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Correct CHOICE is (a) dbcont

The explanation is: The dbcont command would allow US to CONTINUE the working of our function after we have ENTERED the debugging mode. The continue command is USED in loops, it won’t help us in this case.

Right choice is (a) dbquit

Easiest explanation: The dbquit command can be used to EXIT from the DEBUGGING MODE. This is pre-defined in MATLAB. dbend and debugend COMMANDS don’t EXIST.

The CORRECT answer is (c) {}

The BEST I can explain: The variables of the condition gets converted to a CELL format if the condition is given in {}. THEREAFTER, the variables cannot be converted into a logical form. It can be given WITHIN () and [].

The correct choice is (a) varargout

The explanation: The varargout command allows 1*N outputs to be asked from the function where it is situated. But the nargchkout command RESTRICTS the total number of outputs that can be SOUGHT from the function. So it REALLY puts a limit to the VALUE of N. Hence, the correct option is varargout.

Correct option is (a) TRUE

The explanation: If the continue statement GETS executed in the final iteration of a loop, the CONTROL breaks the loop. The break statement will exit control IRRESPECTIVE of the number of iterations left and HENCE the above statement is true.

Right answer is (b) nested if STRUCTURE

Easiest explanation: If the continue statement is present deep-rooted in a nested if structure, it will only stop the current ITERATION. It won’t exit the current ONGOING LOOP or the EXTERNAL loop.

Correct choice is (a) True

The BEST explanation: Any logical operation is pre-defined in MATLAB to give a logical 1 if the result DERIVED from the operation is true. If the result is false, the result returned will be a logical 0.

Right option is (d) Unary Operator

To explain: ~ is a unary operator since the NOT FUNCTION operates on only one OPERAND. It isn’t a relational operator since it doesn’t do any COMPARISON and it’s not an arithmetic operator since it doesn’t perform any arithmetic OPERATION.

Correct choice is (a) multiple elseif

The best explanation: If multiple elseif and nested if has the same NUMBER of conditions. Multiple elseif checks at each step if it at all it has to go to the next condition. But nested if checks each condition before LEAVING the entire control STRUCTURE. Hence, the number of STEPS COVERED in multiple elseif is less than nested if. Thus the former will take less time.

The CORRECT answer is (b) Entire loop

For EXPLANATION: The BREAK STATEMENT will exit the loop where the break statement is PRESENT. It won’t take control out of the external loop.

Correct CHOICE is (B) False

The BEST explanation: The continue statement is only allowed for and while loops. If we give the continue statement WITHIN a switch-case structure, MATLAB will give an error.

Correct answer is (a) break

The explanation is: If the if-else structure is not within any loop, we cannot USE the break STATEMENT. The break statement is only ALLOWED for loops. If the if-else structure is part of a loop, we can use the break statement to END the loop before it reaches its limit.

Correct option is (C) command window

For EXPLANATION: The debug commands can only be run from the command window. If they are present in user-defined functions or LIVE SCRIPTS, the working of the function would ENTIRELY stop when any debug command is invoked while evaluation of the function.

The CORRECT OPTION is (c) result in an error while running the function

To elaborate: This command will result in an error if it is PLACED within an m.file. This is because debugging commands can only be used when the control enters debug mode and we need to give these commands only from the command window.

The CORRECT OPTION is (a) Sorting

For EXPLANATION: The sorting procedure is the easiest way to GET the highest of n numbers. This is because the code complexity will increase, drastically, if we use an if-else STRUCTURE or a switch-case structure.

The correct OPTION is (d) No change

To ELABORATE: The purpose of both the commands is SIMPLY to MAKE the commands, provided in the input argument, WORK. They do not hamper the precision with which the commands evaluate a value.

Correct choice is (b) False

Easy explanation: The input argument to the feval COMMAND is given WITHIN parentheses. Hence, MATLAB will return an ERROR if we use [].

Right CHOICE is (a) A single command

The best I can EXPLAIN: The input STRING argument to the feval command should contain only 1 command. If we GIVE multiple commands to be evaluated, it will give an error.

The correct answer is (b) Multiple

To explain I would say: The switch-case STRUCTURE has a versatile SYNTAX in MATLAB. We can give many numbers of case values to match with the input. This can help US in solving COMPLEX problems where we need selection of values.

Right choice is (a) Pauses, for debugging, after the line which dbstop indicates

Best explanation: For anonymous FUNCTIONS, the dbstop command works DIFFERENTLY in contrast to pre-defined functions. This nature of working is only for anonymous functions which are not stored in the MATLAB MEMORY. The dbquit command is USED to exit from the debugging MODE.

The correct option is (a) diary

For explanation: The diary COMMAND GETS disabled when we try to use the evalc command in MATLAB. The commands sin and ROUND work just fine while Inf is not a function.

