InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 2401. |
With the help of tables, find the values, correct to places of decimals, of each of the following : tan(2015^(@)24'). |
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| 2402. |
Show that the four points with position vectors bara,barb,barc,bard are coplaner if [barb barc bard]+[barc bara bard]+[bara barb bard]=[bara barb barc] |
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Answer» `[[BARABARBBARC]` |
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| 2405. |
If (baraxxbarb)xx(barcxxbard)=[barabarbbard]barc +kbard then k = |
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Answer» `[barbbarabarc]` |
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| 2406. |
A point P(x, y) moves so that the product of the slopes of the two lines joining P to the two points (-2, 1) and (6, 5) is -4. Show that the locus is an ellipse and locate its centre. |
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| 2407. |
The probability of happening of an event is 0.6 for one experiment. In three such experiments, find the probability of happening the event at least one time. |
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| 2408. |
If n(U)= 700, n(A)= 200, n(B)= 300, n(A cap B)= 100" then"n(A' cap B')="………." |
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Answer» 400 |
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| 2409. |
Let vec(a) + m vec(b) + n vec(c )= vec(0).vec(a) xx vec(b) + vec(b) xx vec(c ) + vec(c ) xx vec(a)= vec(0) for |
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Answer» `m + N = -1` |
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| 2410. |
If sin h^(-1) (2) + sin h^(-1) (3) = x then cos h(x) = |
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Answer» `(1)/(2) (3 sqrt(5) + 2 sqrt(10))` |
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| 2411. |
Check whether the given sentence is a statement or not : "5 is a prime number" |
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| 2412. |
Solve |x-1|+|x-2|ge4,x in R. |
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Answer» Solution : Putting `x -1=0 and x-2=0`, we get `x =1 and x =2` as the critical points, These points DIVIDE the whole realline into three parts, namely`(-oo,1),[1,2) and [2,oo)`. So, we consider the following three CASES. Case I When `-ooltxlt1`. In this case, `x-1lt0 and x-2lt0`. `THEREFORE |x-1|=-(x-1)=-x+1 and|x-2|=-(x-2)=-x+2`. Now, `|x-1|+|x-2|ge4` `rArr-x+1-x+2ge4` `rArr -2x+3ge4rArr-2xge4-3rArr=-2xge1rArrxle(-1)/(2)` `rArr x in(-oo,(-1)/(2)]`. But, `-ooltxlt1.` `therefore` solution set in this case `=(-oo,(-1)/(2)]cap(-oo,1)=(-oo,(-1)/(2)]`. Case II When `1le x lt 2`. In this, case, `x-1ge0 and x-2lt0`. `therefore |x-1|=x-1and|x-2|=-(x-2)=-x+2`. Now, `|x-1|+|x-2|ge4` `rArr x-1-x+2ge4rArr-1ge4`, which is absured. So, the given inequation has no solution in `[1,2)`. Case III When `2 le x lt oo`. In this case, `x-2ge0and x-1gt0`. `therefore |x-2|=x-2 and |x-1|=x-1.` Now, `|x-1|+|x-2|ge4` `rArr x-1+x-2ge4rArr2x-3ge4 rArr2xge7 rArrxge(7)/(2)`. ALSO, in this case, we have `XGE 2`. `therefore` solution set in this case `=[(7)/(2),oo)nn[2,oo),=[(7)/(2),oo)`. Hence, from all the above cases, we have Solution set `=(-oo,(-1)/(2)]uu[(7)/(2),oo)`. |
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| 2413. |
Find (dy)/(dx) for the function (using logarithms). y = (x ^(3) sqrt ( 2+ 3x))/( (1- x ) (2 + x)) |
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| 2414. |
Let f(x) = sqrt(x-1) + sqrt(x+ 24-10sqrt(x-1)),1 lt x lt 26 be real valued function. Then f'(x)for 1 lt x lt 26 is |
| Answer» Answer :A | |
| 2416. |
The origin is shifted to (2,3) by the translation of axes. If a point P has changed as (i) (4, -3), find the coordinates of P in the originalsystem. (ii) (4, 5), find the coordinates of P in the original system. |
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Answer» (II) (6, 8) |
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| 2417. |
Consider the A.P. 18,15,12.... Find the sum to n terms of the A.P. |
| Answer» SOLUTION :`N/2[39-3N]` | |
| 2418. |
A square matrix (a_(ij)) where a_(ij)=0 for i!=j and a_(ij)=k (constant) for i=j is called |
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Answer» UNIT matrix |
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| 2419. |
Number of functions defined from f{1,2,3,4,5,6} rarr {7,8,9,10} such that the sum f(1)+f(2)+f(3)+f(4)+f(5)+f(6) is odd is ______ |
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Answer» `2^(11)` |
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| 2420. |
If (1+x)^n=C_(0)+C_(1)x+C_(2)x^2+….+C_(n)x^n then prove that(SigmaSigma)_(0 le i lt j le n ) C_(i)C_(j)^2=(n-1)^(2n)C_(n)+2^(2n) |
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Answer» Solution :L.H.S =`underset(0 LE i lt j le n )(SigmaSigma) C_(i)C_(j)^2=(n-1)^(2n)C_(n)+2^(2n)` `(C_(0)+C_(1))^2+(C_(0)+C_2)^2+....+(C_(0)+C_(n))^2+(C_1C_2)^2+(C_1+C_3)^2+....+(C_1+C_c)^2+(C_2+C_3)^2+(C_(2)+C_4)^2+....+(C_2+C_n)^2+......+(C_(n-1)+C_n)^2` `=n(C_(0)^2+C_1^2+C_2^2+....+C_n^2)+2underset(0 le i lt j le n )(SigmaSigma) C_(i)C_(j)` `n.""^(2n)C_(n)+2{2^(2n-1)-(2n !)/(2.n!n!)} "" {"from Illustration 17 "}` `=n.""^(2n)C_n+2^(2n)-""^(2n)C_n= (n-1).""^(2n)C_(n)+2^(2n)= R.H.S` |
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| 2421. |
