InterviewSolution
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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
A particle having mass m and charge q is projected at an angle of 75° to the horizontal with a speed u. A uniform electric field `E=(mg)/(q)` exists in horizontal direction. Find the time after projection when the velocity of particle makes an angle of 45° with horizontal. |
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Answer» Correct Answer - `u/(2sqrt(2g))` |
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| 2. |
A particle of mass m and charge q is projected into a uniform magnetic field `underset(B)to=-B_(0)hatK` with velocity `underset(V)to-V_(0)hati` from origin. The position vector of the particle at time t is `underset(r)to`. Find the impulse of magnetic force on the particle by the time `underset(r)to.underset(V)to` becomes zero for the first time. |
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Answer» Correct Answer - `2 mv_(0)hati` |
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| 3. |
AB and CD are two parallel planes perpendicular to the X axis. There is a uniform magnetic field (B) in the space between them directed in negative Z direction. Width of the region having field is d and rest of the space is hav- ing no field. A particle having mass m and charge + q enters the region with a velocity V making an angle q with the X direction as shown. (a) Find the values of d for which the particle will come out of the magnetic field crossing CD.(b) For `d=((sqrt2-1)/(2))(mv)/(qB)` and `0=(pi)/(6)` find the angular deviation in the path of the particle. (c) Find the deviation in path of the particle if `d=(5mv)/(4qB)(1-sin 0)` |
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Answer» Correct Answer - `(a) dlt(mv)/(qG)(1-sin 0) (b) 15^(@)` `(c) pi-20` |
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