Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Two cards are drawn from a pack of 52 cards . What is the probability of getting both kings if the card drawn in first draw is replaced before 2^(nd) draw.

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ANSWER :`(1)/(169)`
2.

Consider a game played by 10 prople in which each flips a fair coin at the same time. If all but one of the coins comes up the same, then the add persons wing (e.g., if there are nine tails and one head then person having lead wins.) If such a situation does not occur, the players flips again. Find the probability that game is settled on or after nth toss.

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SOLUTION :(i) the probability that ONE GETS tail and nine get head is `""^(10)C_(1)1/2((1)/(2))^(9)`
(ii) The probability that one gets head and nine hets tail is `""^(10)C_(1)1/2((1)/(2))^(9)`
Hence, probability that the game is settled is
`2xx""^(10)C_(1)1/2((1)/(2))^(9)=(5)/(2^(8))`
If the game is not settled in the FIRST TOSS, its probability is `1-5//2^(8).` If the game is not settled in the second toss, its probability is `(1-5//2^(8))^(n-1),` whihc isequal to the probability that the game is settled on or after the nth toss.
3.

Let I_(1)=int_(0)^(oo)ln(x+1/x)(dx)/(1+x^(2)) and l_(2)=int_(0)^(pi//2)((theta)/(sintheta))^(2)d theta, then which of the following is/are correct?

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`I_(1)gtI_(2)`
`I_(2)gtI_(1)`
`I_(1)=I_(2)`
`I_(1)+I_(2)=0`

SOLUTION :`I_(2)=int_(0)^(pi//2)((theta)/(sintheta))^(2) d theta=int_(0)^(pi//2) theta^(2)cosec^(2) theta d theta`
`=[-theta^(2) cot theta]_(0)^(pi//2)+int_(0)^(pi//2) 2 theta cot theta d theta`
Use: integration by parts
`=- int_(0)^(pi//2)L nsin theta=pi l n 2`
`I_(1)=int_(0)^(oo)ln(X+1/x)(dx)/(1+x^(2))`
Let `tan^(-1)x = theta`
`=int_(0)^(pi//2)l n (tan theta+cot theta) d theta`
`=-int_(0)^(pi//2)(ln sin theta+l n cos theta) d theta=pi l N2`
`:.I_(1)=I_(2)`
4.

Let f :R ^(+) to R be a differentiable function with f (1)=3 and satisfying : int _(1) ^(xy) f(t) dt =y int_(1) ^(x) f (t) dt +x int_(1) ^(y) f (t) dt AA x, y in R^(+), then f (e) =

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3
4
1
None of these

Answer :D
5.

Findthe valuesof a,b,c,d, if 1,2,3,4are therootsof x^4+ax^3 +bx^2 +cx+d=0

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ANSWER :`-10 ,35,-50,24`
6.

Find the number of ways of selecting 5 objects from 9 dissimilar objects such that a particular object is included

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ANSWER :`""^8C_4`
7.

Find the number of ways of selecting 5 objects from 9 dissimilar objects such that a particular object is not included

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ANSWER :`""^8C_5`
8.

Integrate the following int(dx)/(x{(Inx)^2+25}

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Solution :`int(dx)/(X{(INX)^2+25}`
[ put `Inx=5tantheta` then `(1/x)dx=5sec^2thetad theta`
`int(5sec^2theta d theta)/(25+25tan^2theta)`
`(1/5)int(sec^2theta)/seca^2theta d theta=(1/5)INTD theta`
`(1/5)tan^(-1)(Inx/5)+C`
9.

If two cards are drawn from a pack, find the probability of getting one king and one queen or both red.

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ANSWER :`(337)/(1326)`
10.

If the vectors ai + j + k, I + bj + k, I + j + ck (a != b, c != 1) are coplanar, then the value of (1)/(1 -a) + (1)/(1 -b ) + (1)/(1 - c) =

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0
3
2
1

Answer :D
11.

