InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1951. |
If A=[31−12], show that A2−5A+I=0. |
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Answer» If A=[31−12], show that A2−5A+I=0. |
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| 1952. |
Simplify: cot A + sin B |
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Answer» Simplify: cot A + sin B |
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| 1953. |
Which of the following statements are true and which are false? In each case give a valid reason for saying so. (i) p : Each radius of a circle is a chord of the circle. (ii) q : The centre of a circle bisects each chord of the circle. (iii) r : Circle is a particular case of an ellipse. (iv) s : If x and y are integers such that x > y , then – x < – y . (v) t : is a rational number. |
| Answer» Which of the following statements are true and which are false? In each case give a valid reason for saying so. (i) p : Each radius of a circle is a chord of the circle. (ii) q : The centre of a circle bisects each chord of the circle. (iii) r : Circle is a particular case of an ellipse. (iv) s : If x and y are integers such that x > y , then – x < – y . (v) t : is a rational number. | |
| 1954. |
The value of the integral ∫x3+x+1x2−1dx is(where C is an arbitrary constant) |
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Answer» The value of the integral ∫x3+x+1x2−1dx is |
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| 1955. |
The sum of three numbers in G.P. is 56. If we subtract 1, 7, 21 from these numbers in that order, we obtain an arithmetic progression. Find the numbers. |
| Answer» The sum of three numbers in G.P. is 56. If we subtract 1, 7, 21 from these numbers in that order, we obtain an arithmetic progression. Find the numbers. | |
| 1956. |
The value of expression 3(1!)−4(2!)+5(3!)−6(4!)+.....−2008(2006!)+(2007!) is |
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Answer» The value of expression |
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| 1957. |
For the parabola y2=4px find the extremities of a double ordinate of length 8p. Prove that the lines from the vertex to its extremities are at right angles. |
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Answer» For the parabola y2=4px find the extremities of a double ordinate of length 8p. Prove that the lines from the vertex to its extremities are at right angles. |
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| 1958. |
limx→0x(2x−1)1−cosx |
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Answer» limx→0x(2x−1)1−cosx |
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| 1959. |
What is 0 divided by 0? |
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Answer» What is 0 divided by 0? |
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| 1960. |
In triangle ABC, right angled at B, if tan A =1/√3, find the value of : sinAcosC+cosAsinC. |
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Answer» In triangle ABC, right angled at B, if tan A =1/√3, find the value of : sinAcosC+cosAsinC. |
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| 1961. |
Q. find the antiderivative of ( x^2-1/x)dx |
| Answer» Q. find the antiderivative of ( x^2-1/x)dx | |
| 1962. |
If the sides a, b, c of a triangle ABC form successive terms of G.P. with common ratio r(>1) then which of the following is correct? |
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Answer» If the sides a, b, c of a triangle ABC form successive terms of G.P. with common ratio r(>1) then which of the following is correct? |
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| 1963. |
If roots of equation z^2+(p+iq)z+r+is=0 are real where p,q,r,s €R, then find s^2+q^2r. |
| Answer» If roots of equation z^2+(p+iq)z+r+is=0 are real where p,q,r,s €R, then find s^2+q^2r. | |
| 1964. |
If A and B are any two different square matrices of order n with A – B is non-singular A3=B3 and A(AB) = B(BA) , then |
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Answer» If A and B are any two different square matrices of order n with A – B is non-singular A3=B3 and A(AB) = B(BA) , then |
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| 1965. |
33. If coefficient of variation is 70% and its standard deviation are 28, then mean is |
| Answer» 33. If coefficient of variation is 70% and its standard deviation are 28, then mean is | |
| 1966. |
If from Lagrange's Mean Value Theorem, we have f'(x1)=f(b)−f(a)b−a, then . |
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Answer» If from Lagrange's Mean Value Theorem, we have f'(x1)=f(b)−f(a)b−a, then |
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| 1967. |
Three cards are drawn successively with replacement from a well shuffled pack of 52 cards. Find the probability distribution of the number of spades. Hence, find the mean of the distribtution. [CBSE 2015] |
| Answer» Three cards are drawn successively with replacement from a well shuffled pack of 52 cards. Find the probability distribution of the number of spades. Hence, find the mean of the distribtution. [CBSE 2015] | |
| 1968. |
All x satisfying the inequality (cot−1x)2−7(cot−1x)+10>0, lie in the interval : |
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Answer» All x satisfying the inequality (cot−1x)2−7(cot−1x)+10>0, lie in the interval : |
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| 1969. |
