InterviewSolution
Saved Bookmarks
InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
In a Bramah press a small force is used to spend a much larger force. This is accomplished byA. increasing the area of cross section of the pump piston.B. decreasing the area of cross section of the press piston.C. increasing the area of cross section of the press piston.D. increasing the long (weight) on the press piston. |
|
Answer» Correct Answer - C By increasing the area of cross section of the press piston, we can make a Bramah press exert a much larger force. |
|
| 2. |
Pressure at a point inside a liquid does not depend on theA. density of the liquidB. height of the liquid column above the point.C. acceleration due to gravityD. base area of the container. |
|
Answer» Correct Answer - D Pressure at a point inside a liquid does not depend on the base area of the container.s |
|
| 3. |
Arrange the following steps in proper sequence to determine the relative density of liquid by using a constant immersion hydrometer. (a) The test tube is made to float in the given liquid. (b) The weight of the test tube with lead shots in air is determined `(W_(1))`. ( c) The depth of the test tube immersed in water (h) is determined. (d) The test tube is made to float in water. (e ) Lead shots are added or removed from the test tube such that the test tube is immersed to the same depth (h) in the given liquid. (f) The relative density of the liquid is measured as `(W_(1))/(W_(1))`. (g) The test tube is taken out from the given liquid and its weight `(W_(2))` is measured.A. b d c a e g fB. b d c a e f gC. b g f e a c dD. b a d c e f g |
|
Answer» Correct Answer - A (a) The weight of the test tube with lead shots in air `(W_(1))` is measured. (b) The test tube is made to float in water. (c ) The depth of the test tube immersed in water (h) is determined. (d) The test tube is made to float in the given liquid. (e ) Lead shots are added or removed from the test tube so that the test tube is immersed to the same depth (h) in the given liquid. (f) The test tube is taken out from the liquid and its weight `(W_(2))` is measured. (g) The relative density of the liquid is measured as `(W_(2))/(W_(1))`. |
|
| 4. |
The weight of a constant immersion hydrometer is 15 gwt. When it is immersed in a liquid, few more lead shots were added to it so that it floats at the same depth as in water. If the weight of the hydrometer now is 20 gwt, find its relative density. |
|
Answer» `R.D.=("Weight of the tube for certain immersion in liquid")/("Weight of the tube for the same immersion in water")=(20 g_(wt))/(15 g_(wt))` R.D. =1.33 |
|
| 5. |
Calculate the depth of water at which a bubble of air would just float. Density of water `=1000 kg^(-3)` and density of air `= 1.29 kg ^(-3)`. Atmospheric pressure =`10^(5)` pa. |
|
Answer» Correct Answer - 0.287 m |
|
| 6. |
An air bubble rises up in water because,A. there is no gravity in water.B. pressure inside the bubble is less than the pressure outside it.C. the upthrust acting on the bubble is more than the weight of the bubble.D. air cannot dissolve in water. |
|
Answer» Correct Answer - C An air bubble rises up in water because the upthrust acting on the bubble is more than the weight of the bubble. |
|
| 7. |
A long metal rod of length I and density p is held vertically with its lower end touching sea-water of density `p_(0)`. Calculate the time in which the whole of the rod will sink into water and the velocity of the rod. Negtect water resistance and assume vertical postion of the rod throughout its motion . |
|
Answer» Correct Answer - `sqrt(2gl(1-(p_(0))/(2pg))), sqrt((pl)/(p_(0)g))cos^(-1)(1-(p_(0))/p)` |
|
| 8. |
The roof of a house blows out during a storm becauseA. the wind blows with high velocity under the roof.B. the weight of the roof is less than the weight of an equal volume of air.C. the wind blows with high velocity over the roof, causing an upthrust on the bottoms side.D. the wind blows with high velocity over the roof, causing low pressure under the roof. |
