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8201.

The point on the curve x^(2)=2y which is nearest to the point (0, 5) is ………..

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`(2sqrt(2), 4)`
`(2sqrt(2), 0)`
(0, 0)
(2, 2)

ANSWER :A
8202.

""^(n-2)C_(r)+2.""^(n-2)C_(r-1)+""^(n-2)C_(r-2) is equal to

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`""^(N+1)C_(R)`
`""^(n)C_(r)`
`""^(n)C_(r+1)`
`""^(n-1)C_(r)`

ANSWER :B
8203.

Prove that(veca.(vecbxxvecc))veca=(vecaxxvecb)xx(vecaxxvecc).

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ANSWER :` (VECA.(VECBXXVECC))veca `
8204.

Evaluate the definite integral in exercise overset(3)underset(2) int (xdx)/(x^(2)+1)

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ANSWER :`(1)/(3)LOG2`
8205.

Consider a polynomial y = P(x) of the least degree passing through A(-1,1) and whose graph has two points of inflection B(1,2) and C with abscissa 0 at which the curve is inclined to the positive axis of abscissa at an angle of sec^(-1)sqrt(2) The equation P(x) =0 has

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three distinct real roots
one real ROOT
three real roots such that one root is repeated
none of these

Solution :Since two points of INFLECTION OCCUR at x=1 and x=0
p(1)=P(0)=0
`therefore P(x)=a(x^(2)-x)`
or `P(x)=a(x^(3)/(3)-x^(2)/(3))`
also given `(dy)/(dx)_(x=0)=sec^(-1)sqrt(2)=tan^(-1)1`
HENCE P(0)=1 so B =1 thus
`P(x)=a(x^(3)/(3)-x^(2)/(2))+1`
`therefore P(x) =a(x^(4)/(12)-x^(3)/(6))=x+c`
As P(1)=2 ,we have
`a((1)/(12)-(1)/(6))+1+c=1`
or `(a)/(12)+c=0`
solving (1) and (2) we have `a =6 and c=1/2`
`P(x) =6(x^(4)/(12)-x^(3)/(6))+x+1/2`
`P(2)=5/2 land p(x)=1/2`
`P(x) =6(x^(3)/(3))-(x^(2)/(2))+1=(x-1)^(2)(2x+1)`
8206.

Consider a polynomial y = P(x) of the least degree passing through A(-1,1) and whose graph has two points of inflection B(1,2) and C with abscissa 0 at which the curve is inclined to the positive axis of abscissa at an angle of sec^(-1)sqrt(2) The value of P(2) ius

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-1
`(-3)/(2)`
`(5)/(2)`
`(7)/(2)`

SOLUTION :Since TWO points of inflection occur at x=1 and x=0
p(1)=P(0)=0
`therefore P(x)=a(x^(2)-x)`
or `P(x)=a(x^(3)/(3)-x^(2)/(3))`
also given `(dy)/(dx)_(x=0)=sec^(-1)sqrt(2)=tan^(-1)1`
Hence P(0)=1 so b =1 thus
`P(x)=a(x^(3))/(3)-(x^(2))/(2)+1`
`therefore P(x) =a(x^(4))/(12)-(x^(3))/(6)=x+c`
As P(1)=2 ,we have
`a(1)/(12)-(1)/(6)+1+c=1`
or `(a)/(12)+c=0`
SOLVING (1) and (2) we have `a =6 and c=1/2`
`P(x) =6(x^(4))/(12)-(x^(3))/(6)+x+1/2`
`P(2)=5/2and p(x)=1/2`
`P(x) =6(x^(3))/(3)-(x^(2))/(2)+1=(x-1)^(2)(2x+1)`
8207.

Consider a polynomial y = P(x) of the least degree passing through A(-1,1) and whose graph has two points of inflection B(1,2) and C with abscissa 0 at which the curve is inclined to the positive axis of abscissa at an angle of sec^(-1)sqrt(2) The value ofP(0) is

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1
0
`3/4`
`1/2`

SOLUTION :Since two points of inflection occur at x=1 and x=0
p(1)=P(0)=0
`therefore P(x)=a(x^(2)-x)`
or `P(x)=a(x^(3)/(3)-x^(2)/(3))`
also given `(dy)/(dx)_(x=0)=SEC^(-1)SQRT(2)=TAN^(-1)1`
Hence P(0)=1 so b =1 thus
`P(x)=a(x^(3)/(3)-x^(2)/(2))+1`
`therefore P(x) =a(x^(4)/(12)-x^(3)/(6))=x+c`
As P(1)=2 ,we have
`a((1)/(12)-(1)/(6))+1+c=1`
or `(a)/(12)+c=0`
SOLVING (1) and (2) we have `a =6 and c=1/2`
`P(x) =6(x^(4)/(12)-x^(3)/(6))+x+1/2`
`P(2)=5/2 land p(x)=1/2`
`P(x) =6(x^(3)/(3))-(x^(2)/(2))+1=(x-1)^(2)(2x+1)`
8208.

