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Answer:

Appends object obj to list

list.remove(obj)

Appends object obj to list

List index (obj).

Returns count how many times obj occurs in list

list.reverse ()

Appends the contents of seq to list.

Answer:

sort ()

Answer:

list.reverse ()

This will produce the following result: 

Extended List : [123, ‘xyz’, ‘zara’, ‘abc’, 123, 2009, ‘manni’] 

This method does not return any value but reverse the given object from the list

list1[0]: physics

It returns item from the list with min value. 

It returns item from the list with max value.

Python has six built-in types of sequences. 

Answer:

It gives the total length of the list.

It gives the total length of the list.

Sum = 12 

Justification: 

A[1] = 4 step size = 2 

A[3] = 8 

S = 4 + 8 = 12

You can update single or multiple elements of lists by giving the slice on the lefthand side of the assignment operator, and you can add elements in a list with the append( ) method. Following is a simple example:

# !/user/bin/python

listl = [‘physics’, ‘chemistry’, 1997, 2000];

print “Value available at index 2 :”

print list[2];

list[2] = 2001;

print “New value available at index 2 :”

print list [2];

Note: append)) method is discussed in subsequent section.

When the above code is executed, it produces the following result:

Value available at index 2 :

1997

New value available at index 2 :

2001

Updating Lists:

You can update single or multiple elements of lists by giving the slice on the lefthand side of the assignment operator, and you can add to elements in a list with the append() method. Following is a simple example:

# !/user/bin/python

list = [‘physics’, ‘chemistry’, 1997, 2000];

print “Value available at index 2 :”

print list[2];

list [2] = 2001;

print “New value available at index 2 :”

print list [2];

When the above code is executed it produces the following result:

Value available at index 2 :

1997

New value available at index 2 :

2001

Delete List Elements:

To remove a list element, you can use either the del statement if you know exactly which element(s) you are deleting of the remove() method if you do not know. Following is a simple example :

# !/user/bin/python

list1 = [‘physics’, ‘chemistry’, 1997, 2000];

print list1; del list1 [2];

print “After deleting value at index 2:”

print list1;

When the above code is executed, it produces the following result:

[‘physics’, ‘chemistry’, 1997, 2001]

After deleting value at index 2 :

[‘physics’, ‘chemistry’, 2000]

def overlapping (a, b): 

11 = len (a) 

12 = len (b) 

for i in range (11): 

for j in range (12): 

if a[i] == b[j] : 

return True 

else 

return False

Import random 

m = input (“Enter the number of rows”) 

n = input (“Enter the number of columns”) 

a = [[random.random () for row in range (m)] for cal in mange (n)] 

if i in range (m):

for j in range (n): 

a[i][j] = input () 

print “First diagonal” 

for i in range (m):

print a[i][j], ‘\t’ 

k = m – 1 

print “second diagonal” 

for j in range (m):

print a[j][k], ‘\t’ 

k- = 1 

else: 

print “Diagonal values are not possible”

def summat (a, m, n): 

s = 0 

for i in range (m): 

for j in range (n): 

s + = a[i][j] 

return s

You can update single or multiple elements of lists by giving the slice on the lefthand side of the assignment operator, and you can add elements in a list with the append( ) method. Following is a simple example: 

# !/user/bin/python

 listl = [‘physics’, ‘chemistry’, 1997, 2000]; 

print “Value available at index 2 :” 

print list[2]; list[2] = 2001; 

print “New value available at index 2 :” 

print list [2];

Note: append)) method is discussed in subsequent section.

When the above code is executed, it produces the following result:

Value available at index 2 : 

1997 

New value available at index 2 : 

2001

Output: 

Final List: [123, ‘xyz’, ’zara1, 2009,’abc1’]

Output: 

A List: abc B List: zara

You can update single or multiple elements of lists by giving the slice on the left-hand side of the assignment operator, and you can add to elements in a list with the append() method. Following is a simple example:

# !/user/bin/python 

list = [‘physics’, ‘chemistry’, 1997, 2000]; 

print “Value available at index 2 :” 

print list[2]; 

list [2] = 2001; 

print “New value available at index 2 :” 

print list [2];

When the above code is executed it produces the following result:

Value available at index 2 : 

1997 New value available at index 2 : 

2001

Delete List Elements:

To remove a list element, you can use either the del statement if you know exactly which element(s) you are deleting of the remove() method if you do not know.

Following is a simple example : 

# !/user/bin/python 

list1 = [‘physics’, ‘chemistry’, 1997, 2000]; 

print list1; del list1 [2]; 

print “After deleting value at index 2:” 

print list1;

When the above code is executed, it produces the following result:

[‘physics’, ‘chemistry’, 1997, 2001] 

After deleting value at index 2 : 

[‘physics’, ‘chemistry’, 2000]

Answer:

Appends the contents of seq to list.