| Answer» Correct Answer - C | |
| 9. |
A tube 1.5 m long and closed at on end is half filled with mercry and is then inverted with its open ends just dipping into a mercury tough.Find the height of mercury in the tube if the reading of the barometer is 0.75 m. |
|
Answer» Correct Answer - `1 :3` |
|
| 10. |
A piece of nail sinks in water but a boat floats in it becauseA. there is no upthrust acting on the nail.B. a nail is heavier than a boat .C. a nail has a pointed end.D. upthrust acting on the nail is less than its weight. |
| Answer» Correct Answer - D | |
| 11. |
The volume of an air bubble becomes 8 times the original volume in rising from the bottom of a lake to its surface. If the barometice height is 0.76 m of mercury (density of mercury is `13.6 g cm^(-3) and g = 9.8 ms^(-2))` what is the depth of the lake ? |
|
Answer» Correct Answer - 73.67 cm,80 cm |
|
| 12. |
A man is a boat scoops out a stone from the bottom o f a lake and puts it in his boat. Will the level of water is the lake rise or fall ? |
|
Answer» Correct Answer - the level will rise |
|
| 13. |
A cube floating on mercry has 1/4 of its volume will remain immresed in mercury? (Relative density of mercury =13.6) |
|
Answer» Correct Answer - 0.19 |
|
| 14. |
In problem 43 , if the piece of ice contains a piece of cork . Will water spill out ? |
|
Answer» Correct Answer - No |
|
| 15. |
In problem 43 if the piece of ice contains a piece of brass, will the water spill out ? |
|
Answer» Correct Answer - yes |
|
| 16. |
A man ina boat drink water from alake. Will the level of water of the lake fall or rise ? |
|
Answer» Correct Answer - no charnge in water level |
|
| 17. |
A breaker filled with water up to the brim contanis a piece of ice floating in the water . Will water spill as ,ice melts ? [ Hint : In th eprocess, total mass (mass of ice + mass of water ) remains constant, show that `H=(M=m)/(A_(Pw))` wher M is the mass if water, m=mass if teh ice, A= area of cross - section of the veaker and `P_(w)` = desnity of water .] |
|
Answer» Correct Answer - NO |
|
| 18. |
A sperical iron shell floats almost, completely submerged submerged in water . If its outer diameter is 0.5 m and the relative density of iron is 8 m find the inner diameter. |
|
Answer» Correct Answer - 0.48 m |
|
| 19. |
A pressure exerted by mercury at the bottom of a container of area of cross section `2 cm^(2)` is 10 Pa. Determine the weight of the mercury in the container. |
|
Answer» Pressure `P=("Thrust(weight)")/("Area")` Thrust =Area `xx` pressure `=2xx10-4xx10=2xx10^(-3)N` Weight of mercury `=2xx10^(-3) N`. |
|
| 20. |
the barral of a common pump (pump for warer ) is 50 cm long and its bottom is 6 m from the surface of water. If the cross - section of the cross - section of the thinner pipe joining the barrel with water in well 3/14 of that of the barrel, find the height of the water in the pipe after the first stoke. (water barometer is 9 m of water . `A xx 1/2 + 3/14Axx (6-x) A(24/14 - 3/14x)A/14(25-3x)` final pressure =(9-x)m of water , now use `P_(1) V_(1) = P_(2) V_(2)`] |
|
Answer» Correct Answer - 1.3 m |
|
| 21. |
two cylinders A and B are of the same dimensions but of different materials. A alone flots in a liquid with half of its length immersed. When B is placed over A , the combination just floats in the same liquid . Compare the densities of the two cylinders A and B. |
|
Answer» Correct Answer - 0.31 m |
|
| 22. |
A cuboid has dimensions as shown. If the mass of the block is 2 kg, find the minimum and maximum pressure it exerts as the orientation of the body is changed. |
|
