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51.

The minimum packet size of Ethernet is(a) 81 bytes(b) 75 bytes(c) 72 bytes(d) 64 bytesThe question was asked in semester exam.Question is taken from Multiple Access Techniques for LAN and Access Algorithms in portion Multiplexing and Multiple Access of Digital Communications

Answer»

Right answer is (c) 72 BYTES

To explain I WOULD say: The minimum packet size is 72 bytes, consisting of 8 BYTE preamble, 14 byte header, 46 byte data, 4 byte parity.

52.

LAN uses _________ cables.(a) Low bandwidth(b) High bandwidth(c) Low & High bandwidth(d) None of the mentionedThe question was posed to me in an online quiz.Origin of the question is Multiple Access Techniques for LAN and Access Algorithms topic in chapter Multiplexing and Multiple Access of Digital Communications

Answer» CORRECT choice is (b) High bandwidth

To EXPLAIN I WOULD say: LOCAL area network uses high bandwidth cables for designing.
53.

The maximum packet size of Ethernet is(a) 1426 bytes(b) 1526 bytes(c) 1256 bytes(d) 1626 bytesThe question was asked by my college professor while I was bunking the class.This key question is from Multiple Access Techniques for LAN and Access Algorithms in portion Multiplexing and Multiple Access of Digital Communications

Answer»

Correct answer is (B) 1526 bytes

Best EXPLANATION: The maximum PACKET size of Ethernet is 1526 bytes where a byte is 8 bits.

54.

A local area network can be used to interconnect(a) Computers(b) Terminals(c) Printers(d) All of the mentionedThis question was posed to me during an online exam.Asked question is from Multiple Access Techniques for LAN and Access Algorithms topic in section Multiplexing and Multiple Access of Digital Communications

Answer»

The correct choice is (d) All of the mentioned

Easy explanation: A local area network can be USED to interconnect computers, terminals, printers and so on located WITHIN a building or a small SET of BUILDINGS.

55.

Which needs precise time coordination?(a) CDMA(b) TDMA(c) CDMA & TDMA(d) None of the mentionedI got this question in an internship interview.I'm obligated to ask this question of Spread Spectrum, TDMA and FDMA topic in portion Multiplexing and Multiple Access of Digital Communications

Answer»

Right OPTION is (b) TDMA

To elaborate: CDMA when COMPARED to TDMA does not NEED precise time COORDINATION among various simultaneous transmitters.

56.

CDMA is(a) Similar to FDMA(b) Similar to TDMA(c) Combination of both(d) None of the mentionedThe question was asked in unit test.Query is from Spread Spectrum, TDMA and FDMA in division Multiplexing and Multiple Access of Digital Communications

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The CORRECT answer is (c) COMBINATION of both

The best explanation: CODE DIVISION multiple access is the technique which is the combination of both TDMA and FDMA.

57.

Frequency modulation technique involves(a) Data modulation(b) Frequency hopping modulation(c) Data & Frequency hopping modulation(d) None of the mentionedI have been asked this question in an interview for internship.Question is from Spread Spectrum, TDMA and FDMA topic in chapter Multiplexing and Multiple Access of Digital Communications

Answer»

The CORRECT answer is (c) Data & Frequency hopping modulation

Best explanation: The FH modulation is considered as a TWO step PROCESS. It includes data modulation and frequency hopping modulation.

58.

The maximum waiting time before transmission of a packet is(a) (M-1)T/M(b) (M-1)M/T(c) (M+1)T/M(d) (M+1)M/TThis question was addressed to me in exam.This is a very interesting question from Spread Spectrum, TDMA and FDMA in section Multiplexing and Multiple Access of Digital Communications

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The correct ANSWER is (a) (M-1)T/M

Easiest explanation: The MAXIMUM WAITING time before TRANSMISSION of a PACKET is given by (M-1)T/M.

59.

Which has a lesser average packet delay?(a) FDMA(b) TDMA(c) Dynamic FDMA(d) None of the mentionedThe question was posed to me in homework.I'm obligated to ask this question of Spread Spectrum, TDMA and FDMA topic in division Multiplexing and Multiple Access of Digital Communications

Answer»

Right answer is (B) TDMA

Easiest EXPLANATION: Both TDMA and FDMA has equivalent PERFORMANCE but when it comes to average PACKET delay TDMA has lesser delay than FDMA.

60.

Which method is efficient?(a) Fixed assignment(b) Dynamic allocation(c) Fixed assignment & Dynamic allocation(d) None of the mentionedThe question was posed to me during an interview for a job.This is a very interesting question from Spread Spectrum, TDMA and FDMA in section Multiplexing and Multiple Access of Digital Communications

Answer» CORRECT choice is (B) DYNAMIC allocation

Easy explanation: Dynamic allocation METHOD is more efficient than FIXED assignment as any slot won’t be wasted unnecessarily.
61.

Uncertainty in the delay measurement is _______ to rise time of the pulse.(a) Directly proportional(b) Inversely proportional(c) Not related(d) None of the mentionedI got this question in an international level competition.My enquiry is from Spread Spectrum, TDMA and FDMA topic in division Multiplexing and Multiple Access of Digital Communications

Answer»

Correct option is (a) Directly proportional

To EXPLAIN I would say: UNCERTAINTY in the delay MEASUREMENT is directly proportional to the rise time of the PULSE and inversely proportional to the bandwidth of the signal pulse.

