InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 601. |
5×2+0×5+8×0+9+8 |
| Answer» =10+0+0+17=10+17=27<br>0<br>5×2+0×5+8×0+9+8= 10+0×5+8×0+9+8= 10\xa0+8×0+9 + 8= 10 + 9 + 8= 19 + 8= 27 | |
| 602. |
1. Find the sum of the sequence 7,77,777,7777,......to n terms. Please give a detailed explanation |
| Answer» 7, 77, 777, 7777 ….to n terms. Sn=7+77+777+7777+……+to n terms introducing 9 = (7/9) [9+99+999+……+ to n terms] = (7/9) [(10-1) + (100-1) + (1000-1) +……...+ to n term] = (7/9) [10+100+1000+……... n terms – (1+1+1+1+…… n terms) = (7/9) [10+100+1000+………n terms –n] \xa0Here a=10, r=10 \xa0= (7/9) [10(10n-1)/ (9) - n] | |
| 603. |
Write the relation R = [(x,x3):x is a prime number less than 10] in a roster form |
| Answer» QUESTIONWrite the relation R = {(x,\xa0x3):\xa0x\xa0is a prime number less than 10} in roster form.SOLUTIONR = {(x,\xa0x3):\xa0x\xa0is a prime number less than 10}The prime numbers less than 10 are 2, 3, 5, and 7.∴R = {(2, 8), (3, 27), (5, 125), (7, 343)} | |
| 604. |
Derivatives?? |
| Answer» hnn ? question pehle tumhara visible hua....but type krke pehle mene rkha tha...gya nii toh meri glti thodi hai??<br>???ohho....prr btya kisne mene aaneko ...toh socho mene pehle se yha ques dlne ki tyri ni ki hogi?!? | |
| 605. |
4-1 = ?? ? |
| Answer» seconds ka frk hai bss dono timing me??lol<br>??? | |
| 606. |
Tan(225°) cos(405) +tan(765°) cot(675°) =0Prove that |
| Answer» | |
| 607. |
Find trigonoometric ratios cosec(-1200) |
| Answer» Ans:- (-√3/2) | |
| 608. |
find the general solution of the equation : sin x + sin 3 x + sin 7 x |
| Answer» Oh okk thank u... But i want to know the answer...<br>General solution are deleted topic from this chapter | |
| 609. |
Find the value of cos\u2061(-960°) |
| Answer» | |
| 610. |
If y=3[x]+2 = 2[x+4] . Find the value of [x+y] a) 26 b) 20 c) 14 d) None |
| Answer» A<br>Hii Aadya ji<br>26<br>The answer is 26 [most probably]First find x3[x]+2 = 2[x+4] [given]3x +\xa02 = 2x + 83x - 2x = 8 - 2therefore x = 6Now, y=3[x]+2 or y =\xa02[x+4]\xa0Putting the value of x ,we get y = 20\xa0now x+y = 20 + 6= 26\xa0\xa0 | |
| 611. |
For any set A and B show that P(A intersection B) = P(A) Intersection P(B) |
| Answer» We have to show that P(A ∩ B) = P(A) ∩ P(B)LHS:Let x ∈ P(A ∩ B)=> x ∈ (A ∩ B)=> x ∈ A and x ∈ B .............1RHS:x ∈ P(A) ∩ P(B)=> x ∈ A and x ∈ B ............2From equation 1 and 2, we getP(A ∩ B) = P(A) ∩ P(B)Hence proved. | |
| 612. |
Integration?? |
| Answer» Hii Aadya ji | |
| 613. |
1-1 = ? ? |
| Answer» | |
| 614. |
1+1 = ? ? |
| Answer» idk | |
| 615. |
4+4-7 |
| Answer» Shi kha....<br>Bhai mzak kr rhe ho kya ?<br>1<br>1<br>Are u serious?!???sry to say this....but agr apko ye nii aata...to 11th ki maths kya ghnta solve krr paoge... | |
| 616. |
X+ygreater than 0,x+3ygreater than 60 |
| Answer» What\'s the question askingHere what to findPlzz mention<br>Ssss | |
| 617. |
Greatest integer function of [0.9 bar] |
| Answer» Hi | |
| 618. |
Which of the following are sets? Justify your answer. |
| Answer» Hi jyoti<br>What are the set<br>Where are the sets | |
| 619. |
tan a + tan b/ sin a+sin b=cot(a-b) prove that |
| Answer» You can saw from google | |
| 620. |
Challenge !!!!If |x| |
| Answer» 1<br>1/2<br>1 /2<br>1 | |
| 621. |
If X =(1,2,3,4...10),A=(1,2,5)and B=(6,7)then prove that - A intersection B\'=A |
| Answer» A=(1,2,5)B=(6,7)X is the universal set for A and B (X=(1,2,3...10)B\'=(1,2,3,4,5,6,7,8,9,10)From LHS side(1,2,3) intersection (1,2,3,4,5,6,7,8,9,10)(1,2,5)(which is equal to A) Hence it is proved<br>A=(1,2,5)B=(6,7)X is the universal set for A and B { X =(1,2,3,4...10)}B\'={1,2,3,4,5,8,9,10} from LHS side{1,2,5} intersection{1,2,3,4,5,8,9,10}{1,2,5} (which is equal to A)Hence it is proved | |
| 622. |
Find the equation of the locus of a point which is at a distance 5 from A(4,-3). |
| Answer» it is a circle whose centre is (4,-3) and radius 5 | |
| 623. |
Find the domain of f(x) = √(log1/4 + log1/3 + log1x/2) |
| Answer» Log/1/2 | |
| 624. |
Greatest integer function ?? |
| Answer» Good morning | |
| 625. |
2+2+2+ |