Answer» The weight exerted by the block = mg `=2 kg x 9.8 m s^(-2)=19.6 N` For the pressure to be minimum, the weight should act on maximum area and the block should be placed with the largest lateral surface on the bottom side. `P_("min")=(19.6 N)/(10xx20xx10^(-1))=980 N m^(-2)` For pressure to be maximum, the area on which the weight of the block acts, should be minimum and the block should be placed with the smallest lateral surface as the bottom side. `P_("min")=(19.6)/(5xx10xx10^(-4))=3920 N m^(-2)` |
|
| 23. |
The density of a given mass of a gas when 10 Pa pressure acts on it is `2 kg m^(-3)`. Calculate the density of the gas if the pressure is increased by 5 Pa at constant temperature. |
|
Answer» ` p alpha d` at constant temperature `(P_(1))/(d_(1))=(P_(2))/(d_(2)), (10)/(2)=(15)/(d)` `5=(15)/(d)` `d=3 kg m^(-3)` |
|
| 24. |
A vessel is filled with mercury to a hiegt of 0.9 m . Could the vessul be completely empited with the aid of a siphon ? If not , to what extent can it be empited ? (Barometer reading is 0.7 m mercury) |
|
Answer» Correct Answer - 0.7 m |
|
| 25. |
The pair of physical quantities having the same units areA. stress and pressure.B. thrust and pressure.C. weight and stress.D. weight and pressure. |
|
Answer» Correct Answer - A The force acting on a unit area is called stress. `therefore` The unit of stress and pressure are same. |
|
| 26. |
Arrange the following steps in proper sequence to determine the pressure exerted by a gas enclosed in a container using a manometer. (a)Connect one end of the manometer to the container filled with gas. (b)Both the limbs of the manometer are exposed to air, mercury level in both the limbs are equal due to atmospheric pressure. (c )Determine the difference in level of the mercury in both the limbs of the manometer (l). (d) If the level of the mercury in the limb connected to the container is above the mercury level in the limb exposed to air, the pressure of the gas in the container is determined as atmospheric pressure -l. (e ) If the level of the mercury in the limb connected to the container is below the mercury level in the limb exposed to air, the pressure of the gas in the container is determined as atmospheric pressure +l. (f) Note the level of the mercury in the limbs of the manometer.A. a b c e f eB. e b a d c fC. b a c f d eD. b c d a f e |
|
Answer» Correct Answer - C (a) Initially both the limbs of manometer are exposed to air, level of mercury in both the limbs are equal due to atmospheric pressure. (b) Connect one end of the manometer to the cylinder filled with gas. (c ) Determine the difference in the level of the mercury in both the limbs of the manometer. (d) Note the level of the mercury in the limbs of the manometer. (e ) If the level of the mercury in the limb connected to the container is above the mercury level in the limb exposed to air, the pressure of the gas in the container is determined as atmospheric pressure - l. (f) If the level of the mercury in the limb connected to the container is below the mercury level in the limb exposed to air, the pressure is determined as atmospheric Pressure +l. |
|
| 27. |
A cylindrical object of the area of cross section `5 cm^(2)` floats (lateral side vertical) in water filled in a cylindrical container of the area of cross section `15 cm^(2)`. When the object is placed in water the level of the water in the container rises by 2 cm and the len. |
|
Answer» (i) `(d_(0))/(d_(w))=("voulume of liquid displaced")/("Volulme of the object")` `=("rise in level") xx (A_(c )-A_(0))/(A_(0)xx(1_(0)))` (ii) `0.6 g cm^(-s)` |
|
| 28. |
Which one of the following statements is true ?A. The weight of a substance in air is always less than its weight in water.B. The mass of a substance is equal to the mass of an equal volume of water.C. The weight of a substance in water is always greater than its weight in some other liquid.D. The weight of a substance in water is always less than its weight in air. |
