Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

What are the advantages of secondary cells over primary cell?

Answer»

The advantages of secondary cells over primary cell are.

a. It gives high current capacity. 

b. Its internal resistance is very low. 

c. It gives a constant current. 

d. It posses very high efficiency. 

e. It posses fairly constant emf. 

f. It posses good mechanical strength. 

g. It posses large storage capacity

h. It can be renewed by charging after it is discharged. 

i. It is durable. 

2.

What is polarization? What is local action?

Answer»

Polarization:

The hydrogen bubbles which are clinging over the surface of copper electrode (anode) becomes a thin film of hydrogen over the copper electrode. This hydrogen film increases the internal resistance and reduces the emf of the cell and hence the cell soon becomes inactive. This effect is known as polarization.

Local action:

In voltaic cell it is observed that, when the cell is not connected to the load and not supplying any current zinc will continuously dissolving in the electrolyte. This is due to the impurities (copper, iron, tin, and lead) in the commercial zinc. So that whenever commercial zinc is used as a electrode, separate small cells are developed between the impurities and zinc with the presence of electrolyte. These local cells consume always zinc and the emf developed by those local cells are always opposite to the main emf. The action of these cells is known as local action. 

3.

What are the differences between primary cell and secondary cell?

Answer»

Primary cells are those cells, which cannot be re-charged after the substances (electrolyte, electrode and container) used in it becomes useless. 

The common primary cells in use are, 

a. Simple voltaic cell (one fluid cell). 

b. Daniel cell (two fluid cell). 

c. Leclanche cell (two fluid cell). 

d. Dry cell. 

e. Standard cell or Weston cadmium cell.

Secondary cells are those cells, which can be re-charged and use again once they discharged or used for the work for number of times with out re-newing it’s materials. 

Most commonly used secondary cells are, 

a. Lead acid cell. 

b. Nickel iron alkaline cell. 

c. Nickel cadmium alkaline cell. 

4.

What are the classifications of cell?

Answer»

The classifications of cell are given below.

a. Primary cells. 

b. Secondary cells. 

5.

What are the classifications of voltages? 

Answer»

a. Low voltage: Voltage not exceeding 250V. That is 0 – 250V. 

b. Medium voltage: Voltage above 250V upto 650V comes under medium voltage. 

c. High voltage: Voltage above 650V upto 33 kV comes under high voltage. 

d. Extra high voltage: Above 33 kV voltages are extra high voltages. 

6.

What are the classifications of DC motor?

Answer»

The classifications of DC motor.

a. DC series motor. 

b. DC shunt motor. 

c. DC compound motor. 

There are two types of DC compound motor. 

a. Differential compound motor. 

b. Commulative compound motor. 

7.

Two point charges +8q and -2q are located at x = 0 and x = L respectively. The point on x axis at which net electric field is zero due to these charges is- (i) 8L (ii) 4L (iii) 2 L (iv) L

Answer»

Answer is (iii) 2L

Let P is the observation point at a distance r from -2q and at (L+r) from +8q. 

Given Now, Net EFI at P = 0

∴ \(\overrightarrow{E_1}\) = EFI (Electric Field Intensity) at P due to +8q

\(\overrightarrow{E_2}\) = EFI (Electric Field Intensity) at P due to -2q

\(|\overrightarrow{E_1|}=|\overrightarrow{E_2}|\)

∴ \(\frac{K(8q)}{(L+r)^2}=\frac{1}{(r)^2}\)

∴ \(\frac{4}{(L+r)^2}=\frac{1}{(r)^2}\)

4r2 = (L+r)2

2r = L+r

r = L

∴ P is at x = L + L = 2L from origin

2L

8.

The factory outlets offer discounts ranging between _____ all the year round. a) 20% - 80% b) 25% - 75% c) 25% - 60% d) 50% - 85%

Answer»

The factory outlets offer discounts ranging between 25% - 75% all the year round. 

9.

Explain Factory Outlets as Store based Retailing.

