Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

If 3x + 8 gt 2, then the smallest integer value of 5x + 12 is

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1
2
3
4

Answer :C
2.

IfDelta = {:[( a_11, a_12, a_113),( a_21,a_22,a_23) ,(a_31,a_32, a_33) ]:} and A_y is Cofactors of a_ijthen value of Deltais given by

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` a_11 A_31+ a_12A_32+a_13A_33`
` a_11A_11+a_12A_21+a_13A_31`
` a_21A_11+a_22A_12+a_23A_13`
`a_11A_11+a_21A_21+a_31A_31`

ANSWER :D
3.

Evaluate the definite integrals int_(0)^(2)(6x+3)/(x^(2)+4)dx

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ANSWER :`3LOG2+(3PI)/8`
4.

Kyle can choose between blue, black, and brown pants, white, yellow, or pink shirts, and whether or not he wears a tie to go with his shirt. How many days can Kyle go without wearing the same combination twice?

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ANSWER :18
5.

The number of value(s) of x satisfying 1-log_(g)(x+1)^(2)=1/2log_(sqrt(3))((x+5)/(x+3)) is

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SOLUTION :`1-log(3^(2))(x+1)^(2)=1/2log_(3^(1//2))((x+5)/(x+3))`
`=1-2/2log_(3)|x+1|2/2=log_(3)((x+5)/(x+3))`
`=log_(3)(3/(|x+1|))=log_(3)((x+5)/(x+3))`
`implies3/(|x+1|)=(x+5)/(x+3)`
Case I1 `x+1gt0impliesxgt-1`
`implies3(x+3)=(x+1)(x+5)`
`impliesx^(2)+3x-4=0`
`impliesx=-4` or `x=1`
`x=-4` rejected `(xgt-1)`
`:.x=1`
Case II `x+1lt0impliesxlt-1`
`3(x+3)-1(x+1)(x+5)`
`impliesx^(2)+9x+14=0`
`impliesx=-2` or `x=-7`
`:.` Set of value of `x` `={-7, -2, 1}`
6.

Find the centre of the conic 14x^(2) - 4xy + 11y^(2) - 44x - 58y +71=0

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ANSWER :`= ( 2,3)`
7.

Consider the following Statements p : A tumbler is half empty. A tumbler is half full. Then, thee combination form of"p if and only if q"is

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a TUMBLER is half empty and half full
a tumbler is half empty if and only if it is half full
Both (a) and (B)
NONE of the these

Answer :B
8.

If I = int xsin^(-1){(1)/(2)sqrt((2a-x)/(a))dx=Kx^(2)sin^(-1){(1)/(2)sqrt((2-x)/(a))}+(1)/(2a){t^((5)/(2))+4a^(2)t^((1)/(2))-(4a)/(3)t^((3)/(2))} + C , t = 2a + x, then K is equal to

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ANSWER :`0.50`
9.

underset(x rarr oo)(lim) (x^(2))/(e^(x)) is

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2
0
`OO`
1

Answer :B
10.

Find the ellipse whose vertices are (2,-2) (2,4) and e=1//3

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ANSWER :`((x-2)^(2))/(8)+((y-1)^(2))/(0)=1`
11.

x and y are the sides of two squares such that y=x-x^(2). Find the rate of change of the area of second square with respect to the area of first square.

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ANSWER :`2X^(2)-3x+1`
12.

The radical centre of the three circles described on the three sides of a triangle as diameter is ......... of the triangle

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the ORTHOCENTRE
the circumcentre
the INCENTRE
the centroid of the triangle

ANSWER :A
13.

Find the equation of the parabola which is symmetric about y-axis, and passes through the point (2,-3) .

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ANSWER :`y^(2)-2x-3y+4=0`
14.

A man on the top of a vertical tower observes a car moving at a uniform speed towards the tower on a horizontal road. If it takes 18 minutes from the angle of depression of the car to change from 30^(@) "to" 45^(@), then after this, the time taken (in minutes) by the car to reach the foot of the tower, is

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`9 (1 + SQRT(3))`
`18 (sqrt(3) - 1)`
`(9)/(2) (sqrt(3) - 1)`
`18 (1 + sqrt(3)`

ANSWER :A
15.

Find the probability of getting. (i) a prime number when a die is rolled. (ii) sum 9 when two dice are rolled. (iii) sum atleast 10 when two dice are rolled.

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Answer :`(i) (1)/(2)` `(ii) (1)/(9)` `(III) (11)/(12)`
16.

If the normal at P on the hyperbola meets the transverse axis at G, S is a foci andthe eccentricity of the hyperbola then SG : SP is equal to

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a
b
e
`1//e`

ANSWER :C
17.

Define linear combination of vectors.