Obtain the equation of the parabola with given conditions:Vertex (6, -3) equation of the directrix 3x - 5y + 1 =0. |
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| 2422. |
The standard deviation of some centigrade (""^@C) temperature is 5. if it is convert in Fahrenheit temperature, then find its variance. |
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Answer» 81 |
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| 2423. |
Find the slope and inclination of the line through each pair of the following points: (0, 0) and (-sqrt(3), 3) |
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| 2424. |
cot^(2) theta ((sec theta -1)/(1+ sin theta ))+ sec^(2) theta ((sin theta -1)/( 1+ sec theta ))= |
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Answer» 0 |
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| 2425. |
Find sin""(x)/(2),cos""(x)/(2)andtan""(x)/(2) in each of the following. cosx=-(1)/(3),x in quadrant III. |
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| 2426. |
Differentiate w.r.t.x Let y= (ax^(2) + bx + c)/( px^(2) + qx+ f) |
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| 2427. |
Ifx log_(e) (log _(e) x) - x^(2) + y^(2) = 4 (y gt 0), then (dy)/(dx) atx = eis equal to |
| Answer» SOLUTION :`( 2e-1)/(2Y)` | |
| 2428. |
If origin is shifted to point (1,-2) then find the new transformed form of the following equation. (i) 2x^(2) + y^(2) - 4x+ 4y =0 (ii) y^(2) - 4x + 4y + 8=0 |
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| 2429. |
If 4 sin^(2)x-8 sinx+3 le 0,0 le x le 2pi, x in |
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Answer» `[0,(PI)/(6)]` |
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| 2430. |
From a pack of 52 cards , 3 cards are drawn at random . Findthe probability of drawing exactly two aces . |
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| 2431. |
What is Kinematics? |
| Answer» SOLUTION :KINEMATICS is the branch of MECHANICS which deals with the MOTION of objects without taking force into ACCOUNT. The Greek word “kinema" means “motion”. | |
| 2432. |
If sin A=1//sqrt(10), sin B= 1//sqrt(5)where A and B are positive and acute , then A +B= |
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Answer» `(PI)/(2)` |
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| 2433. |
The orbit of the earth around the sum is an ellipse. The sun is at one of the focus of this ellipse. If the length of its major axis of this ellipse. If the leght of its major axis of this ellipse is 30 million. Km. and eccentricity is 0,.0167 then find minimum and maximum distance of the earth from the sun. |
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Answer» MINIMUM distance 147495000 km. |
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| 2434. |
Consider the G.p 3, 6, 12…Find its n^th term and sum to n terms |
| Answer» SOLUTION :`3xx2^(n-1)3(2^n-1)` | |
| 2435. |
If bara,barb,barc are any three vectors such that (bara+ barb) . barc = (bara - barb) . barc = 0 then (baraxx barb)xxbarc = |
| Answer» ANSWER :A | |
| 2436. |
Given : f(x)=x^((1)/(x)),(xgt0) has the maximum value at x=e , then |
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Answer» `E^(X)gtpi^(e)` |
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| 2439. |
The value of tan840^(@) is equal to |
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Answer» `(1)/(SQRT(3))` |
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| 2440. |
If a line through A(1, 0) meets the lines of the pair 2x^2 - xy = 0 at P and Q. If the point R is on the segment PQ such that AP, AR, AQ are in H.P then find the locus of the point R. |
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| 2441. |
A car starts from and attains the speed of 1 km/hr nad 2,ms/hr at the end of 1st and 2nd minutes. IF the car moves onstraight road, the distance travelled in 2 minutes is |
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Answer» `(1)/(4)` km |
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| 2442. |
Solve: x^(2)+x+1=0. |
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| 2443. |
A= {a, b {c, d}, e} which of the following statements are correct? phi in A |
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| 2444. |
If | cos theta{ sin theta + sqrt( sin^(2) theta + sin^(2) alpha)}|le k, then the value of k is |
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Answer» `sqrt(1+ COS^(2) alpha)` |
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| 2445. |
Triangle ABC is isosceles with AB=AC and BC=65 cm. P is a point on BC such that the perpendicular distances from P to AB and AC are 24 cm and 36 cm, respectively. The area of triangle ABC (in sq.cm is) |
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Answer» 1254 |
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| 2446. |
Prove that the product of the 2^(nd) and 3^(rd) terms of an arithmetic progression exceeds the product of the first and fourth by twice the square of the difference between the 1^(st) and 2^(nd). |
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| 2449. |
If tan.(A)/(2)=(5)/(6)andtan.(C)/(2)=(2)/(5) then determine the relation between a, b,c |
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| 2450. |
If y = log {((1 +x)/(1-x )) ^(1//4) } -1/2 Tan ^(-1) (x ), then (dy)/(dx)= |
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Answer» `X/(1-x^2)` |
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