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11301.

f: R rarr R , f(x) =x^(2)+1. Find the preimage of 17 and -3.

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SOLUTION :N/A
11302.

Write down the first three terms is the following expansions(3 + 4x)^(-2//3)

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ANSWER :`(1)/(3^(2/3) ),- (8X)/(3^(8/3)),(80x^2)/(3^(14/3))`
11303.

If vec a and vec b are collinear vectors, then which of the following are incorrect?

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`vecb=lambdaveca`,for some SCALAR `lambda`
`veca=+-vecb`
the RESPECTIVE components of `vecaandvecb` are not proportional
both the VECTORS `vecaandvecb` have same DIRECTION , but different magnitudes.

Answer :B::C::D
11304.

[(a xx b) xx (a xx c)]. D =

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(a.d) [a B C]
(b.d) [a b c]
(c.d) [a b c]
0

Answer :A
11305.

Let E_(1)={x in R :x ne 1 and (x)/(x-1) gt 0} and E_(2)={x in E_(1):sin^(-1)(log_(e)((x)/(x-1))) " is real number"} (Here, the inverse trigonometric function sin^(-1)x assumes values in [-(pi)/(2),(pi)/(2)].) Let f:E_(1) to R be the function defined by f(x)=log_(e)((x)/(x-1)) and g:E_(2) to Rbe the function defined byg(x)=sin^(-1)(log_(e)((x)/(x-1))) . The correct option is

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`a to s, b to Q, C to p, d to p`
`a to R, b to r, c to u, d to t`
`a to s, b to q, c to p, d to u`
`a to s, b to r, c to u, d to t`

Solution :`E_(1):(x)/(x-1) gt 0`
`implies x in (-OO ,0) cup (1,oo)`
Also `E_(2) : -1 lt log_(e)((x)/(x-1)) le 1`
`implies (1)/(e) le (x)/(x-1) le e`
`implies (1)/(e) le 1 +(1)/(x-1) lee`
`implies (1)/(e)-1 le (1)/(x-1) le e-1`
`implies (x-1) in (-oo, (e)/(1-e)] cup [(1)/(e-1),oo)`
`implies x in (-oo, (e)/(1-e)] cup [(1)/(e-1),oo)`
Now, `(x)/(x-1) in (0, oo)-{1} AA x in E_(1)`
`implies log_(e) ((x)/(x-1)) in (-oo,oo)-{0}`
`implies sin^(-1)(log_(e)((x)/(x-1))) in [-(pi)/(2),(pi)/(2)]-{0}`
`("considering "log_(e) ((x)/(x-1)) in [-1,1]-{0})`
11306.

Find limit of the ratio of the area of the triangle formed by the orgin and intersection points of the parabola y-4x^2 and the line y=a^2,to the area between the parabola and the line as a approaches to zero.

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ANSWER :`3/2`
11307.

z_(1) = 1 +i , z_(2) = -sqrt3 + i , z_(3) = 1 + sqrt3i , z_(4) = 1 - i Arrange z_(1) , z_(2) , z_(3) , z_(4) is descending order of their principal values

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`z_(3) , z_(2) , z_(1) , z_(4)`
`z_(2) , z_(3) , z_(1) , z_(4)`
`z_(3) , z_(1) , z_(2) , z_(4)`
`z_(4) , z_(1) , z_(3) , z_(2)`

ANSWER :B
11308.

Determine order and degree (if defined) of the following differential equations y''' + 2y'' + y' = 0

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SOLUTION :The highest ORDER derivative in the DIFFERENTIAL equation is y... and its degree is 1. `therefore` The order and the degree of the differential equation are 3 and 1 RESPECTIVELY.
11309.

If the equation of conic 2x^(2) + xy+3y^(2) - 3x+ 5y + lambda =0 represents a single point, then find the value of lambda.

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ANSWER :`THEREFORE lambda=4`
11310.

Solve the following equations 2x^5+x^4-12x^3-12x^2+x2=0

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ANSWER :`-1,-2 ,(-1)/(2) ,(3 +- SQRT(5))/(2)`
11311.