Right OPTION is (b) last started ongoing

Explanation: The break STATEMENT EXITS the LOOP in which it is only CALLED. It doesn’t care about the remaining number of iterations in the loop but it only exits from the inner loop and the control still remains in the outer loop.

Correct choice is (d) Moves on to the next block

The EXPLANATION is: If we don’t give an otherwise block to our SWITCH STRUCTURE, it will not give any error. It will simply continue with the EXECUTION of STATEMENTS after the switch structure.

Correct answer is (b) >,>=,&,|

Explanation: Amongst the given operators, the correct HIERARCHY is <, <=, >, >=, &, |. Thus the most plausible >,>=,&,| according to the pre-defined hierarchy of OPERATIONS in MATLAB.

Correct option is (a) only REAL PART of complex numbers

Explanation: Some relational OPERATORS do not operate on the IMAGINARY part of the complex numbers. But all relational operators operate on the real part of complex numbers.

The correct choice is (b) Logical structure

The explanation: Any case in the switch structure gets executed if the SWITCHING variable and the case value SATISFIES the logical CONDITION of equality. Hence the switch-case is a logical structure since based on the equality of the two VALUES, the case will get executed.

The correct answer is (a) True

To explain I WOULD say: The WORKING of the return command is SIMILAR to the DBCONT command. It will get from the debugging mode and return to evaluate the function COMPLETELY.

Correct OPTION is (b) CURRENT iteration

Explanation: The continue STATEMENT will only end the current iteration and it will start the NEXT iteration. It won’t exit from the ENTIRE loop.

Correct OPTION is (a) TRUE

Easiest EXPLANATION: The following statement is true for MATLAB. One may use it to make it easier to CHECK a loop but MATLAB won’t give an error if we don’t use indentation.

Correct option is (b) NESTED if

To explain: We NEED to END each if structure within a nested if structure EVERY time we GIVE one. The end command should be placed after the end of each if structure or MATLAB will give an error.

The correct choice is (d) from display of output

To explain: The entire output is displayed as a character array using evalc while the eval command displays the output itself. There is no DIFFERENCE in PRECISION or nature of output.

Right CHOICE is (a) ‘’

EXPLANATION: The ‘’ is used while DEALING with characters. If we haven’t declared our characters before using them, we can compare characters by placing them WITHIN ‘’.

The correct answer is (B) False

The explanation: While in DEBUGGING MODE, we are really trying out the function. So, when the debugging mode starts, the command line is halted at a CERTAIN line in the function and the evaluation of the function is stopped. HENCE, it’s not possible to bring a change in the function and save it in the directory. We’ve to exit from the debugging mode and then we can save the function.

The correct answer is (b) False

For explanation: The hierarchy for PRECEDENCE of OPERATORS for the aforementioned operators is :, &, |. HENCE the given statement is false.

Right choice is (b) give error when we enter dbcont in DEBUG mode

Easiest explanation: The FUNCTION will be saved and it will run. After enter the debugging mode, and making any desirable CHANGE, when we enter the dbcont COMMAND, the function will keep working until it invokes the dbcont command. Then it will result in an error and the control will break the evaluation of the function entirely.

Right choice is (a) HOLD on

Easy EXPLANATION: The hold on command can be used to PLOT MULTIPLE graphs in the same WINDOW by using a loop. Hold off is used to exit the functioning of the hold on command. Hence, the correct option is hold on.

Correct option is (b) PAUSES for the DEBUGGING mode when a condition is reached only

For explanation I would say: The dbstop command STOPS the debugging mode. Now, we can give the dbstop command in many ways. One of the ways is MENTIONING a condition, regarding when the working of the function should stop, to ENTER the debugging mode. To exit from the debugging mode, we need to use the dbquit command.

Right option is (a) CURRENT iteration

The explanation is: The continue statement stops the current iteration and restarts a NEW iteration of the same loop if the condition is not matched. It does not EXIT from the outer or the INNER loop.

Right option is (d) No statement

The best I can explain: MATLAB is not like C. So, we don’t have to GIVE the break statement every time we END a case. We can write the next case and during runtime, the CONTROL will LEAVE the switch-case structure after executing the matched case. We can give the break statement during looping and the return statement during if-else structure.

Correct answer is (d) Break statement

To explain I WOULD SAY: The break statement is not ALLOWED within an if-else structure, it is strictly for a LOOP structure. We can use the return statement and the end statement but the break statement will give an error.

Correct choice is (a) pause the evaluation of the FUNCTION before the mentioned line

To explain I would say: In contrast to ANONYMOUS FUNCTIONS, the dbstop COMMAND will pause the working of a function just before the mentioned line. It will pause the evaluation and enter the debugging mode.

Right OPTION is (d) Assignment OPERATOR

The EXPLANATION is: p=2 assigns the value 2 to the variable p. Hence, ‘=’ is an assignment operator. It doesn’t perform arithmetic operations so it isn’t an arithmetic operator. It isn’t a relational operator UNLIKE ‘==’.