This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
There are 10 books in a shelf with different titles:five or these have red cover and others have green cover. In how many ways can these be arranged so that the red books are placed together ? |
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Answer» Solution :There are 10 books in a SHELF with different titles, 5 of these are red COVERS and others are green covers considering 5 red COVERED books as one book, we have all TOTAL 6 books as one book, we have all total 6 books which can be arranged in "6!" ways. The FIVE red cover books arranged among themselves in 5! ways. `:.` The total number of arrangements `=5!xx6!` |
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| 2. |
Let y=f(x) be the solution of the differential equation (dy)/(dx)+k/7 x tan x=1+xtanx-sinx, where f(0)=1 and let k be the minimum value of g(x) where g(x)="max"|(sqrt(193)-1)/2cosy+cos(y+(pi)/3)-x| where yepsilonR then Number of solution of the equation f(x)=2^(x)-x^(2)+x+cosx is equal to |
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Answer» 3 So, `g(x)={(|x+7|, ,, XGE0),(|x-7|, ,, xlt0):}` So, `g(x)_("min")=7` So, `F(x)=x+cosx`s |
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| 3. |
If the tangent and normal to the hyperbola x^(2) - y^(2) = 4 at a point cut off intercepts a_(1) and a^(2) respectively on the x-axis, and b_(1) and b_(2) respectively on the y-axis, then the value of a_(1)a_(2) + b_(1)b_(2) is |
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Answer» `-1` |
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| 4. |
If z = x + iy and if the point P in the argand plane represents z , then the locus of P satisfying the equation Amplitude of (z -1) is (pi)/(2) |
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| 5. |
Let y=f(x) be the solution of the differential equation (dy)/(dx)+k/7 x tan x=1+xtanx-sinx, where f(0)=1 and let k be the minimum value of g(x) where g(x)="max"|(sqrt(193)-1)/2cosy+cos(y+(pi)/3)-x| where yepsilonR then Area bounded by y=f(x) and its inverse between x=(pi)/2 and x=(7pi)/2 is |
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Answer» Solution :`-7 LE ((sqrt(193)-1))/2 cosy+cos(y+(pi)/3) le 7` So, `g(x)={(|x+7|, ,, xge0),(|x-7|, ,, XLT0):}` So, `g(x)_("min")=7` So, `f(x)=x+cosx`s `A = 3xx2 int_(pi//2)^(3pi//2) (x-(x+cos x)dx)` `=-3xx2(SIN x)_(pi//2)^(3pi//2)` `= -6(-1-1)=12`
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| 6. |
If z = x + iy and if the point P in the argand plane represents z , then the locus of P satisfying the equation {z in C , |z - 2| = 2 |z - 1| } |
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| 7. |
Show that x + y + 1= 0 touches the circle x^(2) + y^(2) -3x + 7y 14 = 0 and find its point of contact. |
| Answer» ANSWER :B | |
| 8. |
Two integers x and y are chosen one by one with replacement from 0, 1, 2,…,100. Find the probability that |x - y| le 3. |
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| 10. |
Using elementary transformations, find the inverseof the matrices [(2,-3,3),(2,2,3),(3,-2,2)] |
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| 11. |
If the normal at any point P on the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1meets the axes in G and g respectively. Find the ratio PG : Pg |
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| 12. |
If A=[{:(2,3),(1,-4):}],B=[{:(1,-20),(-1,3):}] then verify (AB)^(-1)=B^(-1)A^(-1) |
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| 13. |
Find the area of the parallelogram whose adjcent sides are determined by the vector. |
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| 14. |
[hati-hatj hatj -hatk hatk-hati] is equal to |
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Answer» 0 |
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| 15. |
Let vec(alpha)=3hat(i)+hat(j), vec(beta)=2hat(i)-hat(j)+3hat(k)and vec(beta)=vec(beta)_(1)-vec(beta)_(2), such that vec(beta)_(1) is parallel to vec(alpha) and vec(beta)_(2) is perpendicular to alpha. Find vec(beta)_(1)xx vec(beta)_(2). |
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Answer» `(1)/(2)(hat(i)-9hat(J)+8hat(K))` |
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| 16. |
