InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 3601. |
Evaluate the following limit: limx→π(x−227) |
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Answer» Evaluate the following limit: |
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| 3602. |
If in a triangle a = √3+1,b=√3−1,C=60∘ then the value of A is ? |
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Answer» If in a triangle a = √3+1,b=√3−1,C=60∘ then the value of A is ? |
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| 3603. |
Given that tan A,tan B are the roots of the equation x2−px+q=0, then the value of sin2(A+B) is |
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Answer» Given that tan A,tan B are the roots of the equation x2−px+q=0, then the value of sin2(A+B) is |
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| 3604. |
{x∈R:cos2x+2cos2x=2} is equal to |
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Answer» {x∈R:cos2x+2cos2x=2} is equal to |
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| 3605. |
The probability that at least one of the events E1 and E2 occurs is 0.6 If the probability of the simultaneous occurrence of E1 and E2 is 0.2, find P(¯E1)+P(¯E2). |
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Answer» The probability that at least one of the events E1 and E2 occurs is 0.6 If the probability of the simultaneous occurrence of E1 and E2 is 0.2, find P(¯E1)+P(¯E2). |
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| 3606. |
Let f(x) = (1+x)n = nC0 + nC1 x2 + nC2 x3 ........nCn xn. If f(1) = S1, f(w) = S2 and f(w2) = S3, find the value of nC0 + nC3 + nC6 + .......... in terms of S1, S2 and S3.[W is the complex cube root of unity] |
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Answer» Let f(x) = (1+x)n = nC0 + nC1 x2 + nC2 x3 ........nCn xn. If f(1) = S1, f(w) = S2 and f(w2) = S3, find the value of nC0 + nC3 + nC6 + .......... in terms of S1, S2 and S3.[W is the complex cube root of unity] |
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| 3607. |
Express (1+i)i in the A+iB form, Where i = √−1 |
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Answer» Express (1+i)i in the A+iB form, Where i = √−1
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| 3608. |
If 112 + 122 + 132 +142 + ........ = π26 then 112 + 132 +152 + ....... = |
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Answer» If 112 + 122 + 132 +142 + ........ = π26 then 112 + 132 +152 + ....... = |
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| 3609. |
Using the principle of mathematical induction prove that (12+22+⋯+n2)>n33 for all values of n ϵ N. Or Evaluate √16−30i |
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Answer» Using the principle of mathematical induction prove that (12+22+⋯+n2)>n33 for all values of n ϵ N. Or Evaluate √16−30i |
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| 3610. |
Let X be a set with exactly 5 elements and Y be a set with exactly 7 elements. If α is the number of one-one functions from X to Y and β is the number of onto functions from Y to X, then the value of 15!(β−α) is |
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Answer» Let X be a set with exactly 5 elements and Y be a set with exactly 7 elements. If α is the number of one-one functions from X to Y and β is the number of onto functions from Y to X, then the value of 15!(β−α) is |
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| 3611. |
Match the following Given sinA=23 and sinB=14 (1) sin(A+B)(p) 2√15−√52+5√3(2) Cos(A−B)(q) 55144(3) Tan(A−B)(r) 2√15+√512(4) Sin(A+B)sin(A−B)(s) 5√3+212 |
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Answer» Match the following |
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| 3612. |
A person standing at the junction (crossing) of two straight paths represented by the equations 2x−3y+4=0 and 3x+4y−5=0 wants to reach the path whose equation is 6x−7y+8=0 in the least time. Find equation of the path that he should follow. |
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Answer» A person standing at the junction (crossing) of two straight paths represented by the equations 2x−3y+4=0 and 3x+4y−5=0 wants to reach the path whose equation is 6x−7y+8=0 in the least time. Find equation of the path that he should follow. |
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| 3613. |
The area of triangle formed by the lines x = 0, y = 0 and xa+yb=1, a and b are positive , is |
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Answer» The area of triangle formed by the lines x = 0, y = 0 and xa+yb=1, a and b are positive , is |
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| 3614. |
12(3x5+4)≥13(x−6). |
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Answer» 12(3x5+4)≥13(x−6). |
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| 3615. |
If the angles of a triangle are in the ratio 4:1:1, then the ratio of the longest side to the perimeter is |
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Answer» If the angles of a triangle are in the ratio 4:1:1, then the ratio of the longest side to the perimeter is |
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| 3616. |
If one root of 5x2 + 13x + k = 0 is reciprocal of the other, then k is equal to : |
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Answer» If one root of 5x2 + 13x + k = 0 is reciprocal of the other, then k is equal to : |
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| 3617. |
Let xn,yn,zn,wn denote nth terms of four different arithmetic progressions with positive terms. If x4+y4+z4+w4=8 and x10+y10+z10+w10=20 then the maximum value of x20⋅y20⋅z20⋅w20 is |
