InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Direction∶ A publisher publishes 3500 books for Rs. 100 cost price per book. He gives 500 books for free to some shops.If he allows 25% discount on the marked price and gives 1 book free for every purchase of 29 books. Find the amount of profit/loss if the marked price of one book is Rs. 160.1). Rs. 1500 loss2). Rs. 2000 profit3). Rs. 2000 loss4). Rs. 2500 profit |
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Answer» Marked price of one book = Rs. 160 Selling price after 25% discount = 160 × 0.75 = Rs. 120 Since he is GIVING 500 books for free, remaining books are 3000 And also he is giving 1 book free for PURCHASE of every 29 books, he will get price of 29 books after giving 30 books. Thus he will get price of 2900 books only; ∴ Selling price for 2900 books = 120 × 2900 = Rs. 348000 And Cost price of 3500 books = 3500 × 100 = Rs. 350000 ∴ Loss = 350000 - 348000 = Rs. 2000 |
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| 2. |
A Paddler buys goods at the rate of Rs. 70 per good. The particular good is part of an overall collection and the value is linked to the number of items that are already on the market. So, the paddler sells the first good for Rs. 7, the second one for Rs. 14, third for Rs. 21…and so on. If he wants to make an overall profit of at least 30%, what is the minimum number of goods he should sell?1). 352). 253). 224). 32 |
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Answer» Let the number of GOODS he buys be ‘n’ Cost price of one good = Rs. 70 ∴ TOTAL Cost price of n goods = Rs. 70n The paddler SELLS the first good for Rs. 7, the second one for Rs. 14, third for Rs. 21…and so on. Total selling price = 2 + 4 + 6 + 8 ….n terms According to the given information: Total selling price should be at least 30% more than total Cost price Total selling price = 130% of Rs. 70n ⇒ 7 + 14 + 21 + 28 ….n terms ≥ 1.3 × 70n ⇒ 7 (1 + 2 + 3 + ….n terms) ≥ 91n $(\Rightarrow {\rm{\;}}7\left( {\frac{{n\left( {n\; + \;1} \right)}}{2}} \right) \ge {\rm{\;}}91{\rm{n\;}})$ ⇒ 7n2 + 7n ≥ 182n ⇒ 7n2 - 175n ≥ 0 ⇒ n ≥ 25 ∴ He should sell a minimum of 25 goods. |
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| 3. |
1). 70 cm2). 70.2 cm3). 76.8 cm4). 76 cm |
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Answer» Let C.P of 1 m cloth = Rs. 1 Professed S.P of 1 m cloth = Rs. 96/100 = Rs. 0.96 = Gain of 25% ACTUAL C.P of cloth sold for Rs. 0.96 $(= \FRAC{{100}}{{125}} \times 0.96 = {\RM{Rs}}.0.768)$ ∴ Actual length of SCALE = Length bought for Rs. 0.768 = 76.8 cm |
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| 4. |
Direction: P, Q and R started a business by investing Rs. 1200, Rs. 2000 and Rs. 2400 respectively. After a quarter, they invested amounts in the ratio 1 : 4 : 2. After another quarter, they invested amounts in the ratio 3 : 2 : 3. In the last quarter, the ratio of investments was same as in 2nd quarter. Also, in the last quarter, the respective amounts of P, Q and R were double than the respective amounts invested in 2nd quarter. The total investment of R before 4th quarter was Rs. 1800 more than that of P during same duration. Also, the ratio of R’s share in profit to total profit at the end of year was 69 : 206. Also, they withdrew the amount after each quarter.The investment of Q in the 3rd quarter is Rs. 600. The respective investments in second quarter was changed and this was in the ratio 2 : 3 : 1. What would be the total investment of all three in the last quarter, if the total investment of all P, Q and R was Rs. 19160 for the whole year?1). Rs. 78202). Rs. 74403). Rs. 69804). Rs. 7260 |
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Answer» ? The investments in second quarter was changed and this was in the ratio 2 : 3 : 1; Suppose the investment in 2nd quarter were RS. 2z, Rs. 3Z and Rs. z; ∴ The investment in last quarter will also be changed and would be Rs. 4Z, Rs. 6z and Rs. 2z; And the investment in 3rd quarter would be Rs. 3y, Rs. 2y and Rs. 3y; ∴ Total investment of all three for the whole year = (1200 + 2z + 3y + 4z) + (2000 + 3z + 2y + 6z) + (2400 + z + 3y + 2z) ⇒ 5600 + 18z + 8y ? The investment of Q = 2y = Rs. 600 ⇒ y = 300 ∴ Putting y = 300; ⇒ 5600 + 18z + 2400 ⇒ 8000 + 18z ? The total investment of P, Q and R was Rs. 19160; ∴ 8000 + 18z = 19160 ⇒ 18z = 11160 ⇒ z = 620 ∴ Total investment of all three in the last quarter = (4 + 6 + 2) × 620 = Rs. 7440 |