From a pack of 52 cards, 3 cards are drawn successively with replacement each time. The probability of getting atleast one king is |
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Answer» `1-(12^(3))/(13^(3))` |
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| 17. |
C_1//1-C_2//2+C_3//3-C_4//4+…+(-1)^(n-1) C_n//n= |
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Answer» `1+(1)/(2)+(1)/(3)+….(1)/(N)` |
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| 19. |
For j =0,1,2…nlet S _(j) be the area of region bounded by the x-axis and the curve ye ^(x)=sin xfor f pi le x le (j +1) pi The value of S_(o) is : |
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Answer» `1/2 (1+E ^(X))` |
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| 20. |
Number of unit squares in a chess board is |
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Answer» 204 |
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| 21. |
Let a die be loaded in such a way that even faces are twice likely to occur as the odd faces. What is the probability that a prime number will show up when the die is tossed? |
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Answer» `(1)/(3)` Probility ofgettingprime number`= (2)/(3) xx (1)/(3) +(1)/(3) xx(2)/(3) = (2)/(9)+ (2)/(9)` `= (4)/(9)` |
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| 22. |
Find the probability that in a family having 4 children, girls are in majority. |
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| 23. |
Find the equation of the circle with centre C and redius r where. C= (0,0), r= 9 |
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| 24. |
Choose the correct answer: In a box containing 100 bulbs, 10 are defective. The probability that out of a sample of 5 bulbs, none is defective is |
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Answer» `10^(-1)` |
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| 25. |
If f(x)= 2x and g(x) = (x^(2))/(2) + 1, then which of the following can be a discontinuous function? |
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Answer» `F(X) + G(x)` |
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| 26. |
Find the parametric equations of the cirlces (i) x^(2)+y^(2)=1 (ii) x^(2)+y^(2)-4x+6y-12=0 (iii) 4(x^(2)+y^(2))=9 (iv) 2x^(2)+2y^(2)=7 (v) (x-3)^(2)+(y-4)^(2)=8^(2) |
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| 27. |
A family consists of father, mother 2 daughter and 2 sons. In how many different ways can they sit at a around table if 2 daughter wish to sit on either |
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| 29. |
Find (dy)/(dx) in the following y= sin^(-1) ((2x)/(1+ x^(2))) |
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| 30. |
ABCisa rightangledisoscelestriangleswithangleB = 90 ^@if Dis a pointon A Bso thatangleDCB= 15 ^@and ifAd = 35cm, thenCD= |
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Answer» `35sqrt(2)cm ` |
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| 31. |
A coin is tossed any number of times until a head appears. If x donotes the number of tosses till head uappear then P(x ge 3)= |
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Answer» `(1)/(2)` |
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| 32. |
Let A be a 3xx3 matrix such that A [(1,2,3),(0,2,3),(0,1,1)]=[(0,0,0),(1,0,0),(0,1,0)], then A^(-1) is : |
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Answer» `[(3,1,2),(3,0,2),(1,0,1)]`
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| 33. |
If the position vector of A,B,C are 2i+3j+4k , i+2j, j+2kand vec(AB) = Pvec(AC) then P= |
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Answer» `-1/2` |
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| 34. |
Let f(x)=x^(2)e^(-2x),x gt 0. The maximum value off(x) is |
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Answer» 0 |
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| 35. |
All three roots of az^3+bz^3+cz+d=0 , z being complex number. Further , assume that the origin, z_1 and z_2 form an equilateral triangle, then : |
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Answer» All a,B,C,d have the same SIGN |
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| 36. |
Find the value of xsqrt(6x^(4) + 4x^(2) + 2) gt -2x^(2) + 5x - 4 |
| Answer» Answer :A | |
| 37. |
