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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1351. |
A 0.1M solution of sodium acetate was prepared. The `K_(h)=5.6xx10^(-10)` . Then :A. The degree of hydrolysis is `7.48xx10^(-6)`B. the `[OH^(-)]` concentration is `7.48xx10^(-3)M`C. the `[OH^(-)]` concentration is `7.48xx10^(-6)M`D. the pH is approximately 8.88 |
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Answer» Correct Answer - c,d |
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| 1352. |
The following acids have been arranged in the order of decreasing acid strength. Identify the correct order ClOH(I), BrOH (II), IOH (III)A. `I gt II gt III`B. `II gt I gt III`C. `III gt II gt I`D. `I gt III gt II` |
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Answer» Correct Answer - A Among oxyacids of the same type formed by different elements, acidic nature increases with increasing electronegativity. In general, the strength of oxyacids decreases as we go down the family in the periodic table. `HOCl (I) gt HOBr(II) gt HOI (III)` |
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| 1353. |
To a solution of `0.1M Mg^(2+)` and `0.8M NH_(4)CI`, and equal volume of `NH_(3)` is added which just gives precipitates. Calculate `[NH_(3)]` in solution. `K_(sp) of Mg(OH)_(2) = 1.4 xx 10^(-11)` and `K_(b) of NH_(4)OH = 1.8 xx 10^(-5)`. |
| Answer» Correct Answer - `0.3710M;` | |
| 1354. |
The pH of an aquoeus solution of `H_(2)O_(2)` is `6.0` . Some chlorine is bubbled through this solution. The pH of the resulting solution will beA. `6`B. `7`C. Less than `6`D. More than `7` |
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Answer» Correct Answer - C `underset(W.A)(H_(2)O_(2)) + Cl_(2) rarr 2underset(S.A)(HCl + O_(2))` |
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| 1355. |
Which is the strongest acid in the following ?A. `H_(2)SO_(4)`B. `HClO_(3)`C. `HClO_(4)`D. `H_(2)SO_(3)` |
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Answer» Correct Answer - C The strength of oxyacids can also be decided with the help of the oxidation number of central atom. Higher the oxidation number of central atom, more acidic is the oxyacid. `H_(2)overset(+6)(SO_(4)),Hoverset(+5)(ClO_(3)),Hoverset(+7)(ClO_(3)),Hoverset(+7)(ClO_(4)),H_(2)overset(+4)(SO_(3))` Order of acidic nature `HClO_(4)gt H_(2)SO_(4)gt HClO_(3)gt H_(2)SO_(3)` Since, in `HClO_(4)`, oxidation number of Cl is highest, so, `HClO_(4)` is the strongest acid among the given acids. |
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| 1356. |
`CH_(3)COOH` does not act as an acid in presence of A) `HCl` , B) `Na_(2)CO_(3)` , C) `H_(2)O` , D) `C_(6)H_(6)`A. All are wrongB. A and D correctC. A and B are correctD. C and D correct |
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Answer» Correct Answer - B HCl is strong acid than `CH_(3)COOH` and `C_(6)H_(6)` is non polar solvent |
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| 1357. |
The strongest base among the following isA. `Cl^(-)`B. `CH_(2)COO^(-)`C. `HSO_(4)^(-)`D. `NO_(3)^(-)` |
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Answer» Correct Answer - B Weak acid give strong conjugate base |
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| 1358. |