If ∫excos(x)dx=F(x)+c, where c is an arbitrary constant, then F(x)= (a) ex(sinx−cosx) (b) ex(sinx+cosx) (c) ex2(sinx−cosx) (d) ex2(sinx+cosx) |
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Answer» If ∫excos(x)dx=F(x)+c, where c is an arbitrary constant, then F(x)= (a) ex(sinx−cosx) (b) ex(sinx+cosx) (c) ex2(sinx−cosx) (d) ex2(sinx+cosx) |
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| 1970. |
Two schools A and B want to award their selected students on the values of sincerity,truthfulness and helpfulness. The school A wants to award Rs x each, Rs y each and Rs z each for the three respective values to 3, 2 and 1 students respectively with a total award money of Rs 1,600. School B wants to spend Rs 2,300 to award its 4, 1 and 3 students on the respective values (by giving the same award money to the three values as before). If the amount of award for one prize on each value is Rs 900,using matrices, find the award money for each value. Apart from these three values,suggest one more value which should be considered for award. |
| Answer» Two schools A and B want to award their selected students on the values of sincerity,truthfulness and helpfulness. The school A wants to award Rs x each, Rs y each and Rs z each for the three respective values to 3, 2 and 1 students respectively with a total award money of Rs 1,600. School B wants to spend Rs 2,300 to award its 4, 1 and 3 students on the respective values (by giving the same award money to the three values as before). If the amount of award for one prize on each value is Rs 900,using matrices, find the award money for each value. Apart from these three values,suggest one more value which should be considered for award. | |
| 1971. |
If f(x)=⎧⎪⎪⎪⎪⎪⎪⎪⎪⎨⎪⎪⎪⎪⎪⎪⎪⎪⎩sin(α+2)x+sinxx ,x<0b ,x=0(x+3x2)13−x13x43 ,x>0 is continuous at x=0 then a+2b is equal to : |
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Answer» If f(x)=⎧⎪ |
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| 1972. |
If αand β are different complexnumbers with= 1, then find. |
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Answer» If α |
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| 1973. |
The general solution of the differential equation dydx=r2(x+y)2, is (where r is a fixed constant and c is a constant of integration ) |
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Answer» The general solution of the differential equation dydx=r2(x+y)2, is (where r is a fixed constant and c is a constant of integration ) |
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| 1974. |
Question 4If tan A = cot B, prove that A+B=90∘. |
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Answer» Question 4 If tan A = cot B, prove that A+B=90∘. |
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| 1975. |
A point p lies in thex-y plane.its position can be specified by x,y co-ordinates or by a radially directed vector r=xi+yj, making an angle †extcent with the x-axis.find a vector ir of unit magnitude in the direction of vector r and a vector iv of unit magnitude normal to the vector ir and lying in the x-y plane |
| Answer» A point p lies in thex-y plane.its position can be specified by x,y co-ordinates or by a radially directed vector r=xi+yj, making an angle †extcent with the x-axis.find a vector ir of unit magnitude in the direction of vector r and a vector iv of unit magnitude normal to the vector ir and lying in the x-y plane | |
| 1976. |
The foot of the perpendicular from P(1, 0, 2) to the line x+13=y−2−2=z+1−1 is |
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Answer» The foot of the perpendicular from P(1, 0, 2) to the line x+13=y−2−2=z+1−1 is |
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| 1977. |
Let PS be the median of the triangle with vertices P(2,2),Q(6,−1) and R(7,3). The equation of the line passing through (1,−1) and parallel to PS is |
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Answer» Let PS be the median of the triangle with vertices P(2,2),Q(6,−1) and R(7,3). The equation of the line passing through (1,−1) and parallel to PS is |
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| 1978. |
9. The time period of a particle executing simple hermonic motion is T,if the time is calculated from the mean position then what will be the time taken by the particle to cover the distance from the mean position to the mid-point of extreme position? |
| Answer» 9. The time period of a particle executing simple hermonic motion is T,if the time is calculated from the mean position then what will be the time taken by the particle to cover the distance from the mean position to the mid-point of extreme position? | |
| 1979. |
Find the domain of(i) sec-13x-1(ii) sec-1x-tan-1x |
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Answer» Find the domain of (i) (ii) |
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| 1980. |
9. n2+2 |
| Answer» 9. n2+2 | |
| 1981. |
f(x) and f’(x) are differentiable at x = c. Which of the following is the condition for f(x) to have a local minimum at x = c, if f’(c) = 0 |
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Answer» f(x) and f’(x) are differentiable at x = c. Which of the following is the condition for f(x) to have a local minimum at x = c, if f’(c) = 0 |
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| 1982. |
The value of the integral ∫x(x−1)2(x+2)dx(where m is an arbitrary constant) |
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Answer» The value of the integral ∫x(x−1)2(x+2)dx |
