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11351.

The value of sin(cot^-1x) is equal to

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`X/(1+x^2)`
`1/(1+x^2)`
`1/sqrt(1+x^2)`
`x/sqrt(1+x^2)`

ANSWER :C
11352.

Let a=alphahat(i)+2hat(j)-3hat(k), b=hat(i)+2alphahat(j)-2hat(k) and c=2hat(i)-alphahat(j)+hat(k). Then the value of 6alpha, such that {(atimesb)times(btimesc)}times(ctimesa)=a, is

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ANSWER :`(4)`
11353.

Let m,n be two positive real numbers and define f(n)=int_(0)^(oo)x^(n-1)e^(-x)dx and g(m,n)=int_(0)^(1)x^(m-1)(1-m)^(n-1)dx. It is known that f(n) for n gt 0 is finite and g(m, n) = g(n, m) for m, n gt 0. int_(0)^(1)x^(m)(log_(e).(1)/(x))dx=

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`(f(n+1))/((m+1)^(n))`
`(f(n))/((m+1)^(n+1))`
`(f(n+1))/((m+1)^(n+1))`
`g(m+1),n+1)`

Solution :PUTTING `log_(e)..(1)/(x)=t`
`rArr""x=e^(-t)`
`rArr""int_(0)^(1)x^(m)(log_(e)(1)/(x))^(n)DX`
`""=int_(OO)^(0)e^(-mt)t^(n)(-e^(t))dt`
`""=int_(0)^(oo)t^(n)e^(-(m+1))dt`
`""=(1)/((m+1)^(n+1))int_(0)^(oo)t^(n)e^(-y)DY" (putting (m + 1) t = y)"`
`""=(f(n+1))/((m+1)^(n+1))`
11354.

Let m,n be two positive real numbers and define f(n)=int_(0)^(oo)x^(n-1)e^(-x)dx and g(m,n)=int_(0)^(1)x^(m-1)(1-m)^(n-1)dx. It is known that f(n) for n gt 0 is finite and g(m, n) = g(n, m) for m, n gt 0. int_(0)^(oo)(x^(m-1))/((1+x)^(m+n))dx=

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g(m,N)
`g(m-1,n)`
`g(m-1,n-1)`
`g(m,n-1)`

SOLUTION :`g(m,n)=int_(0)^(1)x^(m-1)(1-x)^(n-1)DT`
Put `x=(1)/(1+y)`
`rArr""g(m,n)=int_(oo)^(0)(1)/((1+y)^(m-1))(1-(1)/(1+y))^(n-1)(-(1)/((1+y)^(2)))dy`
`""=int_(0)^(oo)(y^(n-1))/((1+y)^(m+n))dy`
`""=int_(0)^(oo)(x^(n-1))/((1+x)^(m+n))dx`
11355.

Let m,n be two positive real numbers and define f(n)=int_(0)^(oo)x^(n-1)e^(-x)dx and g(m,n)=int_(0)^(1)x^(m-1)(1-m)^(n-1)dx.It is known that f(n) for n gt 0 is finite and g(m, n) = g(n, m) for m, n gt 0.int_(0)^(1)(x^(m-1)+x^(n-1))/((1+x)^(m+n))dx=

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g(N, m)
`g(m-1,n+1)`
`g(m-1,n-1)`
`g(m+1,n-1)`

Solution :`I=int_(0)^(1)(x^(m-1)+x^(n-1))/((1+x)^(m+n))DX`
`=int_(0)^(1)(x^(m-1))/((1+x)^(m+1))dx+int_(0)^(1)(x^(n-1))/((1+x)^(m+n))dx`
`=I_(1)+I_(2)`
In `I_(2)`, put `x=(1)/(t)`, then `I_(2)=int_(oo)^(1)((1)/(t^(n-1)))/((1+(1)/(t))^(m+n))dx`
`""=int_(1)^(oo)(x^(m-1))/((1+x)^(m+n))dx`
`therefore""I=int_(0)^(1)(x^(m-1))/((1+x)^(m+n))dx+int_(1)^(oo)(x^(m-1))/((1+x)^(m+n))dx`
`=int_(0)^(oo)(x^(m-1))/((1+x)^(m+n))dx=g(m,n)`
11356.