An acid is a compound which furnishes (Bronsted-Lowery concept)A. An electronB. A protonC. An electron and a protonD. None of the above |
| Answer» Correct Answer - B | |
| 1359. |
The Bronsted acids in the reversible reaction are `HCO_(3)^(-)(aq.) + OH^(-) (aq.) CO_(3)^(2-)(aq.) + H_(2)O`A. `OH^(-)` and `CO_(3)^(2-)`B. `OH^(-)` and `H_(2)O`C. `HCO_(3)^(-)` and `H_(2)O`D. `HCO_(3)^(-)` and `CO_(3)^(2-)` |
| Answer» Correct Answer - C | |
| 1360. |
The pH of the `10^(-3)M NH_(4)OH(Kb = 10^(-5))` isA. 3B. 11C. 10D. 4 |
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Answer» Correct Answer - C `[OH^(-)] = sqrt(kb.c)` `P^(OH) = -"log"[OH^(-)]` `P^(H) + P^(OH) = 14` `P^(H) = 14 - 4 = 10` |
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| 1361. |
The `P^(H)` of `0.01 M` solution of acetic acid is `5.0` What are the values of `[H^(+)]` and `Ka` respectively ?A. `2 xx 10^(-4)M, 2 xx 10^(-8)`B. `1 xx 10^(-5) M, 1 xx 10^(-9)`C. `1 xx 10^(-5) M, 1 xx 10^(-8)`D. `1 xx 10^(-4) M, 1 xx 10^(-6)` |
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Answer» Correct Answer - C `[H^(+)] = 10^(-PH) = 10^(-5)` `= sqrt(Ka xx c)` `(":. C = 0.01 M)` `rArr Ka = ([H^(+)]^(2))/(C) = (10^(-10))/(10^(-2)) = 10^(-8)` |
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| 1362. |
Which acid is the strongest ?A. `H_3BO_3`B. `H_3PO_4`C. `H_2SO_3`D. `HClO_3` |
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Answer» Correct Answer - D |
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| 1363. |
Which of the following is used as a differentiating solvent for acids,A. `CH_(3)COOH`B. `NH_(3)`C. `H_(2)O`D. `HCl_(4)` |
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Answer» Correct Answer - A Weak acids used as a differentiating solvents for acids |
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| 1364. |
Which of the following is not a Bronsted acidA. Bisulphate ionB. Nitride ionC. Nitric acidD. Hydroxide ion |
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Answer» Correct Answer - B `H^(+)` donor is boronsted acid |
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| 1365. |
Which one is the strongest electrolyte in the followingA. NaClB. `CH_(3)COOH`C. `NH_(4)OH`D. `C_(6)H_(12)O_(6)` |
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Answer» Correct Answer - A NaCl, being a salt, is a strong electrolyte. |
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| 1366. |
Which of the following is acidic in nature ?A. `Be(OH)_(2)`B. `Mg(OH)_(2)`C. `B(OH)_(3)`D. `Al(OH)_(3)` |
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Answer» Correct Answer - C `Mg(OH)_(3)` is distinctly basic, `Be(OH)_(2)` and `Al(OH)_(3)` are amphoteric. Only `B(OH)_(3)` is distinctly acidic. |
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| 1367. |
The degree of dissociation of `0.1N CH_(3)COOH` is `(K_(a)= 1xx10^(-5))`A. `10^(-6)`B. `10^(-7)`C. `10^(-3)`D. `10^(-2)` |
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Answer» Correct Answer - D `alpha = sqrt((Ka)/(C))` `= sqrt((1 xx 10^(-5))/(0.1))` `= sqrt(10^(-4)) = 10^(-2)` |
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| 1368. |