| Answer» Correct Answer - D | |
| 29. |
Which one of the following statements is true ?A. Water forms concave meniscus on account of high cohesive forces.B. Mercury forms concave meniscus on account of more adhesive force than the cohesive forces.C. Water forms convex meniscxus on account of high adhesive forces than the cohesive forces.D. Mercury forms convex meniscus on account of more cohesive force than adhesive force. |
| Answer» Correct Answer - D | |
| 30. |
the base of cylindrical vessel is hemesphericl in shape with rdius R . If the vessel is filled with liquid of density p up to a height h. calculate the thrust on the base. |
|
Answer» Correct Answer - `2pi R^(2) pg(h/4 -R/3)` |
|
| 31. |
an oil tanker moving with speed `v` decelerates uniformly and comes to a stop within a distance s . Find the pressure due to the oil to the back and front walll of the tanker during the period of deceleration. Assume the taker to be a parallelpiped of length l, width b and heigth lt and the density of the oil to be p. |
|
Answer» Correct Answer - `F_(1)=1/2pbh((gh+v^(2)l)/(4s))and F_(2)=1/2 pbh(gh-(V^(2)l)/(4s))` |
|
| 32. |
The weight of the liquid displaced by a body when the body is immersed in it is called,A. apparent weightB. upthrustC. lateral pressureD. relative density of the body |
| Answer» Correct Answer - B | |
| 33. |
Two non - viscous, incompressible and immiscible liquids of densities (rho) and (1.5 rho) are poured into the two limbs of a circular tube of radius ( R) and small cross section kept fixed in a vertical plane as shown in fig. Each liquid occupies one fourth the cirumference of the tube. . (a) Find the angle (theta) that the radius to the interface makes with the verticles in equilibrium position. (b) If the whole is given a small displacement from its equilibrium position, show that the resulting oscillations are simple harmonic. Find the period of these oscillations. |
|
Answer» Correct Answer - `theta=(tan^(-1))(1)/(5) = 11.3 ^(@) T=2pisqrt((2.5 pi R)/(g))` |
|
| 34. |
Gases do not have rigidity. Select the reason from the following .A. The cohesive force is negligibleB. The adhesive force is very highC. The cohesive force is very highD. None of the above |
|
Answer» Correct Answer - A Cohesive force in gas is negligible because of this the molecules in gases are largely separated. |
|
| 35. |
If `F_(CS), F_(CL), F_(CG)` represents cohesive force of solids, cohesive force of liquid and cohesive force of gases, then the choose the correct answer.A. `F_(CS)=F_(CL)= F_(CG)`B. `F_(CS) gt F_(CL) gt F_(CG)`C. `F_(CS) lt F_(CL) lt F_(CG)`D. `F_(CS) gt F_(CL) = F_(CG)` |
|
Answer» Correct Answer - B `F_(CS) gt F_(CL) gt F_(CG)` As the molecules is solids are closely packed compared to liquid and compared to gases, the cohesive force of solid `gt ` cohesive force of liquid `gt` cohesive in gas. |
|
| 36. |
Similar objects are dropped into two different liquids A and B. The displacement of the objects in A and B in 5s is `S_(1) " and " S_(2)`, respectively. If density of the liquid A is greater than the density of the liquid B, which among the following relation is correct ?A. `S_(1) = S_(2)`B. `S_(1) gt S_(2)`C. `S_(1) lt S_(2)`D. Cannot be determined |
|
Answer» Correct Answer - C The net acceleration in B is greater than the net acceleration in A. Therefore, distance travelled in B is greater than the distance travelled in `A. therefore S_(1) lt S_(2)`. |
|
| 37. |
A convex meniscus is formed when the cohesive force is ____ the adhesive force.A. equal toB. less thanC. greater thanD. less than or equal to |
|
Answer» Correct Answer - C A convex meniscus is formed when the cohesive force greater than the adhesive. |
|
| 38. |
A cuboid of dimensions `3 m xx 2m xx 1m` is placed on a surface such that the face with maximum surface area is in contact. If the weight of the cuboid is `1kg_(wt)`, the pressure exerted by it on the surface is _____. (take `g=10 m s^(-2))`. |
