This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
If 3x + 8 gt 2, then the smallest integer value of 5x + 12 is |
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Answer» 1 |
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| 2. |
IfDelta = {:[( a_11, a_12, a_113),( a_21,a_22,a_23) ,(a_31,a_32, a_33) ]:} and A_y is Cofactors of a_ijthen value of Deltais given by |
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Answer» ` a_11 A_31+ a_12A_32+a_13A_33` |
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| 4. |
Kyle can choose between blue, black, and brown pants, white, yellow, or pink shirts, and whether or not he wears a tie to go with his shirt. How many days can Kyle go without wearing the same combination twice? |
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| 5. |
The number of value(s) of x satisfying 1-log_(g)(x+1)^(2)=1/2log_(sqrt(3))((x+5)/(x+3)) is |
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Answer» `=1-2/2log_(3)|x+1|2/2=log_(3)((x+5)/(x+3))` `=log_(3)(3/(|x+1|))=log_(3)((x+5)/(x+3))` `implies3/(|x+1|)=(x+5)/(x+3)` Case I1 `x+1gt0impliesxgt-1` `implies3(x+3)=(x+1)(x+5)` `impliesx^(2)+3x-4=0` `impliesx=-4` or `x=1` `x=-4` rejected `(xgt-1)` `:.x=1` Case II `x+1lt0impliesxlt-1` `3(x+3)-1(x+1)(x+5)` `impliesx^(2)+9x+14=0` `impliesx=-2` or `x=-7` `:.` Set of value of `x` `={-7, -2, 1}` |
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| 6. |
Find the centre of the conic 14x^(2) - 4xy + 11y^(2) - 44x - 58y +71=0 |
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| 7. |
Consider the following Statements p : A tumbler is half empty. A tumbler is half full. Then, thee combination form of"p if and only if q"is |
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Answer» a TUMBLER is half empty and half full |
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| 8. |
If I = int xsin^(-1){(1)/(2)sqrt((2a-x)/(a))dx=Kx^(2)sin^(-1){(1)/(2)sqrt((2-x)/(a))}+(1)/(2a){t^((5)/(2))+4a^(2)t^((1)/(2))-(4a)/(3)t^((3)/(2))} + C , t = 2a + x, then K is equal to |
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| 10. |
Find the ellipse whose vertices are (2,-2) (2,4) and e=1//3 |
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| 11. |
x and y are the sides of two squares such that y=x-x^(2). Find the rate of change of the area of second square with respect to the area of first square. |
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| 12. |
The radical centre of the three circles described on the three sides of a triangle as diameter is ......... of the triangle |
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Answer» the ORTHOCENTRE |
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| 13. |
Find the equation of the parabola which is symmetric about y-axis, and passes through the point (2,-3) . |
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| 14. |
A man on the top of a vertical tower observes a car moving at a uniform speed towards the tower on a horizontal road. If it takes 18 minutes from the angle of depression of the car to change from 30^(@) "to" 45^(@), then after this, the time taken (in minutes) by the car to reach the foot of the tower, is |
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Answer» `9 (1 + SQRT(3))` |
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| 15. |
Find the probability of getting. (i) a prime number when a die is rolled. (ii) sum 9 when two dice are rolled. (iii) sum atleast 10 when two dice are rolled. |
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| 16. |
If the normal at P on the hyperbola meets the transverse axis at G, S is a foci andthe eccentricity of the hyperbola then SG : SP is equal to |
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Answer» a |
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| 19. |
f : (0, pi)to R, f(x)=2x+cot x. Find the intervals in which f(x) is strictly increasing or strictly decreasing. |
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| 20. |
Evaluate the integrals by using substitution int_(0)^(1)x/(x^(2)+1)dx |
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| 21. |
If alpha=5/(2!xx3)+(5xx7)/(3!xx3^(2))+(5xx7xx9)/(4!xx3^(3))+...," then "alpha^(2)+4alpha= |
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Answer» 21 |
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| 22. |
Three distinguishable dice are rolled. In how many ways we can get a total 15? |
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| 23. |
vec(a)=hatj-hatk and vec( c )=hati-hatj-hatk. The vector vec(b) is such that vec(a) xx vec(b)+vec( c )=0 and vec(a)*vec(b)=3 then vec(b) = ……….. |
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Answer» `-hati+hatj-2hatk` |
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| 24. |
If f(x) = underset(nrarroo)limn^(2)(x^(1//n)-x^(1//(n+1))),xgt0 then int x f(x) dx is equal to |