If `K_(sp)` for `HgSO_(4)` is `6.4 xx 10^(-5)`, then solubility of the salt isA. `8 xx 10^(-3)`B. `8 xx 10^(-6)`C. `6.4 xx 10^(-5)`D. `6.4 xx 10^(-3)` |
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Answer» Correct Answer - A `HgSO_(4)` of `K_(sp) = S^(2)` `S = sqrt(K_(sp)) , S = sqrt(6.4 xx 10^(-5)) , S = 8 xx 10^(-3)` m/l. |
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| 1369. |
How much water must be added to `300 mL` of a `0.2M` solution of `CH_(3)COOH` for the degree of dissociation of the acid to double ? ( Assume `K_(a)` of acetic is of order of `10^(-5)M)`A. `900 ml`B. `300ml`C. `600 ml`D. `1200ml` |
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Answer» Correct Answer - 1 Initially degree of dissociation `alpha=sqrt((K_(a))/(C))` Now degree of dissociation, `alpha_(1)=2alpha=sqrt((4K_(a))/(C))=sqrt((K_(a))/(C_(1)))` so `" "C_(1)=(C)/(4)" "rArr" "` Hence we have `300xx0.2rArrV_(1)xx(0.2)/(4)" "`so `V_(f)=1200ml` Hence water added `=1200-300=900ml` |
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| 1370. |
If solubility product of `HgSO_(4)` is `6.4 xx 10^(-5)`, then its solubility isA. `8 xx 10^(-3)` mole/litreB. `6.4 xx 10^(-5)` mole/litreC. `6.4 xx 10^(-3)` mole/litreD. `2.8 xx 10^(-6)` mole/litre |
| Answer» Correct Answer - A | |
| 1371. |
What is the `pH` of `0.01 M` glycine solution? For glycine, `K_(a_(1))=4.5xx10^(-3)` and `K_(a_(2))=1.7xx10^(-10)` at `298 K`A. `3.0`B. `10.0`C. `6.1`D. `7.1` |
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Answer» Correct Answer - D `K = K_(a_(1)) xx K_(a_(2)) = 4.5 xx 10^(-3) xx 1.7 xx 10^(-10)` `= 7.65 xx 10^(-13)` `= 76.5 xx 10^(-14)` `[H^(+)] = sqrt(KC) = sqrt(76.5 xx 10^(-14) xx 10^(-2))` `= sqrt(76.5 xx 10^(-16))` `[H^(+)] = 8.7 xx 10^(-8)` `P^(H) = -"log"_(10) [8.7 xx 10^(-8)]` `= 8 - "log" 8.7, = 8 - 0.9395` `P^(H) = 7.1` |
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| 1372. |
What is the pH of 0.01 M glycine solution? For glycine `K_(a_(1)) = 4.5 xx 10^(-3)` and `Ka_(2) = 1.7 xx 10^(-10)` at 298 KA. `3.0`B. `10.0`C. 6.1D. 7.2 |
| Answer» Correct Answer - C | |
| 1373. |
The `p^(H)` of a 1 lit solution is 2. It is diluted with water till it becomes `4`. How many liters of water is added?A. `99`B. `9`C. `999`D. `9.9` |
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Answer» Correct Answer - A `p^(H) = 2 , (H^(+)) = 10^(-2)` `10^(-2) xx 1 = 10^(-4) xx V` `V_(2) = (10^(-2))/(10^(-4)) = 10^(2) = 100` Use of water `= V_(2) - V_(1)` `= 100 - 1 = 99` |
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| 1374. |
The sum of bascities of `H_(3)PO_(4), H_(3)PO_(3)` and `H_(3)PO_(2)` is |
| Answer» Correct Answer - 6 | |
| 1375. |
The hydrogen ion concentration in pure water is `10^(-7) g`. Ions/lit. An aqueous solution will be acidic , if its hydrogen ions concentration in g. ions/lit, isA. `10^(-6)`B. `10^(-7)`C. `10^(-8)`D. `10^(-9)` |
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Answer» Correct Answer - A If the solution is acidic `[H^(+)] gt 10^(-7)` |
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| 1376. |
`Ksp` of `M(OH)_(2)` is `5 xx 10^(-16)` at `25^(0)C`. The pH of its saturated solution at `25^(0)C` is |
| Answer» Correct Answer - 9 | |
| 1377. |
