Explore topic-wise InterviewSolutions in Current Affairs.

• Secular trend 

• Seasonal variation 

• Cyclical variation 

• Irregular/Random variation.

It is the average number of years a person aged x can expected to live under the prevailing mortalite conditions.

If Σa_i – availiability = Σb_j – Requirements, then T.P is called balanced.

1. The parameter is ‘n’ called d.f. 

2. Mean = E(x) = 0 and

Var(x) = \(\frac{n}{n-2}\) for n > 2

Let the initial cost price be “x”

Selling price = s

Market price = m

According to given information

s – x = m – s

2s = m + x       ----(I)

Profit percentage made initially, p = (s – x)/x × 100

When cost piece and selling price are interchanged, new discount percentage

d = (m – x)/m × 100

Required ratio = p/d = m(s – x)/x(m - x) = m/2x [from (I)]

Statement I

m = 1.4x

p/d = 3/2x = 1.4x/2x = 0.7

Statement II

s = 0.8m

2s = m + x

1.6m = m + x

0.6m = x

m/x = 10/6

p/d = m/2x = 10/12 = 0.833

Hence, each statement alone can answer the question.

Feasible region is the area which satistifies by all constraints and non-negativity restrictions.

Given :

The total amount distributed by the man = Rs. 846

The ratio of shares of his two sons and a daughter = (1/4) : (1/5) : (1/3)

Calculation :

Let the ratio of shares of his two sons and a daughter be x, y and z respectively

According to the question,

x : y : z = (1/4) : (1/5) : (1/3)

To convert it into a simple ratio multiply LCM of 4, 5 and 3

Now, L.C.M. of (4, 5, 3) = 60

So, x : y : z = (60/4) : (60/5) : (60/3)

⇒ 15 : 12 : 20

Again, according to the question,

x + y + z = 846

⇒ (15 + 12 + 20) unit = 846

⇒ 47 unit  = 846

⇒ 1 unit = 18

Daughter's share = 20 unit

⇒ 20 × 18

⇒ Rs. 360

∴ The share of his daughter is Rs. 360.

Initial investment of S = 20000

Time = 18 months (i.e. 1.5 years)

From statement I:

Total investment of S = 20000 × 6 + 25000 × 6 + 30000 × 6 = 450000

Let the initial investment of T be ‘3y’ and U be ‘5y’.

Total investment of T = 3y × 18 = 54y

Total investment of U = 5y × 9 + (5y - 5000) × 9 = 90y – 45000

By this information alone we can’t get the answer so statement I alone is not sufficient.

From statement II:

Ratio of profit = 10 : 6 : 9

Statement II alone is not sufficient.

From statement I and II:

Ratio of the profit share = 450000 : 54y : (90y - 45000) = 25000 : 3y : (5y - 2500)

Comparing this with statement II

We get,

25000/3y = 10/6

⇒ y = 5000

So, initial investment of U = 5y = 5 × 5000 = Rs. 25000

Hence, I and II together are sufficient.

Concept:

Objective function: Linear function Z = ax + by, where a, b are constants, which has to be maximized or minimized is called a linear objective function.
In the above example, Z = ax + by is a linear objective function. Variables x and y are called decision variables.

By putting values of variables (coordinates of the point) in linear objective function we get the value of the point. 

Calculations:

Given:

Objective function for all LPP is t = 2x + 3y

Putting coordinates of points in the equation we gate value of the point

e.g for corner point (6, 8)

t = 2x + 3y = 2 × 6 + 3 × 8 = 36

Hence from the table, we can conclude that the minimum value of t occurs at (0, 2) 

p.m.f is P(x) =(1/4)^x (1-1/4)^1-x : x = 0,1

= (0.25^)x (0.75)^1-x : x = 0 , 1.

Answer is (d) π/2

It is distribution of the values of a statistic for different samples by same size.

Control chart is a graphical device which is used to verify whether the production process is in control or not.

Stock replenishment is the rate at which the items are added to the Inventory to maintain a certain level. The cost associated with delay or inability to meet the demand because of shortage of stock is called shortage cost, denoted by C₂.