For some natureal number 'n', the sum of the fist 'n' natural numbers is 240 less than the sum of the first (n+5) natural numbers. Then n itself is the sum of how many natural numbers starting with 1.

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ANSWER :9
8209.

Evaluate : intsqrt(4ax-x^(2))dx.

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ANSWER :`(1)/(2)(x-2a)SQRT(4ax-x^(2))+2a^(2)SIN^(-1)((x-2a)/(2a))+C`
8210.

Find the number of element of P(P(P(phi)))

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<P>

SOLUTION :`|P(P(P(PHI)))|=2^2=4`
8211.

Find the optimal solutionof the aboveLPPand alsofind the value of Z_(max) from the graph of feasible region

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ANSWER :A::D
8212.

Find the correct statement in the following given four points A, B, C, D are coplanar only of the following condition is satisfied.

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`vec(AB)+vec(BC)+vec(CA)=0`
`[vec(AB), vec(AC), vec(AD)]=0`
`vec(AB) XX vec(CD)=0`
`vec(AB)*vec(CD)=0`

Solution :N/A
8213.

Integrate the following function : int(x)/(x^(2)+3x+2)dx

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Answer :`(1)/(2)log|x^(2)+3x+2|-(3)/(2)log|(x+1)/(x+2)|+c`
8214.

Let f(x) be a polynomial function of second degree. If f(1) = f(-1) and a, b. c are in A.P., then f'(a), f'(b),f'(c) are in

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G.P.
H.P.
Arithmetic-Geometric Progression
A.P.

Answer :D
8215.

Let f(x)=x(1)/(x-1)+(1)/(x)+(1)/(x+1) x lt 1 then

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`f(X) LE 1`
`1 le f(x) le 2`
`2le f(x) le 3`
`f(x) gt3`

Answer :C
8216.

Number of integers satisfying the inequality log_2sqrtx-2log_(1//4)^2x+1gt0,is

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ANSWER :3
8217.

An isosceles triangle is inscribed in the circle x ^(2) + y ^(2) - 6x - 8y =0 with vertex at the origin and one of the equal sides along the axis ofx. Equation of the other side through the origin is

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`7X -24Y =0`
`24x-7Y=0`
`7x+ 24=0`
`24x + 7y =0`

ANSWER :D
8218.

Three vectors vec(a),vec(b),vec(c) are such that vec(a)xxvec(b)=4(vec(a)xxvec(c))and|vec(a)|=|vec(b)|=1and|vec(c)|=(1)/(4). If the angle between vec(b)andvec(c)" is "(pi)/(3), then vec(b) is

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`VEC(a)+4vec(C)`
`vec(a)-4vec(c)`
`4vec(c)-vec(a)`
`2vec(c)-vec(a)`

ANSWER :A::C
8219.

If1 , omega , omega^(2) are the cube roots of unity , then find the values of the following . ( i + omega )^(3 ) + ( 1 + omega^(2))^(3)

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ANSWER :-2
8220.

((1 + ""^nC_1 + ""^nC_2 + ""^nC_3+…….+nC_n)^2)/(1 + ""^(2n)C_1 + ""^(2n)C_2 + ""^(2n)C_3 + ……… + ""^(2n)C_(2n)) =

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1
`-1`
2
3

Answer :A
8221.

Divide 20 into two parts such that the product of one part and the cube of the other part is maximum.

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ANSWER :5, 15
8222.

The solution of (dy)/(dx) = (x-y)^(2) is

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`(x -y + 1) = c (1 -x + y) E^(2X)`
`(x + y + 1) = c (1 -x + y) e^(2x)`
`(x -y+ 1) = c (1 -x -y) e^(2x)`
`(x+ y + 1) = c (1 + x + y) e^(2x)`

ANSWER :A
8223.

int(1)/(1+cos^(2)x)dx=.....