A solution containing `10^(-3) M Sr(C1O_(4))_(2)` and `0.05 M KNO_(3)` was found to have only `75%` of its strontium in the uncomplexed `Sr^(2+)` form, the rest being `Sr(NO_(3))^(o+)`. Calcualate the `K_(1)` for complexation reaction: `Sr^(2+) + NO_(3)^(Theta) rarr Sr (NO_(3))^(Theta)` |
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Answer» `Sr^(2+)` forms a very unstable complex with `NO_(3)^(Theta)`. `{:(,Sr^(2+)+,NO_(3)^(Theta)rarr,Sr(NO_(3))^(Theta),),("Initial",rArr10^(-3)=0.001,0.05,0,),("used up",rArr0.00025,0.00025,,),("Ateq",rArr(0.001xx75)/(100),,,),(,=0.0075,0.05-0.00025,0.0025,),(,,~~0.05,,):}` `K_(1) = ([Sr(NO_(3)^(o+))])/([Sr^(2+)][NO_(3)^(Theta)]) = (0.00025)/((0.00075)(0.05)) = 6.7` |
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| 1378. |
338 mL clear saturated solution of `AgBrO_(3)` requires just `30.4mL of H_(2)S_((g))` at `23^(@)C` and 748 mm Hg to precipitate all the `Ag^(+)` ions `Ag_(2)S`. What will be `K_(SP)of AgBrO_(3)` ? |
| Answer» Correct Answer - `5.29xx10^(-5);` | |
| 1379. |
`25.0 mL` clear saturated solution of `PbI_(2(aq.))` requires `13.3mL of AgNO_(3(aq.))` solution for complete precipitation. What is molarity of `AgNO_(3)` solution ? `(K_(SP) "of Pb"I_(2)` is `7.1xx10^(-9))` |
| Answer» Correct Answer - `4.55xx10^(-3)`; | |
| 1380. |
`K_(sp)` of AgCl,`Ag_(2)CrO_(4)` and AgBr are `10^(-10),10^(-13)` and `10^(-12)` respectively. If to a solution of 0.1 M each of `Cl^(-), CrO_(4)^(2-)` and `Br^(-)` ions, `AgNO_(3)` is added slowly, which will precipitate first :A. AgClB. `Ag_(2)CrO_(4)`C. AgBrD. All simultaneously |
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Answer» Correct Answer - c |
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| 1381. |
The `K_(sp)` of `Ag_(2)CrO_(4), AgCl, AgBr` and AgI are respectively, `1.1 xx 10^(-12), 1.8 xx 10^(-10), 5.0 xx 10^(-13), 8.3 xx 10^(-17)`. Which one of the following salts will precipitate last if `AgNO_(3)` solution is added to the solution containing equal moles of NaCl, NaBr, NaI and `Na_(2)CrO_(4)`A. AgClB. AgBrC. `Ag_(2)CrO_(4)`D. AgI |
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Answer» Correct Answer - C `{:(K_(sp) " of " Ag_(2)CrO_(4),,= 1.1 xx 10^(-12)),(K_(sp) " of " AgCl,,= 1.8 xx 10^(-10)),(K_(sp) " of " AgBr,,= 5.0 xx 10^(-13)),(K_(sp) " of "AgI,,= 8.3 xx 10^(-17)),([Ag^(+)]^(2)[C],,= 1.1 xx 10^(-12)):}` `[Ag^(+)] = sqrt((1.1 xx 10^(-12))/([C]))` If we take [C] = 1 then the maximum requirement of `[Ag^(+)]` will be case of `Ag_(2)CrO_(4)` |
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| 1382. |
In 1L saturated solution of `AgCI [K_(sp) (AgCI) = 1.6 xx 10^(-10)], 0.1 mol` of `CuCI [K_(sp)(CuCI) = 1.0 xx 10^(-6)]` is added. The resultant concentration of `Ag^(+)` in the solution is `1.6 xx 10^(-x)`. The value of "x" is. |
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Answer» Correct Answer - 7 |
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| 1383. |
In 1 L saturated solution of `AgCl[K_(sp) (AgCl) = 1.6 xx 10^(-10)]` 0.1 mol of CuCl `[K_(sp)(CuCl) = 1.0 xx 10^(-6)]` is added. The resultant concentration of `Ag^(+)` in the solution is `1.6 xx 10^(-x)`. The value of "x" is |
