InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 3551. |
The solution of xdx+ydy=x2ydy−xy2dy is (where C1,C2,C3,C4 are integration constant) |
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Answer» The solution of xdx+ydy=x2ydy−xy2dy is |
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| 3552. |
Given standard equation of ellipse,x2a2+y2b2=1,a>b,with eccentricity e.Match the following a)Major axisi)2a(1−e2)b)Minor axisii)y=0c)Double ordinateiii)x=0d)Latus Rectum lengthiv)x=−aev)√1−b2a2 |
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Answer» Given standard equation of ellipse, |
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| 3553. |
The area of the quadrilateral PQRS whose vertices are P (-5, 7), Q (-4, -5), R (-1, -6) and S (4, 5) is |
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Answer» The area of the quadrilateral PQRS whose vertices are P (-5, 7), Q (-4, -5), R (-1, -6) and S (4, 5) is |
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| 3554. |
If a cos θ − b sin θ = c, then a sin θ + b cos θ =(a) ±a2+b2+c2(b) ±a2+ b2-c2(c) ±c2-a2-b2(d) None of these |
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Answer» If a cos θ − b sin θ = c, then a sin θ + b cos θ = (a) (b) (c) (d) None of these |
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| 3555. |
The value(s) of x satisfying the equation tan−1x−1x−2+tan−1x+1x+2=π4 is (are) |
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Answer» The value(s) of x satisfying the equation tan−1x−1x−2+tan−1x+1x+2=π4 is (are) |
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| 3556. |
The equations of the lines through (−1,−1) and making angle 45∘ with the line x+y=0 are given by |
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Answer» The equations of the lines through (−1,−1) and making angle 45∘ with the line x+y=0 are given by |
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| 3557. |
Mark the correct alternative in the following question:If in an A.P. Sn=n2q and Sm=m2q, where Sr denotes the sum of r terms of the A.P., then Sq equalsa q32 b mnq c q3 d m2+n2q |
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Answer» Mark the correct alternative in the following question: |
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| 3558. |
The sum of 1+25+352+453+....... upto n terms is[MP PET 1982] |
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Answer» The sum of 1+25+352+453+....... upto n terms is [MP PET 1982] |
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| 3559. |
what is the order of minus I effect when ha\log ens are in conjugatio |
| Answer» what is the order of minus I effect when ha\log ens are in conjugatio | |
| 3560. |
a^3 +b^3/8+c^3 /27=1/2abc then a:b:c is equal to? |
| Answer» a^3 +b^3/8+c^3 /27=1/2abc then a:b:c is equal to? | |
| 3561. |
Which of the following is/are null sets? |
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Answer» Which of the following is/are null sets? |
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| 3562. |
The probability of obtaining an even prime number on each die, when a pair of dice is rolled is (A) 0 (B) (C) (D) |
| Answer» The probability of obtaining an even prime number on each die, when a pair of dice is rolled is (A) 0 (B) (C) (D) | |
| 3563. |
Bravias lattice |
| Answer» Bravias lattice | |
| 3564. |
The sum of the mean and variance of a binomial distribution is 15 and the sum of their squares is 117. Probability of atmost one success in case of these trials will be: |
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Answer» The sum of the mean and variance of a binomial distribution is 15 and the sum of their squares is 117. Probability of atmost one success in case of these trials will be: |
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| 3565. |