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`(1)/(sqrt(2))tan^(-1)(TANX)+c`
`(1)/(sqrt(2))tan^(-1)((1)/(2)tanx)+c`
`(1)/(sqrt(2))tan^(-1)((1)/(sqrt(2))tanx)+c`
NONE of these

Answer :C
8224.

If the equation 2^(2x)+a*2^(x+1)+a+1=0 has roots of opposite sign, then the exhaustive set of real values of a is

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`(-OO,0)`
`(-1,(-2)/(3))`
`(-oo,(-2)/(3))`
`(-1,oo)`

Solution :`(b)` Put `2^(X)=t`
`implies t^(2)+2a*t+(a+1)=0`
Now, `t=1` should lie between the roots of above EQUATION.
Let `f(t)=t^(2)+2a*t+(a+1)`
`:.f(1) lt 0` and `f(0) gt 0`
`implies a lt (-2)/(3)` and `a gt -1`
`:.a in (-1,(-2)/(3))`
8225.

The value of int_(0)^(pi) sin^(n) x cos^(2m+1) x dx is

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`((2m+1)!)/( (n!)^(2) ) `
`((2m+1)!)/( n!)`
`int_(0)^(pi)COS^(2m-1) X dx`
NONE of these

Answer :C
8226.

Show by an example that for AneO,BneO,AB=O.

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ANSWER :`=O`
8227.

int log (2- 3x) dx =

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`(x- (2)/(3)) `LOG |2 -3X| - x +c
(x -2) log |2- 3 x | + 3x + c
`(1)/(3) `(x -2) log | 2- 3x | -3x + c
`(1)/(3)` (x -2) log |2-3x| - 3x + c

Answer :A
8228.

Find the centre and radius of the following circles : x^2 + y^2 + 6x -4y -12 = 0

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Solution :`x^2 + y^2 + 6X -4y -12 = 0`
`therefore` 2g = 6, 2F = -4, c = -12
`therefore` g = 3, f = -2
`therefore` CENTRE of (-g, -f) = (-3, 2)
and radius = `sqrt(g^2 + f^2 -c)`
= `sqrt(9 + 4 + 12)` = 5
8229.

Let f(x)=(x^(2)-4)^(1//3), then f has a :

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LOCAL maxima at x = 0
local MINIMA at x = 0
point of INFLEXION at x = 0
None of these.

Answer :B
8230.

Twenty meters of wire is available to fence off a flower bed in the form of a sector. If the flower bed has the maximum surface then radius is

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10
`5/2`
5
`15//2`

ANSWER :C
8231.

Let X represent the difference between the number of head and the number of tails obtained when a coin is tossed 6 times. What are possible values of X?

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ANSWER :X=6, 4, 2, 0
8232.

Consider the following complexes (I) [Cr(CO)_(x)], (II) [Cr(CO)_((x-1))PF_(3)] If PF_(3) is better pi accepter than CO, what be the order of bond length of CO in complexes (I) and (II) :

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`IgtII`
`IIgtI`
I=II
can not be COMPARED

SOLUTION :If `PF_(3)` is better `pi` ACCEPTOR than Co, than C-O bond order in II COMPLEX is more than I complex and the C-O bond order in II complex is more than I complex and the C-O bond length in `IgtII`.]
8233.

Find the coefficient of a^(5) b^(5)c^(5)d^(8) in the expansion of the following expression. (bcd + acd + abd+ abc)^(7)

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ANSWER :630
8234.

int(root(3)(1+root(4)(x)))/(sqrtx)dx is equal to :

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`12(((1+root(4)(X))^(7//3))/(7)+((1+root(4)(x))^(4//3))/(4))+C`
`12(((1+root(4)(x))^(7//3))/(7)-((1+root(4)(x))^(4//3))/(4))+C`
`6(((1+root(4)(x))^(7//3))/(7)-((1+root(4)(x))^(4//2))/(4))+C`
None of these

Answer :B
8235.

A soft drinks firm has two bottling plants, one located at P and the other located at Q.Each plant produces three different soft drinks A, B and C.The capacities of two plants in number of bottles per day, are as follows: A market survey indicates that during the month of April, there will be a demand for 24,000 bottles of A, 16,000 bottles of B and 48,000 bottles of C.The cost of running the two plants P and Q are respectively ₹6,000 and ₹ 4,000 per day.Find graphically, the number of days for which either of the two plants P and Q should be run in the month of April so as to minimise production cost while still meeting the market demand.

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ANSWER :12 DAYS
8236.

