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    				This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 51. | A car is moving with speed `30m//sec` on a circular path of radius 500 m . Its speed is increasing at the rate of , `2m//sec^(2)`, What is the acceleration of the carA. `2 ms^(-2)`B. `2.7ms^(-2)`C. `1.82 ms^(-2)`D. `9.82ms^(-2)` | 
| Answer» Correct Answer - B Net acceleration in non-uniform circular motion, `a=sqrt(a_(t)^(2)+a_(c)^(2))` `=sqrt((2)^(2)+[(900)/(500)]^(2))=2.7 ms^(-2) ` | |
| 52. | The calculated mass of ` ""_(20)Ca^(40)` is 40.328 u. It releases 306.3 MeV energy in a nuclear process . Its isotopic mass isA. 39.998B. 40.657C. 0.329D. `2.85xx10^(4)` | 
| Answer» Correct Answer - A `BE= Deltam xx 931 MeV ` ` 306.3 = Delta m xx 931` `Delta=0.3290` `Deltam`=calcualted mass - isotopic mass - Isotopic mass =` Delta m`- calculated mass =0.3290-40.328 =- 39.998 `:.` Isotopic mass = 39.998 | |
| 53. | The derivative of ` cos x^(3)` w.r.t. ` x^(3)` isA. `- cot x `B. `cot x `C. `tan x `D. `-tan x ` | 
| Answer» Correct Answer - A Let ` u=cos^(3)x, v=sin^(3) x ` `(du)/(dx)=- 3 cos^(2) x sinx, (dv)/(dx)=3 sin^(2)x cos x` Now ,`(du)/(dv)=(-3 cos^(2) x sin x)/(3 sin^(2) x cos x)` `=-( cosx)/( sin x )` `= - cotx ` | |
| 54. | An element ` ""_(x)A^(y)` emits ` 5 alpha and 4 beta` paricles to give ` ""_(82)B^(207)`. The number of protons and neutrons in A are respectivelyA. ` 88,227`B. 88139C. 82227D. 84139 | 
| Answer» Correct Answer - B `""_(x)A^(y) to ""_(82)B^(207) +5_(2)He^(4) +4""_(-1)beta^(0)` On comparing , ` x= 82+5xx2+4(-1)=88` `y= 207+5xx4+4xx0` `= 227` In `""_(88)A^(227)` the number of protons = 88 the number of neutrons =227-88=139 | |