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| 5. |
1).2). 20%3). 30%4). 22.22% |
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Answer» Ginny bought a scooter at Rs. 30000, and sold it to HONEY at a loss of 20%. Loss MADE by Ginny = 20% of Rs. 30000 = Rs. 30000 × (20/100) = Rs. 6000 Later, Ginny bought the scooter BACK from Honey at Rs. 28000. Net Loss = 10000 To compensate for losses, Ginny must sell it now at a profit of Rs. 10000. We know, Profit percentage = (Profit/Cost PRICE) × 100 ∴ Profit at which Ginny should sell the scooter = (10000/28000) × 100 = 35.71% |
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| 6. |
Jaspreet bought a goat and a cow at total price of Rs 10320. He sells the goat at the profit of 25% and cow at a loss of 18%. He neither gained nor lost any money in whole transaction. If he sells goat at 25% profit then at what price he should sell the cow to gain a total profit of 15% in whole transaction?1). Rs. 64682). Rs. 63563). Rs. 54004). Rs. 3852 |
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Answer» Let us ASSUME the cost price of goat and cow is Rs. X and Rs. Y respectively. Total cost price = X + Y = 10320----(1) We know that, SELLING price of goat = X + (25% of X) = 1.25X Selling price of cow = Y – (18% of Y) = 0.82Y Since he NEITHER gained nor LOST any money, ∴ Total selling price of goat and cow = total cost price = 10320 ⇒ 1.25X + 0.82Y = 10320----(2) Solving EQUATION (1) and (2), we get: X = 4320; Y = 6000 Selling price of goat after 25% profit = 1.25X = 1.25 × 4320 = 5400 To get a total profit of 15% total selling price should be, ⇒ Total Selling price = 10320 × 1.15 = 11868 ∴ Selling price of cow = 11868 – 5400 = Rs. 6468 |
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| 7. |
1). Rs. 11002). Rs. 10503). Rs. 11044). Rs. 1140 |
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Answer» P sold his carpet to R at 10% profit. We know, Selling price = Cost Price × (1 + (Profit %)/100) Cost price for R = Selling price for P = RS. 600 × (1+10/100) = Rs. 660 Then, R sold the carpet to S at 10% loss. We know, Selling price = Cost Price × (1 – (Loss %)/100) Cost price for S for first carpet = Selling price for R = Rs. 660 × (1 – 10/100) = Rs. 594 Q sold his carpet to S at 15% loss. Cost price for S for SECOND carpet = Selling price for Q = Rs. 600 × (1 – 15/100) = Rs. 510 ∴ Price at which S bought the two carpets = Rs. 594 + Rs. 510 = Rs. 1104 |
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| 8. |
Quantity B: A shopkeeper sells 32 oranges for Rs. 1 at 40% loss. How many oranges for a rupee should he sell to earn 20% profit?1). Quantity A > Quantity B2). Quantity A < Quantity B3). Quantity A ≥ Quantity B4). Quantity A ≤ Quantity B |
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Answer» Quantity A: Suppose the cost price of 1000 gm goods is Rs. 1000; Since he sells the goods at 5% profit; ∴ SELLING price of 1000 gm goods = Rs. 1050 But he uses 10% less weight that MEANS he gives 900 gm goods for Rs. 1050; ∴ Actual selling price of 1000 gm goods = (1050/900) × 1000 = Rs. 1166.67 ∴ Actual profit earned by the shopkeeper = (1166.67 – 1000)/1000 = 16.67% Quantity B: Since the shopkeeper sells 32 oranges for Rs. 1; ∴ Selling price of 1 orange = Rs. 1/32 He SUFFERS a loss of 40%; ∴ Cost price of 1 orange = (1/32)/0.6 = Rs. (1/19.2) Selling price of 1 orange for earning 20% profit = (1/19.2) × 1.2 = Rs. 1/16 ∴ He should sell 16 oranges for Rs. 1 to EARN 20% profit. ∴ Quantity A > Quantity B |
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| 9. |