The solution of (dy)/(dx) +(Tan y)/(1+x) = (1+x)e^(x)sec y is

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`(SIN y)/(1+x) = e^(x) + c`
`(COS y)/(1+x) = e^(x) + c`
`(cos y)/(1-x) = e^(x) + c`
`(cos y)/(x+1) = e^(y) + c`

ANSWER :A
8237.

I = int {log _(e) log _(e) x + (1)/( (log _(e) x ) ^(2))} dx is equal to:

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`X log _(e) log _(e) x +C`
`x log _(e) log _(e) x - (x)/( log _(e) x) +C`
`XLOG _(e) log _(e) x + (x)/( log _(e) x) +C`
NONE of these

ANSWER :B
8238.

Formation of real image using a biconves lens is shown below: If the whole set up is immersed in water without disturbing the object and the screen positions, what will one observe onthe secreen ?

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IMAGE disappears
MAGNIFIED image
Erect real image
no change

SOLUTION :NA
8239.

If the equation ax ^(2) + 2 (a^(2) + ab 16) ay + by ^(2) + 2ax + 2by - 4 sqrt2=0 represents a circle, the radius of the circle is

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2
`2SQRT2`
`SQRT2`
`4sqrt2`

ANSWER :A
8240.

Locus of the poles of focal chord of a parabola is

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the axis
a FOCAL chord
the directrix
the TANGENT at the vertex

Answer :C
8241.

If A, B, C are three events, then which of the following is/are not correct?a.P (Exactly two of A, B and C occur)leP(AnnB)+P(BnnC)+P(CnnA)b.P(AuuBuuC)leP(A)+P(B)+P(C) c.P (Exactly one of A, B and C occur)leP(A)+P(B)+P(C)-P(BnnC)-P(CnnA)-P(AnnB)d.None of these

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P (Exactly two of A, B and C occur)
`LEP(AnnB)+P(BNNC)+P(CnnA)`
`P(AuuBuuC)leP(A)+P(B)+P(C)`
P (Exactly one of A, B and C occur)
`leP(A)+P(B)+P(C)-P(BnnC)-P(CnnA)-P(AnnB)`
NONE of these

Answer :D
8242.

Find the sum of all four digit numbers (without repetition of digits) formed using the digits 1,2, 3, 4, 5.

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ANSWER :399960
8243.

How many of them are divisible by 3

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ANSWER :72
8244.

Let Delta=|(Ax,x^(2),1),(By,y^(2),1),(Cz,z^(2),1)| and Delta_(1)=|(A,B,C),(x,y,z),(zy,zx,xy)| then

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1.`Delta_(1)=-Delta`
2.`Delta_(1)=Delta`
3.`Delta_(1)NE Delta`
4.`Dela_(1)=2DELTA`

Answer :B
8245.

Ifveca.vecb=vecb.vecc=vecc.veca=0,then the value of|[veca,vecb,vecc]|is________

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` |veca||vecb||vecC| `
` (1)/(3)|veca||vecb||vecC| `
1
-1

Answer :a
8246.

Which of the following statement (s) is (are) correct ?

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Sum of the RECIPROCAL of all the n harmonic means inserted between a and b is equal to n times the harmonic mean between two GIVEN numbers a and b.
Sum of the cubes of first n natural NUMBER is equal to square of the sum of the first a natural numbers.
If `a , A_(1), A_(2), A_(3), ….., A_(2n), b` are in A.P. then `sum _( I =1) ^(2n) A_(L) =n (a+b).`
If the first term of the geometric progression `g _(1), g _(2), g _(3), ……, oo` is unity, then the value of the common ratio of the progression such that `(4g _(2)+5g _(3))` is MINIMUM equals `2/5.`

Answer :B::C
8247.

Let f(x) be a twice differentiable function and f^(11)(0)=2, then Lim_(x to 0) (2f(x)-3f(2x)+f(4x))/(x^(2)) is

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a
2a
3a
4a

Answer :C
8248.

Velocity-time graph for a particle, which is moving in straight line is given below. Displacement of particle between t=2 sec to t=5 sec is :-

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5m
10m
15m
20m

8249.

Find the projection of the point (7,-5,3) on yz -plane,

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SOLUTION :(0,-5,3),
8250.

If p and q are two propositions, then ~(p harr q) is

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<P>`~p ^^ ~Q`
`~p VV ~q`
`(p ^^ ~q) vv (~p ^^ q)`
`~p rarr ~q`

Answer :C