If equation of the plane passing through i+2j-k and perpendicular to the line of intersection of the planes r.(3i-j+k)=4 and r.(i+4j+2k)=12, is (x)/(a)+(y)/(b)+(z)/(c )=1, then 91(a+b+c)=________

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ANSWER :`26.50`
11312.

Find the vector equation of the plane passing through the intersection of the planes vecr.(hati+hatj+hatk)=6 and vecr.(2hati+3hatj+4hatk)=-5 and the points (1,1,1).

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ANSWER :`VECR.(20hati+23hatj+26hatk)=69`
11313.

If ((10),(x-1)) gt 2((10),(x)) ,then

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X`EPSI` [2,9]
x=8,9,10
x `epsi` [6,10]
NONE of these

Answer :B
11314.

Find the values of k so that the function f is continuous at the indicated point f(x)= {(kx+1",","if" x le pi),(cos x,"if" x gt pi):} " at " x= pi

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ANSWER :`K= - (2)/(PI)`
11315.

Let 3f(x)-2f((1)/(x))=x the f'(2) is equal to

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`2/7`
`1/2`
2
`7/2`

ANSWER :B
11316.

If A,B,C are angles of a triangle such thatx = cis A , y = cis B , z = cis C, then find the value of xyz .

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ANSWER :-1
11317.

The solution of the differential equation (dy)/(dx)+xyln y=x^(3)y is equal to (where, C is the constant of integration)

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`lny=X^(2)+Ce^(-x^(2))`
`lny=x^(2)-2+Ce^(-x^(2))`
`lny=x^(2)-2+ce^(-(x^(2))/(2))`
`lny =x^(2)+Ce^(-(x^(2))/(2))`

ANSWER :C
11318.

alpha , beta, gamma are the roots of the equation x^(3)-10x^(2)+7x+8=0, Match the following columns and choose the correct answer. {:("Column I","Column II"),("A)"alpha+beta+gamma,"1)"(-43)/(4)),("B)"alpha^(2)+beta^(2)+gamma^(2),"2)"(-7)/(8)),("C)"1/alpha+1/beta+1/gamma,"3)"86),("D)"(alpha)/(beta gamma)+(beta)/(gammaalpha)+(gamma)/(alpha+beta),"4)"0),(,"5)"10):}

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`{:("(A)","(B)","(C)","(D)"),(5,3,1,2):}`
`{:("(A)","(B)","(C)","(D)"),(4,3,1,2):}`
`{:("(A)","(B)","(C)","(D)"),(5,3,2,1):}`
`{:("(A)","(B)","(C)","(D)"),(5,2,3,1):}`

ANSWER :A
11319.

If water sample are taken from sea, rivers or lake, they will be found to contain hydrogen and oxygen in the approximate ratio 1 : 8. This indicates the law of :-

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MULTIPLE PROPORTION
Definite proportion
RECIPROCAL proportions
NONE of these

Answer :A
11320.

A variable line L intersects the parabola y=x^(2) at points P and Q whose x- coordinate are alpha and beta respectively with alpha lt beta the area of the figure enclosed by the segment PQ and the parabola is always equal to 4/3. The variable segment PQ has its middle point as M Which of the following is/are correct?

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<P>equations of the pair of TANGENTS, drawn to the curve, represented by locus of `M` from origin are `y=2x` and `y=-2x`
equation of pair of tangents to be curve, represented by locus of `M` from origin are `y=x` and `y=-x`
area of the region enclosed between the curve, represented by locus of `M`, and the pair of tangents drawn to it from origin is `2/3` sq. units
area of the region enclosed beween the curve, represented by locus of `M`, and the pair of tangents drawn of it, from origin is `1/3` sq. units

Solution :Any two point on `y=x^(2)` is `P(ALPHA,alpha^(2)),Q(beta,beta^(2))`
Equation of `PQ, y-alpha^(2)=(alpha+beta)(x-alpha)`
`y=(alpha+beta)x-alpha beta`
Required area `int_(alpha)^(beta)((alpha+beta)x-alpha beta-x^(2))dx`
`IMPLIES beta-alpha=2`
Pair of tangents from origin are `y=2x` and `y=-2x`
Area `int_(0)^(1)((x^(2)+)-2x)dx=2/3`
11321.

