Explore topic-wise InterviewSolutions in .

This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

1.

Propagation within building is not influenced by _________(a) Layout of the building(b) Construction materials(c) Building type(d) Trees outside the buildingI had been asked this question by my college professor while I was bunking the class.This interesting question is from Indoor Propagation Models in chapter Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

Right choice is (d) TREES outside the building

To ELABORATE: It has been OBSERVED that propagation within buildings is strongly influenced by specific features. These features are LAYOUT of the building, the construction materials, and the building type.

2.

Smaller propagation distances make it more difficult to insure far-field radiation for all receiver location and types of antenna.(a) True(b) FalseThe question was asked during a job interview.I need to ask this question from Indoor Propagation Models topic in chapter Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer» RIGHT choice is (a) True

To elaborate: Smaller propagation distances make it more difficult to insure far FIELD RADIATION for all receiver location and types of antenna. The condition is very VARIABLE for smaller propagation distances.
3.

The extra term for additional attenuation due to urban clutter near the receiving antenna is called __________(a) Power factor(b) Urban gain(c) Clutter factor(d) Urban factorThis question was posed to me in an online interview.Question is taken from Outdoor Propagation Models topic in section Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

Correct CHOICE is (d) Urban factor

For EXPLANATION: The urban factor (UF) is DERIVED by COMPARING the predictions by the original Longley –Rice model with those obtained by Okumura. It deals with RADIO propagation in urban areas and is relevant to mobile radio.

4.

The phase difference between a direct line of sight path and diffracted path is function of _______(a) Height and position of obstruction(b) Only height(c) Operating frequency(d) PolarizationI had been asked this question in an online quiz.I'm obligated to ask this question of Diffraction in portion Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer» CORRECT option is (a) Height and position of obstruction

To ELABORATE: The phase difference between a direct LINE of SIGHT path and diffracted path is a function of height and position of the DIFFRACTION. It is also a function of transmitter and receiver location.
5.

Which of the following is not a practical path loss estimation technique?(a) Log distance path loss model(b) Log normal shadowing(c) Determination of percentage of coverage area(d) Hata modelThe question was posed to me in unit test.Enquiry is from Practical Link Budget Design Using Path Loss Models topic in division Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

Right option is (d) Hata model

Explanation: Log normal shadowing, log DISTANCE PATH LOSS model and determination of percentage of coverage area are practical pat loss estimation techniques. Hata model is only VALID for exterior environment.

6.

Which principle explains the phenomenon of diffraction?(a) Principle of Simultaneity(b) Pascal’s Principle(c) Archimedes’ Principle(d) Huygen’s principleThis question was addressed to me in an online interview.Asked question is from Diffraction in portion Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

Right choice is (d) Huygen’s PRINCIPLE

Easy explanation: The phenomenon of diffraction can be explained by Huygen’s principle. It STATES that all points on a wavefront can be considered as point sources for the production of SECONDARY WAVELETS. And these wavelets combine to produce a new wavefront in direction of PROPAGATION.

7.

Diffraction allows radio signals to propagate around ________(a) Continuous surface(b) Smooth surface(c) Curved surface of Earth(d) Does not allow propagationI got this question in an interview for internship.This interesting question is from Diffraction in chapter Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

The correct answer is (C) Curved surface of Earth

The explanation is: Diffraction allows radio signals to propagate around the curved surface of the Earth. Signals can propagate BEYOND the HORIZON and to propagate behind obstruction. It is the slight bending of light as it passes around the EDGE of an OBJECT.

8.

The free space model predicts that received signal decays as a function of _________(a) Gain of transmitter antenna(b) T-R separation(c) Power of transmitter antenna(d) Effective aperture of the antennaI got this question in an online interview.Asked question is from Free Space Propagation Model in section Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

Correct answer is (b) T-R separation

Easiest EXPLANATION: As with most large scale radio wave PROPAGATION models, the free space model predicts that received signal decays as a function of the T-R separation DISTANCE raised to some power. Often it is given as a function of negative SQUARE root of the distance.

9.

Hata model is well suited for _________(a) Personal communication system(b) Large cell mobile radio system(c) Small cell mobile radio system(d) Every mobile radio systemI have been asked this question during an internship interview.I'd like to ask this question from Outdoor Propagation Models in division Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

Right option is (b) LARGE CELL mobile radio SYSTEM

Easiest explanation: Hata model is well SUITED for large cell mobile radio systems. But it is not well suited for personal communication system (PCS) which have cells on the ORDER of 1 km radius. Hata model does not have any path specific corrections which are available in Okumura model.

