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101.

There is no difference between Navier-Stokes and Euler equations with respect to the continuity equation. Why?(a) Convection term plays the diffusion term’s role(b) Diffusion cannot be removed from the continuity equation(c) Its source term balances the difference(d) The continuity equation by itself has no diffusion termI got this question in examination.Query is from Euler Equation in chapter Governing Equations of Fluid Dynamics of Computational Fluid Dynamics

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Correct option is (d) The continuity EQUATION by itself has no DIFFUSION term

The explanation is: Diffusion term, in GENERAL, is given by DIV(ΓgradΦ). For the continuity equation, Φ=1. And grad Φ=0. So, the continuity equation by itself has no diffusion term.

102.

Turbulence problems particularly depend on this term of the Navier-Stokes equations. Which is that term?(a) Rate of change term(b) Convection term(c) Diffusion term(d) Source termThe question was asked in homework.I'm obligated to ask this question of Navier Stokes Equation topic in section Governing Equations of Fluid Dynamics of Computational Fluid Dynamics

Answer» CORRECT answer is (c) DIFFUSION term

The explanation is: Turbulence is caused by abrupt changes in velocities perpendicular to the FLOW. This, in turn, can be given in viscosity terms. Diffusion term of the Navier-Stokes equations holds the viscosity terms. So, WITHOUT diffusion terms, we cannot model turbulence.
103.

The source term in the momentum equation is ________(a) Pressure force(b) Body forces(c) Viscous force(d) AccelerationThe question was asked in quiz.The above asked question is from Momentum Equation topic in chapter Governing Equations of Fluid Dynamics of Computational Fluid Dynamics

Answer»

The correct answer is (b) Body forces

Explanation: The effect of SURFACE forces are EXTERNAL. They are not produced inside the body. Body forces are created inside the body of conservation. So, the body FORCE term is the SOURCE term.

104.

For a control volume moving along with the flow, which of these properties is a constant?(a) Volume(b) Shape(c) Mass(d) VelocityI got this question at a job interview.The doubt is from Governing Equations in section Governing Equations of Fluid Dynamics of Computational Fluid Dynamics

Answer»

The correct option is (c) Mass

To explain I would say: Mass of a control volume moving along with the flow will not vary. It is CONSTANT with time. The volume, shape and velocity of the control volume may not be the same at all POINTS of time.

105.

The independent variables in Eulerian approach are __________ and __________(a) instantaneous time and instantaneous position(b) initial time and instantaneous position(c) instantaneous time and Initial position(d) initial time and initial positionThis question was posed to me in quiz.The origin of the question is Governing Equations topic in section Governing Equations of Fluid Dynamics of Computational Fluid Dynamics

Answer»

The correct option is (a) INSTANTANEOUS time and instantaneous POSITION

The best EXPLANATION: Current position and time are the variables on which other variables depend on in Eulerian APPROACH. These are the independent variables.

106.

Gauss divergence theorem is used to convert a surface integral to volume integral. This is used in Reynolds Transport theorem. What is the purpose of this conversion?(a) Simplifying the term(b) Differentiating the flow property(c) Adding the flow property(d) Grouping terms related to control volumeThis question was addressed to me during an online exam.I'd like to ask this question from Governing Equations topic in division Governing Equations of Fluid Dynamics of Computational Fluid Dynamics

Answer»

Right choice is (d) Grouping terms related to control volume

The explanation is: ONE term related to control volume is a volume integral. The other term is a surface integral. To group these two terms together, Gauss Divergence Theorem is USED.

107.

The principle of conservation is applicable to _______ systems.(a) isolated system(b) closed system(c) open system(d) all the systems irrespective of its typeThe question was posed to me in a job interview.This intriguing question comes from Governing Equations topic in division Governing Equations of Fluid Dynamics of Computational Fluid Dynamics

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Correct option is (a) ISOLATED system

To explain I WOULD say: The PRINCIPLE of CONSERVATION is applicable only to the systems where there will not be any TRANSFER of matter or energy. Isolated system will have these characters.

108.

