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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 4201. |
Send all Formulas of surfaces areas and volumes |
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Answer» TSA of cuboid =2[lb×bh×lh]TSA of cube= 6(side)2CSA of cuboid=2(l+b)hCSA of cube=4a2CSA of cylinder=2πrhTSA of cylinder=2πr(r+h)CSA of cone=πrlTSA of cone=πr(r+l)SA of sphere=4πr2CSA of hemisphere=2πr2TSA of hemudphere=3πr2Volume of cuboid=l×b×hVolume cube=(side)3Volume cylinder=πr2rhVolume of cone =1/3πr2hVolume of hemisphere=2/3πr3Volume of sphere=4/3πr3 • Total surface area of a cuboid = 2[lb + bh + lh]• Total surface area of a cube = 6(side)2• Lateral surface area of a cuboid = Area of walls of a room = 2(l + b) × h• Lateral surface area of a cube = 4a2• Curved surface area of cylinder = 2πrh• Total surface area of a cylinder = 2πr(r + h)• Curved surface area of a cone = πrl• Total surface area of a cone = πr(r + l)• Surface area of a sphere = 4πr2• Curved surface area of a hemisphere = 2πr2• Total surface area of a hemisphere = 3πr2• Volume of a\'cuboid = l × b × h• Volume of a cube = (side)3• Volume of a cylinder = πr2rhSOLIDS AND THEIR SURFACE AREASThe bodies occupying space are called solids, such as a cuboid, a cube, a cylinder, a cone, a sphere, etc.These solids have plane or curved surfaces.SURFACE AREA OF A CUBOID AND A CUBEThe outer surface of a cuboid is made up of six rectangles. If we take the length of the cuboid as l, breadth as b and the height as h, thenSurface area of a cuboid = 2[lb + bh + hl]Surface area of a cube = 6a2Note:\xa0I. Sometimes a cuboid does not have bottom and top faces. is called the lateral surface area. II. Lateral surface area of a cuboid is 2(l + b)h. III. Lateral surface area of a cube is 4a2. IV. Surface area of a cuboid or cube means total surface area. |
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| 4202. |
16*2^n+1-4*2^n/16*2 ^n+2-2*2^n+2 |
| Answer» I dont no | |
| 4203. |
Find the volume of sphere whose surface area is 55.44 cm2 |
| Answer» Picture kaise daala? | |
| 4204. |
Theorem 8.10 |
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| 4205. |
If the diagonal of parallogram are equal ,then show that it is rect. |
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| 4206. |
Why parallelogram is a right angled triangles |
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| 4207. |
What will be the measure of angle which is compliment of itself |
| Answer» 45 | |
| 4208. |
(a+b)= |
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Answer» There must be square on it.. Qustion is wrong It is wrong question |
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| 4209. |
How to make the class interval continuous in a histogram |
| Answer» It should be done according to the question. | |
| 4210. |
Factorise:x^3-23x^2+142x-120 |
| Answer» Factors are ( x -1 ) ,( x-10 ), (x- 12 ) | |
| 4211. |
0\\0=2 prove that |
| Answer» Ur question is wrong | |
| 4212. |
20000÷5 |
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Answer» 4000 4000 4000 20000 ÷ 5 = 4000 |
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| 4213. |
Find the area of triangle if the side are 120 350 157 |
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Answer» A Area of triangle =1/2×base×height a=120, b=350, c=157Here a+c=120+157=277Hence a+c < bSo Such triangle is not possible ,Pl check your data a = 120b = 350c = 157a + c = 120 + 157 = 277Here a + c < bSo triangle not possible |
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| 4214. |
A cost of a notebook in 5 times in cost of a calander |
| Answer» 5 rupees | |
| 4215. |
9.1 theorum |
| Answer» Parallelograms on same base and between same parallel lines | |
| 4216. |
find the area of triangle the base is 25 cm long and the corresponding height is 10.8 CM |
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Answer» 135.0 sq cm Sq cm 135.0 |
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| 4217. |
Write formula to find area of an equilateral triangle of side \'a\' |
| Answer» Root3/4 a square | |
| 4218. |
Find the remainder when x^3 +3x^2 +3x+1 is divided by x-1 |
| Answer» 14 | |
| 4219. |
There is one and only one circle passing through three non-collinear points |
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Answer» Yes it is possible Steps - • Draw a circle with out using rounder.• take any 3 points in the circle and say A , B & C.• join them AB & BC .• draw a perpendicular bisector from AB & BC .• And where the they both intersect at a piont say O .• atlast O is the centre of a circle.I hope my answer easy to understand and satisfied you Yes |
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| 4220. |
The perpendicular from the centre of a circle to a chord bisects the chord |
| Answer» The centre of a circle lies on the perpendicular bisector of a chord of the circle in the same circle or equal circles , chord equidistant from the centre are equal in length ( chord equidistant from centre are equal.) | |
| 4221. |
find the area of right triangle whose sides containing the right angle are 5 and 6 cm |
| Answer» Height = 6cmBase = 5 cmTherefore Area of right triangle = 1/2 × base × height = 1/2 × 5 × 6 = 15 cm^2 | |
| 4222. |
Simplify:√5-√2/√5+√2+√5+√2/√5-√2 |
| Answer» =√5-√2/√5+√2+√5+√2/√5--√2=√5+√5=2√5 | |
| 4223. |
What is the radius and curved surface area of a cone made from quadrant of a circle of radius 28cm |
