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4801.

Let f(x)=alphax^(2)-a+(1)/(x)"where"alpha is real constant. The smallest alphafor f(x)ge0"for all"xgt0 is-

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`(2^(2))/(3^(3))`
`(2^(3))/(3^(3))`
`(2^(4))/(3^(3))`
`(2^(5))/(3^(3))`

SOLUTION :`F(x)=alphax^(2)-2+(1)/(x)`
`f(x)=(alphax^(3)-2x+1)/(x)AAx(0,oo)`
`sophi(x)=AX^(3)--ax+1` should be positive
`phi(x)=ax^(3)-2x+1`
`phi^(')(x)=3alphax^(2)-2=0`
`x=+-sqrt((2)/(3alpha))`
Clearly `x=sqrt((2)/(3alpha))` point of minima
`phi(sqrt((2)/(3alpha)))ge0`
`sqrt((2)/(3alpha)){ALPHA.(2)/(3alpha)-2}+1ge0`
`sqrt((2)/(3alpha))(-(4)/(3))+1ge0`
`sqrt((2)/(3alpha))((4)/(3))lel`
`sqrt((2)/(3alpha))le(3)/(4)`
`(2)/(alpha)le(3^(2))/(4^(2))`
`alphage(32)/(27)`
4802.

If b=i-j+3k, c=j+2k" and "a is a unit vector, then the maximum value of the scalar triple product [a b c] is

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`SQRT(30)`
`sqrt(29)`
`sqrt(26)`
`sqrt(60)`

ANSWER :A
4803.

Write down a unit vector in XY - plane making an angle of 30^(@) with the positive direction of x- axis.

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Answer :`(SQRT(3))/(2)HATI+(1)/(2)HATJ`
4804.

Let A and B be events with P(A)= 3/8, P(B)= 1/2 andP(A cap B) = 1/4, Find P(A cup B)

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<P>

ANSWER :`P(A)=3/8,P(B)=1/2,P(ACAPB)=1/4`
`P(ACUPB)=P(A)+P(B)-P(AcapB)`
`3/8+1/2-1/4=(3+4-2)/8=5/8`
4805.

Find the sum of the vectorsveca=hati-2hatj+hatk,vecb=-2hati+4hatj+5hatkandvecc=hati-6hatj-7hatk.

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ANSWER :`-4hatj=hatk`
4806.

Find the points where the following function are not differentiable.sin|x|

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SOLUTION :sin|x| is not DIFFERENTIABLE at x=0
4807.

Match the following:

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ANSWER :`(PI)/(2)-LOG2`
4808.

Let f(x) =1/[sin x] then (where [*] denotes the greatest integer function)

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domain of `F(x)` is `(2npi + pi, 2npi + 2pi) cup {2npi + pi//2}`
f(x) is CONTINOUS when `x in (2npi + pi, 2npi + 2pi)`
`f(x)` is continous at `x=2npi +pi//2`
`f(x)` has period `2pi`

ANSWER :A::B::D
4809.

Represent the following equations on the number line provided. y-4""

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ANSWER :`(##GRE_MAT_MAN_PRP_C03_E01_003_A01##)`
4810.

Two unit squares are chosen at random on a chess board. The probability that they have a side in common is

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`(1)/(9)`
`(2)/(7)`
`(1)/(18)`
`(1)/(3)`

ANSWER :C
4811.

Trigonometric and inverse trigonometric functions and differentiable in their respective domain.

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ANSWER :1
4812.

Chemoreceptors for CO_(2) and H^(+) ion concentration are present in :-

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ARTERIES and MEDULLA
VEINS and PONS
Arteries and veins and medulla
Vein and pons and medulla

Answer :A
4813.

If int (1)/( e^(x) + 1) dx= px- q log |1+e^(x) | + C then p+q=….........

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0
2
`-2`
`1`

ANSWER :B
4814.

Solve (dy)/(dx) + (y)/(x) = x^(2)y^(6)

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ANSWER :`5X^(3)/(2)+C`
4815.

Let A be any finite set having n elements. Then number of one - one function from A to Aare

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` N^(2)`
` n!`
` 2N `
NONE of these

Answer :B
4816.

There are two bags each of which contains n balls. A main has to select and equal number of balls from both the bags. The number of ways in which the man can choose at least one ball from each bas is

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`""^(2N) C_n`
`""^(2n) C_(N-1)`
`""^(2n) C_(n-1)`
`""^(n) C_(n-1)`

ANSWER :C
4817.

if [ ( cos alpha,- sinalpha),(sin alpha, cos alpha)] andA +A^1 =I then alpha=……

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`PI/6`
`pi/3`
`pi`
`(3PI)/(2)`

ANSWER :B
4818.