Answer»

Factory Outlet- deals in surplus stock , Directly sold by the manufacturer at a discount. Stock can be either first-quality merchandise or discontinued, irregular, cancelled orders at a very low price. The discount can range from 25-75%.

10.

State any difference between store baseband non store based retailing.

Answer»
Store basedNon-store based
They have a brick and mortar retail shops with permanent location.They are click and sell retail store with no permanent structure.
Example \(\rightarrow\) convenience store , super market , etc.Example \(\rightarrow\) telemarketing , online retailing , etc.
11.

A. Watt-sB. Kilowatt-hourC. eVD. J-s

Answer» Option d Bcz other then d all the units are  of Energy while option d is unit of plank constant...
12.

A charge `Q_1` is placed at O inside a hollow conducting sphere having inner and outer radii as 10 m and 11 m as shown. The force experienced by `Q_2` at P is `F_1` and force experienced by `Q_2` when `Q_1` is placed at `O_1 is F_2`. Then `F_1//F_2` is equal to A. 1B. `(12/13)^2`C. `(13/12)^2`D. none of these

Answer» Correct Answer - A
Force on `Q_(2)` will be due to induced charge on outer surface only which will be same in both cases along with its distribution. Hence the ratio is `1`.
13.

The value of ((A) + (B)) ×  ((A) - (B)) is A. 0B. A2-B2C. (B)×(A)D. 2((B)×(A))

Answer»

(A+B)×(A-B)

=(A+B)×A-(A×B)×B

=(A×A)+(B×A)-(A×B)-(B×B)

BCZ[A×(B−C)=A×B−A×C]

=(B×A)+(B×A)[BCZ A×A=0,A×B=-(B×A)]

=2(B×A)

ANSWER

14.

The statement that is incorrect about the intertitial compounds is - (1) they are very hard (2) they have metallica conductivity (3) they have high melting points (4) they are chemically reactive  

Answer»

Correct option (4) they are chemically reactive

Explanation:

Intustitial compound are – 

 (i) hard 

 (ii) chemically inert 

 (iv) high m.p. As interstitial compounds are chamically inert

15.

The complex ion that will lose its crystal field stabilization energy upon oxidation of its metal to +3 state is :(1) [Fe(phen)3] 2+ (2) [Zn(phen)3] 2+ (3) [Co(phen)3] 2+ (4) [Ni('phen)3] 2+ 

Answer»

Correct option (1) [Fe(phen)3] 2+  

Explanation:

In the complexes of Fe2+, CO2+, Ni2+ upon oxidation, complexes of Fe3+, CO2+ & Ni3+ stabilizes whereas in case of removing 3rd electron from Zn becomes difficult.

16.

The process with negative entropy change is (1) Dissociation of CaSO4(s) to CaO(s) and SO3(g) (2) Dissolution of iodine in water (3) Synthesis of ammonia from N2 and H2 (4) Sublimation of dry ice

Answer»

The correct option is (3) Synthesis of ammonia from N2 and H2.

Explanation:

where Δng > O

17.

The hardness of a water sample (in terms of equivalents of CaCO3) containing 10–3M CaSO4 is : (molar mass of CaSO4 = 136g mol–1) (1) 10ppm (2) 90ppm (3) 50ppm (4) 100ppm

Answer»

The correct option (4) 100 ppm

Explanation:

Moles of CaSO4 = 10–3 moles 

Mass of water = 1000g 

DOH (in terms of CaCO3) = (10-3 x 100)/1000 x 106 = 100ppm

18.

Sum of oxidation state (magnitude) and coordination number of cobalt in Na[Co(bpy)Cl4] is__.

Answer»

Correct answer is 9

Coordination no. = 6 

Oxidation state = 3 

6 + 3 = 9

19.

Correct statement about photo-chemical smog is : (A) It occurs in humid climate. (B) It is a mixture of smoke, fog and SO2 (C) It is reducing smog. (D) It results from reaction of unsaturated hydrocarbons.

Answer»

(D) It results from reaction of unsaturated hydrocarbons.

Photo chemical smog results from the action of sunlight on unsaturated hydro carbons and nitrogen oxide

20.