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Answer» Let xn,yn,zn,wn denote nth terms of four different arithmetic progressions with positive terms. If x4+y4+z4+w4=8 and x10+y10+z10+w10=20 then the maximum value of x20⋅y20⋅z20⋅w20 is |
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| 3618. |
(A) If there is high variability in the distribution of income and wealth of the country then which value is compromised? (B) Mean and standard deviation of two distributions of 100 and 150 items are 50, 5 and 40, 6 respectively. Find the standard deviation of all the 250 items taken together. |
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Answer» (A) If there is high variability in the distribution of income and wealth of the country then which value is compromised? (B) Mean and standard deviation of two distributions of 100 and 150 items are 50, 5 and 40, 6 respectively. Find the standard deviation of all the 250 items taken together. |
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| 3619. |
Let a1,a2,…,a30 be in A.P., S=30∑i=1ai and T=15∑i=1a2i−1. If a5=27 and S−2T=75, then the value of a10 is |
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Answer» Let a1,a2,…,a30 be in A.P., S=30∑i=1ai and T=15∑i=1a2i−1. If a5=27 and S−2T=75, then the value of a10 is |
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| 3620. |
The value of limx→ 01x sin−1(2x1+x2)is |
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Answer» The value of limx→ 01x sin−1(2x1+x2)is |
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| 3621. |
If cosθ=−513 and π2 < θ < π then find the values of (i) sin 3 θ +sin 5 θ (ii) tan 3 θ |
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Answer» If cosθ=−513 and π2 < θ < π then find the values of (i) sin 3 θ +sin 5 θ (ii) tan 3 θ |
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| 3622. |
Find the sum of the product of the corresponding terms of the sequences 2, 4 ,16 and 32 128, 32, 8 ,2 12. |
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Answer» Find the sum of the product of the corresponding terms of the sequences 2, 4 ,16 and 32 128, 32, 8 ,2 12. |
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| 3623. |
5 harmonic means are inserted between 5 and 10. The common difference of corresponding A.P is. |
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Answer» 5 harmonic means are inserted between 5 and 10. The common difference of corresponding A.P is. |
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| 3624. |
if f(x) = 1x and g(x) = x2 find f(g(x)) |
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Answer» if f(x) = 1x and g(x) = x2 find f(g(x)) |
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| 3625. |
Let ‘A’, ‘B’ and ‘C’ be three independent events with P(A)=13,P(B)=12 and P(C)=14. The probability of exactly 2 of these events occurring, is equal to: |
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Answer» Let ‘A’, ‘B’ and ‘C’ be three independent events with P(A)=13,P(B)=12 and P(C)=14. The probability of exactly 2 of these events occurring, is equal to: |
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| 3626. |
A function f:(R−A)→R is defined as f(x)=x+2x2−3x+4, where R is one set of real numbers and A is a finite set of points where f(x) is not defined. Then n(A)=___. |
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Answer» A function f:(R−A)→R is defined as f(x)=x+2x2−3x+4, where R is one set of real numbers and A is a finite set of points where f(x) is not defined. Then n(A)= |
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| 3627. |
In a triangle ABC,cosAa=cosBb=cosCc If a=1√6 then the area of the triangle (in square unit) is |
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Answer» In a triangle ABC,cosAa=cosBb=cosCc If a=1√6 then the area of the triangle (in square unit) is |
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| 3628. |
Let f(x)=cosx(sinx+√sin2x+sin2θ),θ is a given const, then max of f(x)is |
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Answer» Let f(x)=cosx(sinx+√sin2x+sin2θ),θ is a given const, then max of f(x)is |
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| 3629. |
A complex number z is said to be unimodular, if |z|=1. If and z1 and z2 are complex numbers such that z1−2z22−(z1¯z2) is unimodular and z2 is not unimodular. Then, the point z1 lies on a |
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Answer» A complex number z is said to be unimodular, if |z|=1. If and z1 and z2 are complex numbers such that z1−2z22−(z1¯z2) is unimodular and z2 is not unimodular. |
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| 3630. |
For any two complex number z1 and z2 and any real numbers a and b; |(az1−bz2)|2 + |(bz1−az2)|2 = |
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Answer» For any two complex number z1 and z2 and any real numbers a and b; |(az1−bz2)|2 + |(bz1−az2)|2 =
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| 3631. |
If a=2√2i then which of the following is correct |
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Answer» If a=2√2i then which of the following is correct
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| 3632. |
The distance between two particles is decreasing at the rate of 6msec. If these particles travel with same speeds and in the same direction, then the separation increase at the rate of 4msec. The particles have speeds as |
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Answer» The distance between two particles is decreasing at the rate of 6msec. If these particles travel with same speeds and in the same direction, then the separation increase at the rate of 4msec. The particles have speeds as |
