This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
I think I will ______ about this bad service. A) complain B) think C) consider D) explain |
|
Answer» Correct option is A) complain |
|
| 2. |
Good health is ______ than money. A) more important B) very important C) as important as D) the most important |
|
Answer» Correct option is A) more important |
|
| 3. |
Who is ______ footballer in Turkey? A) very good B) a better C) the best D) best |
|
Answer» Correct option is C) the best |
|
| 4. |
Describe the role played by protein pumps during active transport in plants. |
|
Answer» Active transport uses energy to pump molecules against a concentration gradient. Active transport is carried out by membrane – proteins. |
|
| 5. |
Name the source of cyclosporin A. How does this bioactive molecule function in our body? |
Answer»
|
|
| 6. |
Explain the structure of a mature female gametophyte in flowering plants. |
Answer»
|
|
| 7. |
How is recombinant DNA technology helping in detecting the presence of mutant genes in cancer patients? |
Answer»
|
|
| 8. |
(a) Diffusion and Osmosis(b) Transpiration and Evaporation(c) Osmotic Pressure and Osmotic Potential(d) Imbibition and Diffusion(e) Apoplast and Symplast pathways of movement of water in plants.(f) Guttation and Transpiration. |
||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
|
Answer» (a) Diffusion and osmosis
(b) Transpiration and evaporation
(c) Osmotic pressure and osmotic potential
(d) Imbibition and diffusion
(e) Apoplast and symplast pathways of movement of water in plants
|
|||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
| 9. |
What are the factors affecting the rate of diffusion? |
|
Answer» Factors affecting the rate of diffusion:
|
|
| 10. |
(a) unidirectional(b) bidirectional(c) multi directional(d) no specific direction |
| Answer» (a) unidirectional | |
| 11. |
(a) Decrease in energy at higher trophic levels(b) Dufficient food supply(c) Polluted air(d) Water |
| Answer» (a) Decrease in energy at higher trophic levels | |
| 12. |
(i) damage to immune system(ii) damage to lungs(iii) skin cancer(iv) peptic ulcers(a) (i) and (ii) (b) (ii) and (iv)(c) (i) and (iii) (d) (iii) and (iv) |
| Answer» (c) (i) and (iii) | |
| 13. |
Which among the following is not a prokaryoteA. NostocB. MycobacteriumC. SaccharomycesD. Oscillatoria |
|
Answer» Correct Answer - C Among the given options, Saccharomyces is a fungus, i.e. it is a eukaryote. They possess a well defined nucleus and other cell organelles. Nostoc and Oscillatioria are cyanobacteria while Mycobacterium is a true bacterium. Cyanobacteria and bacteria both are prokaryotes as they lack a well-defined nucleus and other cell organelles. |
|
| 14. |
(i) Wood, paper, leather(ii) Polythene, detergent, PVC(iii) Plastic, detergent, grass(iv) Plastic, bakelite, DDT(a) (iii) (b) (iv)(c) (i) and (iii) (d) (ii) and (iv) |
| Answer» (d) (ii) and (iv) | |
| 15. |
The Golgi complex participates inA. respiration in bacteriaB. formation of secretory vesicleC. fatty acid breakdownD. activation of amino acid |
|
Answer» Correct Answer - B Golgi complex participates in the formation of secretory vesicles. It is a cytoplasmic structure found in eukaryotic cells. It is made up of four parts, cistemae, tubules, vesicles and vacuoles. The forming face or cisternae receives vesicles from endoplasmic reticulum. Their contents pass through various cisternae with the help of coated vesicles and intercisternal connectives. They ultimately reach the maturing face where they are budded off as, coated secretory or Golgian vesicles or vacuoles. In bacteria, respiration occurs with the help of mesosomes. The breakdown of fatty acid occurs in peroxisomes and mitochondria. Activation of amino acid is an important step of protein synthesis and it occurs in cytoplasm. In this process, amino acids get attached to tRNA molecules. |
|
| 16. |
Secondary xylem and phloem in dicot stem are produced byA. phellogenB. vascular cambiumC. apical meristemsD. axillary merstems |
|
Answer» Correct Answer - B Secondary vascular tissues, i.e, secondary xylem and pholem are formed by the vascular cambium. It is produced by two types of meristems, fascicular or intrafascicular and interfescicular cambium. Intrafascicuiar cambium is a primary meristem which occurs as strips in vascular bundles. It divides to form secondary phloem on outer side and secondary xylem on the inner side. Interfascicular cambium arises secondarily from the cells of medullaxy rays. Phellogen or cork cambium is produced in the outer cortical cells of dicob stems, It is helpful in increasing the girth. Apical maristems are present at the tips of stem, root and their branches. They are responsible for increase in length of the plant. Axillary menistem is found in axillary buds. These cells are left behind from shoot apical mexistem during the formation of leaves and elongation of stems. |