When is Leibniz rule applicable to control volume?(a) When control volume is moving(b) When control volume is deforming(c) When control volume is fixed(d) In all conditionsI have been asked this question during an online interview.I need to ask this question from Governing Equations topic in section Governing Equations of Fluid Dynamics of Computational Fluid Dynamics

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The correct ANSWER is (c) When control volume is fixed

To explain: LEIBNIZ rule is APPLICABLE to a system only if a system variable is independent. When control volume is fixed, position of the control volume becomes independent. So, Leibniz rule is applicable only to fixed control VOLUMES.

109.

The physical principle behind the energy equation is _____________(a) Newton’s second law of motion(b) Zeroth law of thermodynamics(c) First law of thermodynamics(d) Newton’s first law of motionThe question was asked in an online quiz.This interesting question is from Energy Equation topic in section Governing Equations of Fluid Dynamics of Computational Fluid Dynamics

Answer»

The correct answer is (c) FIRST law of thermodynamics

Easiest explanation: First law of thermodynamics is the physical principle BEHIND the energy equation. This law STATES that “Energy can neither be produced nor be destroyed but can be converted from one FORM into another”.

110.

\(\frac{\partial(\rho\hat{u})}{\partial t}+\nabla.(\rho\vec{V}\hat{u}) = -\nabla.\dot{q_s}-p\nabla.\vec{V}-\tau:\nabla\vec{V}+\dot{q_v}\). This form of the energy equation is applicable to _________(a) Both Newtonian and non-Newtonian fluids(b) Newtonian fluids(c) Non-Newtonian fluids(d) Pseudo-plasticsI have been asked this question in examination.I'm obligated to ask this question of Energy Equation topic in portion Governing Equations of Fluid Dynamics of Computational Fluid Dynamics

Answer»

Right choice is (a) Both Newtonian and non-Newtonian FLUIDS

Explanation: The ENERGY equation given here is in terms of shear stresses. So, no RESTRICTIONS based on the VISCOSITY of the FLUID. It is applicable to both Newtonian and Non-Newtonian fluids.

111.

To which of these flows, the Euler equation is applicable?(a) Couette flow(b) Potential flow(c) Stokes Flow(d) Poiseuille’s flowI had been asked this question in a job interview.I want to ask this question from Euler Equation topic in chapter Governing Equations of Fluid Dynamics of Computational Fluid Dynamics

Answer»

The correct choice is (b) POTENTIAL flow

Best explanation: AMONG the given FLOWS, only potential flows are in-viscid. So, the EULER equation is applicable to only potential flows among the above.

112.

The general transport equation is \(\frac{\partial(\rho \Phi)}{\partial t}+div(\rho \Phi \vec{u})+div(\Gamma grad \Phi)+S\). For Eulerian equations, which of the variables in the equation becomes zero?(a) Γ(b) ρ(c) Φ(d) \(\vec{u}\)This question was addressed to me in an interview.I want to ask this question from Euler Equation in division Governing Equations of Fluid Dynamics of Computational Fluid Dynamics

Answer»

Correct CHOICE is (a) Γ

Explanation: Γ is the diffusion COEFFICIENT in the GENERAL TRANSPORT equation. Diffusion of any PROPERTY is not included in Eulerian equations. So, Γ=0.

113.

The viscosity terms in x-momentum equation is \(\frac{\partial\tau_{xx}}{\partial x}+\frac{\partial\tau_{yx}}{\partial y}+\frac{\partial\tau_{zx}}{\partial z}\). In a more general form, this becomes div(μ gradu). Which of these relations is used for this transformation?(a) Thermodynamic relations(b) Stress-strain relations(c) Fluid flow relations(d) Geometric relationsThe question was posed to me during an online interview.The query is from Navier Stokes Equation topic in portion Governing Equations of Fluid Dynamics of Computational Fluid Dynamics

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114.

