InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 8551. |
(x-2y) 12 |
| Answer» Typt the whole question pls | |
| 8552. |
Show that A union B=A intersection B impliesA=B |
| Answer» Let A = BAUB = A\xa0A intersection B = A implies A U B = A intersection BA = B implies AU B = intersection B ---- (1)Now let A U B = A intersection\xa0B. Then we have to prove that A = B. For this let x belongs to A implies x belongs to A U B= x belongs to A intersection B= x belongs to A and x Belongs to B= x belongs to Bso A subset of B --- (2)Now we will let y belong to B which implies y belongs to A U B\xa0= y belongs to A intersection B= y belongs to A and y belongs to B= y belongs to ATherefore, B subset of A --- (3)from (2) and (3) we get A=Bso A union B will be equal to A intersection B implies A = B ---(4)From (1) and (4) we will get A union B = A INTERSECTION B Implies A = B | |
| 8553. |
if 2 5p3=np4 find the value of n |
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| 8554. |
Rationalize 2+6√3i/5+√3i |
| Answer» | |
| 8555. |
Find modulus, argument & write the polar form for or 2 Plus 6 root 3 iota upon 5 + root 3 iota |
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| 8556. |
What is the period of function? |
| Answer» | |
| 8557. |
Maximum value of 3sinx-4cosx=? |
| Answer» 5 | |
| 8558. |
Universal sets |
| Answer» The Universal set is a set which contains all elements including itself. | |
| 8559. |
What is the minimum value of sinA |
| Answer» -1<br>0<br>0<br>-1<br>-1<br>+3 | |
| 8560. |
R={(a,b)€z ,a+b =even } prove that R is in equivalence with z |
| Answer» R is reflexive , as 2 divides a-a = 0Now (a,b){tex}\\in {/tex}R implies (a-b) is divided by 2{tex}\\Rightarrow{/tex}\xa0(b-a) is also divided by 2Hence, (b,a){tex}\\in {/tex}RHence,\xa0R is symmetric.Now ,Let a,b,c {tex}\\in{/tex}ZIf (a,b) {tex}\\in {/tex}RAnd (b,c) {tex}\\in {/tex}RThen a-b and b-c divided by 2Therefore a-b is even and b-c is even{tex}\\Rightarrow{/tex}a-b +b-c is even, as sum of two even numbers is even\xa0{tex}\\Rightarrow{/tex}(a-c) is evenSo a-c is divided by 2{tex}\\Rightarrow{/tex}(a,c) {tex}\\in {/tex}RHence it is transitive.Therefore R is reflexive,symmetric and transitiveSo R is an equivalence relation | |
| 8561. |
Show that the sum of(m+n)th and (m-n)th term of an A.P is equal to twice the (m)th term |
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| 8562. |
The function of f from R to R is defined by fx=modulus of x+1 show the graph of modulus function |
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| 8563. |
2+2+5+5+5+5+8+0+8+5+5 |
| Answer» 2 + 2 + 5 + 5 + 5 + 5 + 8 + 0 + 8 + 5 + 5=50<br>The original answer is fifty [50]<br>50<br>50<br>50<br>2+2+5+5+5+5+8+0+8+5+5= 4 + 20 + 16 + 10= 24 + 26= 50<br>50 | |
| 8564. |
If A={1,3,5,7},B={1,2,3,4}&C={2,3,5,8} find |
| Answer» What we have to find<br>What<br>0 | |
| 8565. |
Cos10° cos30° cos50° cos70° = 3/16 |
| Answer» cos 10° cos 30° cos 50° cos 70° =\xa0{tex}\\frac{3}{16}{/tex}LHS = cos 10° cos 30° cos 50° cos 70°= cos 30° cos 10° cos 50° cos 70°{tex}=\\frac{\\sqrt{3}}{2}{/tex}\xa0(cos 10° cos 50° cos 70°){tex}=\\frac{\\sqrt{3}}{2}{/tex}\xa0(cos 10° cos 50°) cos 70°{tex}=\\frac{\\sqrt{3}}{4}{/tex}\xa0(2 cos 10° cos 50°) cos 70° [Multiplying and dividing by 2]Also,{tex}\\Rightarrow{/tex}\xa02 cos A cos B = cos (A + B) + cos (A - B) ...(i){tex}=\\frac{\\sqrt{3}}{4}{/tex}\xa0cos 70° {cos (50° + 10°) + cos (10° - 50°)}{tex}=\\frac{\\sqrt{3}}{4}{/tex}\xa0cos 70° {cos 60° + cos (-40°)}Now,Cos (-x) = cos x{tex}=\\frac{\\sqrt{3}}{4}{/tex}\xa0cos\xa070° [{tex}\\frac {1} {2}{/tex}\xa0+ cos 40°] [{tex}\\because{/tex}\xa0cos 60° =\xa0{tex}\\frac {1} {2}{/tex}]{tex}=\\frac{\\sqrt{3}}{4}{/tex}\xa0cos 70° +\xa0{tex}\\frac{\\sqrt{3}}{4}{/tex}\xa0cos 70° cos 40°{tex}=\\frac{\\sqrt{3}}{4}{/tex}\xa0cos 70° +\xa0{tex}\\frac{\\sqrt{3}}{8}{/tex}\xa0(2 cos 70° cos 40°){tex}= \\frac{\\sqrt{3}}{8}{/tex}\xa0[cos 70° + cos (70° + 40°) + cos (70° - 40°)] [from (i)]{tex}= \\frac{\\sqrt{3}}{8}{/tex}\xa0[cos 70° + cos 110° + cos 30°]{tex}= \\frac{\\sqrt{3}}{8}{/tex}\xa0[cos 70° + cos (180° - 70° +\xa0{tex}\\frac{\\sqrt{3}}{2}{/tex}]{tex}= \\frac{\\sqrt{3}}{8}{/tex}\xa0[cos 70° - cos 70° +\xa0{tex}\\frac{\\sqrt{3}}{2}{/tex}] [{tex}\\because{/tex}\xa0cos (180° - x) = - cos x]{tex}=\\frac{\\sqrt{3}}{8} \\times \\frac{\\sqrt{3}}{2}=\\frac{3}{16}{/tex}= RHS | |
