InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 8701. |
show that x^2+cosx is an even function |
| Answer» my answer is x^2+cosx | |
| 8702. |
3.3da 4th sum |
| Answer» | |
| 8703. |
Values of all cosec° |
| Answer» | |
| 8704. |
126*45/100+90*25/100 |
| Answer» Use calculator<br>126*45/100+90×25/100 = (5670 / 2350)(1/100) = 567 / 23500 = 0.0241276596 | |
| 8705. |
Two plants a and b of a factory |
| Answer» | |
| 8706. |
Find the number of diagonals of an octagon. |
| Answer» You can find it by nC2-n for ex. 8C2-8<br>From one point we can draw 5 diagonals and an octagon has 8 points therefore we can draw 8*5 = 40 diagonals | |
| 8707. |
Prove that: tan70=tan20+2tan50 |
| Answer» Tan70=tan(50+20)Tan(50+20)=tan50+tan20/1-tan50.tan20Tan70=tan50+tan20/1-tan50.tan20Tan70 - tan70.tan50.tan20=Tan50+tan20(by cross multiple)We know tan70.tan20=1Sotan70-tan50=tan50+tan20tan70=2tan50+tan20 | |
| 8708. |
Prove that de morgan law |
| Answer» | |
| 8709. |
How many dimentions in n sides polygon? Explain |
| Answer» | |
| 8710. |
n!(n+2)!=n!+(n+1)! |
| Answer» | |
| 8711. |
Domain and range |
| Answer» Domain is the input value of x in the equation Whereas range is the output value of y.<br>What | |
| 8712. |
Prove that :7cos^x+sin^x=4 |
| Answer» | |
| 8713. |
Class 11 maths...exercise 11.3 |
| Answer» Visit my cbse guide<br>Visit ncert solution from this app? | |
| 8714. |
If n(A)=1,then n(P(P(P(A)))) |
| Answer» 16<br>16 here<br>16 | |
| 8715. |
Find cos(55°) + cos65° + cos(75°) |
| Answer» | |
| 8716. |
let a and v the two sets such that a union b =a then a intersect b is equal |
| Answer» B<br>No its will be B | |
| 8717. |
tan70° = tan20°+2tan50° |
| Answer» Tan70=tan(20+50)Nd using the identity of tan(A+B)Tan70(1-tan20.tan50)=tan20+tan50Tan70-tan20.tan70.tan50=tan20+tan50And..tan70.tan20=tan70cot70=1NowTan70-tan50=tan20+tan50OrTan70=tan20+2tan50 | |
| 8718. |
Derivation of 1 by root 3 by first principle |
| Answer» | |
| 8719. |
solve√3cosx+sinx=√2 |
| Answer» √3 cosx +sinx = √2√3 cosx = √2 -sinxNow square both sides,3 cos²x = 2 + sin²x -2√2 sinx3(1-sin²x) = 2 + sin²x -2√2 sinx3-3sin²x = 2 + sin²x -2√2 sinx0 = -1 + 4sin²x -2√2 sinx4sin²x - 2√2 sinx - 1 = 0let y = sinx, then,4y² -2√2y -1 =0y = {2√2±√(8+16)}/8y = {2√2 ±2√6}/8y = {√2 ±√6}/4sinx = {√2 ±√6}/4x = sin inverse {√2 ±√6}/4 | |
| 8720. |
Prove that cot15/2°=root2+root3+root4+root6 |
| Answer» | |
| 8721. |
Where permutation and combination used |
| Answer» Permutations is used about no. of arrangments of anything Combination is used about no.of ways to select any thing | |
| 8722. |
Sin(n+1)xsin(n+2)x+cos(n+1)xcos(n+2)x=cosx |
| Answer» Taking LHS Let (n+1) = Aand (n+2)=BSin (n+1)xsin (n+2)x +cos (n+1)xcos (n+2)x=sinAxsinBx +cosAxcosBx=cos [(n+1)x - (n+2)x]=cos x (n+1-n-2)=cos(-x)=cosx<br>We know that,CosACosB+SinASinB=Cos (A-B)Using this IdentitySo,=Cos (n+2-n-1)x=Cosx=RHS Hence Proved. | |
| 8723. |
Prove :-Tan70° = Tan20° + Tan50° |
| Answer» Tan (A+B) by formula<br>Agar mera chehra dekhna hai tohttps://www.youtube.com/watch?v=IobHZNAPys0 par click karo<br>Your question is wrong | |