B(OH)_(3)(aq)+" glycol "toproduct X. How many chelate rings are present in product X.

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SOLUTION :
11322.

a != 0, b != 0, C != 0, a xx b = 0, b xx c implies a xx c =

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b
a
0
I + J + k

Answer :C
11323.

Integrate the functions xsin3x

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ANSWER :`-x/3cos3x+1/9sin3x+C`
11324.

int(x^(2)+cos^(2)x)/((1+x^(2))sin^(2)x)dx=

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`cotx+tan^(-1)x+c`
`cotx-tan^(-1)x+c`
`-cotx+tan^(-1)x+c`
`-cotx-tan^(-1)x+c`

ANSWER :D
11325.

Integrate the following functions xsinx

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Solution :`INT x SINX dx`
=`x(-COSX)- int 1XX -cosx dx`
=`-xcosx + int cosx dx`
=`-x cosx +sinx+c`
11326.

Identify statements S_(1),S_(2),S_(3) in order for true(T)false(F) S_(1)="If A"=[{:(,cos theta,-sin theta,0),(,sin theta,cos theta,0),(,0,0,1)]:} then adj=A=A' S_(2)="If A"=[{:(,a,0,0),(,0,b,0),(,0,0,c):}]"then "A^(-1)=[{:(,a,0,0),(,0,b,0),(,0,0,c):}] S_(3): If B is non-singular matrix A is a squre matrix, then det (B^(-1),AB) =det(A)

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TTF
FTT
TFT
TTT

Answer :C
11327.

For 0 lt theta lt (pi)/(2), four tangents are drawn at the four points ( pm 3 cos theta, pm 2 sin theta ) to the ellipse (x^(2))/(9)+(y^(2))/(4)=1 . If A(theta) denote the area of the quadrilateral formed by these four tangents, the minimum value of A(theta) is

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21
24
27
30

Solution :`{:((X cos theta)/(3)+(y sin theta)/(2)=1),((x cos theta)/(3)-(y sin theta)/(2)=1):}}x= 3 sec theta,y=0`
`(-x cos theta)/(3)+(y sin theta)/(2)=1`
`(-x cos theta)/(3)-(y sin theta)/(2)=1`
`x=0,y=2 cos theta`
AREA `=4.(1)/(2) 3 sin theta. 2 cos theta`
`=(12)/( sin theta cos theta)=(24)/( sin 2 theta)`
`:. ` MIN. area =24
11328.

If onerootof10 x^3-x^2 - 278x + 165=0is5 thenproductof theremainingtworootsis

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33
`-33/5`
`-(33)/(10)`
`(33)/(10)`

ANSWER :C
11329.

Which of the following points maximise the objective function P=x/2+y/3?

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(4,0)
(0,6)
(2,3)
(3,2)

ANSWER :D
11330.

20.0 kg of N_(2(g)) and 3.0 kg of H_(2(g)) are mixed to produce NH_(3(g)). The amount of NH_(3(g)) formed is :-

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17 kg
34 kg
20 kg
3 kg

Answer :A
11331.

check the validity of the following statement (a) r : if x is a real number such that x^3+9x then x is 0. (b) r : If x is an integer and x^3 is even , then x is also even (c) r : If a polygon regular thon it is equiangular and equilateral.

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Solution :(a) Component STATEMENTS are
p : X is a real number such that `x^3+9x=0`
Q : x is 0
Now to check validity of r
(i) Direct Method : Let p is true, then q is true.
`therefore` x is real number such that `x^3+9x=0`
`therefore` x is a real number such that `x(x^2+9)=0`
`therefore x=0`
`therefore` q is true
Thus , p is true `rArr` q is true
So, given statement r is true
(ii) Contrapositive Method : Let q is false , i.e.,`x ne 0`
Now , according to p
x is real number such that `x^3+9x=0`
So, `x(x^2+9)=0`
It shows that x is real number and x=0 , but according to q , `x ne 0` , so this is a contradiction
So, r is true
Component statement are
p : x is an integer and `x^3` is even
q : x is an even integer
Suppose q is false (i.e.,~q is true) i.e.,x is an odd integer
So, `x^3= " odd"xx "odd"xx"odd "`
`=" (odd"xx "odd)"xx"odd "`
`" odd"xx "odd"`
`x^3` is also odd , so p is false
It shows that `~q rArr ~p`
(C) Component statements of r be
p : A polygon is REGULAR.
q : A polygon is equiangular and equilateral.
11332.