| Answer» Answer :D | |
| 25. |
Cosine of the angle between the lines overliner=5hati-hatj+4hatk+lamda(hati+2hatj+2hatk)and overliner=7hati+2hatj+2hatk+mu(3hati+2hatj+6hatk)is |
| Answer» Answer :C | |
| 26. |
f : R to R : f (x) = x^(3)is |
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Answer» ONE-one and onto |
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| 28. |
Examine the existence of the following limits:lim_(xto0) cosecx |
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Answer» Solution :L.H.L.`=lim_(xto0-)` COSECX `=lim_(hto0)` COSEC(-h) `=lim_(hto0)` -1/sin h`=-infty` R.H.L.`=lim_(hto0+)`cosecx `=lim_(hto0)`cosec(h)=`infty` As L.H.L.neR.H.L. the LIMIT does not exist. |
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| 29. |
Choose the correct answer. The general solution of a differential equation e^x dy + (y e^x + 2x) dx = 0 is...a) x e^x + x^2 = cb) x e^y + y^2 = cc) x e^y + y^2 = cd) y e^x + x^2 = c |
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Answer» `X e^x + x^2 = C` |
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| 30. |
y^(2)=4xandy^(2)=-8(x-a) intersect at points A and C. Points O(0,0), A,B (a,0), and c are concyclic. Tangents to the parabola y^(2)=4x at A and C intersect at point D and tangents to the parabola y^(2)=-8(x-a) intersect at point E. Then the area of quadrilateral DAEC is |
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Answer» `96sqrt(2)` Solving the fiven parabolas , we have -8(x-1)=4x `orx=(2A)/(3)` Therefore, the INTERSECTION are `(2a//3,pmsqrt(8a//3))`. Now, OABC is cyclic quadrilateral. Hence, `angleOAB` must be a right angle. So, Slope of `OAxx` Slope of AB=-1 `or(sqrt(8a//3))/(2a//3)xx(sqrt(8a//3))/(a-(2a//3))=-1` `ora=12` Therefore, the coordinates of A and B are `(8,4sqrt(2))and(8,-4sqrt(2))`, respectively. So, Length of COMMON chord `=8sqrt(2)` Area of quadrilateral `=(1)/(2)OBxxAC` `=(1)/(2)xx12xx8sqrt(2)` `48sqrt(2)` Tangent to the parabola `y^(2)=4xat(8,4sqrt(2))" is "4sqrt(2)y=2(x+8)orx-2sqrt(2)y+8=0`, which meets the x-axis at D(-8,0). Tangent to the parabola `y^(2)=-8(x-12)at(8,4sqrt(2))" is "4sqrt(2)y=-4(x+8)+96orx+sqrt(2)y=16=0`, which meets the x-axis at E(16,0). Hence, Area of quadrilateral `DAEC=(1)/(2)DExxAC` `(1)/(2)xx24xx8sqrt(2)` `=96sqrt(2)` |
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| 31. |
Integrate the following functions x logx |
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Answer» SOLUTION :`intx logx dx = INT logx xx X dx` =`logx xx x^2/2 - int 1/x xx x^2/2 dx` `(x^2logx)/2 -1/2 int x dx` =`(x^2logx)/2 -1/2 x^2/2 +c` =`x^2/2 logx - x^2/4 +c` |
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| 32. |
Integrate the following rational functions : int((x^(3)-1)/(x^(3)+1))dx |
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| 33. |
If f : R to R is a continuous defined by f(x)=[x]cos ((2x-1)/(2))pi, where [x] denotes the greatest integer function, then f is |
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Answer» DISCONTINUOUS only at non-zero INTEGRAL VALUES of x |
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| 34. |
A dice is tossed twice. Find probability of getting a number greater than 3 on each toss. |
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| 35. |
Number of Irrational terms in the expansion of (2^(1/3)+3^(1/2)+5^(1/6))^(10) is equal to :- |
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Answer» Number of rational terms = 3 Irrational terms = 66 - 3 = 63 terms. |
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| 36. |
Accoding to kelper's law if a planet revolves around the sun, its trajectory is elliptical with sun sweeps equal areas is equal interyals of time. Given the ratio f magnetitude of maximum velocity (u) to minimum velocity (v) of planet as 3 and shortance distance between plonet and sun is (a)/(2). Elccentricity of elliptical orbit is |
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Answer» `(2)/(3)` |
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| 37. |
Accoding to kelper's law if a planet revolves around the sun, its trajectory is elliptical with sun sweeps equal areas is equal interyals of time. Given the ratio f magnetitude of maximum velocity (u) to minimum velocity (v) of planet as 3 and shortance distance between plonet and sun is (a)/(2). Time taken by planet two revolves once is (ka)/(u) then k is |
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Answer» `PI` |
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| 38. |
Accoding to kelper's law if a planet revolves around the sun, its trajectory is elliptical with sun sweeps equal areas is equal interyals of time. Given the ratio f magnetitude of maximum velocity (u) to minimum velocity (v) of planet as 3 and shortance distance between plonet and sun is (a)/(2). If velocity at the end of axis of the elliptical orbit is v. then magnetiduce of u, v,vare in |