10.

In mobile communication system, diffraction loss occurs due to ______(a) Dielectric medium(b) Obstruction(c) Electric field(d) Operating frequencyThe question was asked during an online exam.I'd like to ask this question from Diffraction topic in portion Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

The correct option is (B) Obstruction

Easy explanation: Diffraction loss occurs from the blockage of SECONDARY WAVES such that only a portion of the energy is diffracted around an OBSTACLE. An obstruction causes a blockage of energy from source some of the Fresnel zones, allowing only some of the transmitted energy to REACH the receiver.

11.

The angle at which no reflection occurs in the medium of origin is called _________(a) Azimuth angle(b) Elevation angle(c) Brewster angle(d) Inclination angleI had been asked this question by my school teacher while I was bunking the class.I'm obligated to ask this question of Reflection in section Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

Right answer is (c) Brewster angle

The best EXPLANATION: The Brewster angle is the angle at which no REFLECTION OCCURS in the MEDIUM of origin. It occurs when the incident angle is such that the reflection coefficient is equal to zero. The critical Brewster’s angles for diamond, glass and WATER are 67.5°, 57° and 53° respectively.

12.

Partitions that can be moved are called _______(a) Soft partitions(b) Hard partitions(c) Disk partition(d) Dynamic partitionI had been asked this question in quiz.The query is from Indoor Propagation Models in chapter Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

Right answer is (a) Soft partitions

Easy explanation: Partitions that may be moved are called soft partitions. They do not span to the ceiling. OFFICE BUILDINGS OFTEN have large open areas which are constructed by using moveable office partitions. THUS, space can be reconfigured easily.

13.

Empirical approach is based on fitting curve or analytical expressions.(a) True(b) FalseI had been asked this question in an interview for job.The origin of the question is Practical Link Budget Design Using Path Loss Models in chapter Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

Right OPTION is (a) True

To elaborate: The empirical approach is BASED on FITTING curves or analytical expressions that recreate a set of MEASURED DATA. This has the advantage of implicitly taking into account all propagation factors, both known and unknown through actual field measurements.

14.

Velocity of electromagnetic wave can be given by _______(a) 1/√(μ∈)(b) μ/∈(c) 1/(μ∈)(d) μ∈This question was posed to me in semester exam.The origin of the question is Reflection topic in section Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

Correct ANSWER is (a) 1/√(μ∈)

Explanation: For a medium with permittivity, ∈ and PERMEABILITY, μ the velocity of electromagnetic WAVE is given by 1/√(μ∈). It is ALSO known as PHASE velocity. The velocity of light is given by 3*10^8 m/s.

15.

Which of the following considers the impact of rooftops and building?(a) Okumura model(b) Hata model(c) Walfisch and Bertoni model(d) Longley- Rice modelI have been asked this question during a job interview.This interesting question is from Outdoor Propagation Models in division Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

Right option is (C) WALFISCH and Bertoni model

The best EXPLANATION: The impact of rooftops and building height is considered by Walfisch and Bertoni model. It uses diffraction to predict AVERAGE signal strength at street level. It considers path loss to be a product of three FACTORS.

16.

A link budget is accounting of all __________(a) Gain and losses from the transmitter(b) Power transmitted by transmitter(c) Power received by receiver(d) Power transmitted and receivedI had been asked this question in an internship interview.My question is taken from Practical Link Budget Design Using Path Loss Models topic in division Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

Right answer is (a) Gain and losses from the transmitter

The best I can explain: A link budget is accounting of all of the gains and losses from the transmitter, through the medium (free space, cable, waveguide, ETC.) to the receiver in a TELECOMMUNICATION system. It accounts for the attenuation of the TRANSMITTED signal due to propagation, as well as the antenna gains and MISCELLANEOUS losses.

17.

Which method is used by Edwards and Durkin algorithm to calculate the loss associated with diffraction edges?(a) Epstein and Peterson method(b) Interpolation method(c) Knife edge diffraction method(d) Fresnel- Kirchoff methodThis question was posed to me in final exam.I'm obligated to ask this question of Outdoor Propagation Models topic in portion Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

Right option is (a) Epstein and PETERSON method

Explanation: The Edwards and Durkin algorithm USES Epstein and Peterson method to calculate the loss associated with two DIFFRACTION edges. It is the sum of two attenuations. First is loss at SECOND diffraction EDGE caused by first diffraction edge. And second is the loss at receiver caused by second diffraction edge.