62.

The preamble consists of(a) Synchronization(b) Addressing(c) Error control sequence(d) All of the mentionedI had been asked this question in class test.Asked question is from Spread Spectrum, TDMA and FDMA topic in section Multiplexing and Multiple Access of Digital Communications

Answer»

Correct ANSWER is (d) All of the mentioned

Easy EXPLANATION: The preamble PORTION consists of synchronization, addressing and error CONTROL SEQUENCES.

63.

Each satellite has ______ transponders.(a) 10(b) 12(c) 15(d) 18The question was posed to me by my school teacher while I was bunking the class.My query is from Spread Spectrum, TDMA and FDMA in division Multiplexing and Multiple Access of Digital Communications

Answer»

Correct OPTION is (b) 12

The best explanation: Each satellite has 12 TRANSPONDERS with a BANDWIDTH of 36 MHZ each.

64.

In spread spectrum technique, the desired signal is multiplied _____ and interference signal is multiplied _____(a) Once, twice(b) Twice, once(c) Twice, thrice(d) Thrice, twiceThe question was posed to me during a job interview.My query is from Spread Spectrum, TDMA and FDMA topic in chapter Multiplexing and Multiple Access of Digital Communications

Answer»

The correct answer is (B) Twice, once

Explanation: In SPREAD SPECTRUM technique, the desired signal is multiplied twice and INTERFERENCE signal is multiplied once.

65.

Uncertainty in the delay measurement is _________ to the bandwidth of signal pulse.(a) Directly proportional(b) Inversely proportional(c) Not related(d) None of the mentionedI got this question in semester exam.This intriguing question originated from Spread Spectrum, TDMA and FDMA topic in division Multiplexing and Multiple Access of Digital Communications

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Correct OPTION is (b) Inversely PROPORTIONAL

Explanation: Uncertainty in the DELAY measurement is inversely proportional to the bandwidth of the signal PULSE.

66.

Spread spectrum signals are used for(a) Ranging(b) Determination of position(c) Ranging & Determination of position(d) None of the mentionedI have been asked this question in class test.The origin of the question is Spread Spectrum, TDMA and FDMA topic in division Multiplexing and Multiple Access of Digital Communications

Answer»

The correct ANSWER is (c) Ranging & Determination of position

For explanation I would say: SPREAD SPECTRUM signals are used for ranging or determination of position location.

67.

The radio meter consists of(a) Low pass filter(b) High pass filter(c) Band pass filter(d) Band reject filterThis question was addressed to me in an interview for internship.My question is based upon Spread Spectrum, TDMA and FDMA topic in portion Multiplexing and Multiple Access of Digital Communications

Answer»

Correct choice is (c) Band PASS filter

Explanation: The radio meter CONSISTS of band pass filter, SQUARING circuit and INTEGRATING circuit.

68.

Jamming is caused by(a) Multipath(b) Natural phenomena(c) Multipath & Natural phenomena(d) None of the mentionedI had been asked this question in my homework.Enquiry is from Spread Spectrum, TDMA and FDMA in chapter Multiplexing and Multiple Access of Digital Communications

Answer» CORRECT choice is (c) Multipath & NATURAL phenomena

Easy EXPLANATION: JAMMING can be CAUSED by natural phenomenon and also is caused by multipath.
69.

Which system makes the detection difficult for all users other than the intended users?(a) Low probability of intercept(b) Low probability of detection(c) Low probability of intercept & detection(d) None of the mentionedI had been asked this question in a job interview.I need to ask this question from Spread Spectrum, TDMA and FDMA topic in portion Multiplexing and Multiple Access of Digital Communications

Answer»

The CORRECT answer is (C) Low probability of intercept & DETECTION

Easiest explanation: Low probability of detection or low probability of intercept is a system which makes the detection difficult for ANYONE but the intended USERS.

70.

Gaussian noise has _____ power spread _____ over all frequencies.(a) Zero, uniformly(b) Zero, non uniformly(c) Infinite, uniformly(d) Infinite, non uniformlyThe question was asked in an international level competition.My query is from Spread Spectrum, TDMA and FDMA in portion Multiplexing and Multiple Access of Digital Communications

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Correct ANSWER is (C) Infinite, uniformly

To elaborate: Gaussian noise is a mathematical MODEL which has infinite POWER spread uniformly over all FREQUENCIES.

71.

In which modulation schemes, the spreading of spectrum occurs?(a) Frequency modulation(b) Amplitude modulation(c) Frequency & Amplitude modulation(d) None of the mentionedI had been asked this question during an internship interview.This question is from Spread Spectrum, TDMA and FDMA in section Multiplexing and Multiple Access of Digital Communications

Answer» CORRECT choice is (a) Frequency modulation

The explanation is: In modulation schemes such as frequency modulation and PULSE code modulation spreading of spectrum occurs but it cannot be CONSIDERED as types of spread spectrum technique.