If x = {1,2,3 …., 10 } and a represents any elements of X then write the follwing sets containing all the elements satisfing the given conditionsa in X but a^2 in X a in X but a//2in X a is factor of 24

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SOLUTION :Given,X= {1, 2, 3, ...,10}
(a) Since `1^2,2^2,3^2 in X`
`{a|a in X and a^2 notin X}` ={4,5,6,7,8,9,10}
(b) ` a in X but a//2 of 24`
`rArra=1,3,5,7,9`
`THEREFORE of 24`
`RARR{a|a in X buta//2in X} `= {1,3,5,7,9}
( c) a is FACTOR of 24
`rArra= 1,2,3,4,5,6,8 `
`therefore{ a|a is" factor of "24 }={ 1,2,3,4,6,5,6,8}`
11333.

The minimum value of x/(1+x^2) is

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`1//2`
2
`-1//2`
none

Answer :C
11334.

If int(sinx)/(cosx(1+cosx))dx = f(x)+c, then f(x) is equal to

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`|(1-COSX)/(cosx)|`
`LOG|(cosx)/(1+cosx)|`
`|(SINX)/(1+sinx)|`
`log|(1+sinx)/(sinx)|`

ANSWER :A
11335.

If n coins are tossed simultaneously, the probability of getting head an odd number of times is

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`(1)/(2^(N))`
`(1)/(3)`
`(1)/(2)`
`(1)/(2^(n-1))`

ANSWER :C
11336.

A={:[( 1,1,1),(1,2,-3),(2,-1,3)]:}Show that A^(3) - 6A^(2) +5A +11 I =O. Hence , findA^(-1)

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ANSWER :`A^(-1) =(1)/(11) {:[( -3,4,5),(9,-1,-4),(5,-3,-1)]:}`
11337.

If alpha, beta, gamma are roots of a cubic equation satisfyingthe relationsalpha + beta + gamma = 2,alpha^(2) + beta^(2) + gamma^(2) = 6 and alpha^(3) + beta^(3) + gamma^(3) = 8then the cubic equation is

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`X^(3) + 2X^(2) - x + 2 = 0 `
`x^(3) - 2x^(2) - x + 2 = 0 `
`x^(3) - 2x^(2) + x + 2 = 0 `
`x^(3) - 2x^(2) - x - 2 = 0`

ANSWER :2
11338.

Compute the integral int_(0)^(pi//4) (dx)/( a^(2) cos^(2) x + b^(2) sin^(2) x) (a gt 0, b gt 0)

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ANSWER :`DX = (PI)/(4)`
11339.

Evaluate int(1)/(2sin^(2)x+3cos^(2)x)dx

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Answer :`(1)/(SQRT(6))tan^(-1)((sqrt(2)tanx)/(sqrt(3)))+c`
11340.

The value of intdx/(16x^2-25) is

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`1/20 LOG|(4x-5)/(4x+5)|+C`
`1/30 log|(4x-5)/(4x+5)|+C`
`1/40 log|(4x-5)/(4x+5)|+C`
NONE of these

Answer :C
11341.

Determine whether a**b=sqrt(a^2+b^2) on Q_+operations as defined by * are binary operations on the sets specified in each case. Give reasons if it is not a binary operation.

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SOLUTION :for all `a,B in Q^+`
`a**b =sqrt(a^2+b^2) !in Q^+`
`:. **` is not a binary operation on `Q^+`.
11342.

If the two lines (x-1)/(3)=(y-k)/(6)=(z+1)/(-2)and(x-2)/(-1)=(y-2)/(4)=(z+1)/(-1) intersect at a point, then k is

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`(13)/(5)`
`(2)/(5)`
`(12)/(5)`
`(7)/(5)`

ANSWER :C
11343.