Let F(x) bet the area bounded by the curve f(t)=(e^(t))/(t) between t=a (a gt 1), t=x and axis of abscissa then the area bounded by g(t)=(e^(t))/(1+t_(0)) (t_(0) gt 0) betweent = a,t = x and axis of abscissais

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`E^(t_(0))[F(x+t_(0))-2F(a+t_(0))]`
`e^(t_(0))[F(x+t_(0))-F(a+t_(0))]`
`e^(-t_(0))[F(x+t_(0))-F(a+t_(0))]`
`e^(-t_(0))[F(x+t_(0))-F(a+t_(0))]`

Answer :C
12.

Verify that|P({a})| =2^1

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<P>

SOLUTION :LET `A ={a} then P(A)={{a},PHI}`
`:.` P(A)=2=2^1`
13.

If n be a natural number define polynomial f_(n)(x) of n^(th) degree as follows f_(n)(costheta)cosntheta i.e. f_(2)(x)=2x^(2)-1 f_(3)(x)=4x^(3)-3x_(1) Then f_(6)(x) is equal to

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`36x^(6)-48X^(4)+18X^(2)-5`
`32x^(6)-48x^(4)+18x^(2)-1`
`36x^(6)-45X^(4)+18x^(2)-8`
`36x^(6)-48x^(4)+18x^(2)-7`

SOLUTION :As, `f(x)=x` & `cos(n+1)theta+cos(n-1)theta=2cos(ntheta).COSTHETA`
`f_((n+1))(x)+f_((n-1))=2x.f_(n)(x)`
`f_(n)(x)=1/(2x)[f_(n+1)(x)+f_(n-1)(x)]`
Now, Put `x=costheta, impliessqrt(x^(2)-1)=isintheta`
`(x+sqrt(x^(2)-1))^(10)+(x-sqrt(x^(2)-1))^(10)=(costheta+isintheta)^(10)+(costheta-isintheta)^(10)`
`=2cos(10theta)=2f_(10)(costheta)=2f_(10)(x)`
14.

If n be a natural number define polynomial f_(n)(x) of n^(th) degree as follows f_(n)(costheta)cosntheta i.e. f_(2)(x)=2x^(2)-1 f_(3)(x)=4x^(3)-3x_(1) Then (x+sqrt(x^(2)-1))^(10)+(x-sqrt(x^(2)-1s))^(10) is equal to

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`f_(10)(x)`
`f_(11)(x)+f_(9)(x)`
`f_(11)(x)`
`2f_(10)(x)`

SOLUTION :As, `f(x)=x` & `cos(N+1)theta+cos(n-1)theta=2cos(ntheta).costheta`
`f_((n+1))(x)+f_((n-1))=2x.f_(n)(x)`
`f_(n)(x)=1/(2x)[f_(n+1)(x)+f_(n-1)(x)]`
Now, Put `x=costheta, impliessqrt(x^(2)-1)=isintheta`
`(x+sqrt(x^(2)-1))^(10)+(x-sqrt(x^(2)-1))^(10)=(costheta+isintheta)^(10)+(costheta-isintheta)^(10)`
`=2cos(10theta)=2f_(10)(costheta)=2f_(10)(x)`
15.

Theproductof all therealrootsofX^2 - 8x+9-(8)/(x)+(1)/(x^2)=0is

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2
1
3
7

Answer :B
16.

1+ 1/(2!)+2/(3!)+4/(2!)+ .... oo =

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`E^2`
`e^(2) +1`
`e^(2) -1`
`1/4 (e^(2) +1)`

ANSWER :D
17.

If S_n denotes the sum of first n natural number then S_1 + S_2x + S_3 x^2 +……+S_n x^(n-1) + ……oo terms =

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`(1 -X )^(-1)`
`(1-x)^(-2)`
`(1 -x)^(-3)`
`(1 - x)^(-4)`

Answer :C
18.