| 8724. |
,ghdfzoho |
| Answer» ❓❓❓ | |
| 8725. |
y²+4x+2y-8=0 find vertex axis focus of parabola |
| Answer» | |
| 8726. |
No NDA papers |
| Answer» Vgdfk | |
| 8727. |
Tangent function is continuous or not ? |
| Answer» | |
| 8728. |
What is the formula to find the area of trapezium |
| Answer» 1/2*(sum of parallel sides) *height<br>Hii | |
| 8729. |
Exact differential equation |
| Answer» Question of exact differential equation | |
| 8730. |
If cosA=√3/2 find the value of tan2A |
| Answer» √3 | |
| 8731. |
How can we find the square of any number easily |
| Answer» If cos A=√3/2 find the value of tan 2A | |
| 8732. |
|2x-1/x-1|>2. Solve the above system of equation in R |
| Answer» | |
| 8733. |
Straight lines ncert sum tutors video |
| Answer» Vubbub | |
| 8734. |
If f(x)=x^2-9x+20 then find f\'(x) |
| Answer» | |
| 8735. |
How can I get yesterday KVPY question paper? |
| Answer» | |
| 8736. |
If the lines ax+12y+1=0,bx +13y+1=0and cx+14y+1=0are concurrent ,then a,b,c are in * |
| Answer» | |
| 8737. |
FIND THE COEFFICIENT OF X^5 IS THE EXTENSION OF (1+2X)^6 (1-X)^7 |
| Answer» | |
| 8738. |
About zeta function |
| Answer» | |
| 8739. |
2+2=4 why |
| Answer» What class did you read<br>Because some say that 2+2 is =22 that why<br>Can I ask, this question came in your mind. why | |
| 8740. |
How to solve whole maths paper in half hour......tell me fast |
| Answer» Just take up a print out of whole answersheet lol | |
| 8741. |
Solve|4-x|+1 |
| Answer» [3,5] | |
| 8742. |
Value using binomial theorem (9999) ^4(ii) (0.998) ^8(iii)(ax-b\\x) ^6 |
| Answer» | |
| 8743. |
find two numbers whose arithmetic mean is 34 and the geometric mean is 16. |
| Answer» | |
| 8744. |
How many no. common terms in the arithmetic progression is 3,7,11,.....,407 and 2,9,16,.....,709. |
| Answer» For the first AP, a =3, d = 4Hence, any nth term would be given by 3+(n-1)4 = 4n-1Also, since 407 is the last term, so, 407 = 4n-1 i.e. maximum value of n can be 102For the second AP, a = 2, d = 7Hence any mth term would be given by 2+(m-1)7 = 7m - 5Also, since 709 is the last terms, so, 709 = 7m-5 i.e. maximum value of m can be 102To find the terms common to both the APs, we can equate the nth term of first AP to the mth term of the second AP4n -1 = 7m-54n = 7m-4Now, since n is a whole number, so 7m-4 needs to be divisible by 4.So, then, m can be equal to all multiples of 4 till 102 i.e. 4, 8, 12, 16, 20, 24, ......100So, the number of terms common to the 2 APs would be 25. > | |
| 8745. |
X2_1 |
| Answer» | |
| 8746. |
F(x)= root 1-xG(x) = rootx+2Determine (F+g)(x)= Domain and range of (F+g)(x) |
| Answer» | |
| 8747. |
Find the value of 1+2+3+.......n |
| Answer» n(n+1)/2 | |
| 8748. |
If A and B are two sets find the no. of elements in set A intetsection (AUB)^c. |
| Answer» Hi | |
| 8749. |
Suppose f{x}={a+bx,x |
| Answer» | |
| 8750. |
it is necessary to explain the answer of MCQs of maths paper |
| Answer» No, not have to explain but you are capable to do sum easily in short time<br>No only write your answer<br>how to sovle big calculations easily<br>No<br>No | |