| Answer» 5+1?<br>ye konse ch me se hai bhai... | |
| 626. |
Can anyone answer my ques ?????? |
| Answer» Bt what was the question<br>Apna question to bolo bro.....<br>Ok if anybody else can answer | |
| 627. |
If A &B are any two sets, find the number of elements in the set A intersection ( A U B) |
| Answer» Answer is A. ...Kyonki (A U B) mein A aur B dono ke saare elements honge... So jab iska A se intersection hoga tab A aaraam se common aa jaayega?<br>A | |
| 628. |
If |x| |
| Answer» | |
| 629. |
Find the value of n!/(n-r)! Where r =4 |
| Answer» | |
| 630. |
Logarithm?? |
| Answer» | |
| 631. |
Find the sum of 17 th term of an AP,5,9,13,17....... |
| Answer» | |
| 632. |
Sin2 6x - sin2 4x = sin 2x sin10x |
| Answer» Hi<br>LHS = sin²(6x) - sin²(4x)Use the formula,(a² - b²) = (a - b)(a + b)= (sin6x -sin4x)(sin6x +sin4x)Now,Use the formula,sinC + sinD = 2sin(C+D)/2.cos(C-D)/2sinC - sinD = 2cos(C+D)/2.sin(C-D)/2={2cos(6x+4x)/2.sin(6x-4x)/2}{2sin(6x+4x)/2.cos(6x-4x)/2}={2cos5x.sinx}{2sin5x.cosx}={2sin5x.cos5x}{2sinx.cosx}Use the formula,sin2A = 2sinA.cosA= sin2(5x).sin2(x)= sin10x.sin2x =RHS | |
| 633. |
F(x)=2x√1-x^2 |
| Answer» | |
| 634. |
Whosoever support but the thing how cheap the people are becoming of India!! |
| Answer» These are nkt people , these are demons and they do not have any right to live in India. I dont know why these hell people are freea<br>Yup.. some Indian People fail to understand that it\'s cricket, it\'s a game. Some day you score,some day you don\'t ..!.....and people shouldn\'t criticise any player for not playing well in a tough situation:( | |
| 635. |
If secX =13\\5x lies in the founts quadrant . Find the value of other five trigonometric function |
| Answer» Answer:1) sec X = 13/5\xa0x lies in 4th quadrant.\xa0cos X = 1/ secx2)\xa0So,\xa0cos\xa0x\xa0=\xa05/13\xa0sin X = √ 1- cos²x3)\xa0sin\xa0X\xa0=\xa0-12/13\xa0⚆As sin functions-ve in 4th quadrant.\xa0cosec X = 1/sin X4)\xa0cosec\xa0X\xa0=\xa0-13/12⚆As\xa0cosec\xa0functions-ve\xa0in\xa04th\xa0quadrant.\xa0tan X = √ sec² x-15)tan\xa0X\xa0=\xa0-12/5\xa0⚆As tan functions-ve in 4th quadrant.\xa0Cot x = 1/ tan X6)Cot\xa0x\xa0=\xa0-5/12 | |
| 636. |
Who is फालतु here. |
| Answer» Oh nice of you?\u200d♀️<br>Vishal Pandey | |
| 637. |
Prove that cot(A+15°) -tan (A-15°) =4cos2A\\ 1+2sin2A |
| Answer» | |
| 638. |
Solve the equation cos theta + sin30 = 2cos20 |
| Answer» | |
| 639. |
If log1216 = a, then the value of log627 in terms of \'a\' is...??? |
| Answer» X^n + y^n/x^n-1 + y^n-1 =root xy | |
| 640. |
The sum of values of x satisfying the following equation is : log4(x+1) + log4(x+4) = 1... |
| Answer» | |
| 641. |
Solve for x :- 1+6log(x+2) 4 = log4(x+2) |
| Answer» F U C K<br>**** | |
| 642. |
Challenge!!!Solve for x:$$\\dfrac{d}{d cosx} (sinx)$$ |
| Answer» Answer is cot x<br>Let u =sinx and v= cosx.....d(sinx)/d (cosx)......d(u/v)= (v du + u dv )/ v².....[ cosx × d(sin x) - sinx × d(cosx)] / (cosx)²Since, d(sin x) = cos x and d(cos x) = -sin xTherefore, [(cosx)² + (Sinx)²]/ (cosx)²= 1/ (cos x)²=(secx)²<br>Mera toh kuch or hii answer arha hai...?sec²x....<br>Not x but solve it | |
| 643. |
Immediately |
| Answer» | |
| 644. |
A set which has exactly 10 elements and it through a defining property |
| Answer» | |
| 645. |
1*6583/700 |
| Answer» | |
| 646. |
If log72 = m, then log4928 is equal to..?? |
| Answer» It\'s Okay!!! ... Gud Mrng!! ?<br>Kisi ne nhi answer btaya ? | |
| 647. |
8÷2(2+2) = ? a) 16 b) 1 c) None |
| Answer» 1<br>1 according to bodmas<br>8 ÷ 2(2 + 2) =\xa08 ÷ 2(4) =\xa08÷ 8 = 1 | |
| 648. |
(x + root 1-x^2)⁴ can anyone solve this by using binomial theorem |
| Answer» | |
| 649. |
Find logx of 5root 0.96 |
| Answer» | |
| 650. |
M maths ki questions solve ni kr pata . Samaj ni atta aur pta bhi nhi chalta.Kase kru?? |
| Answer» I think apko Maths ki basic knowledge nahii hai....If I\'m right....then why did u take maths subject in 11th... agar itni hi difficulty ho rhi hai smjhne mein toh koi or subject le lete na!?!<br>aage ka ho jayega socho mat ki nahi hooga karke dekho hoga<br>just start karo ek taraf se<br>Mt kr fir | |