If current I=3A sinwt and I'=4A coswt, then l" which is equal to I+I' is equal to(1) 5A sin (wt 37^° ) (4) 5A sin (wt+ 30^° ) (2) 5A sin (wt + 53^° ) (3) 5A sin (wt +45^°) |
| Answer» If current I=3A sinwt and I'=4A coswt, then l" which is equal to I+I' is equal to(1) 5A sin (wt 37^° ) (4) 5A sin (wt+ 30^° ) (2) 5A sin (wt + 53^° ) (3) 5A sin (wt +45^°) | |
| 3566. |
Round off 2.357987 to two significant figures.And also explain what will nine turn into if we have to raise it by one. |
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Answer» Round off 2.357987 to two significant figures. And also explain what will nine turn into if we have to raise it by one. |
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| 3567. |
Find the shortest distance between the lines and |
| Answer» Find the shortest distance between the lines and | |
| 3568. |
If x=exy, prove that dydx=x-yxlogx |
| Answer» | |
| 3569. |
If 3sinθ+5cosθ=5, then the absolute value of 5sinθ−3cosθ is |
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Answer» If 3sinθ+5cosθ=5, then the absolute value of 5sinθ−3cosθ is |
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| 3570. |
In an R-L-C circuit v = 20 sin (314t+5π/6) and i = 10 sin(314 t+2π/3). The power factor of the circuit is |
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Answer» In an R-L-C circuit v = 20 sin (314t+5π/6) and i = 10 sin(314 t+2π/3). The power factor of the circuit is |
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| 3571. |
If z1,z2,z3 are three complex numbers such that 5z1−13z2+8z3=0, then the value of ∣∣∣∣z1¯z11z2¯z21z3¯z31∣∣∣∣ is |
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Answer» If z1,z2,z3 are three complex numbers such that 5z1−13z2+8z3=0, then the value of ∣∣ ∣∣z1¯z11z2¯z21z3¯z31∣∣ ∣∣ is |
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| 3572. |
If f, g:R-R are two functions defined as f(X) =|X|+X and g(X)=|X|-X , for every X belong to R then, find fog and god. |
| Answer» If f, g:R-R are two functions defined as f(X) =|X|+X and g(X)=|X|-X , for every X belong to R then, find fog and god. | |
| 3573. |
The reflection of the point A(1,0,0) in the line x−12=y+1−3=z+108 is: |
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Answer» The reflection of the point A(1,0,0) in the line x−12=y+1−3=z+108 is: |
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| 3574. |
The equation of line(s) joining the vertex of y2=6x to the point on it whose abscissa is 24, is (are) |
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Answer» The equation of line(s) joining the vertex of y2=6x to the point on it whose abscissa is 24, is (are) |
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| 3575. |
The slope of the line passing through (4,3) and (2,3) is coming out as 0/2=0 does this mean that the line lies on the x-axis? If not then what's the reason? Slope as 0 means there must not be any inclination with the x-axis. Therefore either it should be parallel. Then why is it showing the x axis values as 4 and 2 it should be 0. |
| Answer» The slope of the line passing through (4,3) and (2,3) is coming out as 0/2=0 does this mean that the line lies on the x-axis? If not then what's the reason? Slope as 0 means there must not be any inclination with the x-axis. Therefore either it should be parallel. Then why is it showing the x axis values as 4 and 2 it should be 0. | |
| 3576. |
A circle (x−3)2+(y−6)2=r2 touches parabola y2=4x at P(a, b). If the slope of common tangent at P is m, then (b, r > 0) |
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Answer» A circle (x−3)2+(y−6)2=r2 touches parabola y2=4x at P(a, b). If the slope of common tangent at P is m, then (b, r > 0) |
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| 3577. |