The colour of the X2 molecules of group 17 elements changes gradually from yellow to violet down the group. This is due to (A) the physical state of X2 at atom temperature changes from gas to solid down the group (B) decrease in HOMO-LUMO gap down the group (C) decrease in π*-σ* gap down the group (D) decrease in ionization energy down the group

Answer»

(B) decrease in HOMO-LUMO gap down the group 

(C) decrease in π*-σ* gap down the group 

Highest occupied molecular orbital (HOMO) ⇒ π* 

Lowest unoccupied molecular orbital (LUMO) ⇒ σ* 

On descending the group gap between π* and σ* decreases.

21.

According to molecular orbital theory, which of the following is true with respect to Li2+ and Li-2 ? (1)  Both are unstable (2)  Li2- is unstable and Li2-  is stable (3)  Li2- is stable and Li2 - is unstable (4)  Both are stable 

Answer»

Correct option (4) Both are stable 

Explanation:

Both Li2+ and Li2-  has 0.5 bond order and hence both are stable

22.

Roasting is doen inA. blast furnaceB. open herath furnaceC. Electric furnaceD. none of these

Answer» Correct Answer - A
Roasting is the process of heating the ore strongly in the presence of excesss of air. It is generally carried in a reverberatory or blast furnace.
23.

The dimensionas of universal gravitational constant are ____

Answer» `F=(Gm_1m_2)/(d^2)impliesG=(Fd^2)/(m_1m_2)`
because `[G]=([MLT^-2][L])/([M^2])=[M^-1L^3T^-2]`
`M^(-1)L^(3)T(-2)`
24.

Speed of soundd calculated is roughlyA. `340m//sec`B. `380m//sec`C. `430m//sec`D. None of these

Answer» `l_(1) = 24.0cm`
`l_(2) = 74.0cm`
`v = 2f_(0) (l_(2)-l_(1)) = 2(340) (0.740 - 0.240)`
`= (2) (340) (0.500) = 340m//sec` .
25.

If mass and specific heat capacity of calormeter is negligible what would be maximum permissible error is `S` Use the data mentioned below `m_(1) rarr 0, S_(c) rarr 0, m_(2) = 1.00kg V = 10.0 V I = 10.0A` `t = 1.00 xx 10^(2) sec theta_(0) = 15^[email protected])C` Corrected `theta_(t) = 65^(@)C` (A) `4%` (B) `5%` (C) `8%` (D) `12%` .

Answer» If `m_(1) rarr 0, S_(c) rarr0`
`S_(l) = (Vit)/(m_(2)(theta_(f)-theta_(0))`
`(DeltaS_(l))/(S_(l))=(DeltaV)/(V)+(DeltaI)/(I)+(Deltat)/(t)+(Deltam_(2))/(m_(2))+(Deltatheta_(f)+Deltatheta_(0))/(theta_(f)-theta_(0))=(0.1)/(10.0)+(0.01xx10^(2))/(1.00xx10^(2))+(0.01)/(1.00)+(1+1)/(50)=8%` .
26.

If mass and specific heat capacity of calormeter is negligible what would be maximum permissible error is `S` Use the data mentioned below `m_(1) rarr 0, S_(c) rarr 0, m_(2) = 1.00kg V = 10.0 V I = 10.0A` `t = 1.00 xx 10^(2) sec theta_(0) = 15^[email protected])C` Corrected `theta_(t) = 65^(@)C` (A) `4%` (B) `5%` (C) `8%` (D) `12%` .

Answer» If `m_(1) rarr 0, S_(c) rarr0`
`S_(l) = (Vit)/(m_(2)(theta_(f)-theta_(0))`
`(DeltaS_(l))/(S_(l))=(DeltaV)/(V)+(DeltaI)/(I)+(Deltat)/(t)+(Deltam_(2))/(m_(2))+(Deltatheta_(f)+Deltatheta_(0))/(theta_(f)-theta_(0))=(0.1)/(10.0)+(0.01xx10^(2))/(1.00xx10^(2))+(0.01)/(1.00)+(1+1)/(50)=8%` .
27.

