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51.

How Many Seconds Will A 500 M Long Train Take To Cross A Man Walking With A Speed Of 3 Km/hr In The Direction Of The Moving Train If The Speed Of The Train Is 63 Km/hr?

Answer»

Speed of train RELATIVE to man = 63 - 3 = 60 km/hr.

= 60 * 5/18 = 50/3 m/sec.

Time TAKEN to PASS the man = 500 * 3/50 = 30 sec.

Speed of train relative to man = 63 - 3 = 60 km/hr.

= 60 * 5/18 = 50/3 m/sec.

Time taken to pass the man = 500 * 3/50 = 30 sec.
Discussion
52.

A Train Moves Fast A Telegraph Post And A Bridge 264 M Long In 8 Sec And 20 Sec Respectively. What Is The Speed Of The Train?

Answer»

Let the LENGTH of the train be x m and its speed be y m/sec.

Then, x/y = 8 => x = 8Y

(x + 264)/20 = y

y = 22

Speed = 22 m/sec = 22 * 18/5 = 79.2 km/hr.

Let the length of the train be x m and its speed be y m/sec.

Then, x/y = 8 => x = 8y

(x + 264)/20 = y

y = 22

Speed = 22 m/sec = 22 * 18/5 = 79.2 km/hr.
Discussion
53.

A Train Speeds Past A Pole In 15 Sec And A Platform 100 M Long In 25 Sec, Its Length Is?

Answer»

Let the LENGTH of the train be X m and its speed be y m/sec.

Then, x/y = 15 => y = x/15

(x + 100)/25 = x/15 => x = 150 m.

Let the length of the train be x m and its speed be y m/sec.

Then, x/y = 15 => y = x/15

(x + 100)/25 = x/15 => x = 150 m.
Discussion
54.

A 300 M Long Train Crosses A Platform In 39 Sec While It Crosses A Signal Pole In 18 Sec. What Is The Length Of The Platform?

Answer»

Speed = 300/18 = 50/3 m/sec.

Let the length of the platform be x METERS.

Then, (x + 300)/39 = 50/3

3X + 900 = 1950 => x = 350 m.

Speed = 300/18 = 50/3 m/sec.

Let the length of the platform be x meters.

Then, (x + 300)/39 = 50/3

3x + 900 = 1950 => x = 350 m.
Discussion
55.

A Train Passes A Station Platform In 36 Sec And A Man Standing On The Platform In 20 Sec. If The Speed Of The Train Is 54 Km/hr. What Is The Length Of The Platform?

Answer»

Speed = 54 * 5/18 = 15 m/sec.

Length of the TRAIN = 15 * 20 = 300 m.

Let the length of the PLATFORM be x m . Then, 

(x + 300)/36 = 15 => x = 240 m.

Speed = 54 * 5/18 = 15 m/sec.

Length of the train = 15 * 20 = 300 m.

Let the length of the platform be x m . Then, 

(x + 300)/36 = 15 => x = 240 m.
Discussion
56.

66% Of 33.33% Of 66.66% Of ? = 30

Answer»

16.66% of 33.33% of 66.66% of x = 30

 = 1/6 of 1/3 of 2/3 of x = 30 

=> (30 * 6 * 3 * 3)/2 => x = 810

16.66% of 33.33% of 66.66% of x = 30

 = 1/6 of 1/3 of 2/3 of x = 30 

=> (30 * 6 * 3 * 3)/2 => x = 810
Discussion
57.

12.5 + 10 1/4 Of 100 ÷ 10% Of 10 = ?

Answer»

12.5 + 10 1/4 of 100 ÷ 10% of 10

= 12.5 + 41/4 of 100 ÷ 10/100 of 10

= 12.5 + 41(25) ÷ 1 = 12.5 + 1025 = 1037.5.

12.5 + 10 1/4 of 100 ÷ 10% of 10

= 12.5 + 41/4 of 100 ÷ 10/100 of 10

= 12.5 + 41(25) ÷ 1 = 12.5 + 1025 = 1037.5.
Discussion