Find the coordinates of the vertex and focus, and the equtions of the directrix and axes of the followingparabolas.

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`y^(2)=16X`
`x^(2)=-4Y`
`3x^(2)-9x+5y-2=0`
`y^(2)-x+4y+5=0`

ANSWER :B
19.

A point P is given on the circumference of a circle of radius r. Chord QR is parallel to the tangent at P. Determine the maximum possible area of the triangle PQR.

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ANSWER :`(3sqrt(3))/4r^(2)` SQ. unit
20.

Area bounded by the curves y = sin (pi x)/(2) and y = x^(3) is equal to

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`(4 - pi)/(pi)` sq. units
`(4 - pi)/(2 pi)` sq. units
`(8 - pi)/(pi)` sq. units
`(8 - pi)/(2 pi)` sq. units

Answer :D
21.

Find the number of ways of arranging the letters of the word SINGING so that relative positions of vowels and consonants are not disturbed.

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ANSWER :30
22.

Find the centre, eccentricity, foci, vertices of ellipse x^(2)+4y^(2)-8x-16y-68=0

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ANSWER :`5SQRT3`
23.

Let S and S' be the foci of an ellipse and B be any one of the extremities of its minor axis. If triangle S'BS is a right angled triangle with right at B and area (triangle S'BS)= 8 sq. units, then the length of a latus rectum of the ellipse is

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`2sqrt(2)`
`4sqrt(2)`
`2`
`4`

ANSWER :D
24.

If y=1/(x(x+1))then what is y_3?

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SOLUTION :`y=1/(X(x+1))=1/x-1/(x+1)rArry_1=(-1)/x^2+1/((x+1))^2y_2=2/x^3-2/((x+1))^4thereforey_3=(-6)/x^4+6/((x+1))^4`
25.

The integral int_(2)^(4)(logx^(2))/(logx^(2)+log(36-12x+x^(2)))dx is equal to

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2
4
1
6

Answer :3
26.

If n is a positive integer then 2^(4n) - 15n - 1 is divisible by

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64
196
225
256

Answer :C
27.

Let a, b, c be such that b(a+c) ne 0. If|[a,a+1,a-1],[-b,b+1,b-1],[c,c-1,c+1]|+ |[a+1,b+1,c-1],[a-1,b-1,c+1],[(-1)^(n+2) a ,(-1)^(n+1) b ,(-1)^(n) c]|=0 then the value of n is

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zero
any EVEN integer
any ODD integer
any integer

Answer :C
28.

If A, B, C are the angle of a triangle and |(sinA,sinB,sinC),(cosA,cosB,cosC),(cos^(3)A,cos^(3)B,cos^(3)C)|=0, then show that DeltaABC is an isosceles.

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ANSWER :
29.

If the probability of chossing an interger "k" out of 2m integers 1,2,3,….,2m is inversely proportional to k^(4)(1leklem).Ifx_(1) is the probability that chosen number is odd and x^(2) is the probability that chosen number is even, then

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`x_(1)gt1//2`
`x_(1)gt2//3`
`x_(2)lt1//2`
`x_(2)lt2//3`

SOLUTION :Let one probabilitt of choosing one INTEGER K be P (K) `=lamda//k^(4).` (`lamda` is one constant of proportionality). Then
`underset(k=1)overset(2M)sum(lamda)/(k^(4))=1`
`or underset(k=1)overset(2m)sum(1)/(k^(4))=1`
Let `x_(1)` be the probability of choosing the odd numer. Then
`x_(1)underset(k=1)overset(m)sumP(2k-1)=lamdaunderset(k=1)overset(m)sum(1)/((2k-1)^(4))`
Also, `1-x_(1)=underset(k=1)overset(m)sumP(2k)`
`=lamdaunderset(k=1)overset(m)sum (1)/((2k)^(4))`
`ltlamdaunderset(k=1)overset(m)sum(1)/((2k-1)^(4))`
`implies1-x_(1)ltx_(1)`
`impliesx_(1)gt1//2`
`impliesx_(2)lt1//2`
30.

