This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Equation of a parabola whose vertex is (2,-3), axis is parallel to the x axis and lastusrectum 8 is |
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Answer» Equation of a parabola whose vertex is (2,-3), axis is parallel to the x axis and lastusrectum 8 is |
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| 2. |
Given a G.P. with a = 729 and 7th term 64. determine S7 |
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Answer» Given a G.P. with a = 729 and 7th term 64. determine S7 |
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| 3. |
'The number of squares of side at least 6 with vertices in S = {(x, y)1 ≤ x, y ≤ 8} is |
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Answer» 'The number of squares of side at least 6 with vertices in S = {(x, y)1 ≤ x, y ≤ 8} is |
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| 4. |
If α+β=π2, then the minimum value of the expression 6sinα−8sinβ+12 is |
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Answer» If α+β=π2, then the minimum value of the expression 6sinα−8sinβ+12 is |
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| 5. |
Two integers r and s are drawn one at a time without replacement from the set 1,2,⋯n. If Pk=P(r≤k/s≤k), the value of 4P7 if n=25 is: |
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Answer» Two integers r and s are drawn one at a time without replacement from the set 1,2,⋯n. If Pk=P(r≤k/s≤k), the value of 4P7 if n=25 is: |
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| 6. |
The domain and range of the function f(x)=2-xx-2 are _________ and _________ respectively. |
| Answer» The domain and range of the function are _________ and _________ respectively. | |
| 7. |
If a vertex of a triangle is (1, 1) and the mid points of two sides through this vertex are (-1, 2) and (3, 2), then what type of triangle is this? |
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Answer» If a vertex of a triangle is (1, 1) and the mid points of two sides through this vertex are (-1, 2) and (3, 2), then what type of triangle is this? |
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| 8. |
A line with positive direction cosines passes through the point P (2 , -1 , 2 ) and makes equal angles with the coordinate axes. The line meets the plane 2x+6y +z = 9 at point Q. The length of the line segment PQ equals |
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Answer» A line with positive direction cosines passes through the point P (2 , -1 , 2 ) and makes equal angles with the coordinate axes. The line meets the plane 2x+6y +z = 9 at point Q. The length of the line segment PQ equals |
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| 9. |
The range of a for which f(x)=sgn((sinx)+a) is continuous for all x∈R. |
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Answer» The range of a for which f(x)=sgn((sinx)+a) is continuous for all x∈R. |
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| 10. |
Let f(x) be defined on [−2,2] and is given by f(x)={−1,−2≤x≤0x−1,0<x≤2,g(x)=|x|. Then fog(x)+gof(x)= |
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Answer» Let f(x) be defined on [−2,2] and is given by f(x)={−1,−2≤x≤0x−1,0<x≤2,g(x)=|x|. Then fog(x)+gof(x)= |
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| 11. |
매력.1tan x1- tan x47.tan-x4 |
| Answer» 매력.1tan x1- tan x47.tan-x4 | |
| 12. |
n(n +3)1.2.3 2.3.4 3.4.5 n(n+I)(n2 4(n+1) (n +2)- |
| Answer» n(n +3)1.2.3 2.3.4 3.4.5 n(n+I)(n2 4(n+1) (n +2)- | |
| 13. |
f(x)=sqrt(-x^(2)+4x-3)+sqrt(sin(pi)/(2)(sin(pi)/(2)(x-1)))Find range. |
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Answer» f(x)=sqrt(-x^(2)+4x-3)+sqrt(sin(pi)/(2)(sin(pi)/(2)(x-1))) Find range. |
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| 14. |
If a→, b→, c→ are non-coplanar vectors, then b→×c→,a→+b→+c→a→ b→ c→ = _______________. |
| Answer» If are non-coplanar vectors, then = _______________. | |
| 15. |
A ray of light is incident along a line which meets another line, 7x–y+1=0, at the point (0,1). The ray is then reflected from this point along the line, y+2x=1. Then the equation of the line of incidence of the ray of light is : |
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Answer» A ray of light is incident along a line which meets another line, 7x–y+1=0, at the point (0,1). The ray is then reflected from this point along the line, y+2x=1. Then the equation of the line of incidence of the ray of light is : |
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| 16. |
If (x1,y1) and (x2,y2) are the extremities of a focal chord of the parabola 3y2=4x, then x1x2+y1y2 is equal to −pq where p,q are co-prime. Then value of q−p is |
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Answer» If (x1,y1) and (x2,y2) are the extremities of a focal chord of the parabola 3y2=4x, then x1x2+y1y2 is equal to −pq where p,q are co-prime. Then value of q−p is |
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| 17. |
L1:x−2y+10=0L2:x+2y−6=0What is the ratio in which the point of intersection of line L1 and L2 divides the line segment AB of L1? |
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Answer» L1:x−2y+10=0 L2:x+2y−6=0 What is the ratio in which the point of intersection of line L1 and L2 divides the line segment AB of L1?