Answer:

This method does not return any value but reverse the given object from the list

Answer:

Returns count how many times obj occurs in list

The list is a most versatile datatype available in Python which can be written as a list of comma- separated values (items) between square brackets. Good thing about a list is that items in a list need not all have the same type. Creating a list is as simple as putting different comma-separated values between square brackets.

For example :

list1 = [‘physics’, ‘chemistry’, 1997,2000];

list2 = [1,2, 3,4, 5];

list3 = ’[‘a”, “b”, “c”, “d”];

ch = 0 

list = [] 

while true : 

print “List Menu” 

print “1. Adding” 

print “2.Modify” 

print “3.Delete” 

print “4.Sort list” 

print “5.Display list” 

print “6.Exit”

ch = int (raw_input (“Enter your choice :”)) if ch = = 1 : 

print “1.Add element” 

print “2.Add a List” 

ch1 = int (raw_input 

(“Enter choice 1 or 2:”)) 

if chi = = 1: 

item = int

(raw_input (“Enter element:”)) 

pos = int (raw_input 

(“Enter position to add : “)) 

list.insert (pos, item) 

elif chi = = 2 : 

list2 = eval (raw_input (“Enter list:”))

list.extend (lst2) 

else: 

print “Valid choices are 1 or 2” 

print “Successfully added” elif ch = = 2 : 

pos = int (raw_input 

(“Enter position :”)) 

intem = int (raw_input 

(“Enter new value :”)) 

old = list[pos] 

list[.pos] = item 

print old, ‘modified with vlaue”, item elif ch = = 3: 

print “1.Delete element by position” 

print “2.Delete element by value”

ch1 = int (raw_input (“Enter you choice 1 or 2’)) 

if chi = = 1: 

pos = int (raw_input (“Enter position :”)) 

item = list.pop (pos)

print item, “deleted” 

elif ch1 = = 2: 

item = int (raw_input (“Enter element:”)) 

pos = list.remove (item) 

print “Succcessfully delted”

else : 

print “Valid choices are 1 or 2” 

elif ch = = 4 : 

print “l.Ascending” 

print “2.Descending” 

chi = int (raw input (“Enter choice 1 or 2”))

 if chi = = 1: 

list. sot () elif ch1 = = 2: 

list.sort (reverse = True) 

else :

print “Valid choices are 1 or 2” 

elif ch = = 5: 

print list elif ch = = 6: 

break

else : 

print “valid choice 1 to 6”

The lists and strings are different in following ways : 

(a) The lists are mutable sequences while strings are immutable. 

(b) Strings store single type of elements, all characters while lists can store elements belonging to different types. 

(c) In consecutive locations, strings store the individual characters while list stores the references of its elements.

Output: 

Final List: [123, ‘xyz’, ‘zara’, 2009, ‘abc’] 

It converts a tuple into list.

Answer:

It converts a tuple into list.

This will produce the following result: 

Index for xyz : 1 Index for xxx : 2

Answer:

It returns item from the list with max value.

The method is used to sort objects of list is-

sort ()

Answer:

It returns item from the list with min value.

This will produce the following result: 

-1 

1 

-1

import random 

m1 = input (“Enter number of rows in first matrix”) 

n1 = input (“Enter number of columns in first matrix”) 

a = [[random.random () for row in range (m1)] for col in range (n1)] 

for i in range (m1): 

for j in range (n1): 

a[i][j] = input () 

m2 = input (“Enter the number of rows in the second matrix”) 

n2 = input (“Enter the number of columns in the second matrix”) 

b = [[random.random () for row in range (m2)] for cal in range (n2)]

for i in range (m2): 

for j in range (n2): 

b[i][j] = input ()

c = [[random.random () for row in range (ml)] for col in range (n2)] 

if (n1 = = m2): 

for i in range (m1): 

for j in range (n2):

c[i][j] = 0 for kin range (n1): 

c[i][j] + = a[i][k]*b[k][j] 

print c[i][j], ‘\t’, 

print 

else: 

print “Multiplication is not possible” 

import random 

m1 = input (“Enter total number of rows in the first matrix”) 

n1 = input (“Enter total number of columns in the first matrix”) 

a = [[random.random() for row in range(m1) for col in range (n1)] 

for i in range (m1) 

for j in range (n1): 

a[i][j] = input()

m2 = input (“Enter total number of rows in the second matrix”) 

n2 = input (“Enter total number of columns in the second matrix”) 

b = [[random.random () for row in range (m2)] for col in range (n2)]

for i in range (m2):

 for j in rnage (n2):

b [i][j] = input () 

c = [[random.random () for row in range (ml)] for col in range (n1)]

 if ((m1 = m2) and (n1 = = b)): 

print “Output is” 

for i in range (m1):

for j in range (n1)] 

c[i][j] = a[i][j] + b[i][j] 

print c[i][j], ‘it’, 

print 

else : 

print “Matrix addition is not possible”