| Answer» Correct Answer - `(5)/(3) pa` | |
| 39. |
A liquid drop takes spherical shape due to surface tension. |
| Answer» Correct Answer - True | |
| 40. |
A beaker containing water is placed on the pan of a balance which shows a reading of 200 g. A lump of sugar weighing 75 g and of volume 30 cc is now suspended inside the water from an external support without touching any part of the beaker. (a) what will be the reading just when the lump of sugar is immersed ? how will the reading change as time passes ? (b) what will be the initial reading if the lump is simply dropped gently into the beaker and how will the reading change? |
|
Answer» Correct Answer - (a)230 g reading will increase up to 275 g (b) 275 g , no change in weight |
|
| 41. |
An object of weight `500 kg_(wt)` is lifted by using a hydraulic press. The radii of the cross sections of the pump piston and press piston are 10 cm and 20 cm, respectively. Calculate the effort required to lift the object. Calculate the displacement of the load if the effort is moved through a distance of 20 cm. |
|
Answer» (i)` ("Load")/("effort")=(("radius of the lift pistion")^(2))/(("radius of the press piston")^(2))` Work done on the load= Work done by the effort. (ii) 5 cm. |
|
| 42. |
Nagarjun sagar dam is filled water till a height of 127 metres. If the mass of water per cubic centimeter is one gram, then find the difference in pressures acting at the following two points. (i) Point exactly at a depth half that of the dam. (ii) Point at the bottom of the dam. |
|
Answer» Height/depth of dam=127 metres. Density (d) `=("Mass")/("Volume")=(1 "gram")/(1 cm^(3))=1 g cm^(-3)=1000 kg m^(-3)` (a) Height of the point =`("depth")/(2)=(127)/(2)=63.5 m` Pressure at a point`(P_(a))=hdg` `=63.5xx10^(3)xx10` `=635xx10^(3)` pascals (b) Depth of the point =127 m Pressure at a point `(P_(b))=127xx10^(3)xx10` `=1270xx10^(3)` pascals. Difference in pressures `=P_(b)-P_(a)=(1270-635)xx10^(3)` `=635xx10^(3) Pa` |
|
| 43. |
Force acting on a unit area is called pressure. |
| Answer» Correct Answer - False | |
| 44. |
Two spheres of volume 250 cc each but of relative densities 0.8 an d 1.2 are connected by a string and the combination is immersed in a liquid. Find the tension T in the string. `(g=10m//s^(2))` |
|
Answer» Correct Answer - 0.49 N |
|
| 45. |
If x is the weight of an object in air and Y is its weight when completely immersed in water, then `(X)/(X-Y)` |
| Answer» Correct Answer - Relative density | |
| 46. |
In the expression buoyant force or upthrust `=V xx rho xx g rho` is the density of the liquid displaced. |
| Answer» Correct Answer - True | |
| 47. |
A common hydrometer has a small portion of its bulb rubbed off due to fequent use. In consquence when placed in wter it appears to indicate the sp . Gravity of water 1.002 find the fraction fo its weight lost dure to frquent use . |
|
Answer» Correct Answer - `1/501` |
|
| 48. |
Wind blowing horizontally over a paper makes it fly away. This can be explained on the basis of Bernoullis principle. |
| Answer» Correct Answer - True | |
| 49. |
The hieght of a mercury barometer is 75.6 cm . the baromter tube has cross -section of `1cm ^(2)` and the volume of the enclosed space above the mercury surface is 10 cc. one cc of air at atmospheric pressure is introduced into the tube. Find the change in the reading of the barometer. |
|
Answer» Correct Answer - 2600 m |
|
| 50. |
the height of a mercury barometer is 76 cm at sea level and 50 cm at the top of a hill. Determine the height of the hill. (Densities of air and mercury are `1.36 kg m^(-3) and 13.6 xx 10^(3) kg m^(-3))` hint : Difference of pressure =76 cm - 50 cm = 26 cm of mercury ` 0.26 xx 9.8 xx 13.6 xx 10^(3) Nm^(-2)` pressure due to h metre of air = `h xx 9.8 xx 1.36`] |
|
Answer» Correct Answer - 74.99 cm |
|