Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

There are 10 books in a shelf with different titles:five or these have red cover and others have green cover. In how many ways can these be arranged so that the red books are placed together ?

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Solution :There are 10 books in a SHELF with different titles, 5 of these are red COVERS and others are green covers considering 5 red COVERED books as one book, we have all TOTAL 6 books as one book, we have all total 6 books which can be arranged in "6!" ways. The FIVE red cover books arranged among themselves in 5! ways.
`:.` The total number of arrangements `=5!xx6!`
2.

Let y=f(x) be the solution of the differential equation (dy)/(dx)+k/7 x tan x=1+xtanx-sinx, where f(0)=1 and let k be the minimum value of g(x) where g(x)="max"|(sqrt(193)-1)/2cosy+cos(y+(pi)/3)-x| where yepsilonR then Number of solution of the equation f(x)=2^(x)-x^(2)+x+cosx is equal to

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3
1
2
4

Solution :`-7 LE ((sqrt(193)-1))/2 cosy+cos(y+(pi)/3) le 7`
So, `g(x)={(|x+7|, ,, XGE0),(|x-7|, ,, xlt0):}`
So, `g(x)_("min")=7`
So, `F(x)=x+cosx`s
3.

If the tangent and normal to the hyperbola x^(2) - y^(2) = 4 at a point cut off intercepts a_(1) and a^(2) respectively on the x-axis, and b_(1) and b_(2) respectively on the y-axis, then the value of a_(1)a_(2) + b_(1)b_(2) is

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`-1`
0
4
1

Answer :B
4.

If z = x + iy and if the point P in the argand plane represents z , then the locus of P satisfying the equation Amplitude of (z -1) is (pi)/(2)

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ANSWER :A
5.

Let y=f(x) be the solution of the differential equation (dy)/(dx)+k/7 x tan x=1+xtanx-sinx, where f(0)=1 and let k be the minimum value of g(x) where g(x)="max"|(sqrt(193)-1)/2cosy+cos(y+(pi)/3)-x| where yepsilonR then Area bounded by y=f(x) and its inverse between x=(pi)/2 and x=(7pi)/2 is

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12
6
9
8

Solution :`-7 LE ((sqrt(193)-1))/2 cosy+cos(y+(pi)/3) le 7`
So, `g(x)={(|x+7|, ,, xge0),(|x-7|, ,, XLT0):}`
So, `g(x)_("min")=7`
So, `f(x)=x+cosx`s
`A = 3xx2 int_(pi//2)^(3pi//2) (x-(x+cos x)dx)`
`=-3xx2(SIN x)_(pi//2)^(3pi//2)`
`= -6(-1-1)=12`
6.

If z = x + iy and if the point P in the argand plane represents z , then the locus of P satisfying the equation {z in C , |z - 2| = 2 |z - 1| }

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ANSWER :B::C::D
7.

Show that x + y + 1= 0 touches the circle x^(2) + y^(2) -3x + 7y 14 = 0 and find its point of contact.

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(1,0)
(2,-3)
(5,3)
(-1,0)

ANSWER :B
8.

Two integers x and y are chosen one by one with replacement from 0, 1, 2,…,100. Find the probability that |x - y| le 3.

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ANSWER :`(695)/(10201)`
9.

int_(0)^(1) (dx)/( x+ sqrt(x)) =……

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`LOG2`
`LOG 3`
`-log 2`
log 4

Answer :D
10.

Using elementary transformations, find the inverseof the matrices [(2,-3,3),(2,2,3),(3,-2,2)]

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ANSWER :`[((-2)/(5),0,(3)/(5)),((-1)/(5),(1)/(5),0),((2)/(5),(1)/(5),(-2)/(5))]`
11.

If the normal at any point P on the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1meets the axes in G and g respectively. Find the ratio PG : Pg

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ANSWER :`B^(2):a^(2)`
12.

If A=[{:(2,3),(1,-4):}],B=[{:(1,-20),(-1,3):}] then verify (AB)^(-1)=B^(-1)A^(-1)

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ANSWER :`(AB)^(-1)=B^(-1)A^(-1)`
13.