|
| 17. |
Which of the following is not a product of light reaction of phtosynthesisA. NADPHB. NADHC. ATPD. Oxygen |
|
Answer» Correct Answer - B During light reaction of photosynthesis NADPH, ATP and oxygen are formed. Oxygen is liberated by the photolysis of water. `4H_(2)OhArr4H^(+)+4OH^(-)` `4OH^(-)underset(Mn^(2+),Ca^(2+),Cl^(-))overset("Oxygen-Evolving complex")to2H_(2)O+O_(2)uarr+4e^(-)` The electrons released during photolysis of water are picked up by `P_(680)` photocentre of PS-II. On receiving light energy photocentre expels an electron which passes over a series of carriers. As a result assimilatory power. i.e. ATP and NADPH is produced. NADH is formed during respiration. |
|
| 18. |
The principle involved in paper chromatography isA. adsorptionB. partitionC. solubilityD. volatility |
|
Answer» Correct Answer - B Paper chromatography is based upon the principle of partition. |
|
| 19. |
The substance which can be used as an adsorbent in column chromatography isA. `Na_(2)O`B. NaClC. `Al_(2)O_(3)`D. Alum |
|
Answer» Correct Answer - B NaCl is the substance which canbe used as an adsorbent in column chromatography. |
|
| 20. |
Arrange `K,Ca` and `Li` in order of increasing electrode potential. |
| Answer» Correct Answer - `LigtKgtCa` | |
| 21. |
C60, an allotrope of carbon contains : (1) 16 hexagons and 16 pentagons. (2) 12 hexagons and 20 pentagons. (3) 18 hexagons and 14 pentagons. (4) 20 hexagons and 12 pentagons. |
|
Answer» Correct option (4) 20 hexagons and 12 pentagons. Explanation: C60 contains 20 hexagons and 12 pentagons |
|
| 22. |
C60 is aromatic allotrope of carbon containing(1) 18 Pentagons, 14 hexagons(2) 16 Pentagons, 16 hexagons(3) 12 Pentagons, 20 hexagons(4) 20 Pentagons, 12 hexagons |
|
Answer» Correct option: (3) 12 Pentagons, 20 hexagons Explanation: C60 Contains 12 Pentagons, 20 hexagons |
|
| 23. |
`underset(("Monosubsitituted benzene"))(P)overset(Na(Hg))underset(+conc. H_(2)SO_(4))rarr Q overset(NaNO_(2))underset(+HCl.0^(@).5^(@)C)rarr R overset(KCN)underset(CuCN)rarr S overset(SnCl_(2))underset(HCl)rarr T` Correct statement are :A. B. C. D. P is treated with `Zn+NH_(4)Cl`, |
| Answer» Correct Answer - A::B::D | |
| 24. |
Which of the following substance is/are identified due to their unique charcteristic smellA. `PH_(3)`B. `O_(3)`C. `NH_(3)`D. `H_(2)S` |
| Answer» Correct Answer - A::B::C::D | |
| 25. |
Which of the properties are INCORRECT regarding `NaHCO_(3)` and `KHCO_(3)`A. Both are fairly soluble in waterB. Both have similar structure of `HCO_(3)^(-)` ion in their solidC. Both solid consists of ion-dipole type of interactionD. Both on heating produces respective carbonate as residue |
| Answer» Correct Answer - A::B | |
| 26. |
Incorrect statements is/are exothermic in natureA. Adsorption is always exothermic in natureB. `CaCl_(2)"cause more coagulation of gold sol than" AlCl_(3)`C. Surface tension of associated colloids increase with increase in concentrationD. With increase in concentration, molar conductance of strong electrolyte decrease repidly than associated colloids |
| Answer» Correct Answer - B::C::D | |
| 27. |
Which among `Na,Mg,Ba` and `Ca` is the poor reducing agent? |
| Answer» Correct Answer - `Mg` | |
| 28. |
The strongest reducing agent is . (a) K (b) Ba (c) Li (d) Na |
|
Answer» The strongest reducing agent is Li. |
|
| 29. |
SO2 can act as (a) Oxidising agent only (b) Reducing agent only (c) Both oxidising and reducing agents (d) Acid and a reducing agent only |
|
Answer» (c) Both oxidising and reducing agents |
|
| 30. |
Brief explanation on Trigonometrical Ratios. |
|
Answer» Trigonometric Ratios are defined as the values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle. The ratios of sides of a right-angled triangle with respect to any of its acute angles are known as the trigonometric ratios of that particular angle. The three sides of the right triangle are:
|
|
| 31. |
What would be the `SI` unit for the quantity `pV^(2)T^(2)//n`? |
| Answer» `SI` units`=(Paxx(m^(3))^(2) K^(2))/(mol)=Pa m^(6) K^(2) mol^(-1)` | |
| 32. |
Why are sulphide ores converted to oxide before reduction?A. Sulphides cannot be reduced easily while oxides can be reduced easily.B. Sulphides decompose on reduction hence they are first converted to oxidesC. Sulphides ore have higher melting points than oxides.D. Oxides are more stable than sulphides hence easy to reduce. |
|
Answer» Correct Answer - A Thermodynamically based on Ellingham diagram it is observed that sulphides cannot be reduced easily as compared to oxides. |
