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51.

A car is moving with speed `30m//sec` on a circular path of radius 500 m . Its speed is increasing at the rate of , `2m//sec^(2)`, What is the acceleration of the carA. `2 ms^(-2)`B. `2.7ms^(-2)`C. `1.82 ms^(-2)`D. `9.82ms^(-2)`

Answer» Correct Answer - B
Net acceleration in non-uniform circular motion,
`a=sqrt(a_(t)^(2)+a_(c)^(2))`
`=sqrt((2)^(2)+[(900)/(500)]^(2))=2.7 ms^(-2) `
52.

The calculated mass of ` ""_(20)Ca^(40)` is 40.328 u. It releases 306.3 MeV energy in a nuclear process . Its isotopic mass isA. 39.998B. 40.657C. 0.329D. `2.85xx10^(4)`

Answer» Correct Answer - A
`BE= Deltam xx 931 MeV `
` 306.3 = Delta m xx 931`
`Delta=0.3290`
`Deltam`=calcualted mass - isotopic mass
- Isotopic mass =` Delta m`- calculated mass
=0.3290-40.328
=- 39.998
`:.` Isotopic mass = 39.998
53.

The derivative of ` cos x^(3)` w.r.t. ` x^(3)` isA. `- cot x `B. `cot x `C. `tan x `D. `-tan x `

Answer» Correct Answer - A
Let ` u=cos^(3)x, v=sin^(3) x `
`(du)/(dx)=- 3 cos^(2) x sinx, (dv)/(dx)=3 sin^(2)x cos x`
Now ,`(du)/(dv)=(-3 cos^(2) x sin x)/(3 sin^(2) x cos x)`
`=-( cosx)/( sin x )`
`= - cotx `
54.

An element ` ""_(x)A^(y)` emits ` 5 alpha and 4 beta` paricles to give ` ""_(82)B^(207)`. The number of protons and neutrons in A are respectivelyA. ` 88,227`B. 88139C. 82227D. 84139

Answer» Correct Answer - B
`""_(x)A^(y) to ""_(82)B^(207) +5_(2)He^(4) +4""_(-1)beta^(0)`
On comparing ,
` x= 82+5xx2+4(-1)=88`
`y= 207+5xx4+4xx0`
`= 227`
In `""_(88)A^(227)`
the number of protons = 88
the number of neutrons =227-88=139