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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
401. |
If the de-Broglie wavelength of a proton is `10^(-13)` m, the electric potentia through which it must have been accelerated isA. `4.07xx10^4 V`B. `8.15xx10^4 V`C. `8.15xx10^3 V`D. `4.07xx10^5 V` |
Answer» Correct Answer - B `:. lambda = (h)/(sqrt2qvm)` `V = (h^2)/(2qmlambda^2)` |
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402. |
A proton and an alpha - particle are accelerated through same potential difference. Then, the ratio of de-Broglie wavelength of proton and alpha-particle isA. `sqrt2`B. `(1)/(sqrt2)`C. `2sqrt2`D. None of these |
Answer» Correct Answer - C `:. lambda = (h)/(sqrt2qvm) or lambda prop (1)/(sqrtqm)` `:. (lambda_p)/(lambda_(alpha)) =(sqrtqm)_(alpha)/(sqrtqm)_p =sqrt(2xx4)/sqrt(1xx1) = 2sqrt2` |
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403. |
Half-life of a radioactive substance `A` is two times the half-life of another radioactive substance `B`. Initially, the number of `A` and `B` are `N_(A)` and `N_(B)`, respectively . After three half-lives of `A`, number of nuclei of both are equal. Then, the ratio `N_(A)//N_(B)` is .A. `1//4`B. `1//8`C. `1//3`D. `1//6` |
Answer» Correct Answer - B |
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404. |
Hydrogen gas in the atomic state is excited to an energy level such tht the electrostatic potential energy of H-atom becomes `-1.7 eV`. Now, a photoelectric plate having work function w=2.3 eV is exposed to the emission spectra of this gas. Assuming all the transitions to be possible, find the minimum de-Broglie wavelength of the ejected photoelectrons. |
Answer» Correct Answer - C `U = - 1.7 eV` `:. E = (U)/(2) =- 0.85 eV = (-13.6)/(n^2)` `:. N =4 ` Ejected photoelectron will have minimum de-Broglie wavelength corresponding to transition from n = 4 to n=1. `Delta E = E_4 -E_1 =- 0.85 - (-13.6)` = 12.75 eV `K_(max) = DeltaE - W = 10.45 eV` `:. lambda = sqrt((150)/(10.45)) Å` (for an electron)` = 3.8 Å |
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405. |
A radioactive source in the form of a metal sphere of diameter 3.2×10^−3m emits β-particle at a constant rate of 6.25×10^10particle/sec. The source is electrically insulated and all the β-particle are emitted from the surface. The potential of the sphere will rise to 1 V in timeA. `180 mus`B. `90 mus`C. `18mus`D. `9mus` |
Answer» Correct Answer - C |
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406. |
An electron and a proton are seperated by a large distance and the electorn approaches the proton with a kinectic energy of 2 eV. If the electron is captured by the proton to form a hydrogen atom in the ground state, what wavelength photon would be given off? |
Answer» Correct Answer - C Energy of electron in ground state of hydrogen atom is -13.6 eV. Earlier it had a kinetic energy of 2 eV. Therefore, energy of photon released durig formation of hydrogen atom, `DeltaE = 2 - (-13.6) = 15.6 eV` `:gt lambda = (12375)/(DeltaE) = (12375)/(15.6)` =793.3 Å` |
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407. |
An electron and a proton are separated by a large distance and the electron approaches the proton with a kinetic energy of 2 eV. If the electron is captured by the proton to form a hydrogen atom in the ground state, what wavelength photon would be given off?A. `1262.2 Å`B. `793.3 Å`C. `1204.6 Å`D. `942.6 Å` |
Answer» Correct Answer - B |
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408. |
An electron and a proton are separated by a large distance and the electron approaches the proton with a kinetic energy of 2 eV. If the electron is captured by the proton to form a hydrogen atom in the ground state, what wavelength photon would be given off?A. `2.4 eV`B. `2.7 eV`C. `2.9 eV`D. `5.4 eV` |
Answer» Correct Answer - B |
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409. |
The frequencies of electromagnetic waves employed in space communication lie in the range of -A. `10^(4) Hz " to " 10^(7) Hz`B. `10^(4) Hz " to " 10^(11) Hz`C. `1 Hz " to " Hz`D. `1 Hz " to " 10^(11) Hz` |
Answer» Correct Answer - B |
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410. |
Two identical p=- a junctions may be connected in seres in which a bettery in three ways , fig . The potential drops access the two p - n junction are equal in A. circuit `1` and circuit`2`B. circuit `2` and circuit`3`C. circuit `3` and circuit`1`D. circuit `1` only |