Consider the continuity equation \(\frac{\partial\rho}{\partial t}+\nabla.(\rho \vec{V})=0\). For an incompressible flow, this equation becomes ___________(a) \(\nabla.(\rho \vec{V})=0\)(b) \(\frac{\partial(\rho\vec{V})}{\partial t}=0\)(c) \(div(\vec{V})=0\)(d) \(div(\rho\vec{V})=0\)The question was posed to me in quiz.Origin of the question is Continuity Equation in portion Governing Equations of Fluid Dynamics of Computational Fluid Dynamics

Answer»

Correct answer is (c) \(div(\VEC{V})=0\)

The best explanation: TAKING the continuity equation,

\(\frac{\PARTIAL\rho}{\partial t}+\nabla.(\rho \vec{V})=0\)

For incompressible flow, ρ is CONSTANT

\(\frac{\partial\rho}{\partial t}+\nabla.(\rho \vec{V})=0\)

The resulting equation is

\(\nabla.(\rho \vec{V})=0\)

\(\rho\nabla.(\vec{V})=0\)

\(\nabla.(\vec{V})=0\)

Thus, for incompressible flow, divergence of \(\vec{V}=0\).

115.

Consider an infinitesimally small fluid element with density ρ (of dimensions dx, dy and dz) fixed in space and fluid is moving across this element with a velocity \(\vec{V}=u\vec{i}+v\vec{j}+w\vec{k}\). What is the final reduced form of net mass flow across the fluid element?(a) \(\frac{\partial\rho}{\partial t}\)(b) \(\rho\vec{V} dx \,dy \,dz\)(c) \(\nabla.(\rho\vec{V})\)(d) \(\nabla.(\rho\vec{V})\)dx dy dzI had been asked this question during an interview.My question comes from Continuity Equation topic in portion Governing Equations of Fluid Dynamics of Computational Fluid Dynamics

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The CORRECT answer is (d) \(\nabla.(\rho\vec{V})\)dx dy dz

The best I can EXPLAIN: Net MASS flow across the element = change in mass flow in x direction + change in mass flow in y direction + change in mass flow in z direction

= \(\FRAC{\partial(\rho u)}{\partial x} dx \,dy \,dz + \frac{\partial(\rho v)}{\partial y} dx \,dy \,dz + \frac{\partial(\rho w)}{\partial z} dx \,dy \,dz \)

=\(\left[(\frac{\partial}{\partial x}\vec{i}+\frac{\partial}{\partial y}\vec{j}+\frac{\partial}{\partial z}\vec{k})dx \,dy \,dz.((\rho u)\vec{i} + (\rho v)\vec{j} + (\rho w)\vec{k})\right] \)

Net mass flow across the element = \([\nabla.(\rho \vec{V})]dx \,dy \,dz\).

116.

The surface integral can be used to represent ____ and ____ terms of the transport equation.(a) Rate of change and diffusion(b) Rate of change and convection(c) Source and diffusion(d) Convection and diffusionI have been asked this question in final exam.This is a very interesting question from General Transport Equation topic in portion Governing Equations of Fluid Dynamics of Computational Fluid Dynamics

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The correct choice is (d) Convection and diffusion

Best EXPLANATION: Convection and diffusion terms are based on a transfer through the BOUNDARIES. The boundaries of a volume are its surfaces which MAKES surface INTEGRALS ideal for convection and diffusion.

117.

Each parcel in the Lagrangian formulation is tagged using __________(a) time-dependent position vector(b) time-independent position vector(c) time-dependent velocity vector(d) time-independent velocity vectorThis question was addressed to me during an online interview.My question is taken from Governing Equations in section Governing Equations of Fluid Dynamics of Computational Fluid Dynamics

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The CORRECT option is (B) time-independent position VECTOR

To elaborate: The tag is time-independent so that the tag does not vary along with the FLOW. Position vector is chosen to follow the parcel along its position.

118.

A flow property has substantial derivative. What does this imply?(a) The property is a function of both time and space(b) The property is a function of time only(c) The property is a function of space only(d) The property is independent of time and spaceI got this question in an interview for internship.I'd like to ask this question from Governing Equations topic in chapter Governing Equations of Fluid Dynamics of Computational Fluid Dynamics

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The correct choice is (a) The property is a function of both time and SPACE

To explain: If a property has SUBSTANTIAL derivative, it is DIFFERENTIABLE by both time and space. This MEANS that it is a function (i.e., dependent on) of time and space.

119.