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Answer» A.P |
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| 39. |
If Tan theta_(1)=k cot theta_(2) then(cos (theta_(1)+theta_(2)))/(cos (theta_(1)-theta_(2)))= |
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Answer» `(1+k)/(1-k)` |
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| 40. |
The standard deviation is not affected by the change of |
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Answer» ORIGIN |
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| 41. |
int1/(x+sqrt(x^(2)-x+1))dx=Plog(x+sqrt(x^(2)-x+1))+Qlog(2x-1+2sqrt(x^(2)-x+1))+R(3/(2x-1+2sqrt(x^(2)-x+1)))+c Then the values of P, Q, R are |
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Answer» `2, 3/2, 1/2` |
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| 42. |
If the general solution of sin x + 3 sin 3x + sin 5 x = 0 " is " x = y then the set of all values of cos y is |
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Answer» `{-1,-(SQRT(3))/(2),(sqrt(3))/(2),1}` |
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| 43. |
If a variable line, 3x + 4y -lambda = 0 is such that the two circles x^(2)+y^(2)-2x-2y+1=0 and x^(2)+y^(2)-18x-2y+78=0 are not its opposite sides, then the set of all values of lambda is the interval |
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Answer» [13, 23] `x^(2)+y^(2)-2x-2y+1=0""...(i)` and `x^(2)+y^(2)-18x-2y+78=0,""...(ii)` are on the opposite side of the variable line `3x+4y-lambda = 0`. Their centres also lie in the opposite sides of the varible line. `RARR[3(1)+4(1)-lambda][3(9)+4(1)-lambda]lt0` [`therefore ` the points ` P(x_(1), y_(1)) and Q (x_(2), y_(2))` lie on the opposite sides of the line AX + by + c =0, `if (ax_(1)+by_(1)+c)(ax_(2)+by_(2)+c)lt0]` `rArr (lambda-7)(lambda-31)lt0` `rArr lambdain(7, 31)""...(iii)` Also, we have `|(3(1)+4(1)-lambda)/(5)|gesqrt(1+1-1)` `(therefore" Distance of centre from the given line is greater than the radius, i.e., " (ax_(1)+by_(1)+c)/(sqrt(a^(2)+b^(2)))GE R)` `rArr |7-lambda| ge5rArrlambdain(-oo,2] uu [12,oo)""(iv)` and`|(3(9)+4(1)-lambda)/(5)|gesqrt((81+1-78))` `rArr|lambda-31|ge10` `rArrlambdain(-oo,21]uu[,oo)""...(v)` From Eqs. (iii), (iv) and (v), we get `lambda in [12, 21]` |
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| 44. |
A point moves in a plane so that its distances PA and PB from the two fixed points A and b in the plane satisfy the relationPA - PB =k( k ne 0,)then the locus of Pis |
| Answer» Answer :C | |
| 45. |
If (2x^(2)+5)/((x+1)^(2)(x-3))=(A)/(x+1)+(B)/((x+1)^(2))+(C)(x-3) then A= |
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Answer» `- (15)/(4)` |
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| 46. |
Consider the following statements A is relative error in the area of a square when the relative error in its side os 0.4 B is relative error in the volume of a sphere when the relative error in its radius is 0.3 C is relative error in the surface area of a closed cylinder whose height is equal to its radius, when the relative error in its height is 0.2 D is approximate error in y = x ^(2)+ x-3 when x =2 and delta x =0.1 The ascending order of the values of errors in these statements is |
| Answer» Answer :C | |
| 47. |
Letf(x) = underset( n rarr oo)("Lim")underset( n=1)overset( n ) ( sum) 3^(n-1) sin^(3) ""(x)/(3^(n)) and g(x) = x- 4f(x) . Evaluate underset( x rarr 0)("Lim") ( 1+ g(x))^("cotx") |
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| 48. |
n whole numbers are randomly chosen and multiplied. Now, match the following lists.{:("List I","List II"),("a. The probability that the last digit is 1, 3, 7, or 9 is","p. "(8^(n)-4^(n))/(10^(n))),("b. The probability that the last digit is 2, 4,6, 8 is ","q. "(5^(n) - 4^(n))/(10^(n))),("c. The probability that the last digit is 5 is","r. " (4^(n))/(10^(n))),("d. The probability that the last digit is zero is","s. "(10^(n) - 8^(n) - 5^(n) + 4^(n))/(10^(n))):} |
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Answer» `{:("a","b","C","d"),("q","s","s","R"):}` b. The required probability is EQUAL to the probability that the last digit is 2, 4, 6, 8 and is given by P(last digit is 1, 2, 3, 4, 6, 7, 8, 9) -P (last digit is 1, 3, 7, 9) = `(8^(n) - 4^(n))/(10^(n))` c. P(1, 3, 5, 7, 9) - P(1, 3, 7, 9) = `(5^(n) - 4^(n))/(10^(n))` d. The required probability is `P(0, 5) - P(5) = ((10^(n) - 8^(n))-(5^(n) - 4^(n)))/(10^(n))` `P(0, 5) - P(5) = ((10^(n) - 8^(n))-(5^(n) - 4^(n)))/(10^(n))` |
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| 49. |
If x ge 0, y ge 0, 2x+y le10 and x+2y ge 10 then the minimum value of f=x+y is |
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Answer» 4 |
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