Explore topic-wise InterviewSolutions in .

(b) sp² hybridised

(i) (b) is chiral.

(ii) (a) 

(i) (b) Chiral.

(ii) (a) will underge S_N² reaction faster.

(a) 1-Bromo,4-Chloro But-2- yne 

(b) 3-Chloro-4-Methyl-hexane

(a) Chiorobenzene

The reaction of methane with excess of chlorine in the presence of sunlight give carbon tetrachioride as major product.

CH₄(Methane) + 4Cl₂ \(\overset{hv}{\longrightarrow}\) CCl₄(carbon tetrachloride) + 4HCl

(b) 2-Chioropropane

Correct answer is (c) CCl₄

The catalyst used in Darzen halogenation of alcohol is Pyridine.

In Finkeistein reaction, the mechanism followed is S_N2.

(v) Assertion and reason both are correct statements but reason is not correct explanation of assertion.

(i) Assertion and reason both are correct and reason is correct explanation of assertion.

(iv) Assertion is wrong but reason is correct statement. 

CH₃Br + alc. AgCN→  CH₃NC + AgBr

Methyl isocyanide.

The IUPAC name of CH₂CHCl is Chloroethene.

The IUPAC name of this compund is 1-Bromo-2, 2-dimethyipropane.

1, 4-dichloro-3-methylbenzene.

2- Phenylethanol.

(1) Unsaturation test with Br₂ water (2) Bayer’s test.

Nitroethane

Detailed Answer:

C₂H₅Cl + AgNO₂→ C₂H₅NO₂ + AgCl₂

Rotation due to one enantiomer is cancelled by another enantiomer.

Detailed Answer:

Racemic mixture contains d and I enantiomers in equal proportions. As the rotation due to one enantiomer is cancelled by equal and opposite rotation of another enantiomer, therefore, it is optically inactive.

Thionyl chloride is preferred for converting alcohol to haloalkane because the byproducts formed are all gases which escape into the atmosphere.

2 ROH +SOCl₂ → RCl +SO_2(g)+HCl_(g)

(ii) Thionyl chloride is best halogen carrier to convert alcohol to alkyl halide because it gives byproducts in gaseous state. Thus, we get pure alkyl halide in this reaction

(ii) (C) > (B) > (A)

Chloroform – ethyl alcohol and bleaching powder Iodoform – Sodium carbonate, ethyl alcohol and iodine

1. Iodoform test 

2. Iodoform test is given by those compounds which are having CH₃CO – group or CH₃CHOH group.

3. Ethyl alcohol gives Iodoform test becuase it has CH₃CHOH group.

In phenol, due to resonance, the carbon –oxygen bond has a partial double bond character and is difficult to break being stronger than a single bond. Therefore it can not be converted to chlorobenzene by reacting with HCl.

Due to difference in electronegativity between the carbon and halogen,the shared pair of electron lies closer to the halogen atom.

(ii) gem-dihalide

(i), (iv)

(i) A carbocation will be formed as an intermediate in the reaction.

(iv) Reaction proceeds through S_N1 mechanism

(i), (iii)

(i) The rate of reaction depends on the concentration of only (b).

(iii) Molecularity of reaction is one.

(i), (iv)

(i) 2-Bromopentane

(iv) Trichloromethane

1-Bromopentane

Detailed Answer:

1-Bromopentane as primary alkyl halides are most reactive for S_N²

(d) Fluoromethane

The structure of Vinyl iodide is CH₂ =CHI.

(a) 3-Chloropentane

The name of CFCl₃ is Freon - 11.

(iv) (a) < (b) < (c)

Correct answer is (b) Allyl

(iii) (a) < (c) < (b)

In haloarenes, there is double bond character b/w carbon and halogen due to resonance effect which makes him less reactive. 

In benzene, carbon being sp² hybridised which is smaller in size than sp³ present in haloalkanes . So C-Cl bond in aryl halides is shorter and stronger. 

2- Bromo -2- methylbutane < 2- Bromopentane < 1- Bromopentane

Correct answer is (d) C<A<B<D