Differentiate the following w.r.t.x. cos^(-1) (sin x).

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ANSWER :`F'(X)= -1`.
11357.

Find the probability of getting equal numbers, when two dice are rolled.

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ANSWER :`(1)/(6)`
11358.

The statement P(n) = 9^(th)- 8^(n),whendividedby 8,alwaysleaves the remainder

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1
3
1
7

Answer :C
11359.

lim_(xtosqrt3)[x]

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SOLUTION :L.H.L.`=lim_(xtosqrt3-)[X]=lim_(hto0)[sqrt3-h]=1`
R.H.L.`=lim_(xtosqrt3+)[x]=lim_(hto0)[sqrt3+h]=1`
Thus L.H.L., R.H.L. both
EXIST and L.H.L.=R.H.L.
So the limit exists and it's value is 1.
11360.

Find all points of discontinuity of f(x) where f is defined by f(x) = {(x^3-3,if, x le 2),(x^3+1,if, x gt 2):}.

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ANSWER :`X = 2` is the only POINT of DISCONTINUITY.
11361.

The velocity of a particle moving along positive X-axis varies as v=alphasqrtx where alpha is a constant.if particle is at x=0 at t=0 , what will be the average velocity of particle during the time it moves a distance S ?

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`alpha/2sqrtS`
`2/ALPHASQRTS`
`alphasqrtS`
`sqrtS/alpha`

11362.

Let L_(1):x=y=z L_(2): x-1=y-2=z-3 be two linesLet from origin O(0,0,0) on L_(1) perpendicular is drawn to L_(2) has foot A. Segment OA is rotated about O by an angle 90^(0) such that L_(2) moves along with it. Without changing its direction & becomes L_(3) A becomes B(alpha,beta,lambda) then alpha+beta+lambda=

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Solution :LET `A(lambda+1,lambda+2,lambda+3)`
`therefore (lambda+1)+l(ambda+2)+(lambda+3)=0implieslambda=-6`
`impliesA(-5,-4,-3)`
Let LINE `L_(1) & L_(3)` LIES on plane P.
then normal to the plane P will be `5i + 4j+3k`.
implies Eq. of plane P is
`5x+4y+3z=0`
therefore Dr's of line through origin `& _|_to L_(3)`is.
`(5i+4j+3k)xx(i+j+k)`
`=lt,-2 1 gt`
therefore line OB: `(x)/(1)=(y)/(-2)=(z)/(1),`Since `OB =OA =5sqrt(2)`
`therefore` Coordinates of point B which lies on `L_(3)` is
`((5sqrt(2))/(sqrt(6)),((5sqrt(2))(-2))/(sqrt(6)),(5sqrt(2))/(sqrt(6)))` or
`((-5sqrt(2))/(sqrt(6)),((5sqrt(2))(2))/(sqrt(6)),(-5sqrt(2))/(sqrt(6)))`
11363.

Prove that the least perimeter of an isosceles triangle in which a circle of radius can be inscribed is 6rsqrt3.

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ANSWER :(0,2)
11364.

Delta=|{:(p,q,r),(p+2a,q+2b,r+2c),(a,b,c):}| then

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a) `Delta=0`
B) `Delta=abc`
C) `Delta=pqr`
d) NONE of these

Answer :A
11365.

y=(x^(3)+(x^(6))/(2)+(x^(9))/(3)+……) then

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`X^(3)=1-E^(-y)`
`x=log(x+y)`
`x^(3)=e^(y)`
`x=1+e^(y)`

ANSWER :A
11366.

Evaluate the integral underset(0)overset(pi//4)int log(1+tanx)dx

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ANSWER :`(PI)/(8) LOG 2`
11367.

If the standard deviation of the binomial distribution (q+p)^(16)is 2, then mean of the distribution is….

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6
8
10
12

Solution :At X=-2, F must be continuous
`THEREFORE(1)/(2)=a+4b""......(1)`
At x=-2, L.H.D.=R.H.D.
`2bx=(1)/(x^(2))""......(2)`
11368.

