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I am not sure what you are asking in this question but if you are asking about the direction of magnetic field than, we will use right hand thumb rule to find the direction of magnetic field.

Case 1.

If the direction of current is upwards then the direction of magnetic field will be anticlockwise. 

Case 2.

If the direction of current is downwards then the direction of magnetic field will be clockwise. 

Correct Option (b) nucellus or integuments 

Correct Option (c) Primary myofilament consists of two proteins 

Correct Option  (C)

Correct Option (a) Oral contraceptive pills 

Correct Option (b) organic acid 

Correct Option (d) stepwise arrangement of all categories for classificatino of plants and animals

Correct Option (c) It acts on collecting tubules

Correct Option (b) in straight line of funicle

Correct Option (b) liver

Correct Option (a) The bundle sheath cells surround the vascular bundles like a ring in C₄ plants. This is called Krnaz anatomy 

Correct option [a] haemochorial placenta

Correct Option (a) SA-node 

Correct option [d] In insects, circulating body fluids serve to distribute oxygen to tissues

Correct Option (a) Ramapithecus 

Answer given below:

https://bit.ly/2YLDQ86

The correct option is (B) vessel wall.

Explanation:

Bordered pits are found in vessel wall. In bordered pits, the thickening material over arches the pit cavity in such a way that a pit chamber opens to the interior by a pit aperture.

Answer is : (d) - 1.25 x 10^-4 J

Energy \(=\frac{1}{2}FI=\frac{1}{2}\frac{F^2L}{AY}\) \(\left[\because Y=\frac{FL}{AI}\right]\)

\(=\frac{1}{2}\times \frac{(100)^2\times 40\times 10^{-2}}{4\times 10^{-4}\times 4\times 10^{10}}\)

= - 1.25 x 10^-4 J

Answer is : (a) 0.99 m

The maximum acceleration for SHM is given by

\(a_{max}=\omega^2A=(2\pi \upsilon)^2\) \(A=4\pi^2\upsilon^2A\)

The block will remains in contact with the piston, if \(a_{max} \leq g\,or\) \(4\pi^2\upsilon^2A<g\)

∴ Maximum amplitude of piston will be

\(A_{max}=\frac{g}{4\pi^2\upsilon^2}\)

\(=\frac{9.8}{4\pi^2(0.5)^2}\) = 0.99 m

Answer is : (b) cryophyte

Chlamydomonas yellowstonensis is a cryophyte. These are the plants (algae) that grow on snow. Parasites are those organisms which feed on another organism called host. Symbionts are those organisms which live in close physical association with each other. Thermophytes are plants which can tolerate high temperature

Correct Option (c) I and II 

Correct Option (d) In anatrophous ovule, the micropyle, funicle and chalaza lie in a straight line

Correct Option (b) Helsinki declaration 

Correct Option (a) II and III 

Correct Option (b) Lateral meristem

Correct Option (c)

Correct option [a] ventral nerve cord

Correct option 

Correct option [d] All of these

2) move with the same velocity in opposite directions

The two masses are equal, so to conserve linear momentum which is zero, they should move in the opposite directions with equal velocity.

Answer is : (a) the stem that totally creeps on the ground

Procumbent is the stem that creeps on the ground totally, e.g. Tribulus, Convolvulus microphyllus.

Correct option (c) O₂    

Explanation:

O₂ is used in respiration. High concentration of O₂ mean well atmosphere. It does not causes greenhouse effect, hence O₂ is not a greenhouse gas.

Correct Option (d) (CH₃)₃N < CH₃NH₂ < (CH₃)₂NH

Explanation :

Such order of basic strength is weighted result of these three factors

(a) Inductive effect 

(b) Solvation effect

(c) Steric hindrance

Correct option (c) Alitame    

Explanation:

Alitame is an artifical sweetner developed by Pfizer in the early 1980s. ALlimate has several distinct advantages over aspartame. ALitame is more stabler than aspartame and 2000 times more sweetner than sugar.

Answer is : (c) (n - 1)G

\(I_g=\frac{V}{G}\) and \(R=\frac{nV}{I_g}-G\) \(=\frac{nV}{V/G}-G\)

= (n - 1)G

Answer is : (d) zero

From Gauss theorem,

\(\phi_E=\frac{q_{in}}{E_0}\) \(=\frac{+8e-8e}{E_0}=0\)

Here MnO4^2-  where Mn is in  +6 state disproportionates  to  MnO₄^1- (where Mn is in +7) and MnO₂ (where Mn is in+4). So The changes are

+6 -> +7 => 1 unit increase

+6 -> +4 => 2 unit decrease

So to balance the redox process the ratio of number of moles of the species produced should be

  MnO₄^2-:   MnO₂ = 2 :1

So the statement (A) supports above fact

The correct option is (i) 

• Stability of carbocation depends on several factors but resonance outweighs every other factor.
• Due to more resonance, benzyl carbocation is most stable.

Correct Option (b) 10 m/s

Correct Option  (d)

Correct Option (d)  y  =  a tan ωt

Correct Option (a) For an isothermal change PV = constant 

Correct Option (d) 60

Correct option (c) 7i-2j+8k

Correct Option (d) 10⁴ Hz to 10¹¹ Hz

Explanation :

Correct Option (b) 5×10¹⁵

Explanation :

An energy,

E = hv = 6.63×10^–34 x 6.05×10¹⁴

= 3.98×10^–19J

Now, number of photons emitted per second n = p/E

Correct option   (a) diffusion in forward biased, drift in reverse bias 

Explanation:

In p-n junction, the diffusion of majority carriers takes place when juncton is forward biased and drifting of minority carrier takes place across teh junction when reverse biased.

Correct option  (c) H-atom    

Explanation:

As, an atom is eelctrically neutral so it is not dfelected in magnetic field.

Correct Option (c) Zero 

Explanation

As the same current is flowing through wires and the net change in flux is zero through the coil, so there will be no induced current.

Correct Option (a) 3 μF 

Explanation

The last three capacitors on teh right. Each of capacitance C = μF are in series and are equivalent to a capacitance C' given by

1/C' = 1/9+1/9+1/9 = 1/3

or  C' = 3μF

Since C' is in parallel with C₁, the equivalent capacitance of the last part of the network is C" = C' + C₁ = 3 + 6 = 9 μF.