Find the area of the parallelogram whose adjcent sides are determined by the vector.

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ANSWER :`15sqrt2`
14.

[hati-hatj hatj -hatk hatk-hati] is equal to

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0
1
2
3

Answer :A
15.

Let vec(alpha)=3hat(i)+hat(j), vec(beta)=2hat(i)-hat(j)+3hat(k)and vec(beta)=vec(beta)_(1)-vec(beta)_(2), such that vec(beta)_(1) is parallel to vec(alpha) and vec(beta)_(2) is perpendicular to alpha. Find vec(beta)_(1)xx vec(beta)_(2).

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`(1)/(2)(hat(i)-9hat(J)+8hat(K))`
`(1)/(2)(hat(i)-3HAT(j)+4hat(k))`
`(1)/(2)(-3hat(i)+9hat(j)+10 hat(k))`
`(3)/(2)(3hat(i)+9hat(j)+10hat(k))`

Answer :C
16.

From a pack of 52 cards, 3 cards are drawn successively with replacement each time. The probability of getting atleast one king is

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`1-(12^(3))/(13^(3))`
`(12^(3))/(13^(3))`
`1-(1)/(13^(3))`
`1-(1)/((13^(3)))`

ANSWER :A
17.

C_1//1-C_2//2+C_3//3-C_4//4+…+(-1)^(n-1) C_n//n=

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`1+(1)/(2)+(1)/(3)+….(1)/(N)`
`1+(1)/(2)-(1)/(2)-(1)/(3)+…(1)/(n)`
`1+(2)/(3)+(3)/(4)+…..+(n)/(n+1)`
none

Answer :A
18.

int_(2)^(3)(2-x)/(sqrt(5x-6-x^2))dx=

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`PI/2`
`- pi/2`
`-pi`
`pi`

ANSWER :B
19.

For j =0,1,2…nlet S _(j) be the area of region bounded by the x-axis and the curve ye ^(x)=sin xfor f pi le x le (j +1) pi The value of S_(o) is :

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`1/2 (1+E ^(X))`
`1/2 (1+e^(-pi))`
`1/2 (1- e ^(-pi))`
`1/2 (e ^(pi)-1)`

ANSWER :B
20.

Number of unit squares in a chess board is

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204
220
242
300

Answer :A
21.

Let a die be loaded in such a way that even faces are twice likely to occur as the odd faces. What is the probability that a prime number will show up when the die is tossed?

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`(1)/(3)`
`(2)/(3)`
`(4)/(9)`
`(5)/(9)`

SOLUTION :Possibleprimenumbers ofthediceare 2,3 and 5.
Probility ofgettingprime number`= (2)/(3) xx (1)/(3) +(1)/(3) xx(2)/(3) = (2)/(9)+ (2)/(9)`
`= (4)/(9)`
22.

Find the probability that in a family having 4 children, girls are in majority.

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ANSWER :`(5)/(16)`
23.

Find the equation of the circle with centre C and redius r where. C= (0,0), r= 9

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ANSWER :` X^(2) + y ^(2)=81`
24.

Choose the correct answer: In a box containing 100 bulbs, 10 are defective. The probability that out of a sample of 5 bulbs, none is defective is

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`10^(-1)`
`((1)/(2))^(5)`
`((9)/(10))^(5)`
`(9)/(10)`

ANSWER :C
25.

If f(x)= 2x and g(x) = (x^(2))/(2) + 1, then which of the following can be a discontinuous function?

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`F(X) + G(x)`
`f(x)- g(x)`
`f(x).g(x)`
`(g(x))/(f(x))`

ANSWER :D
26.

Find the parametric equations of the cirlces (i) x^(2)+y^(2)=1 (ii) x^(2)+y^(2)-4x+6y-12=0 (iii) 4(x^(2)+y^(2))=9 (iv) 2x^(2)+2y^(2)=7 (v) (x-3)^(2)+(y-4)^(2)=8^(2)

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ANSWER :` X= (3)/(2) cos THETA , y =(3)/(2)SIN theta`
27.