Why a surface integral is used to represent flow of B into and out of the control volume?(a) Control volume is moving(b) Flow of fluid is through the control surfaces(c) Fluid only on the control surfaces(d) Control volume is stationaryThis question was addressed to me in an online interview.This intriguing question comes from Governing Equations topic in chapter Governing Equations of Fluid Dynamics of Computational Fluid Dynamics

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Correct answer is (b) Flow of fluid is through the CONTROL SURFACES

To elaborate: Fluid can ENTER into or exit from the control VOLUME through the control surface. If this flow velocity is integrated ALONG the control surfaces, we can get the net inflow or outflow of fluid to the control volume.

120.

The relationship between the rate of heat transfer per unit area \(\dot{q}_s\)=-(k∇T). Where, k is a scalar value of thermal conductivity and ∇T is the gradient of temperature. Which of these following is wrong according to the above equation?(a) Heat transfer is different in different directions(b) The rate of heat transfer depends upon the temperature gradient(c) Heat transfer is in the opposite direction of increasing temperature(d) k is the proportionality constantI got this question in exam.I'm obligated to ask this question of Energy Equation in section Governing Equations of Fluid Dynamics of Computational Fluid Dynamics

Answer»

Correct CHOICE is (a) Heat TRANSFER is DIFFERENT in different directions

Easiest explanation: The statement “Heat transfer is different in different directions” is wrong. K is a scalar means that the heat transfer is the same in all directions and the material is isotropic. For different heat transfers in different directions (ANISOTROPIC material), the proportionality constant should be a tensor.

121.

The Navier-Stokes equations are all partial differential equations. What will be the best reason behind this?(a) Ordinary differentials are not present in the Navier-Stokes equations(b) The dependent variables are functions of all of the independent variables(c) Each dependent variable depends on only one of the independent variables(d) Partial differentials are only present in the Navier-Stokes equationsThe question was asked in an internship interview.My question is from Navier Stokes Equation topic in division Governing Equations of Fluid Dynamics of Computational Fluid Dynamics

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The CORRECT option is (b) The DEPENDENT variables are FUNCTIONS of all of the independent variables

To elaborate: Each dependent variable in the Navier-Stokes equations depends on all of the independent variables. So, partial differentials are used to indicate that the other independent variables should be kept fixed while DIFFERENTIATING.

122.

What is the relationship between bulk viscosity coefficient (λ) and the dynamic viscosity coefficient (μ)?(a) λ=\(-\frac{2}{3}\) μ(b) λ=\(\frac{2}{3}\) μ(c) λ=\(-\frac{1}{3}\) μ(d) λ=\(-\frac{1}{2}\) μI got this question during a job interview.I want to ask this question from Governing Equations topic in division Governing Equations of Fluid Dynamics of Computational Fluid Dynamics

Answer»

Right option is (a) λ=\(-\frac{2}{3}\) μ

Easy explanation: The bulk VISCOSITY COEFFICIENT REPRESENTS fluid COMPRESSIBILITY effects. λ=\(-\frac{2}{3}\) μ is the relationship between the bulk viscosity coefficient and the dynamic viscosity coefficient.

123.

What are the two viscosity coefficients involved in the relationship between stress tensor and strain rate of fluids?(a) Kinematic viscosity and bulk viscosity(b) Dynamic viscosity and kinematic viscosity(c) Dynamic viscosity and bulk viscosity(d) Kinematic viscosity and volume viscosityThis question was posed to me during an interview for a job.I need to ask this question from Governing Equations in chapter Governing Equations of Fluid Dynamics of Computational Fluid Dynamics

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Right option is (c) Dynamic viscosity and BULK viscosity

To explain: The TWO viscosities involved in stress train relationship of fluids is dynamic viscosity COEFFICIENT and bulk viscosity coefficient. Bulk viscosity coefficient for DIAGONAL elements respectively.

124.