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ANSWER :`BAR(a_1),bar(a_2),bar(a_3),……….(a_n)`.
18.

The value of int_(-1)^(1) (2|x| - |x|^3)dx is :

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3
`3/2`
`0`
`3/4`

ANSWER :B
19.

f : (0, pi)to R, f(x)=2x+cot x. Find the intervals in which f(x) is strictly increasing or strictly decreasing.

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ANSWER :DECREASE in `(0,(pi)/(4))`, increase in `((pi)/(4),(3PI)/(4))`, decrease in `((3pi)/(4),pi)`
20.

Evaluate the integrals by using substitution int_(0)^(1)x/(x^(2)+1)dx

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ANSWER :`1/2log2`
21.

If alpha=5/(2!xx3)+(5xx7)/(3!xx3^(2))+(5xx7xx9)/(4!xx3^(3))+...," then "alpha^(2)+4alpha=

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21
23
25
27

Answer :B
22.

Three distinguishable dice are rolled. In how many ways we can get a total 15?

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ANSWER :10
23.

vec(a)=hatj-hatk and vec( c )=hati-hatj-hatk. The vector vec(b) is such that vec(a) xx vec(b)+vec( c )=0 and vec(a)*vec(b)=3 then vec(b) = ………..

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`-hati+hatj-2hatk`
`2hati-hatj+2hatk`
`hati-hatj-2hatk`
`hati+hatj-2hatk`

ANSWER :A
24.

If f(x) = underset(nrarroo)limn^(2)(x^(1//n)-x^(1//(n+1))),xgt0 then int x f(x) dx is equal to

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`X^(2)//2`
0
`x^(2)log x - (1)/(2) x^(2) + C`
none of these

Answer :D
25.

Cosine of the angle between the lines overliner=5hati-hatj+4hatk+lamda(hati+2hatj+2hatk)and overliner=7hati+2hatj+2hatk+mu(3hati+2hatj+6hatk)is

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0
`(1)/(2)`
`(19)/(21)`
`(1)/(3)`

Answer :C
26.

f : R to R : f (x) = x^(3)is

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ONE-one and onto
one-one and into
many - one and onto
many -one and into

Answer :A
27.

Show that the function given by f(x)=e^(2x) is increasing on R.

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ANSWER :`2E^(2X)GT 0`
28.

Examine the existence of the following limits:lim_(xto0) cosecx

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Solution :L.H.L.`=lim_(xto0-)` COSECX
`=lim_(hto0)` COSEC(-h)
`=lim_(hto0)` -1/sin h`=-infty`
R.H.L.`=lim_(hto0+)`cosecx
`=lim_(hto0)`cosec(h)=`infty`
As L.H.L.neR.H.L. the LIMIT does not exist.
29.

Choose the correct answer. The general solution of a differential equation e^x dy + (y e^x + 2x) dx = 0 is...a) x e^x + x^2 = cb) x e^y + y^2 = cc) x e^y + y^2 = cd) y e^x + x^2 = c

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`X e^x + x^2 = C`
`x e^y + y^2 = c`
`y e^x + x^2 = c`
`y e^x + x^2 = c`

ANSWER :C
30.

y^(2)=4xandy^(2)=-8(x-a) intersect at points A and C. Points O(0,0), A,B (a,0), and c are concyclic. Tangents to the parabola y^(2)=4x at A and C intersect at point D and tangents to the parabola y^(2)=-8(x-a) intersect at point E. Then the area of quadrilateral DAEC is

Answer»

`96sqrt(2)`
`48sqrt(3)`
`54sqrt(5)`
`36sqrt(6)`

Solution :(1)
Solving the fiven parabolas , we have
-8(x-1)=4x
`orx=(2A)/(3)`
Therefore, the INTERSECTION are `(2a//3,pmsqrt(8a//3))`.
Now, OABC is cyclic quadrilateral.

Hence, `angleOAB` must be a right angle. So,
Slope of `OAxx` Slope of AB=-1
`or(sqrt(8a//3))/(2a//3)xx(sqrt(8a//3))/(a-(2a//3))=-1`
`ora=12`
Therefore, the coordinates of A and B are `(8,4sqrt(2))and(8,-4sqrt(2))`, respectively. So,
Length of COMMON chord `=8sqrt(2)`
Area of quadrilateral `=(1)/(2)OBxxAC`
`=(1)/(2)xx12xx8sqrt(2)`
`48sqrt(2)`
Tangent to the parabola `y^(2)=4xat(8,4sqrt(2))" is "4sqrt(2)y=2(x+8)orx-2sqrt(2)y+8=0`, which meets the x-axis at D(-8,0).
Tangent to the parabola `y^(2)=-8(x-12)at(8,4sqrt(2))" is "4sqrt(2)y=-4(x+8)+96orx+sqrt(2)y=16=0`, which meets the x-axis at E(16,0). Hence,
Area of quadrilateral `DAEC=(1)/(2)DExxAC`
`(1)/(2)xx24xx8sqrt(2)`
`=96sqrt(2)`
31.