Find the direction cosines of the line joining the two points P(-2, 4, -5) and Q(1, 2, 3). 6. Prove that the points (1, 2, 3), (3, 1, 7) and (7, -1, 15) are collinear.

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Answer :`(3)/(SQRT(77)),(-2)/(sqrt(77)),(8)/(sqrt(77))`
11369.

Find all points of discontinuity of f, where f(x)= {((sin x)/(x)",","if " x lt 0),(x+1",","if" x ge 0):}

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ANSWER :`X in R`
11370.

Find the locus of the incentre of the triangle formed by xy-4x-4y+16=0 and x+y=a (agt4,a nesqrt(2) " ""and a is the parameter").

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11371.

Find the area bounded by the curve y=l nxthe X-axis and the straight line x=e

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ANSWER :1 SQ. UNITS.
11372.

Which of the following scatterplots shows a relationship that is appropriately modeled with the equation y=ax^(b) , where a is positive and b is negative?

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Solution :The graph of `y = a x ^(b)` , where a is positive and b is NEGATIVE, has a positive y-intercept and rapidly decreases (in PARTICULAR, decreases at a faster rate than a linear function) toward the x-axis as x increases. Of the scatterplots shown, only the ONE in choice B would be APPROPRIATELY modeled by such a function.
Choice A is incorrect, as this scatterplot is appropriately modeled by a linear function. Choice C is incorrect, as this scatterplot is appropriately modeled by an increasing function.Choice D is incorrect, as this scatterplot shows no clear relationship between x and y.
11373.

Match the following

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a,b,C,d
c,b,d,a
b,a,d,c
a,b,d,c

Answer :B
11374.

If the distances from the origin to the centres of three circles x^(2)+y^(2)-2kix=c^(2), (i=1,2,3) are in G.P, then the length of the tangents drawn to them from any point on the circle x^(2)+y^(2)=c^(2)" are in "

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A.P
G.P
H.P
A.G.P

ANSWER :B
11375.

Find the equation of the curve passing through the point (0,1), if the slope of the tangent to the curve at any point (x,y), is equal to the sum of x coordinate and product of x coordinate and y coordinate of that point.

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ANSWER :`y = -1 + 2E^((X^(2))/(2))`
11376.

A committee consisting of atleast three members is to be formed from a group of 6 boys and 6 girls, such that it always has a boy and a girl. Number of ways to form such committee is………

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`2^(12)-2^(7)-13`
`2^(11)-2^(6)-13`
`2^(11)-2^(7)-35`
`2^(12)-2^(7)-35`

SOLUTION :Set x + 8 = u, use `Am GE GM`
11377.

Find the centre of gravity of the first are of the cycloid: x=a (t - sin t), y= a (1- cos t) (0 le t le 2pi).

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ANSWER :`(4)/(3) a`
11378.

Differentiate.(sqrtx+1/sqrtx)x tanx

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SOLUTION :`y=(sqrtx+1/sqrtx)XTAN=(X^(3/2)+x^(1/2))TANX`
`dy/dx=(3/2x^(1/2)+1/2x^(1/2))tanx`
`+(x^(3/2)+x^(1/2))sec^2x
11379.

If x=CiSθ, then find the value of (x^6+(1/x^6))

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2cos4θ
cos6θ
2cos6θ
cos4θ

Answer :C
11380.

If the solution of cosec^(2)x(dy)/(dx) - (1)/(y) = 0 is ax + b sin 2x + cy^(2) = k, a gt 0 then ascending order of a,b,c is

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a,B,c
c,b,a
c,a,b
b,a,c

Answer :B
11381.

Evaluate int_(a)^(b) x dx as the limit of a sum.

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ANSWER :`1/2 (B^(2)-a^(2))`
11382.

Match the following

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a,C,b
b,c,a
d,c,b
c,d,a

Answer :A
11383.

Expand f(x) = (1)/(x) about x =2 upto four terms

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ANSWER :`(1)/(X) = (1)/(2) - ((x-2))/(4) + ((x-2)^(2))/(8) - ((x -2)^(3))/(16) + ….`
11384.