If alpha le 2 sin^(-1) x + cos^(-1) x le beta, then

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1)`alpha=0, beta=2pi`
2)`alpha=0, beta=PI`
3)`alpha= (-pi)/(2), beta= (3pi)/(2)`
4)`alpha= (-pi)/(2) beta= (pi)/(2)`

Answer :B
4819.

A: int (1)/(4+5 sinx)dx=(1)/(3)log|(2tan(x//2)+1)/(2tan(x//2)+4)|+c R : If 0 lt a lt b, then int(dx)/(a+b sin x)=(1)/(sqrt(b^(2)-a^(2)))log|(a tan (x//2)+b-sqrt(b^(2)-a^(2)))/(a tan (x//2)+b+sqrt(b^(2)-a^(2)))|+c

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Both A and R are TRUE and R is the CORRECT explanation of A
Both A and R are true and R is not correct explanation of A
A is true R is false
A is false but R is true.

Answer :1
4820.

If these are 8 points on a circle, then number of different line segments formed by joining these points is

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28
38
48
58

Answer :A
4821.

A bag of pennies could be divided among 6 children, or 7 children, or 8 children, with each getting the same number and with 1 penny left over in each case. What is the smallest number of pennies that could be in the bag?

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22
43
57
169

Answer :D
4822.

Consider a binary opertion ** on the set {1,2,3,4,5} given by the following multiplication table (Table 1.2) (i) Compute (2 **3) **4 and 2 ** (3**4) (ii) Is ** commutative ? (iii) Compute (2 **3) ** (4 **5).

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ANSWER :(i) ` (2 **3) ** 4=1 and 2 ** (3 ** 4) =1 ` (ii) YES (iii) 1
4823.

If z_(1), z_(2), z_(3), z_(4) are complex numbers in an Argand plane satisfying z_(1)+z_(3)=z_(2)+z_(4). A compex number 'z' lies on the line joining z_(1) and z_(4) such that Arg((z-z_(2))/(z_(1)-z_(2)))=Arg((z_(3)-z_(2))/(z-z_(2))). It is given that |z-z_(4)|=5,|z-z_(2)|=|z-z_(3)|=6 then

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AREA of triangle formed by `Z,z_(1),z_(2)` is `3sqrt(7)` SQ units
area of the triangle formed by `z, z_(3), z_(4)` is `(15sqrt(7))/3` sq. units
area of the quadrilateral formed by the points `z_(1),z_(2),z_(3),z_(4)` taken in orders is `(27sqrt(7))` sq. units
area of the quadrilateral formed by the points `z_(1),z_(2),z_(3),z_(4)` taken in order is `(27sqrt(7))/4` sq. units

Solution :`a=B+5`
and `b/6=6/a`
`implies ab=36`
`b^(2)+5b-36=0`
`implies b=4`
4824.

The value of median for the data Income (in Rs. )"" 1000 "" 1100"" 1200"" 1300"" 1400"" 1500 No. of persons :"" 14 "" 26 "" 21"" 18"" 28"" 15is

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1300
1200
1250
1150

Answer :B
4825.

If int_(0)^(1)f(x)dx=5, then the value of ……………………….+ 100 int_(0)^(1)x^(9)f(x^(10))dx is equal to

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275
55
125
625

Answer :C
4826.

Let a^(2)+b^(2)=a^(2)+beta^(2)=2. Then show that the maximum value of S=(1-alpha)(a-b)+(1-alpha)(1-beta) is 8.

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SOLUTION :Let `alpha=sqrt(2)cos THETA, b=sqrt(2)sin theta`.
`alpha=sqrt(2)cos phi, beta=sqrt(2)sin phi`
`RARR S=2-2(sin(theta+pi//4))+sin(phi+pi//4)+2[cos(theta-phi)]`
Maximum value OCCURS when `theta=phi=5pi//4`
`rArr S_("max")=2[-1-1]+2=8`
4827.

Solvesin^2 theta tan theta+cos^2 theta cot theta-sin 2 theta=1+tan theta+cot theta

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` (pi)/(4)`
` pi`
`(7 pi)/(12) `
None of these

Answer :C
4828.

Find least non negative integer r such that 7xx13xx23xx413 -= r "(mod 11)"

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Solution :`7xx13xx23xx412 -="r(mod11)"`
Now `7xx13 -= "MOD 11"
" 23-= 1 "mod" 11
413 -= 6 "mod" 11`
`:. 7xx13xx23xx413 -= 3xx1xx6 "mod" 11`
`-= 18 "mod" 11 `
` -= 7 "mod" 11`
`:. r =7`
4829.