Integrate the following functions x logx

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SOLUTION :`intx logx dx = INT logx xx X dx`
=`logx xx x^2/2 - int 1/x xx x^2/2 dx`
`(x^2logx)/2 -1/2 int x dx`
=`(x^2logx)/2 -1/2 x^2/2 +c`
=`x^2/2 logx - x^2/4 +c`
32.

Integrate the following rational functions : int((x^(3)-1)/(x^(3)+1))dx

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ANSWER :`X-log|x|-tan^(-1)x+(1)/(2)log|x^(2)+1|+c`
33.

If f : R to R is a continuous defined by f(x)=[x]cos ((2x-1)/(2))pi, where [x] denotes the greatest integer function, then f is

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DISCONTINUOUS only at non-zero INTEGRAL VALUES of x
continuous only at y
continuous only at x
discontinuous only

ANSWER :C
34.

A dice is tossed twice. Find probability of getting a number greater than 3 on each toss.

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ANSWER :`(1)/(4)`
35.

Number of Irrational terms in the expansion of (2^(1/3)+3^(1/2)+5^(1/6))^(10) is equal to :-

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Solution :Total TERMS= `.^(12)C_(2) = 66` ,
Number of rational terms = 3
Irrational terms = 66 - 3 = 63 terms.
36.

Accoding to kelper's law if a planet revolves around the sun, its trajectory is elliptical with sun sweeps equal areas is equal interyals of time. Given the ratio f magnetitude of maximum velocity (u) to minimum velocity (v) of planet as 3 and shortance distance between plonet and sun is (a)/(2). Elccentricity of elliptical orbit is

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`(2)/(3)`
`(2)/(4)`
`(2)/(1)`
`(1)/(SQRT(2))`

ANSWER :C
37.

Accoding to kelper's law if a planet revolves around the sun, its trajectory is elliptical with sun sweeps equal areas is equal interyals of time. Given the ratio f magnetitude of maximum velocity (u) to minimum velocity (v) of planet as 3 and shortance distance between plonet and sun is (a)/(2). Time taken by planet two revolves once is (ka)/(u) then k is

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`PI`
`2 SQRT(3)pi`
`(sqrt(3))/(2) pi`
none of these

Answer :B
38.

Accoding to kelper's law if a planet revolves around the sun, its trajectory is elliptical with sun sweeps equal areas is equal interyals of time. Given the ratio f magnetitude of maximum velocity (u) to minimum velocity (v) of planet as 3 and shortance distance between plonet and sun is (a)/(2). If velocity at the end of axis of the elliptical orbit is v. then magnetiduce of u, v,vare in

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A.P
H.P
G.P
none of these

Answer :C
39.

If Tan theta_(1)=k cot theta_(2) then(cos (theta_(1)+theta_(2)))/(cos (theta_(1)-theta_(2)))=

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`(1+k)/(1-k)`
`(1-k)/(1+k)`
`(k+1)/(k-1)`
`(k-1)/(k+1)`

ANSWER :B
40.

The standard deviation is not affected by the change of

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ORIGIN
SCALE
origin and scale
NONE of these

ANSWER :A
41.

int1/(x+sqrt(x^(2)-x+1))dx=Plog(x+sqrt(x^(2)-x+1))+Qlog(2x-1+2sqrt(x^(2)-x+1))+R(3/(2x-1+2sqrt(x^(2)-x+1)))+c Then the values of P, Q, R are

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`2, 3/2, 1/2`
`2, -3/2, 1/2`
`2, -3/2, -1/2`
NONE of these

Answer :C
42.

If the general solution of sin x + 3 sin 3x + sin 5 x = 0 " is " x = y then the set of all values of cos y is

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`{-1,-(SQRT(3))/(2),(sqrt(3))/(2),1}`
`{-1,(1)/(2),1}`
`{-(sqrt(3))/(2),0,1,(sqrt(3))/(2)}`
`{-1,-(1)/(2),(1)/(2),1}`

ANSWER :D
43.