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| 1983. |
Conisder the recurrance relation ak=−8 ak−1−15ak−2 with initial condition a0=0 and a1=2. which of the following is an explicit solution to this recurrance relation ? |
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Answer» Conisder the recurrance relation ak=−8 ak−1−15ak−2 with initial condition a0=0 and a1=2. which of the following is an explicit solution to this recurrance relation ? |
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| 1984. |
Prove the following trigonometric identities.tanθ1-cotθ+cotθ1-tanθ=1+tanθ+cotθ |
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Answer» Prove the following trigonometric identities. |
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| 1985. |
If the number of terms in the expansion of (x+y+z)n is 36, then the value of n is |
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Answer» If the number of terms in the expansion of (x+y+z)n is 36, then the value of n is |
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| 1986. |
If the vectors a→ and b→ are such that a→=3,b→=23 and a→×b→ is a unit vector, then write the angle between a→ and b→. [CBSE 2014] |
| Answer» If the vectors and are such that and is a unit vector, then write the angle between and . [CBSE 2014] | |
| 1987. |
If log2(9x−1+7)−log2(3x−1+1)=2 then x values are |
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Answer» If log2(9x−1+7)−log2(3x−1+1)=2 then x values are |
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| 1988. |
If f(x)=max{x4,x2,14},∀ x∈[0,∞), then the sum of square of reciprocal of all the values of x, where f(x) is not differentiable is: |
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Answer» If f(x)=max{x4,x2,14},∀ x∈[0,∞), then the sum of square of reciprocal of all the values of x, where f(x) is not differentiable is: |
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| 1989. |
If ⎡⎢⎣1sinθ1−sinθ1sinθ−1−sinθ1⎤⎥⎦ ; then for all θ∈(3π4,5π4),det(A) lies in the interval : |
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Answer» If ⎡⎢⎣1sinθ1−sinθ1sinθ−1−sinθ1⎤⎥⎦ ; then for all |
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| 1990. |
If the first of a G.P. a1,a2,a3,....... is unity such that 4 a2+5 a3 is least, then the common ratio of G.P. is |
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Answer» If the first of a G.P. a1,a2,a3,....... is unity such that 4 a2+5 a3 is least, then the common ratio of G.P. is |
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| 1991. |
Show that , is an increasing function of x throughout its domain. |
| Answer» Show that , is an increasing function of x throughout its domain. | |
| 1992. |
Find the values of cos−1x in terms of given options. |
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Answer» Find the values of cos−1x in terms of given options. |
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| 1993. |
Consider the region R={(x,y)∈R×R:x≥0 and y2≤4−x}.Let F be the family of all circles that are contained in R and have centers on the x−axis. Let C be the circle that has largest radius among the circles in F. Let (α,β) be a point where the circle C meets the curve y2=4−x.The radius of the circle C is |
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Answer» Consider the region R={(x,y)∈R×R:x≥0 and y2≤4−x}. Let F be the family of all circles that are contained in R and have centers on the x−axis. Let C be the circle that has largest radius among the circles in F. Let (α,β) be a point where the circle C meets the curve y2=4−x. The radius of the circle C is |
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| 1994. |
If x=acost+log tant2 and y=asint, evaluate d2ydx2 at t=π3. |
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| 1995. |
ntLet f ,g and h be defined from R-R byn ntf(x) = x2-1n ntg(x)=(1+x2)1/2n nth(x)={0, x0n ntFind (hofog)(x)n |
| Answer» ntLet f ,g and h be defined from R-R byn ntf(x) = x2-1n ntg(x)=(1+x2)1/2n nth(x)={0, x<0n nt {x, x >0n ntFind (hofog)(x)n | |
| 1996. |
Write the middle term in the expansion of (2x23+32x2)10. |
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Answer» Write the middle term in the expansion of (2x23+32x2)10. |
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| 1997. |
16. The general solution of the differential equation x dy-0 is(A)xy=C(B) x=Of(C) y=Cr(D) y=Cr2 |
| Answer» 16. The general solution of the differential equation x dy-0 is(A)xy=C(B) x=Of(C) y=Cr(D) y=Cr2 | |
| 1998. |
In ΔABC, the value of (a−b)2cos2C2+(a+b)2sin2C2= |
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Answer» In ΔABC, the value of (a−b)2cos2C2+(a+b)2sin2C2= |
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| 1999. |
By introducing a new variable t, putting x=cos t , the expression is (1−x2)d2ydx2−xdydx+ytransformed into : |
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Answer» By introducing a new variable t, putting x=cos t , the expression is (1−x2)d2ydx2−xdydx+ytransformed into : |
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| 2000. |
Find the derivative of the function f(x)=2x2+3x−5 at x=−1. Also prove that f′(0)+3f′(−1)=0 |
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Answer» Find the derivative of the function f(x)=2x2+3x−5 at x=−1. Also prove that f′(0)+3f′(−1)=0 |
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