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| 4224. |
State and prove the mid point theorm. |
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Answer» You can refer guide all in one its better You can refer to maths textbook |
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| 4225. |
can theorems are necessary to prove in exam |
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Answer» If it is said that to prove the theorm then prove it. But otherwise it it not necessary to prove it. You only need to remember the theory. yes because they are the main reason which can give or you can score marks |
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| 4226. |
Are theorems important or proving them? |
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| 4227. |
How to prove two triangles congruent using RHS congruence rule ? |
| Answer» If the hypotenuse and a side of a right- angled triangle is equivalent to the hypotenuse and a side of the second right- angled triangle, the right triangles are said to be congruent by RHS rule.In above figure, hypotenuse XZ = RT and side YZ=ST, hence triangle XYZ ≅ triangle RST. | |
| 4228. |
ConeHeight is given 24 cm ,curved surface area of cone is 550 then find volume of cone? |
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| 4229. |
529 lcm |
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| 4230. |
Proove that two ||gms on same base and lying b/w same || lines have same areas?????? |
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| 4231. |
The perimeter of square PQRS is 40cm. Find the length of diagonal PR. |
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Answer» Underroot 20 cm PQ=QR=RS=PS=10cm So by pythagoras theorem PR=QS=2root 100 |
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| 4232. |
If x + Y + Z =0 show that x cube + y cube + Z cube = 3 x y z |
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Answer» x^3+y^3+z^3=3xyzx^3+y^3+z^3-3xyz=(x+y+z)(x^2+y^2+z^2-xy-yz-zx). x^3+y^3+z^3-3xyz=0. (because(x+y+z)=0)Therefore, x^3+y^3+z^3=3xyz. Hence proved ? TO PROVE : x^3 + y^3 + z^3 =3xyzGIVEN : x+y+z =0PROOF : [ USING IDENTITY: x^3 + y^3 + z^3 - 3xyz = (x+y+z)(x^2 + y^2 + z^2 - xy - yz - zx)] x^3 + y^3 + z^3 - 3xyz =(0)(x^2 + y^2 + z^2 -xy - yz - zx)] {GIVEN : x+y+z=0} x^3 + y^3 + z^3 - 3xyz = 0 {Any number multiplied by 0 the result is 0} x^3 + y^3 + z^3 = 3xyz {Any number is in negative on L.H.S it result as positive on R.H.S} Hence , proved that x^3 + y^3 + z^3 =3xyz { NOTIFICATION : The mark ^ represent raise to power.} |
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| 4233. |
X 12,20,27,33,x,54F 8,16,48,90,30,8If the mean is 31.87. Find the missing term |
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| 4234. |
In triangle ABC AB=AC and angle B =2\\5 of angle A .find the measure of angle A |
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| 4235. |
8+9+3*0 |
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Answer» 8+9+3×0=8+9+0=8+9=17 8+9+3×0=8+9+0=8+9÷17 |
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| 4236. |
P(x)=5x×x-3x+7 at x=1 |
| Answer» P(x) = 5x × x - 3x + 7x = 1P(1) = 5(1) × (1) - 3(1) + 7= 5 - 3 + 7= 2 + 7= 9 | |
| 4237. |
Show that in a right angle triangle hypotenuse is the longest side |
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| 4238. |
Convert the following in p\\q form0.289 |
| Answer» 289/1000 | |
| 4239. |
B square upon under root a square +b square +a |
| Answer» | |
| 4240. |
A cuboidal vessel is 10m long and 8m wide. How high must be made to hold 380m cube of liquid |
| Answer» Volume of cubical vessel = l x b x h380 = 10 x 8 x h380 = 80 x hh = 4.75Thus, the cubical vessel must be made 4.75 m high. | |
| 4241. |
Axiom and postlute |
| Answer» Axioms means universal truth that needs not to prove and postulate means a statement that has to prove | |
| 4242. |
2.93bar q=/0 |
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Answer» 27/99 291 / 100 |
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| 4243. |
2x+3y=0 |
| Answer» 2x +3y=03y =-2xY=-2x/3 | |
| 4244. |
prove (a+b)^2=a^2+2ab+b^2 |
| Answer» (a+b)^2=(a+b)(a+b)=a^2+b^2+ab+ab=a^2+b^2+2abHence proved | |
| 4245. |
Evaluate (998)3 using suitble identities? |
| Answer» 998=1000-2998³=(1000-2)³,which is in the form of (a-b) ³(a-b) ³=a³-b³-3ab(a-b)that implies, 1000³-2³-3*1000*2(1000-2)=1000000000-8-6000(998)=1000000000-5988000-8=994011992therefore, 998³=994011992 | |
| 4246. |
How do you expand(-x/2 + y + 1/4)^2 |
| Answer» (-x/2)^2+y^2+1/4^2+2(-x/2)(y)+2(y)(1/4)+2+(1/4)(-x/2)x^2/4+y^2+1/16-xy+1/2y-x/4 | |
| 4247. |
x^2+2x-3whole root (x^4+2x^3-2x^2+x-1) |
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| 4248. |
Square root of 2425 |
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Answer» 49.25 approx 49.244 |
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| 4249. |
Can you please send explain chapter 10 |
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Answer» Yeh its a tough chapter compared to others ?? Ya i had the same thinking when I first saw it but believe it totally depends on our thinking. Our thinking makes anything easy or difficult. ? Akansha but circles some look\'s tough Circles is not so tough . Just practice its theorems and exercises. You will surely understand it?? |
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| 4250. |
Verify that the sum of 2 sides of a triangle is greater than 3rd side |
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