The isoelectronic set of ions is : (1) F– , Li+ , Na+ and Mg2+ (2) Li+ , Na+ , O2– and F– (3) N3– , O2– , F– and Na+ (4) N3– , Li+ , Mg2+ and O2– 

Answer»

Correct option (3) N3– , O2– , F and Na+ 

Explanation:

In this we have to choose isoelectronic set of ions 

Isoelectronic species are those which have same no. of electron in total. 

So option 3 : is correct.

28.

Polysubstition is a major drawback in - (1) Reimer Tiemann reaction (2) Friedel Craft's acylation (3) Friedel Craft's alkylation (4) Acetylation of aniline 

Answer»

Correct option (3) Friedel Craft's alkylation

Explanation:

Polysubstitution is a major drawback of Friedal –Craft alkylation 

–CH3 gp in highly activating group 

 due to +H effect of its  

29.

Dimensions  of pascal x sec will be :(1) ML-1T-1(2) M2L1T2(3) M-1L3T(4) ML3T2

Answer»

Correct option is (1) ML-1T-1

Pt = Ft/A = change in momentum/Area

MLT-1/L= ML-1T-1

30.

Equation of SHM of particle is given by x = sinπ (t + 1/3), then velocity at t = 1 sec. is (1) -π/2(2) π(3) -π/3(4) -π/4

Answer»

Correct option is (1) -π/2

v = dx/dt = πcosπ(t+ 1/3)

v at t = 1 = πcosπ(1+ 1/3)

= πcos(π + π/3)

= -πcos π/3

= -π/2

31.

In the following reaction carbonyl compound + MeOH acetal Rate of the reaction is the highest for : (1) Propanal as substrate and methanol in stoichiometric amount (2) Propanal as substrate and methanol in excess (3) Acetone as substrate and methanol in stoichiometric amound (4) Acetone as substrate and methanol in excess

Answer»

Correct option (2) Propanal as substrate and methanol in excess

Explanation:

Ketones < Aldehydes →Rate of NAR 

Only aldehydes are responsible for the function of acetals.

32.

The correct statements among I to III regarding group 13 element oxides are, (I) Boron trioxide is acidic. (II) Oxides of aluminium and gallium are amphoteric. (III)Oxides of indium and thallium are basic. (1) (I) and (II) only (2) (I) and (III) only (3) (II) and (III) only (4) (I), (II) and (III) only

Answer»

Correct option (4) (I), (II) and (III) only

Explanation:

B2O3 is acrolic in nature Al2O3 and Ca2O3 are amphoteric oxides of In and Tl are basic in nature.

33.

Among the following species, the diamagnetic molecule is : (1) NO (2) O2 (3) CO (4) B2

Answer»

Correct option (3) CO

Explanation:

CO is diamagnetic in nature

34.

Which of the following is diamagnetic ?(a)  O2(b)  CO(c)  B2(d)  NO

Answer»

Correct option  (1)  CO

Explanation:

According to MOT, O2, B2 & NO are paramagnetic, only CO is diamagentic.

35.

Arrange the following compounds in the correct increasing rate of aromatic electrophilic substitution.

Answer»

Correct option: (2) D < A < B < C

36.

The fundamental frequency in an open organ pipe is equal to the third harmonic of a closed organ pipe. If the length of the closed organ pipe is 20 cm, the length of the open organ pipe isA. 12.5cmB. 8 cmC. 13.3cmD. 16cm

Answer» Correct Answer - C
37.

In a given system of unit standard measurement of mass is 100 gm standard measurement of length is 200 cm and standard measurement of time is 5 sec 10 J energy in the given system of unit has value N, then value of N is

Answer» Correct Answer - `0625`
[E]`=mL^(2) T^(-2)`
`K_(2)=K_(1)[m_(1)/m_(2)]^(a)[L_(1)/L_(2)]^(b)[T_(1)/T_(2)]^(c)`
`=10[(1kg)/(100gm)]^(1)[(1m)/(200cm)]^(2)[(1sec)/(5 sec)]^(2)`
`=10[(1000gm)/(100gm)][(100cm)/(200cm)]^(2)[5]^(2)`
`=10xx10xx1/4xx25=625`
38.