If a variable line, 3x + 4y -lambda = 0 is such that the two circles x^(2)+y^(2)-2x-2y+1=0 and x^(2)+y^(2)-18x-2y+78=0 are not its opposite sides, then the set of all values of lambda is the interval

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[13, 23]
[2,17]
[12,21]
[23,31]

Solution :The GIVEN circle,
`x^(2)+y^(2)-2x-2y+1=0""...(i)`
and `x^(2)+y^(2)-18x-2y+78=0,""...(ii)`
are on the opposite side of the variable line `3x+4y-lambda = 0`. Their centres also lie in the opposite sides of the varible line.
`RARR[3(1)+4(1)-lambda][3(9)+4(1)-lambda]lt0`
[`therefore ` the points ` P(x_(1), y_(1)) and Q (x_(2), y_(2))` lie on the opposite sides of the line AX + by + c =0,
`if (ax_(1)+by_(1)+c)(ax_(2)+by_(2)+c)lt0]`
`rArr (lambda-7)(lambda-31)lt0`
`rArr lambdain(7, 31)""...(iii)`
Also, we have `|(3(1)+4(1)-lambda)/(5)|gesqrt(1+1-1)`
`(therefore" Distance of centre from the given line is greater than the radius, i.e., " (ax_(1)+by_(1)+c)/(sqrt(a^(2)+b^(2)))GE R)`
`rArr |7-lambda| ge5rArrlambdain(-oo,2] uu [12,oo)""(iv)`
and`|(3(9)+4(1)-lambda)/(5)|gesqrt((81+1-78))`
`rArr|lambda-31|ge10`
`rArrlambdain(-oo,21]uu[,oo)""...(v)`
From Eqs. (iii), (iv) and (v), we get
`lambda in [12, 21]`
44.

A point moves in a plane so that its distances PA and PB from the two fixed points A and b in the plane satisfy the relationPA - PB =k( k ne 0,)then the locus of Pis

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a PARABOLA
an elipse
a hyperbola
a BRANCH of a hyperbola

Answer :C
45.

If (2x^(2)+5)/((x+1)^(2)(x-3))=(A)/(x+1)+(B)/((x+1)^(2))+(C)(x-3) then A=

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`- (15)/(4)`
`15/4`
`9/16`
`- 9/16`

ANSWER :C
46.

Consider the following statements A is relative error in the area of a square when the relative error in its side os 0.4 B is relative error in the volume of a sphere when the relative error in its radius is 0.3 C is relative error in the surface area of a closed cylinder whose height is equal to its radius, when the relative error in its height is 0.2 D is approximate error in y = x ^(2)+ x-3 when x =2 and delta x =0.1 The ascending order of the values of errors in these statements is

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B,C,A,D
A,C,B,D
C,D,A,B
D,A,C,B

Answer :C
47.

Letf(x) = underset( n rarr oo)("Lim")underset( n=1)overset( n ) ( sum) 3^(n-1) sin^(3) ""(x)/(3^(n)) and g(x) = x- 4f(x) . Evaluate underset( x rarr 0)("Lim") ( 1+ g(x))^("cotx")

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ANSWER :`g(X) = sin x ` and l =E
48.

n whole numbers are randomly chosen and multiplied. Now, match the following lists.{:("List I","List II"),("a. The probability that the last digit is 1, 3, 7, or 9 is","p. "(8^(n)-4^(n))/(10^(n))),("b. The probability that the last digit is 2, 4,6, 8 is ","q. "(5^(n) - 4^(n))/(10^(n))),("c. The probability that the last digit is 5 is","r. " (4^(n))/(10^(n))),("d. The probability that the last digit is zero is","s. "(10^(n) - 8^(n) - 5^(n) + 4^(n))/(10^(n))):}

Answer»

`{:("a","b","C","d"),("q","s","s","R"):}`
`{:("a","b","c","d"),("r","q","q","p"):}`
`{:("a","b","c","d"),("q","p","p","s"):}`
`{:("a","b","c","d"),("q","s","p","r"):}`

Solution :a. The required event will occur if last digit in all the chosen numbers is 1, 3, 7, or 9. Therefore, the required probability is `(4//10)^(n)`.
b. The required probability is EQUAL to the probability that the last digit is 2, 4, 6, 8 and is given by
P(last digit is 1, 2, 3, 4, 6, 7, 8, 9)
-P (last digit is 1, 3, 7, 9) = `(8^(n) - 4^(n))/(10^(n))`
c. P(1, 3, 5, 7, 9) - P(1, 3, 7, 9) = `(5^(n) - 4^(n))/(10^(n))`
d. The required probability is
`P(0, 5) - P(5) = ((10^(n) - 8^(n))-(5^(n) - 4^(n)))/(10^(n))`
`P(0, 5) - P(5) = ((10^(n) - 8^(n))-(5^(n) - 4^(n)))/(10^(n))`
49.

If x ge 0, y ge 0, 2x+y le10 and x+2y ge 10 then the minimum value of f=x+y is

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4
5
0
2

Answer :D
50.

If int_(0)^(oo) (log(1+x^(2)))/(1+x^(2))dx=kint_(0)^(oo) (log(1+x))/(1+x^(2))dx, then k=

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4
8
`PI`
`2PI`

ANSWER :B