If the equation of plane passing through the mirror image of a point (2, 3, 1) with respect to line x+12=y−31=z+2−1 and containing the line x−23=1−y2=z+11 is αx+βy+γz=24, then α+β+γ is equal to : |
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Answer» If the equation of plane passing through the mirror image of a point (2, 3, 1) with respect to line x+12=y−31=z+2−1 and containing the line x−23=1−y2=z+11 is αx+βy+γz=24, then α+β+γ is equal to : |
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| 3578. |
If the distance between the foci fo a hyperbola is 16 its ecentricity is √2.then then obtain its equation. |
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Answer» If the distance between the foci fo a hyperbola is 16 its ecentricity is √2.then then obtain its equation. |
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| 3579. |
If x−1l=y−2m=z+1n is the equation of the line through (1, 2, -1) and (-1, 0, 1), then (l, m, n) is [MP PET 1992] |
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Answer» If x−1l=y−2m=z+1n is the equation of the line through (1, 2, -1) and (-1, 0, 1), then (l, m, n) is [MP PET 1992]
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| 3580. |
If 1x-2<0, then x _______ 2. |
| Answer» If then x _______ 2. | |
| 3581. |
The values of λ for which the circle x2+y2+6x+5+λ(x2+y2−8x+7)=0 dwindles into a point are |
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Answer» The values of λ for which the circle x2+y2+6x+5+λ(x2+y2−8x+7)=0 dwindles into a point are |
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| 3582. |
A long straight wire, carrying current I, is bent at its midpoint to form an angle of 45∘. Induction of magnetic field at point P, distant R from point of bending is equal to |
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Answer» A long straight wire, carrying current I, is bent at its midpoint to form an angle of 45∘. Induction of magnetic field at point P, distant R from point of bending is equal to |
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| 3583. |
Calculate APC and MPC: INCOME (Y)CONSUMPTION (C)041012202030284036 |
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Answer» Calculate APC and MPC: INCOME (Y)CONSUMPTION (C)041012202030284036 |
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| 3584. |
If A(1, 2, 3), B(2, 3, 1) and C(3, 1, 2) are the vertices of the triangle. Find the coordinates of its orthocenter (O) and In center (I). |
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Answer» If A(1, 2, 3), B(2, 3, 1) and C(3, 1, 2) are the vertices of the triangle. Find the coordinates of its orthocenter (O) and In center (I). |
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| 3585. |
Find no. Of solutions of sinx=x/10 |
| Answer» Find no. Of solutions of sinx=x/10 | |
| 3586. |
Minimize and maximize Z = 5x + 10y subject to constraints are x + 2y ≤ 120, x + y ≥ 60, x - 2y ≥ 0 and x, y ≥ 0. |
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Answer» Minimize and maximize Z = 5x + 10y subject to constraints are x + 2y ≤ 120, x + y ≥ 60, x - 2y ≥ 0 and x, y ≥ 0. |
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| 3587. |
9. IfA-13, 6, 9, 12, 15, 18, 21), B 14, 8, 12, 16, 20 ),C= { 2, 4, 6, 8, 10, 12, 14, 16 }, D= {5, 10, 15, 20 }; find(G) A - B(v) C-A(vi) D(ix)A-C-AD-B(ii) A D iv) B-A(vii) B- C v) B D(ii)Vi1ViliC-B(x) |
| Answer» 9. IfA-13, 6, 9, 12, 15, 18, 21), B 14, 8, 12, 16, 20 ),C= { 2, 4, 6, 8, 10, 12, 14, 16 }, D= {5, 10, 15, 20 }; find(G) A - B(v) C-A(vi) D(ix)A-C-AD-B(ii) A D iv) B-A(vii) B- C v) B D(ii)Vi1ViliC-B(x) | |
| 3588. |
You have two red and two blue blocks. How many different towers can you build that are four blocks high using these blocks?6 |
Answer» You have two red and two blue blocks. How many different towers can you build that are four blocks high using these blocks?