18.

Log normal shadowing implies that measured signal levels at specific T-R separation have ______ distribution when signal levels have values in dB units.(a) Rayleigh(b) Gamma(c) Gaussian(d) NakagamiI had been asked this question in an online quiz.This question is from Practical Link Budget Design Using Path Loss Models topic in portion Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

Correct ANSWER is (c) GAUSSIAN

To explain: Log normal shadowing implies that measured SIGNAL levels at a specific T-R separation have Gaussian (Normal) DISTRIBUTION. It is about the distance dependent mean of 4.68 where the signal levels have VALUES in dB units.

19.

Surface roughness are often tested using __________(a) Rayleigh criterion(b) Lawson criterion(c) Barkhausen stability criterion(d) Nyquist criterionThe question was posed to me during an internship interview.My doubt is from Scattering in section Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

Right choice is (a) Rayleigh criterion

The BEST explanation: Rough surface is often tested using a Rayleigh criterion. It defines the CRITICAL height of surface protuberances for a GIVEN angle of incidence. The Rayleigh criterion is the criterion for the minimum resolvable detail. The IMAGING process is said to be diffraction-limited when the first diffraction minimum of the image of one source point coincides with the MAXIMUM of another.

20.

Difference between the direct path and the diffracted path is called _______(a) Average length(b) Radio path length(c) Excess path length(d) WavelengthThis question was addressed to me during an interview.My enquiry is from Diffraction in section Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

Right option is (c) Excess path LENGTH

Best explanation: Excess path length DENOTED by ∆, is the difference between the direct path and the DIFFRACTED path. It is calculated with the help of Fresnel ZONE geometry.

21.

Fraunhofer distance is given by _____(a) 2D2/λ(b) 2D/λ(c) D/λ(d) 2D/λ2The question was posed to me in an internship interview.Enquiry is from Free Space Propagation Model topic in section Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

The correct choice is (a) 2D2/λ

Easiest EXPLANATION: Fraunhofer DISTANCE, also KNOWN as far field distance is inversely proportional to wavelength. It DEPENDS on the largest physical dimension of the antennal (D). This distance basically denotes the boundary between far field and near field region.

22.

What is the dimension of object as compared to wavelength of propagating wave when reflection occurs?(a) Large(b) Small(c) Same(d) Very smallThis question was addressed to me in examination.Query is from Reflection in division Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

Right option is (a) Large

For explanation: Reflection occurs when a propagating electromagnetic WAVE impinges upon an object which has very large dimensions when compared to the wavelength of the PROPAGATION wave. Reflection occurs from the surface of the Earth and from BUILDINGS and WALLS.

23.

Technique of drawing a single ray between the transmitter and receiver is called ______(a) Secondary ray tracing(b) Primary ray tracing(c) Line of sight(d) Straight line tracingThe question was posed to me by my college director while I was bunking the class.My question is taken from Indoor Propagation Models in portion Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

The correct answer is (b) PRIMARY RAY tracing

Easy explanation: PAF (path attenuation FACTOR) represents a specific obstruction encountered by a ray drawn between the transmitter and receiver in 3-D. This TECHNIQUE of drawing a single ray between transmitter and receiver is called primary ray tracing.

24.

Which of the most widely used model for signal prediction in urban areas?(a) Ericsson Multiple Breakpoint Model(b) Log distance path loss model(c) Okumura model(d) Attenuation factor modelI have been asked this question in an international level competition.This intriguing question comes from Outdoor Propagation Models in section Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer» CORRECT OPTION is (c) Okumura model

For explanation: Okumura’s model is one of the most widely used models for signal PREDICTION in urban areas. This model is applicable for frequencies in the range 150 MHz to 1920 MHz (Extrapolated upto 3000 MHz).
25.

Longley-Rice prediction model is also referred as _________(a) Okumura model(b) Hata model(c) ITS irregular terrain model(d) Bertoni modelI have been asked this question during an interview.My question is taken from Outdoor Propagation Models topic in portion Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

Correct answer is (c) ITS IRREGULAR terrain model

For explanation I would say: The Longley Rice prediction model is also referred to as ITS irregular terrain model. The model is based on electromagnetic theory and on STATISTICAL ANALYSES of both terrain features and radio measurements. It predicts the median attenuation of a radio SIGNAL as a function of DISTANCE and the variability of the signal in time and in space.