Answer» Correct Answer - B Since and Alaminium are trivalent are in series , therefore the potential drop acros , be propotional will be equal , the potaltial will equal its circuit I , the two p -n junction are atteched such that the one is biased (low resistant) and after is reverse biased (high resistence ) whererase in the ather two circuit both are forward biased or reversed biased |
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411. |
which of the following are not electromagnetic waves ?A. cosmic raysB. `Gamma rays`C. `beta- rays`D. X- rays |
Answer» Correct Answer - C `beta - rays` are fast moving beam of electrons |
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412. |
a p -n juction (D) shown in the figure can act an a rectifier An alternatting current source (V) is connected in the circuit The corrent (I ) in the resistor® can be shown by :A. B. C. D. |
Answer» Correct Answer - B We know that a single p -n diade connected to an a- c souece acts as a wave rectifier [ forward biased in one half cycle and reverse biased in the other half cycle ] |
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413. |
In the forward blas arrangement of a `p-n` junction rectifier , the `p` and is connected to the ….. Terminal of the bettery and the direction of the currect is from …… to …. In the reclifier . |
Answer» Correct Answer - A Positive , `p- part , n- part |
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414. |
The part of a transistor which is most heavily doped to product large number of majority carriers isA. emmiterB. baseC. collectorD. can be any of the above three |
Answer» Correct Answer - A Emitted sands majority charge carriers toward the collector . Therefore is most heavily doped |
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415. |
A full - wave rectifier circult along the out - put is shown in figure . The contribution (s) from the diode `1` is are .` A. `C`B. `A,C`C. `B,D`D. `A,B,C,D` |
Answer» Correct Answer - B As shown in the fig (i) during one half cycle the reversed biased and bence non conducting. `(# JMA_MP_C17_037_S01.png" width="80%"> During the ofter half cycle, diode (i) gets forward biased and is conducting . Thus diode (1) conduct in the ofter so the correct option is (b) (a and c) |
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416. |
The energy band gap is maximum inA. metalsB. superoonductorsC. insulatorsD. semiconductors |
Answer» Correct Answer - C The energy band gap is maximum in insulators |
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417. |
The probbility of electrons to be found in the conduction band of an intrinsit semiconductor at a finile temperatureA. increase exponenially with increases band gapB. decreases exponenially with increases band gapC. decreases with increases temperatureD. is independent of the temperature and the band gap |
Answer» Correct Answer - B KEY CONCEPT: For a semi condactor `n = n_(0)e^(bar Eg//kT)` where `n_(0) = no ` of free electrons at absolute zero `n = no` of free electron at T kelvin, E_(g)= Energy gap , k = Boizmana constant` . As E_(g) ` increase , `n` decrease exponentially. |
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418. |
By increasing the temperature , the specific of a conductor and a semiconductorA. increases for bothB. decrases for bothC. increases, decreasesD. decreases , increases |
Answer» Correct Answer - C Specific resistance is resistively which is given by `p = (m)/(ne^(2) tau) ` where `n = no` , of free electron per unit valume and `tau = `average relacation time for a conducter with rise in temperatute and `tau `decreases But decreases in `tau` is more dominant than increase in `n` resulting an increase in the value of p for a semiconducter with rise in temperatute and `tau `increases and `tau` decreases but the increases i `n` more dominant than decrease in `tau` resulting an decrease is the value of p |
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419. |
If `N_(0)` is the original mass of the substance of half - life period `t_(1//2) = 5 year` then the amount of substance left after `15` year isA. `N_(0)//8`B. `N_(0)//16`C. `N_(0)//2`D. `N_(0)//4` |
Answer» Correct Answer - A After every half - life , the mass of the substance reduces to half its initial value `N_(0) overset(5year)rarr N_(0)/(2) overset(5 years)rarrN_(0)/(2^(2)) overset(5 years)rarrN_(0)/(8)` |
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