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| 18. |
dy14,= ytan x ; y = 1 when x = 0dr |
| Answer» dy14,= ytan x ; y = 1 when x = 0dr | |
| 19. |
100.what is huckel's rule |
| Answer» 100.what is huckel's rule | |
| 20. |
A man starts repaying a loan as first instalment of Rs. 100. If he increases the instalments by Rs. 5 every month, what amount he will pay in the 30th instalment? |
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Answer» A man starts repaying a loan as first instalment of Rs. 100. If he increases the instalments by Rs. 5 every month, what amount he will pay in the 30th instalment? |
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| 21. |
What is the locus of a point for which y = 0, z = 0? |
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Answer» What is the locus of a point for which y = 0, z = 0?
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| 22. |
Let P=⎡⎢⎣3−1−220α3−50⎤⎥⎦, where αϵR. Suppose Q=[qij] is a matrix such that PQ = kI, where kϵR, k≠0 and I is the identity matrix of order 3. If q23=−k8 and det(Q)=k22 then |
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Answer» Let P=⎡⎢⎣3−1−220α3−50⎤⎥⎦, where αϵR. Suppose Q=[qij] is a matrix such that PQ = kI, where kϵR, k≠0 and I is the identity matrix of order 3. If q23=−k8 and det(Q)=k22 then |
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| 23. |
If y=cos ax,then ∣∣∣∣yy1y2y3y4y5y6y7y8∣∣∣∣= (where yn=dnydxn) |
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Answer» If y=cos ax,then ∣∣ |
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| 24. |
Let f(x) be a polynomial of degree 3 such that f(k)=−2k for k=2,3,4,5. Then the value of 52−10f(10) is equal to |
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Answer» Let f(x) be a polynomial of degree 3 such that f(k)=−2k for k=2,3,4,5. Then the value of 52−10f(10) is equal to |
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| 25. |
∫cosec2(4x+9)dx is equal to(where C is the constant of integration) |
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Answer» ∫cosec2(4x+9)dx is equal to (where C is the constant of integration) |
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| 26. |
If N=√5328/961, then (31×N) is |
| Answer» If N=√5328/961, then (31×N) is | |
| 27. |
The total number number of ways in which all the digits of the number 79853 can be arranged such that no digit will occur in its original position as given in the number is |
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Answer» The total number number of ways in which all the digits of the number 79853 can be arranged such that no digit will occur in its original position as given in the number is |
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| 28. |
The value of the integral a∫0dxx+√a2−x2 is |
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Answer» The value of the integral a∫0dxx+√a2−x2 is |
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| 29. |
In column 1 different setup for Young’s double slit experiment is given. Distance between two slits S1 and S2 is ‘d’ and between slits and screen is ‘D’ in every setup. In column 2 location of central maxima is given. In column 3 path difference ΔP is given at point P which is θ angle above MO line (d << D) Which of the following is correct when light is incident at an angle θ0 |
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Answer» In column 1 different setup for Young’s double slit experiment is given. Distance between two slits S1 and S2 is ‘d’ and between slits and screen is ‘D’ in every setup. In column 2 location of central maxima is given. In column 3 path difference ΔP is given at point P which is θ angle above MO line (d << D)
Which of the following is correct when light is incident at an angle θ0 |
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| 30. |
The latusrectum of a hyperbola subtends a right angle at its centre,then its e = |
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Answer» The latusrectum of a hyperbola subtends a right angle at its centre,then its e = |
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| 31. |
Question 16If D (−12,52), E (7,3) and F (72,72) are the mid-points of sides of ΔABC, then find the area of the ΔABC. |
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Answer» Question 16 If D (−12,52), E (7,3) and F (72,72) are the mid-points of sides of ΔABC, then find the area of the ΔABC. |
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| 32. |
limx→π2cos2 x1−sin x |
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Answer» limx→π2cos2 x1−sin x |
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| 33. |
If the curves y2=4ax and xy=c2 cut each other orthogonally then c4a4= |
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Answer» If the curves y2=4ax and xy=c2 cut each other orthogonally then c4a4= |
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| 34. |
The value of a for which the curves y2=4x and x2+y2−2ax=0 intersect exactly at one point is |
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Answer» The value of a for which the curves y2=4x and x2+y2−2ax=0 intersect exactly at one point is |