Find (dy)/(dx)," if "x=a(cos t+log tan""t/2), y=a sin t.

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ANSWER :`TAN t`
31.

Integrate the following functions : sin2xlog(cosx)

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Answer :`-cos^(2)x.log(cosx)+(cos^(2)x)/(2)+C`
32.

x = (sin^3t)/(sqrt(cos 2t)), y = (cos^3 t)/(sqrt(cos 2t)).

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ANSWER :`-COT 3T`
33.

If x=a(theta-sin theta) and y=a(1+cos theta), then proe that (dy)/(dx)=-cot""(theta/2).

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ANSWER :`-COT (THETA)/(2)`
34.

Find int(x^(2))/((x^(2)+1)(x^(2)+4))dx

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Answer :`(-1)/(3) TAN^(-1) x+(2)/(3) tan^(-1)((x)/(2))+C`
35.

x = cos theta - cos 2 theta, y = sin theta - sin 2 theta. then find dy/dx

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ANSWER :`(cos theta- 2 cos 2 theta)/(2 SIN 2theta- sin theta)`
36.

x = sin t, y = cos 2 t.

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ANSWER :`-4 SIN t`
37.

x = 4t, y = 4/t then find dy/dx

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ANSWER :`-(1)/(t^2)`
38.

x = a cos theta, y = b sin theta.

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ANSWER :`(B)/(a)`
39.

If x and y are connected parametrically by the equationswithout eliminating the parameter, Find (dy)/(dx). x= 2at^(2), y= at^(4).

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ANSWER :`t^2`
40.

The probability of a man hitting a target is 0.25. He shoots 7 times, then what is the probability of his hitting atleast twice ?

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ANSWER :`(4547)/(8192)`
41.

The radius of an air bubble is increasing at the rate of (1)/(2) cm/s. At what rate is the volume of the bubble increasing when the radius is 1 cm ?

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ANSWER :`= 2PI CM^(3)//SEC`.
42.

Obtain following definite integrals : overset(1)underset(0)int (dx)/(e^(x)+e^(-x))

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ANSWER :`:.I=tan^(-1)(E)-(PI)/(4)`
43.

Find the number of positive intergral solutions of x_1x_2x_3=54 where x_1,x_2,x_3 ne 1

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ANSWER :9
44.

x = a sec theta, y = b tan theta.

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ANSWER :`(B)/(a)" COSEC "THETA`
45.

x = a (cos theta + theta sin theta), y = a (sin theta - theta cos theta). then find dy/dx

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ANSWER :`TAN THETA`
46.

The proposition (pto q ) harr (~p to~q)is a

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tautology
contradiction
contingency
none of these

Answer :C
47.

R is thesum of squareof 50 consectiveevenintegers statingwith1.S is whatpercentageless thanR ?

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0.25
0.33
0.5
0.75

Answer :D
48.

Evalute the following integrals int (3x+ 1)/((x + 1)^(2) (x + 3))dx

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Answer :`2 LOG |(x + 1)/(x + 3)| + (1)/(x + 1) + C `
49.

Let N denotes the set of all natural numbers. Define two binary relations on N as R_(1) ={(x,y) in N xx N : 2x + y=10} R_(2) = {(x,y) in N xx N , x+2y = 10} Then

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range of `R_(1)` is {2,4,8}
range of `R_(2)` is {1,2,3,4}
both `R_(1)`and `R_2` are symmetric relations
both `R_(1)` and `R_2` are TRANSITIVE relations

Answer :B
50.

Expand in ascending powers of x.2^x,

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SOLUTION :`2x=e^x(log_e2)=1+x(log_e2)+(x^2(log_e2)^2)/(2!)+(x^3(log_e2)^3)/(3!)+…`