26.

Path loss in free space model is defined as difference of ________(a) Effective transmitted power and gain(b) Effective received power and distance between T-R(c) Gain and received power(d) Effective transmitter power and receiver powerThis question was addressed to me by my college director while I was bunking the class.This question is from Free Space Propagation Model topic in portion Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer» CORRECT option is (d) Effective transmitter power and receiver power

Explanation: I Path loss is defined as difference of effective transmitter power and receiver power. Free-space path loss is the loss in signal STRENGTH of an electromagnetic wave that WOULD result from a line-of-sight path through free space, with no obstacles nearby to CAUSE reflection or diffraction.
27.

________ is a process of converting plain text into cipher text.(a) Authentication(b) Decryption(c) Encryption(d) CompressionI got this question in my homework.This interesting question is from Indoor Propagation Models topic in chapter Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

The correct choice is (c) Encryption

The explanation is: Encryption is the most effective way to ACHIEVE data security. It is the PROCESS of encoding a message in such a way that only AUTHORIZED parties can access it. Encryption does not itself prevent interference but denies the INTELLIGIBLE CONTENT to a would-be interceptor.

28.

Which of the following is the major disadvantage of the Okumura model?(a) Complex(b) Inaccurate(c) Not practical(d) Slow response to rapid change in terrainThe question was asked in an internship interview.This interesting question is from Outdoor Propagation Models topic in portion Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

Correct choice is (d) Slow response to rapid change in terrain

Explanation: The major disadvantage with the model is its slow response to rapid changes in terrain. THEREFORE the model is FAIRLY good in urban and suburban AREAS, but not as good in rural areas. Common STANDARD deviations between PREDICTED and measured path loss values are 10 dB to 14 dB.

29.

Antenna’s efficiency is given by the ratio of __________(a) Losses(b) Physical aperture to effective aperture(c) Signal power to noise power(d) Effective aperture to physical apertureI got this question by my college director while I was bunking the class.The doubt is from Practical Link Budget Design Using Path Loss Models topic in portion Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

Correct answer is (d) Effective aperture to physical aperture

To elaborate: The larger the antenna aperture the larger is the resulting signal power DENSITY in the desired DIRECTION. The ratio of effective aperture to the physical aperture is the antenna’s EFFICIENCY.

30.

What is the case of reflection, in course of second medium being a perfect dielectric?(a) Loss of energy during absorption(b) Total energy reflected back to first medium(c) No loss of energy in absorption(d) Total energy transmitted into second mediumThe question was asked in semester exam.Asked question is from Reflection in portion Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

Correct option is (C) No loss of energy in ABSORPTION

Easy explanation: If the plane wave is INCIDENT on a perfect dielectric, part of the energy is TRANSMITTED into the SECOND medium and part of the energy is reflected back into the first medium. There is no loss of energy in absorption.

31.

_______ reduces the cell size to increase capacity.(a) Intelligent cell approach(b) Microcell approach(c) Top down approach(d) Bottom up approachI got this question in an online quiz.The above asked question is from Indoor Propagation Models in section Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

The correct option is (b) Microcell approach

Explanation: The microcell zone concept is used in cellular SYSTEMS to specifically increase the CAPACITY and coverage in cellular systems. A HANDOFF is not required at MSC when the mobile travels between zones WITHIN a cell or when a mobile travels from one zone to another within the cell.

32.

Log normal shadowing is a phenomenon that occurs with same T-R separation having same level clutter on the propagation path.(a) True(b) FalseThis question was posed to me in an interview.My question is based upon Practical Link Budget Design Using Path Loss Models topic in chapter Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

The CORRECT choice is (b) False

To ELABORATE: Log normal shadowing OCCURS over a large number of measurement LOCATIONS which have the same T-R separation, but have different levels of clutter on the propagation path. It FOLLOWS log normal distribution.

33.

Longley Rice model’s merit is to provide corrections due to environmental factors.(a) True(b) FalseThis question was posed to me in homework.The doubt is from Outdoor Propagation Models in section Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer» CORRECT option is (b) False

The best I can explain: One shortcoming of the Longley –Rice model is that it does not provide a way of determining CORRECTIONS due to environmental factors. It does not CONSIDER correction factors to ACCOUNT for the effects of buildings and foliage. Multipath is also not considered.
34.