| 8566. |
All formulas and identities of class 10 and 11 from ncert and abd book |
| Answer» Thanks<br>Check online<br>See ncert nook of class 10 and11<br>Please give answer fastly | |
| 8567. |
Solve the following equation for x1. 4x-1×(0.5)3-2x=(1/8)x |
| Answer» -60/25 | |
| 8568. |
How we identified arrow on graph in exercise 6.2 |
| Answer» | |
| 8569. |
Varsha ke mahine ka samuchchya mein se kaun se parisimi hai or kaun se aaparisimit hai |
| Answer» | |
| 8570. |
Sin(_5467) |
| Answer» | |
| 8571. |
Find derivative of logx2 |
| Answer» 1/x^2×2x=2/x | |
| 8572. |
What is the passing criteria in 11th class |
| Answer» | |
| 8573. |
|2/x-4|>1 , x is not equal to 4. |
| Answer» All positive natural except 4 | |
| 8574. |
Class 7sylabus |
| Answer» It is if class 11 not 7 | |
| 8575. |
Class 7 ch 2 simple eqation exercise 4.4 question 5 andwer |
| Answer» It is class 11?? | |
| 8576. |
Explain venn diagram |
| Answer» The diagram comprising of two overlapping circles in which on the either sides the differences are written and in the centre the similarities are written you can simply draw it\'s figure on your copy | |
| 8577. |
Integral sin(ax+b) |
| Answer» | |
| 8578. |
Prove that : (n!)2 |
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| 8579. |
Find a relation between x and y such that the point xy is equidistant from the point 3,6 and -3,4 |
| Answer» The relation between x and y is that 3x-y=5 | |
| 8580. |
Find range and domain of x/1+x^2 |
| Answer» Domain =R Range=R | |
| 8581. |
tan(theta) + tan(2 theta) + (root 3) tan(theta) tan(2 theta) = (root 3) |
| Answer» | |
| 8582. |
50digree37\'30" change into rediyen ........ |
| Answer» Thanks<br>30"=(30/60)\'=(1/2)\'37\'30"=(37+1/2)\'=(75/2)\'=(75/2×60)degree=(5/8)degree50degree37\'30"=(50+5/8)degree=(405/8)degree(405/8)degree=phi/180×405/8radians=9phi/32radians | |
| 8583. |
500 |
| Answer» Galti se submitt hua question<br>500 = five hundred = 300 + 200 = panch soo.....<br>Did u dont know that its a number ,?What do u want to ask??? | |
| 8584. |
A 2,4,6 B a ,b |
| Answer» | |
| 8585. |
Tan69 + tan66/1-tan69tan66=-1 |
| Answer» Solved :-Tan(69+66)=Tan135 =-1<br>Bhai tera question wrong hai(Tan69+Tan66)/(1-Tan69*Tan66) = -1<br>Tan69 +tan66/1-tan69tan66 = tan (69+66) =tan135 =tan(90+45)= -tan45=-(1)=-1 | |
| 8586. |
Tan/ SEC-1 - SIN/ 1+COS = 2COT |
| Answer» Bhai \'\'angle" kaha hai<br>0 | |
| 8587. |
Why sin 5pi/ 3 gives -√3/2 rather than giving √3/2 |
| Answer» Sin 5pi/3 = sin(300) =Sin(360-60) =-Sin60 =-√3/2<br>sin5pi/3 =sin300°= sin(360-60) =sin(-60)=-sin60 = -√3/2 | |
| 8588. |
99+4577580432478 |
| Answer» 4577580432577<br>99 + 4577580432478 = 4577580432577 | |
| 8589. |
find the angle between power hand and minute hand at 4:45? |
| Answer» 25 degree | |
| 8590. |
How many has taken non medical |
| Answer» India is the second largest country where doctor and engineer are made<br>I know | |
| 8591. |
If U ={x:x |
| Answer» {2}<br>A=2,3,5,7B=2,4,6,8Then, A intersection B =(2) | |
| 8592. |
If sin=3/5 cos=-12/13 find tan(a-b) |
| Answer» | |
| 8593. |
Cosec15+sec15 = how much |
| Answer» Cosec(45-30)+sec(45-30)=Cosec(45-30)+cosec[90-(45-30)]=Cosec(45-30)+cosec(45+30)=Sin[90-(45-30)]+sin[90-(45+30)]=Sin(45+30)+sin(45-30)=2.sin45.cos30=√6/2 | |
| 8594. |
Find arg for 1-i |
| Answer» | |
| 8595. |
Find the coffecient of x in the expansion of (1-3x+7x^2)(1-x)^16 |
| Answer» | |
| 8596. |
Sin2x+2 sin4x+sin6 x |
| Answer» Question<br>This<br>I know | |
| 8597. |
If the angles of a triangle are in A.P then the measured of one angle in radian is? |
| Answer» | |
| 8598. |
Plot the graph of greatest integer function and also write the domain, codomain, and range. |
| Answer» | |
| 8599. |
Write the set A=(x:x is an integer -1 |
| Answer» In roaster form<br>-infinity to -1 tak bhai<br>...,-3,-2,-1. | |
| 8600. |
Class 11th maths syllbus sa1 &sa2 |
| Answer» Sa 1 ka half book or sa 2 Ka pura book okk | |