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| 3589. |
The area, in square unit, bounded by the curves y=x3,y=x2 and the ordinates x = 1, x = 2 is |
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Answer» The area, in square unit, bounded by the curves y=x3,y=x2 and the ordinates x = 1, x = 2 is |
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| 3590. |
(i) Find the value of k for which x = 1 is a root of the equation x2+kx+3=0. Also, find the other root.(ii) Find the values of a and b for which x=34 and x=-2 are the roots of the equation ax2+bx-6=0. |
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Answer» (i) Find the value of k for which x = 1 is a root of the equation . Also, find the other root. (ii) Find the values of a and b for which are the roots of the equation |
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| 3591. |
Solution of differential equation (y+x√xy(x+y))dx+(y√xy(x+y)−x)dy=0 is |
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Answer» Solution of differential equation (y+x√xy(x+y))dx+(y√xy(x+y)−x)dy=0 is |
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| 3592. |
Show thateach of the relation R in the set,given by (i) (ii) is anequivalence relation. Find the set of all elements related to 1 ineach case. |
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Answer» Show that
is an |
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| 3593. |
If f(x) = 3x + 10 and g(x) = x2 –1, then (fog)–1 is equal to ___________. |
| Answer» If f(x) = 3x + 10 and g(x) = x2 –1, then (fog)–1 is equal to ___________. | |
| 3594. |
Boyle's law may be represented as 1.[dp/dv]T=K/V 2.[dp/dv]T=-K/V 3.[dp/dv]T=-K/V 4.[dp/dv]T=K/V^2 |
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Answer» Boyle's law may be represented as 1.[dp/dv]T=K/V 2.[dp/dv]T=-K/V 3.[dp/dv]T=-K/V 4.[dp/dv]T=K/V^2 |
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| 3595. |
The value of definite integral ∫e1√xln(x)dx is |
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Answer» The value of definite integral ∫e1√xln(x)dx is |
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| 3596. |
Find the mean and standard deviation of each of the following probability distributions:(i) xi : 2 3 4 pi : 0.2 0.5 0.3 [NCERT EXEMPLAR](ii) xi : 1 3 4 5 pi : 0.4 0.1 0.2 0.3 (iii) xi : −5 −4 1 2 pi : 14 18 12 18 (iv) xi : −1 0 1 2 3 pi : 0.3 0.1 0.1 0.3 0.2 (v) xi : 1 2 3 4 pi : 0.4 0.3 0.2 0.1 (vi) xi : 0 1 3 5 pi : 0.2 0.5 0.2 0.1 (vii) xi : −2 −1 0 1 2 pi : 0.1 0.2 0.4 0.2 0.1 (viii) xi : −3 −1 0 1 3 pi : 0.05 0.45 0.20 0.25 0.05 (ix) xi : 0 1 2 3 4 5 pi : 16 518 29 16 19 118 [NCERT EXEMPLAR] |
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Answer» Find the mean and standard deviation of each of the following probability distributions: (i)
[NCERT EXEMPLAR] (ii)
(iii)
(iv)
(v)
(vi)
(vii)
(viii)
(ix)
[NCERT EXEMPLAR] |
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| 3597. |
If α,β are the roots of the equation ax2 +2bx +c = 0 and α+δ, β+δ are the roots of Ax2 + 2Bx + C= 0 , then b2–acB2–AC = |
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Answer» If α,β are the roots of the equation ax2 +2bx +c = 0 and α+δ, β+δ are the roots of Ax2 + 2Bx + C= 0 , then b2–acB2–AC = |
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| 3598. |
Let f:R→R satisfy the equation f(x+y)=f(x)⋅f(y) for all x,y∈R and f(x)≠0 for any x∈R. If the function f is differentiable at x=0 and f′(0)=3, then limh→01h(f(h)−1) is equal to |
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Answer» Let f:R→R satisfy the equation f(x+y)=f(x)⋅f(y) for all x,y∈R and f(x)≠0 for any x∈R. If the function f is differentiable at x=0 and f′(0)=3, then limh→01h(f(h)−1) is equal to |
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| 3599. |
How many 3-digit numbers can be formed from the digits 1, 2, 3, 4 and 5 assuming that (i) repetition of the digits is allowed? (ii) repetition of the digits is not allowed? |
| Answer» How many 3-digit numbers can be formed from the digits 1, 2, 3, 4 and 5 assuming that (i) repetition of the digits is allowed? (ii) repetition of the digits is not allowed? | |
| 3600. |
If y=xna coslogx+b sinlogx, prove that x2d2ydx2+1-2nxdydx+1+n2y=0.Disclaimer: There is a misprint in the question. It must be x2d2ydx2+1-2nxdydx+1+n2y=0 instead of x2d2ydx2+1-2ndydx+1+n2y=0. |
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Answer» Disclaimer: There is a misprint in the question. It must be instead of . |
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