|
| 33. |
For the reduction of FeO with C at the temperature corresponding to (D) , which of the following statements is correct ?A. carbon reduces FeO below the temperature at point (D)B. `DeltaG^(@)` value for overall reduction with CO is zero.C. `DeltaG^(@)` value for the reaction at point (D) is positive .D. Below point (D) , for the metal exists in molten state. |
|
Answer» Correct Answer - B `DeltaG_("reactant")^(@)= DeltaG_("product")^(@)` at the point of intersection , so `DeltaG^(@)` become zero for the overall reaction. |
|
| 34. |
At the points of intersection of `Al_(2)O_(3)` and MgO curves (A), `DeltaG^(@)` becomes zero for reaction, `(2)/(3)Al_(2)O_(3) + 2Mg to 2MgO + 4/3 Al` Above this point, magnesium can reduce alumina. Although thermodynamically feasible, Mg is not used to reduction of `Al_(2)O_(3)` becauseA. temperature required is very highB. the yield of metal is very lowC. value of `DeltaG` becomes positiveD. magnesium is not used as reducing agent for any reaction. |
|
Answer» Correct Answer - A Temperature above the point of intersection of `Al_(2)O_(3)` and MgO to reduce `Al_(2)O_(3)` but the temperature required would be so high that the process is difficult to carry out. |
|
| 35. |
Write de Broglies equation. |
|
Answer» λ = h/mv or h/mc |
|
| 36. |
What is limiting reagent. |
|
Answer» The reactant which gets consumed limits the amount of product formed is called limiting reagent. |
|
| 37. |
Given below are two statements : one is labelled as Assertion A and the other is labelled as Reason R. Assertion A: LiF is sparingly soluble in water. Reason R: The ionic radius of Li+ ion is smallest among its group members, hence has least hydration enthalpy. In the light of the above statements, choose the most appropriate answer from the options given below.(A) Both A and R are true and R is the correct explanation of A(B) Both A and R are true but R is NOT the correct explanation of A(C) A is true but R is false(D) A is false but R is true |
|
Answer» Correct option is (C) A is true but R is false Due to high lattice energy LiF is sparingly soluble in water. Li+ has high hydration energy among its group members due to smallest size. |
|
| 38. |
The backbone of nucleic acid structure is constructed by |
|
Answer» The chain of sugars made by the phosphodiester bonds form the backbone of the nucleic acids. The backbone of every nucleic acid is the same, but each sugar can contain one of four different bases. Two of the bases, (A)adenine and guanine (G), are derivatives of purine. |
|
| 39. |
Markonic of addition reaction |
|
Answer» In an addition reaction of a protic acid HX (hydrogen chloride, hydrogen bromide, or hydrogen iodide) to an alkene or alkyne, the hydrogen atom of HX becomes bonded to the carbon atom that had the greatest number of hydrogen atoms in the starting alkene or alkyne. |
|
| 40. |
polysaccharides are |
Answer»
|
|
| 41. |
an increase melting temperature of duplex DNA results from a high content of |
|
Answer» Answer: Cytosine + Guanine |
|
| 42. |
the normal serum GOT activity ranges from |
Answer»
|
|
| 43. |
DNA rich in A-T pairs have (A) 1 Hydrogen bond (B) 2 Hydrogen bonds (C) 3 Hydrogen bonds(D) 4 Hydrogen bonds |
|
Answer» (B) 2 Hydrogen bonds |
|
| 44. |
In DNA molecule (A) Guanine content does not equal cytosine content (B) Adenine content does not equal thymine content (C) Adenine content equals uracil content (D) Guanine content equals cytosine content |
|
Answer» (D) Guanine content equals cytosine content |
|
| 45. |
DNA rich in G-C pairs have (A) 1 Hydrogen bond (B) 2 Hydrogen bonds (C) 3 Hydrogen bonds (D) 4 Hydrogen bonds |
|
Answer» (C) 3 Hydrogen bonds |
|
| 46. |
The fact that DNA bears the genetic information of an organism implies that (A) Base composition should be identical from species to species (B) DNA base composition should charge with age (C) DNA from different tissues in the same organism should usually have the same base composition (D) DNA base composition is altered with nutritional state of an organism |
|
Answer» (C) DNA from different tissues in the same organism should usually have the same base composition |
|
| 47. |
How many isomers are possible in [CO(en)2Cl2] ? (a) 2 (b) 4 (c) 6 (d) 1 |
|
Answer» 4 isomers are possible in [CO(en)2Cl2] . |
|
| 48. |
Which is the mixture of carbogen. (a) H2 + O2(b) H2 + S(c) O2 + CO2(d) SO2 + O |
|
Answer» O2 + CO2 is the mixture of carbogen. |
|
| 49. |
Sweetest of all sugars is:(a) Glucose(b) Lactose(c) Sucrose(d) Fructose |
|
Answer» Answer is (c) Sucrose |
|
| 50. |
The derivative of ax is(a) ax log a(b) ax (c) \(\frac{a^x}{log\, \alpha}\)(d) None of these |
|
Answer» (a) ax log a The derivative of ax is ax log a. |
|