Which of the following is not an outdoor propagation model?(a) Longley-Rice model(b) Ericson Multiple Breakpoint Model(c) Hata model(d) Okumura modelThis question was addressed to me during an interview.Question is from Outdoor Propagation Models topic in chapter Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer» CORRECT option is (b) ERICSON Multiple BREAKPOINT MODEL

Best explanation: Ericson multiple breakpoint model is an indoor propagation model. Longley-Rice, Hata and Okumura model are outdoor propagation models. Most of these models are based on a systematic interpretation of measurement data OBTAINED in the service area.
35.

Power density is basically termed as ________ power per unit area.(a) Reflected(b) Refracted(c) Radiated(d) DiffractedThis question was posed to me in a national level competition.My question is based upon Scattering in portion Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

The correct answer is (c) RADIATED

The BEST I can explain: Power density is the amount of power (time rate of energy transfer) per unit VOLUME. It is also termed as radiated power per unit AREA. In energy transformers including batteries, fuel cells, motors, etc., power density refers to a volume. It is then also called volume power density.

36.

RCS of scattering object is defined as the ratio of _______(a) Power density of signal scattered to power density of radio wave incident(b) Power density of radio wave incident to power density of signal scattered(c) Power density of incident waves to power density of reflected wave(d) Power density of reflected wave to power density of incident wavesI have been asked this question in class test.I'm obligated to ask this question of Scattering in portion Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

Right answer is (a) Power DENSITY of signal scattered to power density of radio wave INCIDENT

The best I can EXPLAIN: The RADAR cross section of a scattering object is defined as the ratio of the power density of the signal scattered in the direction of the receiver to the power density of the radio wave incident upon the scattering object. It has unit of square meters.

37.

Scattering occurs when medium consists of objects with dimensions _______ compared to the wavelength.(a) Same(b) Small(c) Large(d) Very largeThe question was posed to me in my homework.This intriguing question comes from Scattering in division Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

Right OPTION is (b) Small

Easiest explanation: Scattering occurs when the medium through which the WAVE travels consists of objects with dimensions that are small compared to the wavelength. But the number of obstacles per unit volume is LARGE.

38.

Polarized wave can be mathematically represented as sum of ________(a) Four orthogonal components(b) Two spatially adjacent components(c) Two spatially orthogonal components(d) Six orthogonal componentsI have been asked this question during an internship interview.Origin of the question is Reflection in division Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

Right option is (c) Two spatially orthogonal components

The best I can explain: A POLARIZED wave may be MATHEMATICALLY REPRESENTED as SUM of two spatially orthogonal components. For an arbitrary polarization, super position may be used to compute the reflected FIELDS from a reflecting surface.

39.

Diffraction is caused by propagation of secondary wavelets into _______(a) Bright region(b) Shadowed region(c) Smooth region(d) Large regionThis question was addressed to me during an interview.This intriguing question originated from Diffraction in section Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

Correct OPTION is (b) Shadowed region

Easiest EXPLANATION: Diffraction is CAUSED due to PROPAGATION of secondary wavelets into a shadowed region. The field strength in the shadowed region is the vector sum of the electric field components of all the secondary wavelets in the space around the obstacle.

40.

Which of the following mechanism do not impact propagation in mobile communication system?(a) Reflection(b) Diffraction(c) Scattering(d) RefractionThis question was addressed to me in class test.This intriguing question comes from Reflection in division Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

The correct choice is (d) Refraction

The best explanation: Reflection, DIFFRACTION and scattering are the three basic PROPAGATION mechanism which impact propagation in mobile communication system. Large scale propagation model and small scale FADING and multipath propagation are DESCRIBED by the PHYSICS of reflection, diffraction and scattering.

41.

Free space propagation model is to predict ______(a) Received signal strength(b) Transmitted power(c) Gain of transmitter(d) Gain of receiverThis question was posed to me in semester exam.Question is taken from Free Space Propagation Model in portion Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

The correct answer is (a) Received signal strength

To explain I would say: Free space PROPAGATION MODEL predicts the received signal strength when there is an unobstructed line of sight path between transmitter and RECEIVER. It assumes the ideal propagation CONDITION that the environment is EMPTY between the transmitter and receiver.

42.