AD, BE, CF are internal angular bisectors of Delta ABC and I is the incentre. If a(b+c)sec.(4)/(2)ID+b(a+c)sec.(B)/(2)IE+c(a+b)sec.(C )/(2)IF=kabc, then the value of k is

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1
2
3
4

Solution :
`(ID)/(AD)=(ID)/((2bc)/(b+c)cos.(A)/(2))=(a(b+c)SEC.(A)/(2).ID)/(2abc)`
Now `(AI)/(ID)=(AB)/(BD)=(c )/((ac)/(b+c))=(b+c)/(a)`
`therefore (ID)/(AD)=(ID)/(AI+ID)=(a)/(a+b+c)`
`therefore(ID)/(AD)+(IE)/(BE)+(IF)/(CF)=(a+b+c)/(a+b+c)=1`
`therefore a(b+c)sec.(A)/(2)ID+b(a+c)sec.(B)/(2)IE + c(a+b)sec.(C )/(2)IF`
= 2abc
`therefore K = 2`
4830.

The solution of x^(2) (dy)/(dx) + (x-2) y = x^(2) e^(-2//x) is

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`xy e^((2)/(X)) = x^(2) + c`
`xy e^((2)/(x)) = (x^(2))/(2) + c`
`xy^(2) e^((2)/(x)) = (x^(2))/(2) + c`
`2 xy e^((2)/(x)) = (x^(2))/(2) + c`

ANSWER :B
4831.

Positive integers a and b are such that a+b=a/b+b/aWhat is the value of a^2 +b^2?

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ANSWER :2
4832.

Applying the formula for multiple integration by parts, calculate the following integrals : (b) int (x^(2) -7x +1) /( root(3) (2x+1) ) dx.

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ANSWER :(b) `(3)/(4) (x^(2) -7X +1) (2x + 1)^(2/3) -(9) /( 40 ) (2x -7) (2x+1) ^(5/3) + (27) /( 320) (2x+1)^(8/3) +C`.
4833.

Differentiatex^(5/3)-x^(1/2)

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SOLUTION :LET `y=X^(5/3)-x^(1/2)`
`dy/dx=5/3x^(2/3)-1/2x^(-1/2)`
4834.

The planes ax+4y+z=0,2y+3z-1=0 and 3x-bz+2=0 will

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meet at a point if `ab ne 15`.
meet on a LINE if ab =15, a=3
have no COMMON point if ab=15, `a ne 3`.
have no common point if ab=15, `ane5`

Answer :A::B::C
4835.

If the normal at a point P to the hyperbola meets the transverse axis at G, and the value of SG/SP is 6, then the eccentricity of the hyperbola is (where S is focus of the hyperbola)

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2
4
6
8

Solution :Equation of NORMAL at point `P(a SEC THETA, b tan theta)` on HYPERBOLA `(x^(2))/(a^(2)) -(y^(2))/(b^(2)) =1` is

`a cos theta x +b COT theta y =a^(20+b^(2)`
`:. G((a^(2)+b^(2))/(a cos theta),0)`
`S (ae,0)`
`SP = e (a sec theta) -a`
Also `SG =(a^(2)+b^(2))/(a cos theta) -ae =(a^(2)e^(2))/(a cos theta) - ae = e[e(a sec theta)-a]`
`rArr SG//SP = e= 6`
4836.

A candidate is required to answer 6 out of 12 questions which are divided into two parts A and B,each containing 6 questions and he/she is not permirred to attempt more than 4 question from any part .In how many different ways can he/she make up his/her choice of 6 questions?

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850
800
750
700

Answer :A
4837.

Using the properties of determinants, prove the following |{:(a,b-c,c+b),(a+c,b,c-a),(a-b,b+a,c):}|=(a+b+c)(a^2+b^2+c^2)

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ANSWER :`(a+b+c)(a^2+b^2+c^2)`
4838.

Match the following : {:("List - I " , " List - II") ,(" (P) If " x^(2)+y^(2)=1 " then minimum value of x +y is " , "(1) -3"), ("(Q) If maximum value of y = a cosx " - 1/3 cos 3x"occurs at " x= pi/6 " then value of a is " , "(2)" -sqrt2),("(R) If f(x) = x -2 sin x "0 le x le 2pi " is increasing in the interval "(a pi b pi) "then a + b is " , "(3) " 3), ("(S) If equation of tangent to the curve y = " - e^(x//2) " where it crosses the y - axis is " y/p + y/q =1 " thenp -q is " , "(4)" 2 ):}

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4,1,2,3
2,4,4,3
1,3,2,3
1,3,4,2

Answer :D
4839.