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| 35. |
If the equation in x, x4+px3+qx2 = 16(2x – 1), where p, q ϵ R has all positive roots and A.M. of roots = H.M. of roots, then |
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Answer» If the equation in x, x4+px3+qx2 = 16(2x – 1), where p, q ϵ R has all positive roots and A.M. of roots = H.M. of roots, then |
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| 36. |
If in △ABC, tanA+tanB+tanC=6 and tanAtanB=2, then sin2A:sin2B:sin2C can be |
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Answer» If in △ABC, tanA+tanB+tanC=6 and tanAtanB=2, then sin2A:sin2B:sin2C can be |
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| 37. |
The number of elements in the set {A=(ab0d):a,b,d∈{−1,0,1} and (I−A)3=I−A3},where I is 2×2 identity matrix, is |
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Answer» The number of elements in the set {A=(ab0d):a,b,d∈{−1,0,1} and (I−A)3=I−A3}, where I is 2×2 identity matrix, is |
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| 38. |
If ln=∫(1+x+x−1)ex+x−1dx= |
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Answer» If ln=∫(1+x+x−1)ex+x−1dx= |
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| 39. |
If the third term in the binomial expansion of (1+xlog2x)5 equals 2560, the a possible value of x is : |
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Answer» If the third term in the binomial expansion of (1+xlog2x)5 equals 2560, the a possible value of x is : |
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| 40. |
if cosA+sinB=m and sinA+cosB=n, prove that 2sin(A+B)=m2+n2-2 |
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Answer» if cosA+sinB=m and sinA+cosB=n, prove that 2sin(A+B)=m2+n2-2 |
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| 41. |
If x+√x+2x−√x+2≥1, then |
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Answer» If x+√x+2x−√x+2≥1, then |
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| 42. |
If the tangent at θ on the ellipse x2a2+y2b2=1 meets the auxiliary circle at two points which subtend a right angle at the centre, then e2(2−cos2θ)= |
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Answer» If the tangent at θ on the ellipse x2a2+y2b2=1 meets the auxiliary circle at two points which subtend a right angle at the centre, then e2(2−cos2θ)= |
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| 43. |
In a triangle ABC, if∠A=600,a=5,b=4,then c is a root of the equation |
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Answer» In a triangle ABC, if∠A=600,a=5,b=4,then c is a root of the equation |
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| 44. |
To obtain the graph of y = - sinx from the graph of y = sinx, phase shift required is |
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Answer» To obtain the graph of y = - sinx from the graph of y = sinx, phase shift required is |
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| 45. |
If the median of a triangle ABC passing through A is perpendicular to AB, then tanA+2tanB= |
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Answer» If the median of a triangle ABC passing through A is perpendicular to AB, then tanA+2tanB= |
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| 46. |
The digits 1, 2, 3.... 9 are arranged in a random order, find the probability that 1, 2, 3 will appear as neighbors in the order mentioned. |
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Answer» The digits 1, 2, 3.... 9 are arranged in a random order, find the probability that 1, 2, 3 will appear as neighbors in the order mentioned. |
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| 47. |
The integral ∫2x12+5x9(x5+x3+1)3 dx is equal to : where C is an arbitary constant. |
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Answer» The integral ∫2x12+5x9(x5+x3+1)3 dx is equal to : where C is an arbitary constant. |
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| 48. |
Let f be differentiable in the interval (0,∞) such that f(1)=1 and limt→xt3f(x)−x3f(t)t−x=1, for each x>0. Then f(2) is equal to AB, where A,B are in the lowest form. The value of A+B is |
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Answer» Let f be differentiable in the interval (0,∞) such that f(1)=1 and limt→xt3f(x)−x3f(t)t−x=1, for each x>0. Then f(2) is equal to AB, where A,B are in the lowest form. The value of A+B is |
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| 49. |
1 3216. 3 0 -5 |
| Answer» 1 3216. 3 0 -5 | |
| 50. |
A tea party is arranged for 16 persons along two sides of a long table with 8 chairs on each side. Four persons wish for sit on one particular side and two on the other side. In how many ways can they be seated ? |
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Answer» A tea party is arranged for 16 persons along two sides of a long table with 8 chairs on each side. Four persons wish for sit on one particular side and two on the other side. In how many ways can they be seated ? |
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