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| 3633. |
Let a1,a2,a3,............. be in harmonic progression with a1 = 5 and a20 = 25. The least positive integer n for which an < 0 is |
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Answer» Let a1,a2,a3,............. be in harmonic progression with a1 = 5 and a20 = 25. The least positive integer n for which an < 0 is |
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| 3634. |
If the digits of the number 12345 are randomly rearranged, what is the probability that the new number is divisible by (i) 3 (ii) 9 [4 MARKS] |
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Answer» If the digits of the number 12345 are randomly rearranged, what is the probability that the new number is divisible by |
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| 3635. |
50 mL of a solution containing 10−3 mole of Ag+ is mixed with 50 mL of a 0.1 M HCl solution how much Ag+ remains in solution? (Ksp of AgCl=1.0×10−10) |
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Answer» 50 mL of a solution containing 10−3 mole of Ag+ is mixed with 50 mL of a 0.1 M HCl solution how much Ag+ remains in solution? (Ksp of AgCl=1.0×10−10) |
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| 3636. |
For observations x1,x2,x3,..........,xn, if ∑ni=1(xi+1)2=9n and ∑ni=1(xi−1)2=5n., then standard deviation of the data is |
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Answer» For observations x1,x2,x3,..........,xn, if ∑ni=1(xi+1)2=9n and ∑ni=1(xi−1)2=5n., then standard deviation of the data is |
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| 3637. |
If (10)9+2(11)1(10)8+3(11)2(10)7+...+10(11)9=k(10)9, then k is equal to : |
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Answer» If (10)9+2(11)1(10)8+3(11)2(10)7+...+10(11)9=k(10)9, then k is equal to : |
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| 3638. |
Find the value of ∑10r=1rnCrnCr−1 |
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Answer» Find the value of ∑10r=1rnCrnCr−1 |
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| 3639. |
Show that the points A(0, 1, 2), B(2, -1, 3) and C(1, -3, 1) are vertices of an isosceles right angled triangle. |
| Answer» Show that the points A(0, 1, 2), B(2, -1, 3) and C(1, -3, 1) are vertices of an isosceles right angled triangle. | |
| 3640. |
The domain of the function cos−1(3x−2) is |
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Answer» The domain of the function cos−1(3x−2) is |
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| 3641. |
If the 6th, 7th and 8th terms in the expansion of (x+a)n are respectively 112, 7 and , 14, find x, a and n. |
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Answer» If the 6th, 7th and 8th terms in the expansion of (x+a)n are respectively 112, 7 and , 14, find x, a and n. |
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| 3642. |
Find the number of middle terms in the expansion of (a+b)21 __ |
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Answer» Find the number of middle terms in the expansion of (a+b)21 |
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| 3643. |
Find the asymptotes of hyperbola xy - 3y - 2x = 0 |
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Answer» Find the asymptotes of hyperbola xy - 3y - 2x = 0 |
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| 3644. |
The value oflimx→1xn+xn−1+xn−2+.......+x2+x−nx−1 |
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Answer» The value oflimx→1xn+xn−1+xn−2+.......+x2+x−nx−1 |
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| 3645. |
Two masses 90 kg and 160 kg are at a distance 5 m apart. Compute the magnitude of intensity of the gravitational field at a point distance 3m from the 90 kg and 4m from the 160 kg mass. G=6.67 × 10−11SI units.. |
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Answer» Two masses 90 kg and 160 kg are at a distance 5 m apart. Compute the magnitude of intensity of the gravitational field at a point distance 3m from the 90 kg and 4m from the 160 kg mass. G=6.67 × 10−11SI units.. |
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| 3646. |
limx→0 (x3cotx)1−cosx = [AI CBSE ; DSSE 1988] |
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Answer» limx→0 (x3cotx)1−cosx = |
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| 3647. |
If A(at2,2at),B(at2,−2at) and C(a, 0), then 2a is equal to |
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Answer» If A(at2,2at),B(at2,−2at) and C(a, 0), then 2a is equal to |
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| 3648. |
Angles made by the lines represented by the equation xy + y = 0 with y-axis are |
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Answer» Angles made by the lines represented by the equation xy + y = 0 with y-axis are |
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| 3649. |
If the ratio of the coefficient of third and fourth term in the expansion of (x−12x)n is 1:2, then the value of n will be |
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Answer» If the ratio of the coefficient of third and fourth term in the expansion of (x−12x)n is 1:2, then the value of n will be |
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| 3650. |
In how many ways a team of 10 players out of 22 players can be made if 6 particular players are always to be included and 4 particular players are always excluded. |
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Answer» In how many ways a team of 10 players out of 22 players can be made if 6 particular players are always to be included and 4 particular players are always excluded. |
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