InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1601. |
Let A & B be two sets containing four and two elements respectively such that A∩B=ϕ. Then the number of subsets of set A×B each having at least five elements is |
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Answer» Let A & B be two sets containing four and two elements respectively such that A∩B=ϕ. Then the number of subsets of set A×B each having at least five elements is |
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| 1602. |
Let A=[1234] and B=A=[abcd] are two matrices such that AB = BA and c≠0, then value of a−d3b−c is : |
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Answer» Let A=[1234] and B=A=[abcd] are two matrices such that AB = BA and c≠0, then value of a−d3b−c is : |
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| 1603. |
If α∈[π2,π], then the value of √1+sinα−√1−sinα is |
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Answer» If α∈[π2,π], then the value of √1+sinα−√1−sinα is |
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| 1604. |
If log2(x−1x−2)>0, then |
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Answer» If log2(x−1x−2)>0, then |
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| 1605. |
If the sum and product of the first three terms in an A.P. are 33 and 1155, respectively, then the value of its 11th term is : |
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Answer» If the sum and product of the first three terms in an A.P. are 33 and 1155, respectively, then the value of its 11th term is : |
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| 1606. |
Solve |x−1|+|x−2|≥4,xϵR |
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Answer» Solve |x−1|+|x−2|≥4,xϵR |
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| 1607. |
If two circles which pass through the points (0, a) and (0, -a) cut each other orthogonally and touch the straight line y=mx+c, then |
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Answer» If two circles which pass through the points (0, a) and (0, -a) cut each other orthogonally and touch the straight line y=mx+c, then |
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| 1608. |
The set of values of b for which f(x)=2x4+bx3+3x2, has a point of inflection |
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Answer» The set of values of b for which f(x)=2x4+bx3+3x2, has a point of inflection |
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| 1609. |
Let f = {(1, 1), (2, 3), (0, -1), (-1, -3)} be a function from Z to Z defined by f(x) = ax + b for some integer a, b. Determine a, b. |
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Answer» Let f = {(1, 1), (2, 3), (0, -1), (-1, -3)} be a function from Z to Z defined by f(x) = ax + b for some integer a, b. Determine a, b. |
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| 1610. |
The bulk modulus of a spherical object is B. If it is subjected to uniform pressure P, the fractional decrease in radius is |
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Answer» The bulk modulus of a spherical object is B. If it is subjected to uniform pressure P, the fractional decrease in radius is |
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| 1611. |
z1 and z2 are the roots of 3z2 + 3z + b = 0. If O(0), A(z1)B(z2) is an equilateral triangle, then |
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Answer» z1 and z2 are the roots of 3z2 + 3z + b = 0. If O(0), A(z1)B(z2) is an equilateral triangle, then |
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| 1612. |
If A={1,2,3,4} and B={5,7,9}, then the number of onto function from A to B is |
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Answer» If A={1,2,3,4} and B={5,7,9}, then the number of onto function from A to B is |
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| 1613. |
Find the general solution of the equation 4 sin x cos x + 2 sin x + 2 cos x +1 = 0. |
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Answer» Find the general solution of the equation 4 sin x cos x + 2 sin x + 2 cos x +1 = 0. |
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| 1614. |
For x ϵ (0,5π2), define f(x)=∫x0√tsin t dt. Then f has |
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Answer» For x ϵ (0,5π2), define f(x)=∫x0√tsin t dt. Then f has |
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| 1615. |
If one of the foci of an ellipse x2a2+y2b2=1 (a>b) coincide with the focus of the parabola y2=8x and they intersect at a point where the ordinate is double the abscissa, then the value of [b2] is(where [.] represents greatest integer function) |
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Answer» If one of the foci of an ellipse x2a2+y2b2=1 (a>b) coincide with the focus of the parabola y2=8x and they intersect at a point where the ordinate is double the abscissa, then the value of [b2] is |
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| 1616. |
nC0×n+1Cn+nC1nCn−1+nC2×n−1Cn−2+.....nCn = |
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Answer» nC0×n+1Cn+nC1nCn−1+nC2×n−1Cn−2+.....nCn = |
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| 1617. |
Positive numbers x,y and z satisfyxyz = 1081 and (log10x)(log10yz)+(log10y)(log10z)=468, then the value of (log10x)2+(log10y)2+(log10z)2 is - |
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Answer» Positive numbers x,y and z satisfy |
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| 1618. |
If k=sinπ18.sin5π18.sin7π18 then the numerical value of k is |
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Answer» If k=sinπ18.sin5π18.sin7π18 then the numerical value of k is |
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| 1619. |
If →u=→a−→b and →v=→a+→b and |→a|=|→b|=2, then |→u×→v|= |