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Answer» Correct Answer - 7 `{:(AgCl(s)hArr,"Ag"^(+),+"Cl"^(-),K_(sp)(AgCl) = 1.6 xx 10^(-10)),(,Z,Z+Y,),(CuCl(s) hArr,Cu^(+),+Cl^(-),K_(sp)(CuCl) = 10^(-6)),(,Y,Z+Y,):}` `Z(Z+Y) = 1.6 xx 10^(-10)` `Y(Z+Y) = 10^(-6)` `rArr (Z + Y)^(2) = 1.6 xx 10^(-10) + 10^(-6) rArr (Z + Y)^(2) ~~ 10^(-6)` `rArr Z + Y = 10^(-3) rArr Z(Z + Y) = 1.6 xx 10^(-10)` `rArr Z xx 10^(-3) = 1.6 xx 10^(-10) rArr Z = 1.6 xx 10^(-7)` `rArr 1.6 xx 10^(-x) = 1.6 xx 10^(-7) rArr x = 7`. |
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| 1384. |
`K_(sp)` of AgCl is `1.96xx10^(-10)`. 100 mL of saturated AgCl solution is titrated with `1xx10^(-5) M NH_(4)SCN`. Volume of `1xx10^(-5) M NH_(4)SCN` required to precipitate all `Ag^(+)` from saturated AgCl solution as AgSCN is :A. 140 mLB. 260 mLC. 70 mLD. 200 mL |
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Answer» Correct Answer - a |
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| 1385. |
To a saturated solution of AgCl containing sufficient amount of solid AgCl, `NH_(3)` is gradually added such that its concentration becomes `0.2M` Which of the following options containing concentration of ion is correct ? [Given" `K_(sp)` of `AgCl=10^(-10),K_(f_(1))` of `Ag(NH_(3))_(2)^(+)=10^(3),K_(f)` of `Ag(NH_(3))_(2)^(+)=10^(8)`]A. `[Cl^(-)]=2xx10^(-2)M`B. `[Ag(NH_(3))_(2)]^(+)=2xx10^(-2)M`C. `[Ag(NH_(3))]^(+)=2xx10^(-2)M`D. `[Ag^(+)]=5xx10^(-9)M` |
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Answer» Correct Answer - a,b,c,d |
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| 1386. |
100 mL of 0.5 M hydrazoic acid `(N_3H, K_a=3.6xx10^(-4))` and 400 mL of 0.1 M cyanic acid `(HOCN, K_a=8xx10^(-4))` are mixed .Which of the following is true for final solution ?A. `[H^(+)]=10^(-2)M`B. `[N_(3)^(-)]=3.6xx10^(-3)M`C. `[OCN^(-)]=6.4xx10^(-3)M`D. `[H^(+)]=1.4xx10^(-2)M` |
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Answer» Correct Answer - a,b,c |
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| 1387. |
Equal volumes of following solutions are mixed. In which case the pH of resulting solution will be average value of pH of two solutions?A. Aqueous `HCl` of pH=2, aqueous `NaOH` of pH=12B. Aqueous HCl of pH=2, aqueous HCl of pH=4C. Aqueous `NaOH` of pH=12, aqueous `NaOH` of pH=10D. Aqueous `CH_(3)COOH` of pH=5, aqueous `NH_(3)` of pH=9. `[K_(a)(CH_(3)COOH)=K_(b)(NH_(3))]` |
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Answer» Correct Answer - a,d |
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| 1388. |
If `K_(a_(1))gtK_(a_(2))` of `H_(2)SO_(4)` are `10^(-2)` and `10^(-6)` respectively then:A. `K_(a_(1))` and `K_(a_(2))` because it is easy to abstract `H^(+)` from `H_(2)SO_(4)` and less easy to abstract `H^(+)` from `HSO_(4)^(-)`B. `K_(a_(1))` and `K_(a_(2))` may be measured in acetic acid.C. `K_(a_(1))` and `K_(a_(2))` are measured in `H_(2)O`.D. the `H^(+)` ion conc of `0.01MH_(2)SO_(4)` will less than `0.02M`. |
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Answer» `H_(2)SO_(4)` is a strong acid and it completely dissociated in `H_(2)O` .Hence it `K_(a_(1))` and `K_(a_(2))` are determine in `CH_(3)COOH`. Also `H(2)SO_(4)` is neutral while `H_(2)SO_(4)^(-)` is neutral while `HSO_(4)^(-)` because the `-ve `change has more affinity towards `H^(+)` ion .Hence choices `A` and `B` are correct while `C` is incorrect. |
