscd to establish national identity.

Compare x and y bond angle from the above given molecules.A. `xgty`B. `ygtx`C. `x=y`D. Cannot be predicted

Which of the following cations of Mn will have highest ionization energy?A. `Mn^(+2)`B. `Mn^(+4)`C. `Mn^(+6)`D. `Mn^(+7)`

Compare x and y bond angle from the above given molecules.A. `xgty`B. `ygtx`C. `x=y`D. Cannot be predicted

Which of the following general properly of geometrical isomer is mis`-`match?A. Dipole moment `rarr` cis `gt` TransB. Stability `rarr`cis `lt` TransC. Boling point `rarr` cis `gt` TransD. Melting Point `rarr` cis `gt` Trans

The following two isomeric alkenes are related as`-` `(I)` `CH_(3)-CH=CH-CH_(2)-CH_(2)-CH_(3)` `(II)` `CH_(3)-CH_(2)-CH=CH-CH_(2)-CH_(3)`A. MetamersB. Positions isomersC. Metamers as well as position isomersD. Geometrical isomers

Total number of isomeric alkene possible with compound having molecular formula `C_(4)H_(8)` isA. `4`B. `5`C. `6`D. `7`

Choose the word from the options given to form a compound word with “dream”. (a) right (b) night (c) day (d) dry

Why do some plants adapted to a dry environment open their stomata only at night?

Dialkyl sulohide are known as :A. sulphonal mercaptanB. mercaptanC. thiethersD. thioesters

The reaction, `(CH_(3))CBr+C_2H_5-O Na to ` yields :A. `CH_(3)-overset(CH_(3))overset(|)underset(CH_(3))underset(|)C-OCH_2CH_3`B. `CH_(3)-underset(CH_(3))underset(|)C=CH_2`C. `CH_(3)-underset(CH_(3))underset(|)overset(CH_(2)CH_(3))overset(|)C-OCH_3`D. All the above

Complete the following flow chart and answer the questions below:i) In which method pine oil is used? ii) Explain that method of concentration in brief.

Number of moles in 1.6 kg of oxygen is A. 30 mol B. 50 mol C. 40 mol D. 60 mol

Observe the figure and answer the following questions.a) Identify the block shown by box A and write an electronic configuration of any one element of this block. b) Identify the block of element denoted by letter B and write its period number.

Quantity R/NA defines A. Plank's constant B. Boltzmann constant C. gravitational constant D. Avagadro's constant

At absolute zero, volume of gas is equal to A. 0 m3 B. 1 m3 C. 2 m3 D. 3 m3

Light travels with a velocity 1.5 x 108 m/s in a medium. On entering second medium its velocity becomes 0.75 x 108 m/s. What is the refractive index of the second medium with respect to the first medium?

Graph of p against 1/V is A. curve B. straight line C. parabola D. hyperbola

Space occupied by gas is A. area B. volume C. space D. mass

Molar gas constant has value A. 7 J mol-1 K-1 B. 8 J mol-1 K-1 C. 8.31 J mol-1 K-1 D. 5 J mol-1 K-1

The ideal gas equation is A. PV = constant B. PT = constant C. V/T D. PV = nRT

10 mole of carbon contains A. 6.02 × 1024 atoms B. 6.03 × 1023 atoms C. 6.02 × 1023 atoms D. 6.04 × 1024 atoms

Escape velocity for a particle is about A. 5 km s-1 B. 8 km s-1 C. 11 km s-1 D. 14 km s-1

If average kinetic energy of molecules is higher, then temperature of gas is A. high B. low C. zero D. infinite

Gases deviate from gas laws at A. high temperature only B. low pressure only C. high pressure and low temperature D. low temperature only

If we double the temperature of an ideal gas, then it's average kinetic energy will be A. halved B. triple the original C. fourth times of original D. doubled

Force exerted on a person by atmosphere is A. 200 000 N B. 300 000 N C. 400 000 N D. 500 000 N

At standard pressure and temperature the average speed of molecules is A. 400 m s-1 B. 500 m s-1 C. 600 m s-1 D. 700 m s-1

Pressure of gas depends on the A. density of gas B. mean square speed of gas molecules C. both A and B D. temperature

As compared to the volume occupied by gas, the volume of particles is A. more B. infinite C. negligible D. less than the volume of gas

Law which relates pressure and volume of gas is A. Charles's law B. Avogadro's law C. Boyle's law D. ideal gas law

Surface area of a typical person is about A. 1 m2 B. 2 m2 C. 3 m2 D. 4 m2

Write the IUPAC names of following hydrocarbons. a) CH3-CHOH-CH3 b) CH3-CH2-COOH

Observe the following reaction and answer the following questions.CuSO4 (aq) + Fe (s) → FeSO4 (aq) + Cu (s) a) Identify and write the type of chemical reaction. b) Write the definition of above reaction.

Normal force exerted per unit area by gas on walls of container is A. temperature B. energy C. pressure D. friction

(i) Which type of microscope has the arrangement of lenses shown in the adjoining figure?ii. Label the figure correctly. iii. Write the working of this microscope. iv. Where does this microscope used? v. Suggest a way to increase the efficiency of this microscope.

Gravitational potential is always A. infinite B. zero C. positive D. negative

Each 1 kg mass experiences force of A. 7 N B. 9.81 N C. 20 N D. 100 N

The closer satellite is to Earth, its speed should be A. more fast B. more slow C. zero D. any constant value

Satellite around Earth follows a circular path because A. gravitational force is parallel to velocity B. gravitational force is anti parallel to velocity C. gravitational force is perpendicular to velocity D. gravitational force is anti perpendicular to

As distance increases, value of gravitational field strength A. also increases B. decreases C. remains constant D. may increase or decrease