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Answer» If →u=→a−→b and →v=→a+→b and |→a|=|→b|=2, then |→u×→v|= |
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| 1620. |
If [x]2−7[x]+10>0, then x lies in the interval(Here, [.] denotes the greatest integer function) |
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Answer» If [x]2−7[x]+10>0, then x lies in the interval |
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| 1621. |
The sum of (n+1) terms of 11+11+2+11+2+3+.......... is |
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Answer» The sum of (n+1) terms of 11+11+2+11+2+3+.......... is |
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| 1622. |
Given that f(x)=sin xx. Then f'(x)=. |
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Answer» Given that f(x)=sin xx. Then f'(x)= |
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| 1623. |
The value of 10∑r=2 rC2⋅ 10Cr is not divisible by |
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Answer» The value of 10∑r=2 rC2⋅ 10Cr is not divisible by |
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| 1624. |
If 22πsin−1x−2(a+2)2πsin−1x+8a<0 for atleast one real x, then |
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Answer» If 22πsin−1x−2(a+2)2πsin−1x+8a<0 for atleast one real x, then |
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| 1625. |
12−|x|≥1,xϵR−{−2,2} |
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Answer» 12−|x|≥1,xϵR−{−2,2} |
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| 1626. |
If the coefficient of x7 in (ax2+1bx)11 is equal to the coefficient of x−7 in (ax−1bx2)11, then ab = |
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Answer» If the coefficient of x7 in (ax2+1bx)11 is equal to the coefficient of x−7 in (ax−1bx2)11, then ab = |
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| 1627. |
List IList II (A)Let n be a number chosen randomly fromthe set of first 100 natural numbers. Thenthe probability that the value of (1+i)nis real, is (P)2(B)If the coefficient of x13 in the expansion of(1−x)5(1+x+x2+x3)4 is k, then thevalue of k4 is(Q)0.35(C)In an examination of 9 papers, a candidate has to pass in more papers than (s)he fails inorder to be successful. If the number ofways in which (s)he can be unsuccessful is 2m,then the value of m4 is (R)0.55(D)A,B,C are three events such that P(A)=0.6,P(B)=0.4,P(C)=0.5,P(A∪B)=0.8,P(A∩C)=0.3 and P(A∩B∩C)=0.2. If P(A∪B∪C)≥0.85and P(B∩C) lies in the interval [0.2,b],then the value of b is(S)1(T)0.5(U)0.25Which of the following is the only INCORRECT combination? |
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Answer» List IList II (A)Let n be a number chosen randomly fromthe set of first 100 natural numbers. Thenthe probability that the value of (1+i)nis real, is (P)2(B)If the coefficient of x13 in the expansion of(1−x)5(1+x+x2+x3)4 is k, then thevalue of k4 is(Q)0.35(C)In an examination of 9 papers, a candidate has to pass in more papers than (s)he fails inorder to be successful. If the number ofways in which (s)he can be unsuccessful is 2m,then the value of m4 is (R)0.55(D)A,B,C are three events such that P(A)=0.6,P(B)=0.4,P(C)=0.5,P(A∪B)=0.8,P(A∩C)=0.3 and P(A∩B∩C)=0.2. If P(A∪B∪C)≥0.85and P(B∩C) lies in the interval [0.2,b],then the value of b is(S)1(T)0.5(U)0.25 Which of the following is the only INCORRECT combination? |
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| 1628. |
A scientist is weighing each of 30 fishes. Their mean weight worked out is 30 gm and a standard deviaiton of 2 gm. Later, it was found that the measuring scale was misaligned and always under-reported every fish weight by 2gm. The correct mean and standard deviation (in gm) of fishes are respectively: |
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Answer» A scientist is weighing each of 30 fishes. Their mean weight worked out is 30 gm and a standard deviaiton of 2 gm. Later, it was found that the measuring scale was misaligned and always under-reported every fish weight by 2gm. The correct mean and standard deviation (in gm) of fishes are respectively: |
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| 1629. |
Let t1 and t2 be the parameters of 2 points on a parabola. What is the value of t1t2 if tangents at these points are at right angle to each other?___ |
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Answer» Let t1 and t2 be the parameters of 2 points on a parabola. What is the value of t1t2 if tangents at these points are at right angle to each other? |
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| 1630. |
The points (0, 83), (1, 3) and (82, 30) are the vertices of |
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Answer» The points (0, 83), (1, 3) and (82, 30) are the vertices of |
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| 1631. |
Total number of ordered pairs (x,y) satisfying |x|+|y|=2, sin(πx23)=1 is |
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Answer» Total number of ordered pairs (x,y) satisfying |x|+|y|=2, sin(πx23)=1 is |
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| 1632. |
The nth term of a sequence of numbers is an and given by the formula an=an−1+2n for n≥2 and a1=1.Using the above information an will be |
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Answer» The nth term of a sequence of numbers is an and given by the formula an=an−1+2n for n≥2 and a1=1. |
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| 1633. |
The standard deviation of 17 numbers is zero. Then |
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Answer» The standard deviation of 17 numbers is zero. Then |
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| 1634. |
