InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 201. |
Find the product by suitable arrangement: 285 x 5 x 60 |
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Answer» 285 x 5 x 60 = 284 x (5 x 60) = 284 x 300 = 85500 |
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| 202. |
Find the product by suitable arrangement:125 x 40 x 8 x 25 |
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Answer» 125 x 40 x 8 x 25 = (125 x 8) x (40 x 25) = 1000 x 1000 = 1000000 |
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| 203. |
Find the product by suitable arrangement:4 x 166 x 25 |
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Answer» 4 x 166 x 25 = (4 x 25) x 166 = 100 x 166 = 16600 |
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| 204. |
Find the product by suitable arrangement 2 x 1768 x 50 |
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Answer» 2 x 1768 x 50 = (2 x 50) x 1768 = 100 x 1768 = 176800 |
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| 205. |
Find the product by suitable arrangement:625 x 279 x 16 |
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Answer» 625 x 279 x 16 = (625 x 16) x 279 = 10000 x 279 = 2790000 |
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| 206. |
Namita travels 20 km 50 m every day. Out of this she travels 10 km 200 m by bus and the rest by auto. How much distance does she travel by auto? |
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Answer» Total distance travel = 20 km 50 m = 20.050 km Distance travelled by bus = 10 km 200 m = 10.200 km Distance travelled by auto = 20.050 – 10.200 = 9.850 km Therefore, 9.850 km distance travels by auto. |
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| 207. |
Find the value of: (–7) + (–9) + 4 + 16 |
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Answer» (–7) + (–9) + 4 + 16 = –7 – 9 + 4 + 16 = –16 + 20 = 4 |
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| 208. |
Find the sum of:-50, -200 and 300 |
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Answer» (–50) + (–200) + 300 = –50 – 200 + 300 = –250 + 300 = 50 |
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| 209. |
Write each of the following as decimals:20+9+4/10+1/100 |
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Answer» 20 + 9 + 0.4 + 0.01 = 29.41 |
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| 210. |
Write each of the following as decimals:7/10+6/100+4/1000 |
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Answer» 0.7 + 0.06 + 0.004 = 0.764 |
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| 211. |
Find the sum of:-312, 39 and 192 |
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Answer» (–312) + 39 + 192 = –312 + 231 = –81 |
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| 212. |
Write each of the following as decimals:137+5/100 |
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Answer» 137 + 0.05 = 137.05 |
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| 213. |
Find the sum of:-52 and 52 |
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Answer» (–52) + 52 = 0 |
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| 214. |
Find the sum of:137 and -354 |
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Answer» 137 + (–354) = 137 – 354 = –217 |
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| 215. |
Encircle the odd one of the following(a) (–1, –2) (b) (–5, +2) (c) (–4, +1) (d) (–9, +7) |
| Answer» (d) (–9, +7) | |
| 216. |
Which of the following does not represent an integer?(a) 0 ÷ (– 7) (b) 20 ÷ (– 4) (c) (– 9) ÷ 3 (d) (– 12) ÷ 5 |
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Answer» (-12) ÷ 5 is not a integer |
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| 217. |
For a non-zero integer a which of the following is not defined?(a) a ÷ 0 (b) 0 ÷ a (c) a ÷ 1 (d) 1 ÷ a |
| Answer» (a) a ÷ 0 is not defined a non zero integer | |
| 218. |
Which of the following shows the maximum rise in temperature?(a) 23° to 32° (b) – 10° to + 1° (c) – 18° to – 11° (d) – 5° to 5° |
| Answer» (b) – 10° to + 1° msximum rise of temprerature | |
| 219. |
If a and b are two integers, then which of the following may not be an integer?(a) a + b (b) a – b (c) a × b (d) a ÷ b |
| Answer» (d) a ÷ b is not an integer | |
| 220. |
(– 16) ÷ 4 is not same as(a) ( – 4) ÷ 16 (b) – ( 16 ÷ 4) (c) 16 ÷ (– 4) (d) – 4 |
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Answer» (– 16) ÷ 4 is not same as ( – 4) ÷ 16 Ans (a) |
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| 221. |
( – 43) × ( – 99) + 43 is equal to(a) 4300 (b) – 4300 (c) 4257 (d) – 4214 |