A family consists of father, mother 2 daughter and 2 sons. In how many different ways can they sit at a around table if 2 daughter wish to sit on either

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ANSWER :12
28.

y = e^(x)(a cos x + b sin x)

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ANSWER :`y" - 2Y' + 2y = 0`
29.

Find (dy)/(dx) in the following y= sin^(-1) ((2x)/(1+ x^(2)))

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ANSWER :`(2)/(1+ X^(2)), |x| GT 1`
30.

ABCisa rightangledisoscelestriangleswithangleB = 90 ^@if Dis a pointon A Bso thatangleDCB= 15 ^@and ifAd = 35cm, thenCD=

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`35sqrt(2)cm `
`70 SQRT(2) cm`
`(35sqrt(2))/( 2) cm`
`35 sqrt(6) cm`

Answer :A
31.

A coin is tossed any number of times until a head appears. If x donotes the number of tosses till head uappear then P(x ge 3)=

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`(1)/(2)`
1
`(1)/(4)`
`(3)/(4)`

Answer :C
32.

Let A be a 3xx3 matrix such that A [(1,2,3),(0,2,3),(0,1,1)]=[(0,0,0),(1,0,0),(0,1,0)], then A^(-1) is :

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`[(3,1,2),(3,0,2),(1,0,1)]`
`[(3,2,1),(3,2,0),(1,1,0)]`
`[(0,1,3),(0,2,3),(2,1,1)]`
`[(1,2,3),(0,1,1),(0,2,3)]`

SOLUTION :`AB=2 " UNITS. "PA +PB LE4`
33.

If the position vector of A,B,C are 2i+3j+4k , i+2j, j+2kand vec(AB) = Pvec(AC) then P=

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`-1/2`
`1/4`
`1/2`
`-1/4`

ANSWER :C
34.

Let f(x)=x^(2)e^(-2x),x gt 0. The maximum value off(x) is

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0
`(1)/(e^(2))`
`(1)/(4E^(2))`
`(1)/(2E)`

Answer :B
35.

All three roots of az^3+bz^3+cz+d=0 , z being complex number. Further , assume that the origin, z_1 and z_2 form an equilateral triangle, then :

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All a,B,C,d have the same SIGN
a,b,c have same sign
a,b,d have same sign
b,c,d have same sign

ANSWER :C
36.

Find the value of xsqrt(6x^(4) + 4x^(2) + 2) gt -2x^(2) + 5x - 4

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`X in (-OO,-1)`
`[-1,1]`
`(1,oo)`
R

Answer :A
37.

Let A = {a, b, c,d). If an equivalence relation R on A has exactly one equivalence class, then number of elements in R is_________

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ANSWER :16
38.

In theintermediateexaminationa candidatehasto passin eachof his6 papers . Thenumber ofwaysin withinhe can fail is

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32
31
64
63

Answer :D
39.

Write down the set of letters forming that word Administration?

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SOLUTION :{a,d,i,m,N,o,R,s,t}
40.

If the system of linear equations x+2ay+az=0, x+3by+bz=0,x+4ch+cz=0 has a non zero solution then a,b,c

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are in G.P.
are in H.P
Satisfy a + 2B + 3C = 0
are in A.P.

Answer :B
41.

Minimise Z=3x+2y subject to the constraints, x+yge8………..1 3x+5yle15…………2 xge0, yge0………..3

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ANSWER :no FEASIBLE SOLUTION.
42.

If Z=cos phi+isin phi(AA phi in ((pi)/(3),pi)), then the value of arg(Z^(2)-Z) is equal to (where, arg(Z) represents the argument of the complex number Z lying in the interval (-pi, pi] and i^(2)=-1)

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`(3phi+pi)/(2)`
`(3phi)/(2)`
`(3)/(2)(phi-pi)`
`(3phi-pi)/(2)`

ANSWER :C
43.

Prove that (b-c)sinA +(c-a)sinB +(a-b)sinC=0

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44.

Find the condition that the point (x,y) may lie on the line joining (1,2) and (5,-3).

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Solution :
`THEREFORE` As the points A,B,C are COLLINEAR we have AREA of the triangle ABC is 0.
`therefore` 1/2 {1(-3-y) + 5(y-2) + X(2+3)} = 0
or, -3-y+5y-10+5x = 0
or,5x + 4y = 13 .
45.