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| 1389. |
Statement : The dissociation constants of polyrotic acid are in the order `K_(1)gtK_(2)gtK_(3)`. Explanation : The `[H^(+)]` furnished in first step of dissociation exerts common ion effect to reduce the secend dissociation so on.A. S is correct but E is wrong.B. S is wrong but E is correc.C. Both S and E are correct and E is correct explanation of S.D. Both S and E are correct but E is correct explanation of S. |
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Answer» Correct Answer - C Explanation is correct reason for statement. |
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| 1390. |
If `K_(a_(1))gtK_(a_(2))` of `H_(2)SO_(4)` are `10^(-2)` and `10^(-6)` respectively then:A. `K_(a_(1))gtK_(a_(2))` because it is easy to abstract `H^(+)` from `H_(2)SO_(4)` and less easy to abstract `H^(+)` from `HSO_(4)^(-)`B. `K_(a_(1))` and `K_(a_(2))` may be measured in acetic acidC. `K_(a_(1))` and `K_(a_(2))` are measured in `H_(2)O`D. the `H^(+)` ion conc. Of `0.01M` `H_(2)SO_(4)` will be less than `0.02`M |
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Answer» Correct Answer - a,b |
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| 1391. |
A gas absorbs 400J of heat and expands by `2 xx 10^(-3) m^(3)` against a constant pressure of `10^(5)Nm^(-2)`. The cahnge in internal energy of gas isA. zeroB. `197.4 J`C. `-600 J`D. `+200J` |
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Answer» Correct Answer - D `Delta E=q+W,q=+400J` `W=-PDeltaV=10^(5)Nm^(-2)xx10^(-3)m^(3)` `=200Nm` as `1J=Nm:. Delta E =+400-200=200`J |
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| 1392. |
Nature of `0.1M` solution of potassium bisulphate isA. AcidicB. AlkalineC. NeutralD. Amphoteric |
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Answer» Correct Answer - A `KHSO_(4)` as one replaceable hydrogen atom |
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| 1393. |
The solubility of a saturated solution of calcium fluoride is `2xx10^(-4)` mol/L. Its solubility product isA. `12 xx 10^(-2)`B. `14 xx 10^(-4)`C. `22 xx 10^(-11)`D. `32 xx 10^(-12)` |
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Answer» Correct Answer - D `CaF_(2) hArr underset(2 xx 10^(-4))(Ca^(2+))+underset(2 xx 2 xx 10^(-4))(2F^(-))` Solubility Product `=[Ca^(2+)][F^(-)]^(2)` `=[2 xx 10^(-4)][2 xx 2 xx 10^(-4)]^(2)` `=32 xx 10^(-12)` |
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| 1394. |
There are three acid-base indicators: methy`1` orange (end point at `pH = 4)`, bromothymol blue (end point `pH = 7)`, and phenolphthalein (end point at `pH = 9)`. Which of the following would you select for the titrations? a. `H_(2)SO_(4)` with `KOH` b. `KCN` with `HCI` c. `NH_(3)` with `HNO_(3)` d. `HF` with `NaOH` |
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Answer» a. Any `(S_(A) vs S_(B))` b. Methy`1` orange `(S_(A) vs salt` of `W_(A)//W_(B))` c. Methy`1` orange `(S_(A) vs W_(B))` d. Phenolphthalein `(W_(A)vs S_(B))` |
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| 1395. |