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Answer» ( – 43) × ( – 99) + 43 is equal to 4300 Ans (a) |
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| 222. |
Add without using number line: (–13) + (+18) |
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Answer» (–13) + 18 = 5 |
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| 223. |
Add without using number line:11 + (–7) |
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Answer» 11 + (–7) = 11 – 7 = 4 |
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| 224. |
Add without using number line: (–10) + (+19) |
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Answer» (–10) + (+19) = –10 + 19 = 9 |
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| 225. |
Express as km using decimals:8 m |
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Answer» 1 m = 1/1000 km 8 m = 1/1000 x 8 = 0.008 km |
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| 226. |
Express as rupees using decimals:20 paise |
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Answer» 1 paisa = Rs.1/100 20 paise = 1/100 x 20 = Rs.0.05 |
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| 227. |
Express as rupees using decimals:50 rupees 90 paise |
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Answer» 1 paisa = Rs.1/100 50+90 paise = 50 + 1/100 x 90 = Rs.50.90 |
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| 228. |
Express as km using decimals:70 km 5 m |
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Answer» 1 m = 1/1000 km 70 km 5 m = 70 + 1/1000 x 5 = 70.005 km |
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| 229. |
Express as kg using decimals:100 g |
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Answer» 1 g = 1/1000 kg 100 g = 1/1000 x 100 = 0.1 kg |
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| 230. |
Express as kg using decimals:2 g |
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Answer» 1 g = 1/1000 kg 2 g = 1/1000 x 2 = 0.002 kg |
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| 231. |
Express as km using decimals:8888 m |
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Answer» 1 m = 1/1000 km 8888 m = 1/1000 x 8888 = 8.888 km |
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| 232. |
Express as rupees using decimals:725 paise |
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Answer» 1 paisa = Rs.1/100 725 paise = 1/100 x 725 =725/100 = Rs.7.25 |
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| 233. |
Express as rupees using decimals:75 paise |
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Answer» 1 paisa = Rs.1/100 75 paise = 1/100 x 75 = Rs.0.75 |
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| 234. |
Express as meters using decimals:2 m 45 cm |
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Answer» 1 cm = 1/100 m 2 m 45 cm = 2 + 1/100 x 45 = 2.45 m |
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| 235. |
Express as meters using decimals:6 cm |
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Answer» 1 cm = 1/100 m 6 cm = 1/100 x 6 = 0.06 m |
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| 236. |
Express as meters using decimals:15 cm |
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Answer» 1 cm = 1/100 m 15 cm = 1/100 x 15 = 0.15 m |
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| 237. |
Express as kg using decimals:26 kg 50 g |
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Answer» 1 g = 1/1000 kg 26 kg 50 g = 26 + 1/1000 x 50 = 26.050 kg |
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| 238. |
Express as cm using decimals:5 mm |
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Answer» 1 mm = 1/10 cm 5 mm = 1/10 x 5 = 0.5 cm |
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| 239. |
Express as meters using decimals:419 cm |
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Answer» 1 cm = 1/100 m 419 cm = 1/100 x 419 = 419/100 = 4.19 m |
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| 240. |
[(– 8) × ( – 3)] × (– 4) is not equal to(a) (– 8) × [(– 3) × (– 4)] (b) [(– 8) × (– 4)] × (– 3)(c) [(– 3) × (– 8)] × (– 4) (d) ( – 8) × (– 3) – (– 8) × (– 4) |
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Answer» [(– 8) × ( – 3)] × (– 4) is not equal to ( – 8) × (– 3) – (– 8) × (– 4) Ans (d) |
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| 241. |
Find the H.C.F. of the following numbers:70, 105, 175 |
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Answer» Factors of 70 = 2 x 5 x 7 Factors of 105 = 3 x 5 x 7 Factors of 175 = 5 x 5 x 7 H.C.F. = 5 x 7 = 35 |
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