Consider the line L-=(x-1)/(2)=(y+2)/(3)=(z-7)/(6). Point P(2, -5, 0) and Q are such that PQ is perpendicular to the line L and the midpoint of PQ lies on line L, then coordinates of Q are

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`(-4, -5, 2)`
`(-3, 0, 1)`
(1, 6, 2)
(1, 5, 7)

Answer :A
4840.

(2 cos theta - 1 ) ( 2 cos 2 theta -1)(2 cos 4 theta -1)(2 cos 8 theta -1)=

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`0`
1
`(2 cos 8 THETA +1)/(2 cos 8+1)`
`(2 cos 160 theta + 1)/(2 cos theta + 1)`

ANSWER :D
4841.

Find the position vector of a point A in space such that vec(OA) is inclined at 60^@ to OX and at 45^@ to OY and |vec(OA)| = 10 units.

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ANSWER :`(5,5sqrt2,5)`
4842.

A : sum_(r=1)^(n-1) cos^(2) (rpi)/(n)=(n)/(2)-1 R :cos alpha + cos ( alpha + beta ) + cos (alpha + 2 beta ) + ......... + cos ( alpha + (n-1)beta ) = (sin(nbeta //2))/(sin ( beta//2)) cos""((2alpha + (n-1) beta )/(2))

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A is TRUE , R is true and R is correct EXPLANATION of A
A is true , R is trueand R is not correct explanation of A
A is true , R is FALSE
A is false , R is true

ANSWER :A
4843.

STATEMENT -1 : If [sin^(-1)x] gt [cos^(-1)x],where [] represents the greatest integer function, then x in [sin1,1] is and STATEMENT -2 : cos^(-1)(cosx)=x,x in [-1,1]

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STATEMENT -1 is TRUE, Statement-2 is True, Statement -2 is a CORRECT explanation for Statement -2
Statement -1 is True, Statement -2 is True, Statement -2 is NOT a correct explanation for Statement -2
Statement-1 is True, Statement -2 is False
Statement -1 is False, Statement -2 is True

Answer :C
4844.

Two fair dice are rolled. Let P(A_(i))gt0 donete the event that the sum of the faces of the dice is divisible by i. For which one of the following (I,j) are the events A_(i)and A_(j) independent ?

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`(3,4)`
`(4,6)`
`(2,3)`
`(4,2)`

SOLUTION :`P(A_(2))=1/2,P(A_(3))=1/3,P(A_(6))=1/6`
`THEREFOREP(A_(2)nnA_(3))=P(A_(2))P(A_(3))`
`impliesP(A_(6))=P(A_(2))P(A_(3))`
`6/36=1/2xx1/3`
HENCE, `A_(2)and A_(3)` are independent.
4845.

Two fair dice are rolled. Let P(A_(i))gt0 donete the event that the sum of the faces of the dice is divisible by i. The number of all possible ordered pair (I,j) for which the events A_(i) and a_(j) are independent is

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6
12
13
25

Solution :Note that `A_(1)` is independent with all events `A_(1),A_(2),A_(3),A_(4)....,A_(12),` Now, total NUMBER of ORDERED pairs is 23.
`underset(22)( underbrace((1.1),(1,2),(1.3),...,(1,11)))+(1,12)`
ALSO that `A_(2),A_(3),andA_(3),A_(2)` are independent. Hence, there are 25 ordered pairs.
4846.

Prove that the function f: [0,oo)rarr R, given by f(x)=9x^(2) +6x -5 is not invertible. Modify the codomain of the functions to make it invertible, and hence find f^(-1)

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ANSWER :REVISED F: [ `0, oo) rarr [-5,oo) ; f^(-1):[ -5,oo) rarr [0,1)`
4847.

What is the order of the product matrix ? [(a),(b),(c)]["123"] .

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ANSWER :`3xx3`
4848.

|(1,1,1),(a,b,c),(a^(3),b^(3),c^(3))|=

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`x=1/3(a+b+c)`
`x=2/3(a+b+c)`
`x=a+b+c`
NONE of these

Answer :A
4849.

inte^(4x)sin3xdx=......+c

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`(E^(4X))/(25)(sinx+cosx)`
`(e^(4x))/(25)(4sin3x-3cos3x)`
`(e^(4x))/(5)(4sin3x-3cos3x)`
`(e^(4x))/(25)(4sin3x-3cos3x)`

ANSWER :B
4850.

A bag contains 4 black and 3 white balls. If two balls are drawn at random without replacement, what is the probability that both balls have each color?

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`1/7`
`3/7`
`4/7`
NONE of these

ANSWER :A