If y = log (log x) then (d^(2)y)/(dx^(2)) is equal to

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1.`(-(1+LOG x))/((x log x)^(2))`
2.`(-(1+log x))/(x^(2)log x)`
3.`((1+log x))/((x log x)^(2))`
4.`((1+log x))/(x^(2)log x)`

Answer :A
11385.

A(2, 1) and B(2, 3) are two points.If Pis a point such that PA + PB - 2, then the locus of P is

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`4X^(2)-12Y^(2)- 16X + 124y-69=0`
`4x^(2)+12y^(2)- 16x - 124y+69=0`
`4x^(2)+12y^(2)+ 16x - 124y+69=0`
`4x^(2)+12y^(2)+ 16x + 124y-69=0`

ANSWER :A
11386.

Differentiate.sec^(-1)(e^x+x)

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SOLUTION :`y=sec^(-1)(e^x+x)`
`dy/dx=1/(|e^x+x|sqrt((e^x+x)^2-1))xxd/dx(e^x+x)`
`=(e^x+1)/(|e^x+x|sqrt((e^x+x)^2-1))`
11387.

int_((-pi)/(4))^((pi)/(4)) (dx)/(1+e^(tan x))

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ANSWER :`(PI)/(4)`
11388.

Differentiate.sin^2(cos^(-1)x)

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SOLUTION :`y=SIN^2(cos^(-1)X)=[sin(cos^(-1)x)]^2`
[sin sin^(-1)SQRT(1-x^2)]^2`
therefore dy/dx =-2x`
11389.

Evaluate the definite integral in exercise overset(1)underset(0)int (2x+3)/(5x^(2)+1)

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ANSWER :`(1)/(5)LOG6+(3)/(SQRT(5))tan^(-1) sqrt(3)`
11390.

For complex number z, the minimum value of |z| + |Z- cos alpha-I sin alpha| + |z-2 (cos alpha +I sin alpha)| is

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4
2
1
3

Answer :B
11391.

Find the relationship between a and b so that the function f defined by f(x)={{:(ax+1-2," if "x le 3),(bx+3," if "x gt 3):} is continuous at x=3.

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ANSWER :`a=b+(2)/(3)`.
11392.

If isqrt(-1), then 4+5(-(1)/(2)+(isqrt(3))/(2))^(334)+3(-(1)/(2)+(isqrt(3))/(2))^(365) is

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`1-isqrt(3)`
`-1+ isqrt(3)`
`isqrt(3)`
`-isqrt(3)`

ANSWER :C
11393.

Solve the differential equation : (x^(3) + x^(2) + x +1)(dy)/(dx) = 2x^(2) + x.

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ANSWER :`y = (1)/(2) log |x +1| + (3)/(4) log|x^(2) +1|-(1)/(2) tan^(-1)(x) + C`
11394.

If the straight line y=x meets y=f(x) at P, where f(x) is a solution of the differential equation (dy)/(dx)=(x^(2)+xy)/(x^(2)+y^(2)) such that f(1)=3, then the value of f'(x) at the point P is

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`(3)/(5)`
`(5)/(3)`
2
1

Answer :D
11395.

Integrate the function in Exercise. sin^(-1)((2x)/(1+x^(2)))

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ANSWER :`1=2xtan^(-1)x-log|(1+x^(2))|+C`
11396.

Evalute the following integrals int (1)/((1 + sqrt(x)) sqrt(x - x^(2)) ) dx

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Answer :`TAN^(-1) (E^(x)) + c `
11397.

Evaluate : int (2x+4)/(sqrt(x^(2)+4x+5))dx

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SOLUTION :N/A
11398.

Find the area of the parallelogram whose adjacent sides are determined by the vectors veca=hati-hatj+3hatk and vecb=2hati-7hatj+hatk

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ANSWER :`15sqrt(2)`
11399.

The region formed by the inequalities 2x+3y-5 le 0, 4x-3y+2 le 0" and " x ge 0 ………

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does not LIE in FIRST QUADRANT
lies in first quadrant and bounded
lies in first quadrant and unbounded
lies in first and SECOND quadrant

Answer :D
11400.

Obtain the following integrals : int(1)/(sqrt(3t-2t^(2)))dt

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Answer :`:. I=(1)/(sqrt(2)) SIN^(-1)((4t-3)/(3))+C`