Answer is (d) 5/8

While playing a game, pure strategy of a player is his determined decision to adopt a specified course of action, irrespective of the course of action of the opponent.

Answer is (b) (1/4) tan^-1 (x/4) + k

Retail/consumer prices.

If an L.P.P. has many optimal solutions, it is said to have multiple solution.

Answer is (d) 0

Search Results Featured snippet from the web A line segment can be divided into 'n' equal parts, where 'n' is any natural number. For example; a line segment of length 10 cm is divided into two equal parts by using a ruler as, Mark a point 5 cm away from one end. 10 cm is divided into two 5 cm line segments.

The set of all admissible values of the parameter is called parameter space.

Incease in employement during harvest season in agriculture sector.

Degrees of freedom = (n – 1 – 1 ) = (n – 2).

Answer is (d) x vector i + y vector j + z vector k 

Poisson distribution.

Mean = variance.

SE (P) = \(\sqrt \frac {P_0Q_0}{n}\) .

‘While estimating the unknown parameter, if a specific’value is proposed as an estimate, which is called Point estimation’. ‘While estimating the unknown parameter instead of a specific value, an interval is proposed, which is likely to contain the parameter is called Interval estimation’

In point estimation a single statistic is used to provide an estimate of the population parameter. 

OR 

while estimating unknown parameter if a special value is proposed as an estimate is called point estimation.

The mean = 0.

It is the probability of rejecting the null hypothesis when it is not true. (1 – β ), 

Here β = P (Type II Error) which is referred as ‘consumers risk.

Vital statistics is the science applied to the analysis and interpretation of numerical facts regarding vital events occurring in a human population.

Answer is (a) 0

Answer is (a) log 2/3

correct option (a) One - one

Null hypothesis is a hypothesis, which is being tested for possible rejection, assuming that it is true. (H₀) null hypothesis is rejected, is called alternative hypothesis (H₁).

Z_A = 200(0)+100(18)= 1800, Z_B = 200 (12)+100(4) = 400
Z_B is maximum and so, the optimal solution is at B: n = 12, y = 0.

L.C.L = X̄¹ – Aσ¹ = 40 – (1.342 × 6) = 31.948 U.C.L 

= X̄¹ + Aσ¹ = 40 + (1.342 × 6) = 48.052

Answer is (b) (x^{n + 1}/(n + 1)) + k

Discrimination against people based on their gender.

Occupational and food restrictions are relaxed

Backward classes are castes or classes who are characterised by low literacy’or lack of education, poverty, exploitation, nonrepresentation in services.

Life table is a tabular presentation of numerical data describing the mortality experience of a cohort.

Answer is (b) 1

1. Caste Panchayaths impose restrictions on social intercourse, marriages, commercial and occupations. 

2. Violations of caste norms attract punishments.

Tarawads were matrilineal institutions. Fathers had no significant properties separate from their own Tarawads to’ give their children, and fathers held no special claims over their children. The Tarawad institutions included family, household, and lands maintained a status and a life beyond any individual. Material support for the household . was drawn from the inseparable lands of the Tarawad.

Properties of Tarawad were managed by a senior male called a ‘Karanavan’. The karanavan as the head of a large extended family. The internal management of the affairs of the tarawad was in fact directed by a senior female – a mother, aunt, of a grandmother of all sharing the wealth and status of the Tarawad.

Both males and females had a whole-life security within their mother’s tarawads; fathers visited only on occasion. The kamavan is an absolute ruler of the family. On his death the next senior male member becomes kamavan.

He can invest money in his own name, can mortgage property, can give money on loan, can give land as gift and is not accountable to any member in respect of income and expenditure. When Tarwad becomes too large, it is divided into Tavashis. A Tavashis in relation . to a woman is “a group of persons consisting of a female, her children and all descendents in the matrilineal.

Answer is (c) 2

(1) Prosperity (2) Decline (3) Depression and (4) Improvement.

Option: (D) (0, 2)