Let A = {a, b, c,d). If an equivalence relation R on A has exactly one equivalence class, then number of elements in R is_________ |
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| 38. |
In theintermediateexaminationa candidatehasto passin eachof his6 papers . Thenumber ofwaysin withinhe can fail is |
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Answer» 32 |
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| 39. |
Write down the set of letters forming that word Administration? |
| Answer» SOLUTION :{a,d,i,m,N,o,R,s,t} | |
| 40. |
If the system of linear equations x+2ay+az=0, x+3by+bz=0,x+4ch+cz=0 has a non zero solution then a,b,c |
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Answer» are in G.P. |
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| 41. |
Minimise Z=3x+2y subject to the constraints, x+yge8………..1 3x+5yle15…………2 xge0, yge0………..3 |
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| 42. |
If Z=cos phi+isin phi(AA phi in ((pi)/(3),pi)), then the value of arg(Z^(2)-Z) is equal to (where, arg(Z) represents the argument of the complex number Z lying in the interval (-pi, pi] and i^(2)=-1) |
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Answer» `(3phi+pi)/(2)` |
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| 43. |
Prove that (b-c)sinA +(c-a)sinB +(a-b)sinC=0 |
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| 44. |
Find the condition that the point (x,y) may lie on the line joining (1,2) and (5,-3). |
Answer» Solution : `THEREFORE` As the points A,B,C are COLLINEAR we have AREA of the triangle ABC is 0. `therefore` 1/2 {1(-3-y) + 5(y-2) + X(2+3)} = 0 or, -3-y+5y-10+5x = 0 or,5x + 4y = 13 . |
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| 45. |
A black and red dice are rolled. Find the conditional probability of obtaining a sum greater than 9, given that the black die resulted in a 5 |
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Answer» SOLUTION :If the event that the "blacl die is resulted in 5" is given then the possible ELEMENTARY cases under consideration are reduced to (5,1),(5,2),(5,3),(5,4),(5,5),(5,6). Out of these 6 cases only two cases are favourable to the event that sum of the number rolled is greater than 9. therefore Required probability =2/6=1/3. |
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| 46. |
If y=sin^(-1)(2^(x+1)/(1+4^x))," find "(dy)/(dx). |
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| 47. |
Let a solution y=y(x) of the differential equation xsqrt(x^(2)-1) dy-ysqrt(y^(2)-1)dx=0 satisfy y(2)=(2)/(sqrt3) Statement-1, y(x)=sec(sec^(-1)x-(pi)/(6)) Statement-2 : y(x) is given by (1)/(y)=(2sqrt3)/(x)-sqrt(1-(1)/(x^(2))) |
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Answer» Statement-1 is TRUE, Statement-2 is True, Statement-2 is a correct explanation for Statement-1. `xsqrt(X^(2)-1)DY=ysqrt(y^(2)-1)dx` `rArr""(1)/(ysqrt(y^(2)-1))dy=(1)/(x sqrt(x^(2)-1))dx` `rArr""int(1)/(ysqrt(y^(2)-1))dy=int(1)/(xsqrt(x^(2)-1))dx` `rArr""SEC^(-1)y=sec^(-1)x+C` It is given that `y=(2)/(sqrt3)` when x = 2 `THEREFORE""sec^(-1).(2)/(sqrt3)=sec^(-1)2+CrArr(pi)/(6)=(pi)/(3)+CrArrC=-(pi)/(6)` Putting `C=-(pi)/(6)` in (i), we get `sec^(-1)y=sec^(-1)x-(pi)/(6)"...(ii)"` `rArr""y=sec(sec^(-1)x-(pi)/(6))` so, statement-1 is true. From (ii), we have `cos^(-1)((1)/(y))=cos^(-1)((1)/(x))-(pi)/(6)` `rArr""(1)/(y)=cos{cos^(-1)((1)/(x))-(pi)/(6)}` `rArr""(1)/(y)=cos{cos^(-1)((1)/(x))}cos((pi)/(6))+sin(cos^(-1).(1)/(x))sin(pi)/(6)` `rArr""(1)/(y)=(sqrt3)/(2x)+(1)/(2)sqrt(1-(1)/(x^(2)))` So, statement-2 is false. |
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| 48. |
Let (1 + x)^(n) = 1 + a_(1)x + a_(2)x^(2) + ... + a_(n)x^(n). If a_(1),a_(2) and a_(3) are in A.P., then the value of n is |
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Answer» 4 |
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| 50. |
Match the following. {:(I." If "(3x)/((x-6)(x+k))=2/(x-6)+1/(x+k) " then "k=, "a) "0), (II." If "(3x-6)/((x-6)(x+k))=2/(x-6)+1/(x+k) " then "k=, "b) "3), (III. " If "(x-4)/(x^(2)-5x-2k)=2/(x-2)-1/(x+k)" then "k=, "c) "-1), (IV." If "(3x^(3)-2x^(2)-1)/(x^(4)+x^(2)+1)=(Ax+B)/(x^(2)+x+1)+(Cx+D)/(x^(2)+kx+1) " then "k=, "d) "-3):} |
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Answer» c, d, a, B |
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