A black and red dice are rolled. Find the conditional probability of obtaining a sum greater than 9, given that the black die resulted in a 5

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SOLUTION :If the event that the "blacl die is resulted in 5" is given then the possible ELEMENTARY cases under consideration are reduced to (5,1),(5,2),(5,3),(5,4),(5,5),(5,6). Out of these 6 cases only two cases are favourable to the event that sum of the number rolled is greater than 9.
therefore Required probability =2/6=1/3.
46.

If y=sin^(-1)(2^(x+1)/(1+4^x))," find "(dy)/(dx).

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Answer :`2/(1+(2^(X))^(2))*2^(x)log_(E)^(2)`
47.

Let a solution y=y(x) of the differential equation xsqrt(x^(2)-1) dy-ysqrt(y^(2)-1)dx=0 satisfy y(2)=(2)/(sqrt3) Statement-1, y(x)=sec(sec^(-1)x-(pi)/(6)) Statement-2 : y(x) is given by (1)/(y)=(2sqrt3)/(x)-sqrt(1-(1)/(x^(2)))

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Statement-1 is TRUE, Statement-2 is True, Statement-2 is a correct explanation for Statement-1.
Statement-1 is True, Statement-2 is True, Statement-2 is not a correct explanation for Statement-1.
Statement-1 is True, Statement-2 is False.
Statement-1 is False, Statement-2 is True.

Solution :We have,
`xsqrt(X^(2)-1)DY=ysqrt(y^(2)-1)dx`
`rArr""(1)/(ysqrt(y^(2)-1))dy=(1)/(x sqrt(x^(2)-1))dx`
`rArr""int(1)/(ysqrt(y^(2)-1))dy=int(1)/(xsqrt(x^(2)-1))dx`
`rArr""SEC^(-1)y=sec^(-1)x+C`
It is given that `y=(2)/(sqrt3)` when x = 2
`THEREFORE""sec^(-1).(2)/(sqrt3)=sec^(-1)2+CrArr(pi)/(6)=(pi)/(3)+CrArrC=-(pi)/(6)`
Putting `C=-(pi)/(6)` in (i), we get
`sec^(-1)y=sec^(-1)x-(pi)/(6)"...(ii)"`
`rArr""y=sec(sec^(-1)x-(pi)/(6))`
so, statement-1 is true.
From (ii), we have
`cos^(-1)((1)/(y))=cos^(-1)((1)/(x))-(pi)/(6)`
`rArr""(1)/(y)=cos{cos^(-1)((1)/(x))-(pi)/(6)}`
`rArr""(1)/(y)=cos{cos^(-1)((1)/(x))}cos((pi)/(6))+sin(cos^(-1).(1)/(x))sin(pi)/(6)`
`rArr""(1)/(y)=(sqrt3)/(2x)+(1)/(2)sqrt(1-(1)/(x^(2)))`
So, statement-2 is false.
48.

Let (1 + x)^(n) = 1 + a_(1)x + a_(2)x^(2) + ... + a_(n)x^(n). If a_(1),a_(2) and a_(3) are in A.P., then the value of n is

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4
5
6
7

Answer :D
49.

int_(0)^(pi//2)sin 2 x.ln(tan x)dx

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1
-1
0
`pi/4`

ANSWER :C
50.

Match the following. {:(I." If "(3x)/((x-6)(x+k))=2/(x-6)+1/(x+k) " then "k=, "a) "0), (II." If "(3x-6)/((x-6)(x+k))=2/(x-6)+1/(x+k) " then "k=, "b) "3), (III. " If "(x-4)/(x^(2)-5x-2k)=2/(x-2)-1/(x+k)" then "k=, "c) "-1), (IV." If "(3x^(3)-2x^(2)-1)/(x^(4)+x^(2)+1)=(Ax+B)/(x^(2)+x+1)+(Cx+D)/(x^(2)+kx+1) " then "k=, "d) "-3):}

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c, d, a, B
b, a, d, c
c, a, b, d
c, b, a, d

Answer :B