Direction: P, Q and R started a business by investing Rs. 1200, Rs. 2000 and Rs. 2400 respectively. After a quarter, they invested amounts in the ratio 1 : 4 : 2. After another quarter, they invested amounts in the ratio 3 : 2 : 3. In the last quarter, the ratio of investments was same as in 2nd quarter. Also, in the last quarter, the respective amounts of P, Q and R were double than the respective amounts invested in 2nd quarter. The total investment of R before 4th quarter was Rs. 1800 more than that of P during same duration. Also, the ratio of R’s share in profit to total profit at the end of year was 69 : 206. Also, they withdrew the amount after each quarter.Find the total amount of investment done by P, Q and R.1). Rs. 206002). Rs. 184003). Rs. 242004). Rs. 15600 |
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Answer» <P>? The ratio of investments in 2nd quarter was 1 : 4 : 2, ∴ Suppose the amounts were Rs. x, Rs. 4x and Rs. 2x; ? The ratio of investments in 3rd quarter was 3 : 2 : 3, ∴ Suppose the amounts were Rs. 3y, Rs. 2y and Rs. 3y; In last quarter, respective amounts are double than the AMOUNT invested in 2nd quarter; ∴ Suppose the amounts were Rs. 2x, Rs. 8x and Rs. 4x; ACCORDING to the given condition: Total investment of R before 4th quarter was Rs. 1800 more than that of P during same duration; ∴ (2400 + 2x + 3y) = 1800 + (1200 + x + 3y) ⇒ 2400 + 2x = 3000 + x ⇒ x = Rs. 600 Now, ratio of profit SHARE: A : B : C = (1200 × 3 + x × 3 + 3y × 3 + 2x × 3) : (2000 × 3 + 4x × 3 + 2y × 3 + 8x × 3) : (2400 × 3 + 2x × 3 + 3y × 3 + 4x × 3) ⇒ (1200 + 3x + 3y) : (2000 + 12x + 2y) : (2400 + 6x + 3y) Putting x = 600; ⇒ 3000 + 3y : 9200 + 2y : 6000 + 3y ? The ratio of R’s share in profit to total profit at the end of year was 69 : 206; ∴ (6000 + 3y) : (18200 + 8y) = 69 : 206 ⇒ 1236000 + 618y = 1255800 + 552y ⇒ 66y = 19800 ⇒ y = 300 ∴ Total investment = 18200 + 8y Putting y = 300 ∴ Total investment = 18200 + 2400 = Rs 20600 |
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| 10. |
Quantity B: 3.6%1). Quantity A > Quantity B2). Quantity A < Quantity B3). Quantity A ≥ Quantity B4). Quantity A ≤ Quantity B |
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Answer» QUANTITY A: Let the marked price of shopkeeper A be RS. ‘x’ and that of shopkeeper B be Rs. ‘y’ SELLING price of shopkeeper A = (100 – 5)% of (100 – 15)% of (100 – 10)% of x = 0.95 × 0.85 × 0.9x = 0.72675x Selling price of shopkeeper B = (100 – 30)% of y = 0.7y ? Their selling price is same, ⇒ 0.72675x = 0.7y ⇒ x = 0.963y ⇒ x = 96.3% of y ⇒ x = (100 – 3.7)% of y ∴ Shopkeeper A should mark his price 3.7% below the price of shopkeeper B Quantity B: 3.6% ∴ Quantity A > Quantity B |
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| 11. |
1). 6.42). 83). 104). 12 |
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Answer» Let the total profit be Rs. X ⇒ Tanishq’s share = 2X/3 ⇒ Arya’s share = X – 2X/3 = X/3 ⇒ Profit RATIO is X/3 : 2X/3 = 1 : 2 Let total capital be Y and Tanishq CONTRIBUTED for Z months So, Tanishq’s investment share is 5/6 of the capital ⇒ Profit ratio = Arya’s investment for 16 months : Tanishq investment for Z months ⇒ 1 : 2 = (Y × 16/6) : (5Y/6 × Z) ⇒ 1/2 = 16/5Z ⇒ Z = 32/5 ⇒ Z = 6.4 months ∴ Tanishq’s money was used for 6.4 months |
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| 12. |
A salesman sells an article at 8% profit. If he had bought it as 8% less and sold it for Rs. 17 less, he would have gained 15%. The cost price of the article is:1). Rs. 672.722). Rs. 658.763). Rs. 772.724). Rs. 780.45 |
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Answer» S.P = Selling price, C.P = COST price S.P of the ARTICLE = C.P + Profit = C.P + (8/100) × C.P =C.P + 0.08C.P. = 1.08C.P. C.P of the article is 8% LESS = C.P1 = C.P – 8%C.P = C.P – (8/100) × C.P. = C.P – 0.08C.P = 0.92C.P S.P Of article when C.P is 8% less = S.P1 = S.P – 17 = 1.08C.P – 17 Profit % when C.P. is 8% less = 15% ⇒ $(\frac{{{\RM{S}}.{\rm{P}}1{\rm{\;}}-{\rm{\;C}}.{\rm{P}}1{\rm{\;}}}}{{C.P1}})$ × 100 = 15 ⇒ 1.08C.P – 17 – 0.92C.P = 15 × (0.92C.P/100) ⇒ 0.16C.P – 17 = 0.138C.P ⇒ (0.16 – 0.138) C.P = 17 ⇒ C.P = 17/0.022 = RS. 772.72 ∴ C.P of the article = Rs. 772.72 |
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