For a series of indicators, the colour and `pH` range over which colour change takes place are as follows: `{:("Indicator",,"Colour change over pH range"),(U,,"Yellow to blue pH 0.0 to 1.6"),(V,,"Red to yellow pH 2.8 to 4.1"),(W,,"Red to yellow pH 4.2 to 5.8"),(X,,"Yellow to blue pH 6.0 to 7.7"),(Y,,"Colourless to red pH 8.2 to 10.0"):}` Which of the followinfg statements is correct ?A. Indicator `V` could be used to find the equivalence point for `0.01M` acetic and `0.1M` ammonium hydroxide (ammonia solution) titration.B. Indicator `Y` could be used to distinguish between `0.1M HCI` and `0.01M NaOH` solutions in water.C. Indicator `X` could be used to distinguish between solution of ammonium chloride and sodium acetate.D. Indicator `W` could be suitable for use in determining the concentration of acetic acid in vinegar by base titration. |
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Answer» Correct Answer - C a. For the titration of `W_(A)` and `W_(B)`, there is no sharp change in the `pH` value near the end point. `(pH` varies between `6.0` and `8.0)` So indicator `V` can not be used. But indicator `X` can be used. `CH_(3)COOH+NH_(4)OH rArr pH = 7` b. `{:(0.01MNaOHhArr,pH=13),(0.001MNaOhhArr,pH=11):}]` `Y` cannot be used. Choose an indicator which has different colour for `pH = 13` and `11`. c. `X` can be used since it will given different colout in both the solutions. `NH_(4)CI ` (Salt of `S_(A)//S_(A) pH lt7)` and `CH_(3)COONa` (salt of `W_(A)//S_(B) pH gt 7)`. d. `Y` will be suitable indicator not `W`. `CH_(3)COOH + Base rArr pH gt 7`. |
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| 1396. |
A solution gives the following colours with different indicators: a. Methy`1` orange `rArr` Yellow b. Methy`1` red `rArr` Yellow c. Bromothymol blue `rArr` Orange What is the `pH` of the solution?A. `gt 4.5`B. `gt 6.0`C. 6.0 to 6.3D. 4.5 to 6 |
| Answer» Correct Answer - C | |
| 1397. |
Species acting as both Bronsted acid and base is:A. `HSO_4^(-)`B. `Na_2CO_3`C. `H_2PO_2^(-) `D. `OH^-` |
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Answer» Correct Answer - A |
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| 1398. |
What is the solubility of calcium hydroxide in `mol.L^(-1)`? A. `1.6xx10^(-2)`B. `1.0xx10^(-2)`C. `2.0xx10^(-3)`D. `1.0xx10^(-3)` |
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Answer» Correct Answer - b |
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| 1399. |
The `K_(sp)` of `Ag_(2)CrO_(4)` is `1.1xx10^(-12)` at `298K`. The solubility (in mol/L) of `Ag_(2)CrO_(4)` in a `0.1 M AgNO_(3)` solution isA. `1.1 xx 10^(-11)`B. `1.1 xx 10^(-10)`C. `1.1 xx 10^(-12)`D. `1.1 xx 10^(9)` |
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Answer» Correct Answer - B `Ag_(2)CrO_(4) underset((0.1"from"AgNO_(3)))underset(2s+0.1)(2Ag^(+))+CrO_(4)^(2-)` `=0.1 M `(as s is negligible as compared 0.1 ) `K_(sp)=|Ag^(+)|^(2)[CrO_(4)^(2-)]` `1.1 xx 10^(-12)=(0.1)^(2) xx s `or `s =1.1 xx 10^(-10)M` |
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| 1400. |
The `pH` indicators areA. salts of strong acids and strong basesB. salts of weak acids and weak basesC. either weak acids or weak basesD. either strong acids or strong bases |
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Answer» Correct Answer - C Factual question. |
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