Explore topic-wise InterviewSolutions in .

This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

1.	Why reducing property of dioxides decreases down the grp from so2 to Teo2 and so2 is a reducing while Teo2 is oxidising agent
Answer» The dioxide molecules contain pπ–pπ bonds which become weaker with increase in atomic number because, increase in atomic number increases size along a group and hence there occurs an increase in the bond length and so the reducing character decreases down the group. Due to presence of d-orbitals(vacant) sulphur can extend its co valency and show oxidation states till +6, which is stable in sulphur (eg: SF₆). Hence it acts as a reducing agent, and now the character decreases down the group because of decrease in strength of the pπ–pπ bonds while, unlike sulphur Te cannot show +6 oxidation state as it is highly unstable due to inert pair effect. Also Te is heavier element electrons are reluctant to take part in bond formation due to poor shielding of d- and f-orbitals thus We can see lower oxidation states. Hence, TeO₂ acts as oxidizing agent.

Why reducing property of dioxides decreases down the grp from so2 to Teo2 and so2 is a reducing while Teo2 is oxidising agent

Answer»

The dioxide molecules contain pπ–pπ bonds which become weaker with increase in atomic number because, increase in atomic number increases size along a group and hence there occurs an increase in the bond length and so the reducing character decreases down the group.

Due to presence of d-orbitals(vacant) sulphur can extend its co valency and show oxidation states till +6, which is stable in sulphur (eg: SF₆). Hence it acts as a reducing agent, and now the character decreases down the group because of decrease in strength of the pπ–pπ bonds while, unlike sulphur Te cannot show +6 oxidation state as it is highly unstable due to inert pair effect. Also Te is heavier element electrons are reluctant to take part in bond formation due to poor shielding of d- and f-orbitals thus We can see lower oxidation states. Hence, TeO₂ acts as oxidizing agent.

Discussion