Let f be a real valued function with (n +1) derivatives at each point of R. For each pair of real numbers a,b, a lt b, such that ln [(f(b)+f (b)+.....+ f ^((n))(b))/(f (a) + f'(a) +.....+ f ^((n))(a))] Statement-1 : There is a number c inh (a,b) for which f ^((n+1))(c) =f (c)because Statement-2: If h (x) be a derivable function such that h (p) =h (q) then by Rolle's theorem h'(d) =9,d in (p,q)

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Statement-1 is TRUE, statemet-2 is true and statement-2 is CORRECT EXPLANATION for statement-1
Statement-1 is true, statement-2 is true and statement-2 is not correct explanation for statement-1
Statement-1 is true, statement-2 is FALSE
Statement-1 is false, statement-2 is true

ANSWER :A
11344.

A dealer wants to purchase 5 litres oil tin and 1 kg ghee tin. He has only Rs. 5760 to invest and has a space for atmost 20 tins. 5 l oil tin costs him Rs. 360 and 1 kg ghee tin costs him Rs. 240. He can sell oil tin at a profit of Rs. 22 and ghee tin at a profit of Rs. 18. Assuming that he can sell all the items that he buys, how should he invest his money for maximum profit ?

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Answer :For maximum profit, A DEALER PURCHASE 8 TINS of oil and 12 tins of ghee.
11345.

Given two independent events A and B such that P(A) = 0 . 3, P (B) = 0 . 6 . FindP(A and B)

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ANSWER :(i) 0.18, (II) 0.12, (III) 0.72, (IV) 0.28
11346.

If x+1/x=2costheta then x^(10)+(1)/(x^(10))=

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`2^(10)cos10 THETA`
`2cos10theta`
`2^(10)COS^(10)theta`
`2cos^(10)theta`

Answer :B
11347.

Evaluate the following : [[2,3,4],[1,-1,3],[4,1,10]]

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SOLUTION :`[[2,3,4],[1,-1,3],[4,1,10]]`=`[[5,3,4],[0,-1,3],[5,1,10]]`
(REPLACING `C_1` by `C_1+C_2`)
`5[[1,3,4],[0,-1,3],[1,1,10]]=[[1,3,4],[0,-1,3],[0,-2,6]]`
(`R_3`~`R_3-R_1`)
= `5xx1[[-1,3],[-2,6]]=5(-6+6)=0`
11348.

If A=[(1,3),(4,2)],B=[(2,-1),(1,2)]," then "|ABB'|=

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100
50
250
-250

Answer :D
11349.

Integrate the following rational functions : int(x^(3))/(x^(2)-4)dx

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ANSWER :`(X^(2))/(2)+2log|x^(2)-4|+c`
11350.

Find the matrix A such that [{:(2,-1), (1,0),(-3,4):}]A=[{:(-1,-8,-10),(1,-2,-5),(9,22,15):}]

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Solution :we have, `[{:(2,-1),(1,0),(-3,4):}]_(3xx2)A=[{:(-1,-8,-10),(1,-2,-5),(9,22,15):}]_(3xx3)`
From the given equation , it is clear that ORDER of A should be `2xx3`
LET `A=[{:(a,b,c),(d,E,f):}]`
`[{:(2,-1),(1,0),(-3,4):}][{:(a,b,c),(d,e,f):}]=[{:(-1,-8,-10),(1,-2,-5),(9,22,15):}]`
`rArr[{:(2a-d,2b-e,2c-f),(a+0d,b+0.e,c+0.f),(-3a+4d,3b+4e,-3c+4l):}]=[{:(-1,-8,-10),(1,-2,-5),( 9,22,15):}]`
`rArr [{:(2a-d,2b-e,2c-f),(a,b,c),(-3a+4d,-3b+4e,-3c+4f):}]=[{:(-1,-8,-10),(1,-2,-5),(9,22,15):}]`
By equality of matrices, we get
`a=1,b=-2,c=-5`
and `2a-d=-1rArrd=2a+1=3`
`rArr 2b-e=-8rArre=2(-2)+8=4`
2c-f=-10`rArr`f=2c+10=0
`therefore A=[{:(1,-2,-5),(3,4,0):}]`