What is known as parallelism of the earth’s axis?

Answer»

The axis of the earth is tilted at an angle of 66 \(\frac{1}2º \)  from the orbital plane and 23 \(\frac{1}2º \)  from the vertical plane. The earth maintains this tilt throughout its revolution. This is known as parallelism of the earth’s axis.

39.

What is meant by apparent movement of the sun? Name the two latitudinal lines that gain importance in this process.

Answer»

Since the parallelism of the earth’s axis is maintained same throughout the revolution, the position of the sun in relation to the earth varies apparently between Tropic of Cancer and Tropic of Capricorn. This is known as the apparent movement of the sun.

The movement of the sun is in between 23 \(\frac{1}2º \) N and 23 \(\frac{1}2º \) S.

40.

What is the tilt of the earth?

Answer»

The tilt of the earth 23 1/2° 

41.

What is the tilt of the earth’s axis at vertical plane and horizontal plane?

Answer»
  • At vertical plane, tilt of the earth’s axis is 23 \(\frac{1}2º \)
  • At horizontal plane, the tilt is 66°.
42.

Fingerlings are larvae of- (a) Honey bee (b) Salamanders (c) Silkworm (d) Fish

Answer»

Fingerlings are larvae of  Fish.

43.

Which of the following muscular disorders is inherited? (1) Tetany (2) Muscular dystrophy (3) Myasthenia gravis (4) Botulism

Answer»

Correct option: (2) Muscular dystrophy

Explanation: 

Progressive degeneration of skeletal muscle mostly due to genetic disorder is muscular dystrophy where as tetany is muscular spasm due to low calcium in body fluid. Myasthenia gravis is an anto immume disorder leading to paralysis of skeletal muscles. Botulism is rare and dangerous type of food poisoning caused by bacterium Clostridium Botulinum.

44.

Which one of the following statements is correct with reference to enzymesA. Apoenzyme= Holoenzyme + CoenzymeB. Holoenzyme = Apoenzyme + CoenzymeC. Coenzyme = Apoenzyme + HoloenzymeD. Holoonzyme = Coenzyme + Cofactor

Answer» Correct Answer - B
Holoenzyme It is a conjugate complete catalytically active enzyme together with its coenzyme.
Apoenzyme The protein part of catabolically active enzyme is called apoenzyme
Coenzyme Some enaymes require additional organic or metallo-organic molecules for their activity. These molecules are called coenzyne
45.

All followings are rich sources of magnesium, except (A) Milk (B) Eggs (C) Meat (D) Cabbage

Answer»

Correct option (C) Meat

46.

To eat less of something to improve your health is to _____ on it. A) strip down B) cut back C) run

Answer»

Correct option is B) cut back

47.

To eat a lot of food is to ______. A) pig out B) roll out C) wear out

Answer»

Correct option is A) pig out

48.

Change the following sentences into Indirect Speech: 1. He said, “I will do it now.”2. He says, “Honesty is the best policy.”3. Ramesh says, “I have written a letter.”4. She said, “Mahesh will be reading a book.”5. She said, “Where is your father?”6. He said to me, “Please take your book.”7. The Principal said to the peon, “Let this boy go out.”8. He said to me, “May you live long!”9. She said, “Goodbye friends!”10. The student said, “Alas! I wasted my time last year.”

Answer»

1. He said that he would do it then.

2. He says that honesty is the best policy.

3. Ramesh says that he has written a letter.

4. She said that Mahesh would be reading a book.

5. She inquired where his father was.

6. He requested me to take my book

7. The Principal ordered the peon to let that boy go out.

8. He prayed that I might live long.

9. She bade goodbye to her friends.

10. The student regretted that he had wasted his time the previous year.

49.

The opposite of dead is ______

Answer»

Correct option is living

50.

The number of hypervariable region in L chain is (A) 1 (B) 2 (C) 3 (D) 4

Answer»

The number of hypervariable region in L chain is 3.