Which of the following do not undergo free space propagation?(a) Satellite communication system(b) Microwave line of sight radio links(c) Wireless line of sight radio links(d) Wired telephone systemsThis question was posed to me in class test.The query is from Free Space Propagation Model topic in section Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

Right CHOICE is (d) Wired TELEPHONE systems

Explanation: EM signals when traveling through wireless channels experience fading EFFECTS due to various effects. But in some cases the transmission is with no OBSTRUCTION and direct LINE of sight such as in satellite communication, microwave and wireless line of sight radio links.

43.

Losses between the floors of the building can be determined using ________(a) Internal dimensions(b) Material used to create antenna(c) External dimension(d) Line of sight pathThe question was asked in final exam.Question is taken from Indoor Propagation Models in division Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

The CORRECT choice is (c) External dimension

To ELABORATE: The losses between floors of a building are determined by external DIMENSIONS as well as MATERIALS of the building. It is also determined using type of construction used to create the floors and external surroundings.

44.

Okumura model is considered to be complex in predicting path loss.(a) True(b) FalseI had been asked this question in a job interview.My doubt is from Outdoor Propagation Models in section Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

Correct choice is (b) False

To explain: OKUMURA’s model is considered to be among the simplest and best in terms of ACCURACY in path loss PREDICTION for MATURE cellular and land mobile radio system. It is very practical and has BECOME a standard for system planning in modern land mobile system in Japan.

45.

The reference distance should not be in the far field of the antenna.(a) True(b) FalseThis question was posed to me in quiz.Origin of the question is Practical Link Budget Design Using Path Loss Models topic in division Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

The CORRECT ANSWER is (b) False

The best I can explain: It is important to select a free SPACE reference distance that is appropriate for the propagation environment. The reference distance should always be in the far field of the antenna so that near field EFFECTS do not alter the reference path loss.

46.

Scattered waves are produced at ________(a) Rough surface(b) Shadowed region(c) Smooth surface(d) HorizonI have been asked this question in an internship interview.The doubt is from Scattering topic in portion Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

Correct CHOICE is (a) Rough surface

Explanation: Scattered waves are produced by rough surfaces, small OBJECTS or by other IRREGULARITIES in the channel. In practice, foliage, street SIGNS, and lamp posts induce scattering in a mobile COMMUNICATION system.

47.

For predicting the field strength in a given service area, it is essential to estimate ______(a) Polarization(b) Magnetic field(c) Height of transmitter(d) Signal attenuationI had been asked this question by my college professor while I was bunking the class.My doubt stems from Diffraction in chapter Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

Right OPTION is (d) Signal attenuation

Best explanation: Estimating the signal attenuation caused by diffraction of radio waves over hills and buildings is ESSENTIAL in predicting the field STRENGTH in a given service area. In PRACTICE, prediction is a process of theoretical approximation modified by necessary empirical CORRECTIONS.

48.

What is the case of reflection, in course of second medium being a perfect conductor?(a) Loss of energy during absorption(b) Total energy reflected back to first medium(c) Partly transmission and reflection(d) Total energy transmitted into second mediumThe question was posed to me in an online interview.This question is from Reflection topic in portion Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

Correct answer is (b) TOTAL energy reflected BACK to FIRST medium

Easiest explanation: If the SECOND medium is perfect conductor, then all incident energy is reflected back into the second medium. There is no loss of energy during absorption.

49.

Propagation model that characterize rapid fluctuation is called _________(a) Hata model(b) Fading model(c) Large scale propagation model(d) Okumura modelThe question was asked during a job interview.Origin of the question is Free Space Propagation Model topic in section Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

Right choice is (b) Fading model

For explanation I would say: Fading MODELS characterize the rapid fluctuations of the received signal strength over very short travel distance (a few WAVELENGTHS) or SHOT time DURATIONS (on the order of seconds).

50.

In ionosphere propagation, waves arriving at the receiving antenna using the phenomenon of _______(a) Scattering(b) Refraction(c) Diffraction(d) RadiationI got this question in an online quiz.I want to ask this question from Scattering in chapter Mobile Radio Propagation: Large – Scale Path Loss of Wireless/Mobile

Answer»

Correct choice is (a) Scattering

The explanation: Scattering is a general PHYSICAL process where some forms of radiation, such as LIGHT, sound, or moving particles, are forced to deviate from a straight TRAJECTORY by ONE or more PATHS. It is due to localized non-uniformities in the medium through which they pass.