A block is fastened at one end of a wire and is rotated in a vertical circle of radius R. Determine the ratio of change in length of the wire at the lowest point to that at the highest point of the circle. Assume that speed of the block at highest and lowest points is the same (v). |
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Answer» A block is fastened at one end of a wire and is rotated in a vertical circle of radius R. Determine the ratio of change in length of the wire at the lowest point to that at the highest point of the circle. Assume that speed of the block at highest and lowest points is the same (v). |
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| 1635. |
f:R→R is defined as f(x)=x4−6x2+12. The range of f(x) is |
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Answer» f:R→R is defined as f(x)=x4−6x2+12. The range of f(x) is |
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| 1636. |
If θ lies in the second quadrant, then the value of √1−sinθ1+sinθ + √1+sinθ1−sinθ. |
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Answer» If θ lies in the second quadrant, then the value of √1−sinθ1+sinθ + √1+sinθ1−sinθ. |
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| 1637. |
If the function f(x)=(1+|sinx|)a|sinx|,−π6<x<0b,x=0etan2xtan3x,0<x<π6, is continuous at x = 0, then |
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Answer» If the function f(x)=(1+|sinx|)a|sinx|,−π6<x<0b,x=0etan2xtan3x,0<x<π6, is continuous at x = 0, then |
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| 1638. |
If 2x−y+1=0 is a tangent to the hyperbolax2a2−y216=1, then which of the following CANNOT be sides of a right triangle? |
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Answer» If 2x−y+1=0 is a tangent to the hyperbolax2a2−y216=1, then which of the following CANNOT be sides of a right triangle? |
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| 1639. |
From the data given below, find the no of items (N) : ∑xy=120, r = 0.5, standard deviation of Y = 8, ∑x2=90, where x and y are deviations from arithmetic mean. |
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Answer» From the data given below, find the no of items (N) : ∑xy=120, r = 0.5, standard deviation of Y = 8, ∑x2=90, where x and y are deviations from arithmetic mean. |
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| 1640. |
The focus of the parabols x2=−16y is |
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Answer» The focus of the parabols x2=−16y is
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| 1641. |
Number of real solutions of the equation |x−3|3x2−10x+3=1 is |
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Answer» Number of real solutions of the equation |x−3|3x2−10x+3=1 is |
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| 1642. |
The following information are extract from the trial balance of M/s Nisha traders on 31 December, 2005. Sundry Debtors80,500Bad debts1,000Provision for bad debts5,000Additional InformationBad DebtsRs. 500 Provision is to be maintained at 2 % of Debtors. Prepare bad debts account, Provision for bad debts account and Profit and Loss account. |
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Answer» The following information are extract from the trial balance of M/s Nisha traders on 31 December, 2005. Sundry Debtors80,500Bad debts1,000Provision for bad debts5,000Additional InformationBad DebtsRs. 500 Provision is to be maintained at 2 % of Debtors. Prepare bad debts account, Provision for bad debts account and Profit and Loss account. |
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| 1643. |
∫3−1(Tan−1xx2+1+Tan−1x2+1x)dx= |
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Answer» ∫3−1(Tan−1xx2+1+Tan−1x2+1x)dx= |
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| 1644. |
If f(x)=⎧⎪⎨⎪⎩mx2+n,x<0nx+m,0≤x≤1nx3+m,x>1. For what integeres m and n does both limx→0f(x) and limx→1f(x) exist ? |
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Answer» If f(x)=⎧⎪⎨⎪⎩mx2+n,x<0nx+m,0≤x≤1nx3+m,x>1. For what integeres m and n does both limx→0f(x) and limx→1f(x) exist ? |
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| 1645. |
If cos4 x + a cos2x + 1 = 0 has atleast one solution then |
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Answer» If cos4 x + a cos2x + 1 = 0 has atleast one solution then |
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| 1646. |
Let f(x)=x1+x2 and g(x)=e−x1+[x], where [.] represents the greatest integer function. Then the number of integral value(s) of x which are not lying in the domain of f+g is |
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Answer» Let f(x)=x1+x2 and g(x)=e−x1+[x], where [.] represents the greatest integer function. Then the number of integral value(s) of x which are not lying in the domain of f+g is |
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| 1647. |
If x = 2 + 5i and 29! + 23!7! = 2ab!, then x3−5x2 + 33x - 19 = |
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Answer» If x = 2 + 5i and 29! + 23!7! = 2ab!, then x3−5x2 + 33x - 19 = |
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| 1648. |
Let f(x)={x2,x≥0ax,x<0The set of real values of a such that f(x) will have local minima at x=0, is: |
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Answer» Let f(x)={x2,x≥0ax,x<0 |
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| 1649. |
If two sets A and B are such that (A−B)=A, then A∩B= |
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Answer» If two sets A and B are such that (A−B)=A, then A∩B= |
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| 1650. |
Prove that sin26x−sin24x = sin 10x sin 2x |
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Answer» Prove that sin26x−sin24x = sin 10x sin 2x |
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