The divergence of the stress tensor is _____(a) Scalar(b) Vector(c) 0(d) 1The question was asked in final exam.I'm obligated to ask this question of Governing Equations topic in section Governing Equations of Fluid Dynamics of Computational Fluid Dynamics

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The CORRECT answer is (b) Vector

To explain: Stress TENSOR is a square MATRIX given by

Τxy = \(\begin{bmatrix}

\tau_{XX} & \tau_{xy} & \tau_{xz} \\

\tau_{yx} & \tau_{yy} & \tau_{yz} \\

\tau_{zx} & \tau_{zy} & \tau_{zz}

\end{bmatrix}\)

The divergence of this will result in a vector

∇. Τ= \(\begin{bmatrix}

\frac{\partial \tau_{xx}}{\partial x}+\frac{\partial \tau_{yx}}{\partial y}+\frac{\partial \tau_{zx}}{\partial Z} \\

\frac{\partial \tau_{xy}}{\partial x}+\frac{\partial \tau_{yy}}{\partial y}+\frac{\partial \tau_{zy}}{\partial z} \\\frac{\partial \tau_{xz}}{\partial x}+\frac{\partial \tau_{yz}}{\partial y}+\frac{\partial \tau_{zz}}{\partial z}

\end{bmatrix}\)

125.

What is the physical statement of mass conservation equation for a finite control volume moving along with the flow?(a) Rate of change of mass inside the control volume = 0(b) Rate of change of mass inside the control volume = constant(c) Net mass flow through the control surface = Rate of change of mass inside the control volume(d) Net mass flow through the control surface≠Rate of change of mass inside the control volumeI had been asked this question in an online interview.Question is taken from Continuity Equation in section Governing Equations of Fluid Dynamics of Computational Fluid Dynamics

Answer» CORRECT choice is (b) Rate of change of mass inside the CONTROL VOLUME = constant

Explanation: Statement of mass conservation equation for a finite control volume MOVING along with the flow:

Mass inside the control volume = constant

Rate of change of mass inside the control volume = 0.
126.

What are the terms included in the transport equation?(a) Rate of change term, advective term, convective term, source term(b) Advective term, diffusive term, convective term, source term(c) Rate of change term, diffusive term, convective term, advective term(d) Rate of change term, diffusive term, convective term, source termThe question was posed to me by my college professor while I was bunking the class.My query is from General Transport Equation topic in portion Governing Equations of Fluid Dynamics of Computational Fluid Dynamics

Answer»

The correct answer is (d) Rate of change term, diffusive term, CONVECTIVE term, source term

The best explanation: Transport equation involves FOUR terms which are rate of change, DIFFUSION, convection and source of properties.

127.

The fluid is subdivided into fluid parcels and every fluid parcel is followed as it moves through space and time. Which kind of formulation is this?(a) Cartesian(b) Eulerian(c) Lagrangian(d) EuclidianI had been asked this question in examination.Enquiry is from Governing Equations topic in division Governing Equations of Fluid Dynamics of Computational Fluid Dynamics

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Right OPTION is (c) LAGRANGIAN

The explanation: In Lagrangian fluid flow specification, the fluid is subdivided into many PARTS and each of this part is followed. These parts are CALLED fluid parcels.

128.

A stationary model will result in ____________(a) Differential equation(b) Non-conservative equation(c) Conservative equation(d) Integral equationI got this question in a national level competition.My question is taken from Governing Equations in chapter Governing Equations of Fluid Dynamics of Computational Fluid Dynamics

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Right option is (C) Conservative EQUATION

To EXPLAIN: A stationary model has its POSITION coordinates independent of time. This gives a conservative equation without any SUBSTANTIAL derivative.

129.

Fluid velocity is very high. Will thermodynamic equilibrium be applicable to fluid flows?(a) Yes, the external conditions help them stay in thermodynamic equilibrium(b) No, their flow properties change abruptly(c) No, they are influenced by external conditions(d) Yes, the fluid can thermodynamically adjust itself quickly to be in thermodynamic equilibriumI had been asked this question in an online interview.This interesting question is from Equations of State in division Governing Equations of Fluid Dynamics of Computational Fluid Dynamics

Answer»

The correct answer is (d) YES, the fluid can thermodynamically adjust itself quickly to be in thermodynamic EQUILIBRIUM

To explain: The velocity of fluid FLOW is very high. This may affect their thermodynamic equilibrium. But, the particles are small ENOUGH to thermodynamically adjust themselves to equilibrium so quickly.